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@@gajendrapurohit sir intergation of f(z) dz = pi/under root a^2-b^2 is formula u mistake their do something about that u have given this formula intergation of f(z) dz = 2pi/under root a^2-b^2
He forgot 1 step, when substituting z=e^(i theta), the limits of the integral would become z=-1 to z=1, so in the answer there is no z, so we will get (pi)/(root(a^(2)-b^(2)))+(pi)/(root(a^(2)-b^(2)))=(2pi)/(root(a^(2)-b^(2)))
From 4:40 to 4:46 sir u have not taken lcm 2 of that quadratic equation ,or fir last m aapne 2 se 2 bhi nhi cancel kiya agr krte toh answer sir pi/root a^2+b^2 aara hota jo ki glt hota, so pls check Q1
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Sir in first problem when we substitute R1 in integral of f(z) dz then it should come πi/√a^2-b^3 But it is coming 2πi/√a^2-b^2 Because 2 is present in denominator and also in numerator . Please check it and tell me sir.
@@AbhishekMaurya-jp4ou ek extra 2 uper aayega jab substitute karenge thetha ki value in terms of z sir galti se wo likhna bhul gye h 😐 baki ans 2π/√(a^2-b^2) hi aayega
Ur final ans is right, But in a step at 4:46 us didn't write 2 in numerator and also at final step of first que u hav cut the denominator 2directly That shows u have memorized the answer
only those who have done it in the copy while watching knows that he memorises most of the answers , also does silly mistakes due to them only.. but his delivering knowledge is commendable .. :) and u r right that 2/2 will get cancelled in the end and will give the answer ..
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Sir 4:41 par ched mai 2 tha vah kaha gaya Mai samaj jata par ek book hai usmai bhi aise hi 2 ka kuch locha hua hai Kya 2 ko kahi par cut karna hai ya mistake hai?
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At 4.47sec u have take Lcm but u dont write 2 at uper side along dz.. Due to this your whole prooof gonna wrong check at lst step where u cancil out i,b but thier is 2 also that have been cancil and your answer become π/√a²-b² but answer is 2π/√a²-b² ✔check this out in vedio....
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At 21:58 you have ignored the - sign while writing the final answer..but considering it...the answer would be in negative..which doesn't match with the answer..sir..please correct me if I am wrong. Thank you.
Sir one thing I noticed is that in all of these problems we had limit from 0 to 2π . So what if we had different limits . For example, 0 to π/2 or -π to 3π/2 ...etc . Because when we convert our original function into a complex function and solve it using contour integration which has no limits of integration but instead a closed contour .
If limit would be 0 to π/2 then the contour will only lie in quadrant 1 and hence would not be closed. Usually we consider a circle as contour which swept 2π angle
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Int.(4z^2-4z+1)/{(z-1)(z^2+4)} about c z=1 by solve both methods residue & Cauchy integral method please sir solve this question imigiatly it's more important question with in two days
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Sir , 8.59 min last answer.... The extra 2 is nothing but that is in 1st putting value ((d theta / a+b cos theta ) = (1/i)( 2/(2az+bz^2+b ))...you miss that 2 ...
At 12:42 what happened at find the poles , how (1-a^2) came? It is nor link don't know sri tharachary method but still i don't know , someone please explain😢
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very HELPFUL SIR IN TODAY WORLD THERE IS NOONE WHO HELPS WITHOUT ASKING MONEY!!!!!!!!!!!!!
ON OTHER HAND THERE ARE GOD LIKE PEOPLE AND UR ONE OF THEM....
THNKS A LOT SIR KEEP IT UP
MAY U LIVE LONGER!!!!!!!!!!!!!!!
Thanks Sir for making Engineering Mathematics simplified and easier .
You helped me score good marks in my exams .
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@@gajendrapurohit sir intergation of f(z) dz = pi/under root a^2-b^2 is formula u mistake their do something about that
u have given this formula
intergation of f(z) dz = 2pi/under root a^2-b^2
lol i am continuing this lecture series like an anime series, so fun and exciting to watch and analyzing complex analysis.. thankyou so much sir
Which semester you are in bro?
@@riteshrk18 now 3rd
@@mafiaboss9876 Which semester you are in bro?
@@riteshrk18 isn't it obvious
Anime ka 14
Sir, at 9:01 you didnt cancel out the 2. You will get an extra 2 in the numerator because you forgot the 2 at 4:46. Otherwise, great job sir!
Even after solving wrong and getting answer right is called mugging.
But thank you sir.
Yes, and there is no error in the solution. I think the result will be without '2' in the numerator. I was also confused there.
He forgot 1 step, when substituting z=e^(i theta), the limits of the integral would become z=-1 to z=1, so in the answer there is no z, so we will get (pi)/(root(a^(2)-b^(2)))+(pi)/(root(a^(2)-b^(2)))=(2pi)/(root(a^(2)-b^(2)))
2 baar 2 khaya sir n lekin bro method daikho aur smjho....itni choti choti ghaltya mat nikalo
From 4:40 to 4:46 sir u have not taken lcm 2 of that quadratic equation ,or fir last m aapne 2 se 2 bhi nhi cancel kiya agr krte toh answer sir pi/root a^2+b^2 aara hota jo ki glt hota, so pls check Q1
I agree
Yes, u are right
Ya
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Sir, I can't thank you enough for making this types of tutorial. From Bangladesh.
Sir contour integral ke proof main last main 2 and 2 cencel hoga and result (pi /√a^2-b^2) hoga [8:56 minutes]
@@RAAGpmr second or third step me mistek hai 2/i hoga vahi se ye continue hoga
sir at 4:40 while taking out constant it should be 2/i .
bhai sir corrected in the end
Sir you saved me from failing in my end sem exam. Thanks a lot!
you have power of making mathematics easy ~huge fan
sir, you forget to write (2) in the equation at 4:46sec
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Yes , there is a mistake
you are right bro
@@gajendrapurohit no sir he asked you to write 2 in 4:46 sec
Correct bros
Sir in first problem when we substitute R1 in integral of f(z) dz then it should come πi/√a^2-b^3
But it is coming 2πi/√a^2-b^2
Because 2 is present in denominator and also in numerator .
Please check it and tell me sir.
Yes u are right sir plz check it
In question remove 2 bro
yes you are right i also faced problem in it
my answer is pie/√a^2-b^2
@@AbhishekMaurya-jp4ou ek extra 2 uper aayega jab substitute karenge thetha ki value in terms of z sir galti se wo likhna bhul gye h 😐 baki ans 2π/√(a^2-b^2) hi aayega
Sir ne LCM lene me mistake ki h LCM le kr 2 aayga starting me hi
Keep up the good work sir .
हिंदी भाषा में एक standard lecture 👏👏
Ur final ans is right,
But in a step at 4:46 us didn't write 2 in numerator and also at final step of first que u hav cut the denominator 2directly
That shows u have memorized the answer
mujah lagta hai ki 2 tha he nahi question mai
only those who have done it in the copy while watching knows that he memorises most of the answers , also does silly mistakes due to them only.. but his delivering knowledge is commendable .. :) and u r right that 2/2 will get cancelled in the end and will give the answer ..
Sir aapki teaching style bhut achi h .....mai net physics ki student hu ....mathematical physics k lie ....mujhe aapki video bhut achi lagi
Addicted to learn and watch your lectures . Thank you so much sir!
U really saved my day sir !!! Thank you...
👍
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At 4:45 the denominator will be
2az + bz^2 + b ....
U r just an awsm teacher...
9:18 pr 2 bhi cancel ho jayega result becomes π/√a^2-b^2 .sir U missed it
Mast paper gayu sir......all credits go to you sir......thnks a lot
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Tq sir for this amazing lecture
Your lecture was very helpful sir
Tq sir❤
5:01 '2' mission
It was add in our syllabus (AKTU) last year(2018- 19) session
Sir 4:41 par ched mai 2 tha vah kaha gaya
Mai samaj jata par ek book hai usmai bhi aise hi 2 ka kuch locha hua hai
Kya 2 ko kahi par cut karna hai ya mistake hai?
Sir,
R1 : -90/( 8*8*8), minus got missed at timeline 22:16
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@@gajendrapurohit sir ur lecture is very good
Thank you sir because this video is very useful for me.
Thank you sir . Your teaching helps me a lot.
Hlo mem...kya aap 1st grade ki preparation kr rhi ho ??
Sir difficult but way of teaching is fantastic Sir
THANKYOU GURUJI
Sir, you are just the best, thank you so much for your made easy lecture.
You are great sir...love from assam
Sir, at 4:47 the equation will be 2 times the function
Thanks sir for making the video on contour integration
Excellent video keep it up💪💪💪💪💪💪 sir stay strong💪💪 sir
9:26 ans is come out of pi/under root a^2-b^2 because 2 are cancel ❌
Sir AAP jo padhathe PURA samje me aata hai
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Best lecture of you sir
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At 4.47sec u have take Lcm but u dont write 2 at uper side along dz..
Due to this your whole prooof gonna wrong check at lst step where u cancil out i,b but thier is 2 also that have been cancil and your answer become π/√a²-b² but answer is 2π/√a²-b²
✔check this out in vedio....
U r right bro
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Akash kishore yah sir is also human so mistakes take place. But yah you can multiplay your answer with 2 so you got correct one answer.
Sir gajab pdate ho aap🙏🙏
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gurujiiii aaptho greaaattttt
At 21:58 you have ignored the - sign while writing the final answer..but considering it...the answer would be in negative..which doesn't match with the answer..sir..please correct me if I am wrong. Thank you.
Actually sir ignored -ve sign two time first while simplifying the equation and second where you are telling so answer will be same at end
JAI RADHESHYAM JAI HANUMAN JI
wow, sir, your explanation is soo good.
Thankq sir!
Kon se college se ho SRM se ho kya
@@sangishsharma5610 no dtu
@@Ritika1d mera math ka exam aaj hai And I am from SRM ncr
@@Ritika1d itni raat ko reply kar rehe ho Matlab aaapka bhi paper aaj ya Kal hai
sir u r osm.. plzz iska aur videos dalo .... limit. 0 to infinity nd - infinity to infinity plzz
Today evening
Sir, "2" has not been written in equation at 4:46.For that final answer will not come out, I think.
You are the best teacher
Sir at 4:42 there is mistek because if we multiply z to bracket b/2[(Z²+1)/Z] Z will cancel out and we get bZ²/2 + b/2
Sir one thing I noticed is that in all of these problems we had limit from 0 to 2π . So what if we had different limits . For example, 0 to π/2 or -π to 3π/2 ...etc .
Because when we convert our original function into a complex function and solve it using contour integration which has no limits of integration but instead a closed contour .
If limit would be 0 to π/2 then the contour will only lie in quadrant 1 and hence would not be closed.
Usually we consider a circle as contour which swept 2π angle
@@fatimaalishah1881 thank u
thank u
@@fatimaalishah1881
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In first question 2 also cancle or if 2 is not cancle the num and dem both have 2
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@@gajendrapurohit matlab comment bina padhe sab pe same reply kar dete ho sir🤦
@@utkarsh5138 sahi kaha :)
Think 2 cancel ho jayega
Sir kaash ham aapke jitna fast kar sakte maths♥️♥️♥️♥️♥️♥️♥️♥️
Nice explanation sir more video
will do it ne b one ....
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Thanks sir for giving this amazing video
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Thank you very much sir it gives me a lot of help in exams
Very nice tarika samjhane ka
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17:00 pe -3 bahar lia h... Es liye bahar sign change hoga... Sir bhul gye
Bhai usme unhone jab square me tha to cut kaise kr diya ?
@@Bored_wreked kaha prr bhai?
@@peskiss2973 Bhai is series me pura complex analysis nahi hai , conformal mapping and power series sir ne nahi padhaya hi
@@Bored_wreked sir kaafi topic skip kr dete h
@@peskiss2973 Bhai kis University se ho?
Thanks for helping 😊
Marvellous sir ji
Sir if limit lies bw o to pi (or any other),then the soln. would be diff. You should have solved those type of q's
Question no 1 mai 2 rhe gya sir ji jo b k upon mai z k sath tha jiski bjha se last prove dekhne mai problem ho Rahi thi 🤙 but I remember it 🙏🏿🙏🏿
At 4:46 there is not bz^2+bz. There is bz^2+b. Sir corrected it later.
Very nice sir
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Sir in question no .1 you had forgotten 2 in numerator after taking LCM in denominator only z is cancelled 2 wil be still there
बेहतरीन प्रयास आपका सर। क्या इस वीडियो में जो उदाहरण आपने कराए है क्या उनका generalized formula बना सकते क्या
sir what if we have give integration of same function from 0 to pie/2, then how to solve it sir?
8:58 sec par galat solve kiye hai,uper me 2 Ni hoga
Shi kahe sir
Haan
Iska answer 4:45 pe milega jo 2 gayab hua h
Yes, 2 will be canceled.
YOU'RE THE BEST SIR, THANK YOU!!!!
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U are such a great person 🙏🙏, u help me a lot, thanku so much sir 🙏
Int.(4z^2-4z+1)/{(z-1)(z^2+4)} about c z=1 by solve both methods residue & Cauchy integral method please sir solve this question imigiatly it's more important question with in two days
Watch Cauchy integral theorem videos it's very easy
I request to you please solve the question
ask this to themathcoach
Maaza aa gaya❤
Sir, I am from Bangladesh and I follow all of your lectures,,
I need to know about tensor,, do you have any vodeo about tensor?
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@@gajendrapurohit wo puch raha hai ki tensor kya hota hai aur tumne ignore maarte hue apna ye copy paste comment daal diya 🙄🙄
7:13 pm
Tuesday, 4 June 2024 (IST)
Time in Nasirabad, Rajasthan
Really, you are the best
Love you Sir 😍😍😍.
Your videos help me a lot.
Sir kindly make more videos on complex analysis for ma in maths
How do you determine which value of z lies inside of circle and outside of circle
It is sad that nobody acknowledge good content.
Very nicely explained sir.
Thanku so much sir
In the last question you forget - sign in the value of residue,,
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@@Rawat-nn2yq I understand he has done a mistake and it's annoying he doesn't acknowledge but shall we be respectful in the comments :)
Sir please make video on branch points and branch cut..🙏🙏🙏🙏
will do it very soon
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Nice and easy explained sir tq so much
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Thank you sir,your videos on Engineering mathematics are the best😊👍
You Are brilliant Sir 👌
You made some mistake in the middle and you corrected it very cleverly in the last.😄😄But your video was very good.
Sir , 8.59 min last answer....
The extra 2 is nothing but that is in 1st putting value ((d theta / a+b cos theta ) = (1/i)( 2/(2az+bz^2+b ))...you miss that 2 ...
At 12:42 what happened at find the poles , how (1-a^2) came? It is nor link don't know sri tharachary method but still i don't know , someone please explain😢
god may fulfil your wishes.
Sir in qstion 1,at (9:0 timing) in last answer 2 is also going to cancel from (2π i /2√a^2 - b^2 ) ...
Sir! sinx ko replace kar cosx ko lete h to kya itna hi value aayega???
Nehi
Thanks sir pura smaj ma aya ha
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Great video Sir ❤
Sir at the last question there is also negative sign with 4 , so answer should be -5π/32
9:00 i do not understand that 2 in numerator will cancel with the 2 in denominator then how come it is giving 2pi in the answer
Your teaching speed is perfect sir !!!!...Awesome teacher...please do makevideos for power series in complex analysis
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Your lectures are so much helpful for us Sir.
You are the best 👍
Ignore all the negative comments Sir... Because you are really best....👍
At 4:34 there is a mistake .... 2 ka lcm lene k baad upar bhi 2 aayega
very nice explanation sir