Conjugate Surds | How to multiply surds

Two surds are said to be conjugate of each other if their product gives rise to a rational number. From our knowledge of difference of two squares, we know that:
(a + b)(a - b) = a² - b² Similarly,
(√a+√b)(√a-√b) = a² - b²
While √a + √b and √a - √b are not rational, their product (a²-b²) is rational. Hence, √a+√b and √a-√b are conjugates of each other.
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Following the method of congruiate, # 3 should have been a plus + and not a minus -.

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Pls sir am confused about how u work the third question. Because the conjugate sure is positive sign but u used the negative sign.

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[@christopherfokoe6717]

Thank for the clear explanation but I'm confused about question three

[@balogunfemu7861]

Thanks sir, but
Which signs are we going to use? Is it d conjugate sign or the question sign?

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Sir for compound surds can we find conjugate?

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Numbers that can be expressed as p/q where both p and q are integer.

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