i spent an hour trying to find a video that explained a question like this this is the best one i found, I ACTUALLY UNDERSTAND MY HOMEWORK NOW THANK YOU SO MUCH
True. To be on top, just post the questions/topics you need help with. I will provide solution in less than 48 hours. All the Best! Here is related video: ua-cam.com/video/qgdpQVs0_AI/v-deo.html Thanks
I think what confused me about these problems growing up was that we technically are finding the distance and time when Dave reaches Lucy's exact position, rather than when he has officially overtooken her position as first. I guess turning this problem into an inequality would be more correct
I have no idea why TV shows elementary school students doing these types of problems, because I was just introduced to them in my first year of college algebra for calculus.
Help! Dan has challenged Dave to a bicycle race. They will ride 3 miles out of town to the old light house, then turn and ride back. If Dan's speed in the race is 20 mph and Dave's speed is only 16 mph, obviously Dan will reach the light house first, turn back towards town, and pass Dave still riding toward the light house. How far, to the nearest foot, will Dave be from the light house when Dan passes Him? (1 mile = 5280feet)
Teacher , can you please solve this problem : From city A to city B, the bus started at a speed of 48 km/h. After half an hour, a motorcyclist who was traveling at a speed of 60 km/h reached it. The motorcyclist reached the city B and after 12 minutes, he started in the opposite direction , so to city A. At a distance of 12 km from city B, he met the bus. Find the distance from A to B.
If dave left one hour later would it not be plus one hour for him since he left after Lucy? That problem for the question says how far from Niagara did dave overtake her telling us he was behind her. so for their times to be equal you would have to add an hour so that you could find the time.
This is a very simple problem which can be solved by this simple formula: "distance ahead divided by difference in rates equals time to overtake" so for the problem shown, based on the 80km/hr Lucy is 80 km ahead. The difference in rates is 100-80=20km/hr. Using the formula 80÷20=4 hours. Multiply that by the rate of the chase car 4×100=400km. So there! If you need info on how I derived the formula just add a reply here.
Here is the explanation Solving chase problems: "Distance ahead (da) divided by difference in rates (r2 - r1) equals time (t) to overtake" where rates r2 > r1. The derivation is hereby explained: Here Car#1 is ahead by distance da. da. dx Car#1 --------------------xxxxxxxxxxxxxxx r1 da + dx Car#2 xxxxxxxxxxxxxxxxxxxxxxxxxxx r2 Since Car#1 is ahead by distance da. It will have to travel dx distance more to be caught up by Car#2. This will use time t which is equal to the time used up by Car#2. so for Car#1 : dx=r1(t). [Equation 1] For Car#2 : da + dx = r2(t) [Equation 2] Substituting Equation 1 into Equation 2 we get da + r1(t) = r2(t). Combining like terms we get: da = r2(t) - r1(t) or da = ( r2 - r1)t Solving for t: t = da/(r2 -r1) which is the time to overtake.
Please, help🙏😖 I don't understand how to solve the following problem: The last part of a triathlon is 10k(10 kilometers or 10000 meters) run. When runner Aña starts this last running part, she is 600 meters behind runner Bea. But Aña can run faster than Bea: Aña can run (on average) 225 meters each minute, and Be a can run (on average) 200 meters each minute. Who wins, Aña or Bea? If Aña wins, when does she catch up with Bea? If Be a wins, how far behind is Aña when Be a finishes?
Teacher, l have a one request. Could you make a one video in which you can point out how we can approach the most common D=s.t problems by comparing different approaches and reasoning out the essence of the critical thinking. Thank you.
Can I use t + 1 for Lucy's time and just t for Dave's or is it not applicable? Because the other video with the same problem but different given i saw, it used t + 1
Plz i need a video showing this...A man leaves his home at 11:50 a.m and drives to rock city which is 108km away,if he arrives at 2:05p.m..what is average speed throughout the journey
Nice video but very confusing, could you explain why you write on distance 80 which was the speed, then you put on the right of the number 80 t despite is under distance. after you write 100 t - 20 t which is 20 t so 80 and 100 have become distance and time i mean sorry but is very confusing.
i doubt you still need this after 11 months, but you can use the same formulas, just make sure that your final answer is in m/s instead of km/h. the formula for speed is distance/time, so divide 5m by 15s and you get 0.3 recurring (or 0.34 rounded to two decimal places). thus your speed should be 0.34 metres per second if i'm not incorrect.
Thanks. Here is a Playlist on Distance Time Word Problems: in HINDI with Short Tricks: ua-cam.com/video/EJ3wBGM1U_4/v-deo.html in English above Tricks: ua-cam.com/video/TOT9yrikd2s/v-deo.html Standard Question on d-s-t Playlist: ua-cam.com/play/PLJ-ma5dJyAqp7kl0KHKhTpIu0JZfswGlz.html
i spent an hour trying to find a video that explained a question like this
this is the best one i found, I ACTUALLY UNDERSTAND MY HOMEWORK NOW
THANK YOU SO MUCH
Thanks. Here is related playlist: ua-cam.com/video/CyURsM4E57Q/v-deo.html
There is no one to compete with this guy
Thank you so much for helping the helpless guy like me
This is the best explanation to the problem that I have found, thank you!
Here are some related examples: ua-cam.com/video/CyURsM4E57Q/v-deo.html
Thanks
Thank you. this was the simplest explanation so far.
This is by far the best video that i found.
math was incredibly easy in elementary and middle school but in high school it gets really confusing
True. To be on top, just post the questions/topics you need help with. I will provide solution in less than 48 hours. All the Best!
Here is related video: ua-cam.com/video/qgdpQVs0_AI/v-deo.html
Thanks
Anil Kumar i had my math test yesterday and because of you i passed with 83% thank you
Great. Congratulations!
It is your sincere effort.
Share your questions, if possible anil.anilkhandelwal@gmail.com
Thanks and All the Best
after this video, maths turned easy.
after this video, maths turned very easy.
I think what confused me about these problems growing up was that we technically are finding the distance and time when Dave reaches Lucy's exact position, rather than when he has officially overtooken her position as first. I guess turning this problem into an inequality would be more correct
BEST EXPLANATION EVER
GUYZ MATHS YASHIKILISANA BUT HE MADE IT BETTER👌👌
Great stuff! Keep teaching us sir!
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thanks, you are very good at explain math
Thank you so much for this meaningful video :) Now I understand my math questions better! This method is so effective :) THANK YOUUU!!! 😇😇😇
You made it look easy, good old boy. may be not so old but good anyway. Thank you.
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Never to fail again
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Oh my thank you so much you made my life easier. Your explanation is very helpful
I know you know this, but of course it is after 400 km. At 400 km, they will be in a dead heat. d > 400 km. Thank you.
thank you im done physics just going over these while i wait for my power engineering program.
I have no idea why TV shows elementary school students doing these types of problems, because I was just introduced to them in my first year of college algebra for calculus.
Thank you
💚 Thank you.
You are so welcome
it was perfect
Thank you for the help with my test
Thnks u save my marks
You made it simple n clear
Great Job !!
Help! Dan has challenged Dave to a bicycle race. They will ride 3 miles out of town to the old light house, then turn and ride back. If Dan's speed in the race is 20 mph and Dave's speed is only 16 mph, obviously Dan will reach the light house first, turn back towards town, and pass Dave still riding toward the light house. How far, to the nearest foot, will Dave be from the light house when Dan passes Him? (1 mile = 5280feet)
ty you for doing this amazing video sir
You can also use a block model, much easier than this and time friendly specialty on board exam.
Thank you for this video, saved me
Good teacher
Teacher , can you please solve this problem :
From city A to city B, the bus started at a speed of 48 km/h. After half an hour, a motorcyclist who was traveling at a speed of 60 km/h reached it. The motorcyclist reached the city B and after 12 minutes, he started in the opposite direction , so to city A. At a distance of 12 km from city B, he met the bus. Find the distance from A to B.
If dave left one hour later would it not be plus one hour for him since he left after Lucy? That problem for the question says how far from Niagara did dave overtake her telling us he was behind her. so for their times to be equal you would have to add an hour so that you could find the time.
Dave's speed was higher than lucy so he would need less time to catch up
so t - 1 hour is the correct assumption
This is a very simple problem which can be solved by this simple formula: "distance ahead divided by difference in rates equals time to overtake" so for the problem shown, based on the 80km/hr Lucy is 80 km ahead. The difference in rates is 100-80=20km/hr. Using the formula 80÷20=4 hours. Multiply that by the rate of the chase car 4×100=400km. So there! If you need info on how I derived the formula just add a reply here.
Here is the explanation
Solving chase problems:
"Distance ahead (da) divided by difference in rates (r2 - r1) equals time (t) to overtake" where rates r2 > r1. The derivation is hereby explained:
Here Car#1 is ahead by distance da.
da. dx
Car#1 --------------------xxxxxxxxxxxxxxx r1
da + dx
Car#2 xxxxxxxxxxxxxxxxxxxxxxxxxxx r2
Since Car#1 is ahead by distance da. It will have to travel dx distance more to be caught up by Car#2. This will use time t which is equal to the time used up by Car#2.
so for Car#1 : dx=r1(t). [Equation 1]
For Car#2 : da + dx = r2(t) [Equation 2]
Substituting Equation 1 into Equation 2 we get
da + r1(t) = r2(t).
Combining like terms we get: da = r2(t) - r1(t) or da = ( r2 - r1)t
Solving for t: t = da/(r2 -r1) which is the time to overtake.
can you make a vid about it
@@l.a5874 ok. I will do it. Give me a a couple of days.
@@l.a5874 Here you go: ua-cam.com/video/3_ZLSMn_c68/v-deo.html
thank you for thissss. this helped me so much
Please, help🙏😖 I don't understand how to solve the following problem: The last part of a triathlon is 10k(10 kilometers or 10000 meters) run. When runner Aña starts this last running part, she is 600 meters behind runner Bea. But Aña can run faster than Bea: Aña can run (on average) 225 meters each minute, and Be a can run (on average) 200 meters each minute. Who wins, Aña or Bea? If Aña wins, when does she catch up with Bea? If Be a wins, how far behind is Aña when Be a finishes?
I get it but can u send a another word problem like this
Teacher, l have a one request.
Could you make a one video in which you can point out how we can approach the most common D=s.t problems by comparing different approaches and reasoning out the essence of the critical thinking.
Thank you.
Thanks. Here is a list of videos for you: ua-cam.com/play/PLJ-ma5dJyAqp7kl0KHKhTpIu0JZfswGlz.html
I am poor in mathematics what can I do to pass tell me some words so that I can pass mathematics and I hate it
Let me know the area which you do not understand so that I can share some concept based videos with you to begin with. Hope that helps. Thanks
Thanks you so much
Can I use t + 1 for Lucy's time and just t for Dave's or is it not applicable? Because the other video with the same problem but different given i saw, it used t + 1
me too
Thanks
im grade 5 and i have to do this its not ez but im trying👁👄👁
Why do we subtract speed while overtaking?
Good
I don't understand where the second 100 comes from when you open the brackets
As dave drives for t-1 hrs, will the time travelled by him be t-1= 5-1 = 4 hrs?
Exactly what I’m confused about lol
This is so confusing but thanks
Plz i need a video showing this...A man leaves his home at 11:50 a.m and drives to rock city which is 108km away,if he arrives at 2:05p.m..what is average speed throughout the journey
108/(2h 15 min) =108/(135 min) = 4/5 km/min = 48 km/h
thanks
Mr.kuma thank u very much
How 80t and 100(t-1)is equal or same
Since it is the same distance traveled by them. Thanks
Ok sir thank u
This video says that "distance is equal to speed into time" but isn't distance equal to speed times time?
Why is t-1?? Thanks
Nice video but very confusing, could you explain why you write on distance 80 which was the speed, then you put on the right of the number 80 t despite is under distance. after you write 100 t - 20 t which is 20 t so 80 and 100 have become distance and time i mean sorry but is very confusing.
What if the given distance is 5 n.m
and the time given is 15s how it's solve this problem? Plss reply
What the speed?
If you solve this problem ill subscribe.
i doubt you still need this after 11 months, but you can use the same formulas, just make sure that your final answer is in m/s instead of km/h. the formula for speed is distance/time, so divide 5m by 15s and you get 0.3 recurring (or 0.34 rounded to two decimal places). thus your speed should be 0.34 metres per second if i'm not incorrect.
not clear yet mr teacher.could u plz convince me where u get from 100-100?
100 x 1 = 100 100 x t = 100t so 100-100t
How t-1 came? Can somebody explain..
Dave left i hour later. He took 1 hour less time. That is why we have t - 1.
Hope it is clear. Thanks
@@MathematicsTutor Sir, but the question does it say Dave overtook?
I more sums
Thanks. Here is a Playlist on Distance Time Word Problems:
in HINDI with Short Tricks: ua-cam.com/video/EJ3wBGM1U_4/v-deo.html
in English above Tricks: ua-cam.com/video/TOT9yrikd2s/v-deo.html
Standard Question on d-s-t Playlist: ua-cam.com/play/PLJ-ma5dJyAqp7kl0KHKhTpIu0JZfswGlz.html
what.
@@dddaaa6965 any questions
srry but i dont understand the accent imma go find another channel,cya
Thank you very much