Thank you for the clear explanation with the magnets. I found another way to explain why all pairs have one black and one red card: We can take two cards from the piles either by taking both cards from one pile or by taking one card from each pile. Either way, there will be one red and one black. And in the remaining piles the top cards will be of different color.
It's possible to do it without the reverse count. 1) cards of even number and in alternate red/black order 2) Cut about half the deck. Doesn't have to be equal 3) Two things can happen here. But you will need to peek the bottom halves a) bottom card of one half is red and the bottom card of the other is black. No adjustment needed. Perform the trick as usual b) bottom cards of both halves are of the same color. Either both red or both black. In this instance, riffle shuffle both halves together; Deal into two piles; Move the bottom card of the first pile to its top. No adjustment needed for second pile. Perform trick as usual.
Yes, all of this is true in the case of an alternating (e.g., Red/Black) deck structure. (See my recent video ua-cam.com/video/QHrmFN4NWzU/v-deo.html) For a general cyclic structure having cycle length larger than 2, however, a proper Gilbreath shuffle is required in which some, none, or all of the cards are "reverse-counted" before the (potentially) two portions are Riffle shuffled together. 👍
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Really cool stuff! Thank you.
Thank you for the clear explanation with the magnets. I found another way to explain why all pairs have one black and one red card: We can take two cards from the piles either by taking both cards from one pile or by taking one card from each pile. Either way, there will be one red and one black. And in the remaining piles the top cards will be of different color.
It's possible to do it without the reverse count.
1) cards of even number and in alternate red/black order
2) Cut about half the deck. Doesn't have to be equal
3) Two things can happen here. But you will need to peek the bottom halves
a) bottom card of one half is red and the bottom card of the other is black. No adjustment needed. Perform the trick as usual
b) bottom cards of both halves are of the same color. Either both red or both black. In this instance, riffle shuffle both halves together; Deal into two piles; Move the bottom card of the first pile to its top. No adjustment needed for second pile. Perform trick as usual.
Yes, all of this is true in the case of an alternating (e.g., Red/Black) deck structure. (See my recent video ua-cam.com/video/QHrmFN4NWzU/v-deo.html) For a general cyclic structure having cycle length larger than 2, however, a proper Gilbreath shuffle is required in which some, none, or all of the cards are "reverse-counted" before the (potentially) two portions are Riffle shuffled together. 👍
This is a great principle and has many uses.👍😊👍😊