Math Olympiad | x²-y²=9 , xy=20 , Find x+y=?? 🤔

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  • Опубліковано 17 тра 2024
  • Math Olympiad | x²-y²=9 , xy=20 , Find x+y=?? 🤔 #Mamta maam #exponentialproblem #matholympaid
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КОМЕНТАРІ • 26

  • @ganeshdas3174
    @ganeshdas3174 Місяць тому +2

    x + y=9

  • @user-go5sy7mu6q
    @user-go5sy7mu6q 28 днів тому +1

    Perfect theorem

  • @aruntiwari5714
    @aruntiwari5714 Місяць тому +1

    Perfect teaching method

  • @ayhanozen8970
    @ayhanozen8970 12 днів тому +1

    X=5, Y=4

  • @Maheshkumar-cw6un
    @Maheshkumar-cw6un Місяць тому +1

    Its nice exponent equation

  • @E.h.a.b
    @E.h.a.b 28 днів тому +2

    (x-y)(x+y) = 9 //From [1]
    (x-y)^2 (x+y)^2 = 81 //Square both sides
    let (x + y)^2 = a
    (x-y)^2 a = 81 -----> [3]
    but we know that
    (x-y)^2 = (x+y)^2 - 4 xy
    (x-y)^2 = a - 4 * 20
    (x-y)^2 = a - 80
    (a - 80) * a = 81 -----> [4]
    a^2 - 80 a - 81 = 0
    a = ( 80 +/- √((-80)^2 - 4 (1) (-81) ) )/2
    a = ( 80 +/- √( 4 * 1600 + 4 * 81 ) )/2
    a = 40 +/- √1681
    a = 40 +/- 41 = {81, -1}
    x+y = +/- √a
    x+y = {-9, 9, -i, i}

  • @harshpathak2359
    @harshpathak2359 Місяць тому +1

    Very good explanation

  • @user-tc9cb8zh7b
    @user-tc9cb8zh7b Місяць тому +1

    Full reasonable explanation

  • @LaxmanKumar-yi4cv
    @LaxmanKumar-yi4cv Місяць тому +1

    Perfect way to go

  • @user-fz8rm8sy9m
    @user-fz8rm8sy9m 28 днів тому +1

    9

  • @manojchaugule794
    @manojchaugule794 Місяць тому +1

    good algebra math

  • @mohinkhan2503
    @mohinkhan2503 Місяць тому

    ❤❤❤❤❤❤❤❤

  • @harikishan1900
    @harikishan1900 Місяць тому +1

    It's correct value

  • @rehansaputra967
    @rehansaputra967 Місяць тому +1

    X = 5, Y = 4
    And X + Y = 9, or
    X = - 4i, Y = 5i
    And X + Y = i

  • @arvindkulkarni6580
    @arvindkulkarni6580 Місяць тому

    X+Y will always be real number as far as I can imagine

  • @SmartMoneyForexTrader
    @SmartMoneyForexTrader Місяць тому +2

    Nice solving but "i" cannot be a solution because X^2 + Y^2 = Positive. It can never be negative. Hence the line you wrote, X^2 + Y^2 = +41 Or -41 can only be positive.
    Hence the solution to the question is +9 or -9 ONLY

    • @christianaxel9719
      @christianaxel9719 Місяць тому

      if any x² or y² is complex the other one can be too resulting the sum in the "cancelation" of imaginary part.

  • @niranjanchakraborty1139
    @niranjanchakraborty1139 27 днів тому +1

    x+y=5+4=9.

  • @SidneiMV
    @SidneiMV 20 днів тому +1

    x² - y² = 9
    xy = 20
    find x + y = A
    (x + y)(x - y) = 9
    x - y = 9/A
    x + y = A
    2x = A + 9/A
    2y = A - 9/A
    A² - 81/A² = 80
    A² = 81 or A² = -1
    *A = ±9 or A = ±i*

  • @josemarino8787
    @josemarino8787 27 днів тому +1

    From y=20/x you get in the first equation x^4-9x^2-400=0. From here you get x^2 =25 or x^2 =-16.

    • @ichdu6710
      @ichdu6710 3 дні тому

      also my idea. this is a more common way to solve such a pair of equation.

  • @jeanlouis7561
    @jeanlouis7561 27 днів тому +1

    Why does she have to complicate a simple problem that a 5th grader can solve in less than two minutes?
    The solution is x =5 and y = 4

  • @MathSync
    @MathSync Місяць тому +1

    “Fantastic explanation! I love how you break down complex concepts. I do similar math tutorials and challenges on my channel. Check it out for a fresh perspective on math problems!”

  • @ganeshdas3174
    @ganeshdas3174 Місяць тому +1

    x + y=9

  • @user-fz8rm8sy9m
    @user-fz8rm8sy9m 28 днів тому +1

    9