I have invested a hell lot of time in understanding this topic from various books but never see anybody explaining this topic as elegantly as u did , thanks a lot sir
Omg!! So cool! I didn't know this is what EE's do. I'm a ME and I just clicked on this video because we need to know what jn junctions do. But we no way go in this much depth.
Nailed it. It got a bit confusing in between and I had to refer somewhere else to get a grip, but really the closure you gave to this topic is quite brilliant! It’s totally visualisable now, how the current actually flows in this junction. Didn’t expect this the first time I read diodes!
I tried to read the text books, listened nptel lectures, but still was not able to understand this concept, but after listening to your video I was able to understand it so well, thanks a lot bro for your help.
How can we assume there be no electric field in neutral regions? We are applying a bias voltage, there should be an electric field throughout the material with the applied bias?
2:10 Sir in previous lecture u said, drift current is independent of applied potential and barrier strength/magnitude. Becos the no of minority carrier near the Junction is independent of that voltages and depends solely on Temperature, as they are generated by Thermal agitation. Please enlighten if I am wrong.
Ohk I got that. In RB when Max Id flows- Id increases and becomes Independent means saturates or isnt able to follow the Barrier Electric field due to fixed no of minority carrier. But the minimum, In case of FB- Id reduces Due to reduction in EF or DR width.
Sir I have doubt in equilibrium of diode when external force is applied.we took a condition where at t=0 light is off so dp/dt not equal to zero.i don't understand why it is not equal to zero
@@ganeshniranjan2003 this playlist ua-cam.com/play/PL311CA3047EB6EC58.html is created with at most care - to have everything explained logically. Please go through the sequence. Hope that helps.
Sir, please help me understand below concept: once the carriers cross the junction..won't it again expose acceptor and donar dopant ions on their respective side and increase the depletion width ??..
Minho Kim Yes it is .. But the Junction voltage changes ... it decreases if the bias is Forwar Bias and it inreases if the bias is Reverse Bias (assuming the bias voltage is directly applied to the junction itself)
+Dhiman Bhowmick I think there are three things you should always consider, Jdiff Jdrift and Va. Here Jdiff is 0 if Va is 0 since it is out of depletion region. Then he used the equation with dp/dx considered with Va to calculate its Jdiff. All of them have been considered. That's how I convinced myself at least. Hope it helps.
+Dhiman Bhowmick wait.....sorry......i shouldn't say Jdiff is 0 if Va is 0....it should be Jdrift =0 no matter what Va is cause the dE/dx=0 in nondepletion region
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These lectures are literal life savers for college undergraduates like myself.
I have invested a hell lot of time in understanding this topic from various books but never see anybody explaining this topic as elegantly as u did , thanks a lot sir
Thank you Achal!
I read book before this video ,and felt confident, But you Sir, Changed my entire Vision
Omg!! So cool! I didn't know this is what EE's do. I'm a ME and I just clicked on this video because we need to know what jn junctions do. But we no way go in this much depth.
I'm a mechatronics engineer. 😎
Nailed it. It got a bit confusing in between and I had to refer somewhere else to get a grip, but really the closure you gave to this topic is quite brilliant! It’s totally visualisable now, how the current actually flows in this junction. Didn’t expect this the first time I read diodes!
I tried to read the text books, listened nptel lectures, but still was not able to understand this concept, but after listening to your video I was able to understand it so well, thanks a lot bro for your help.
You are doing great work by helping us. Thank you for your quality content.
wow, crystal clear explanation... i got confused even after taking class by gate faculty.. but you make it crystal clear sir...tnq...feeling boosted
Thanks a lot sir, that was an amazing and very educational video. Greetings from a Greek university student!
YOU ARE AMAZING! Thank you so much for making and uploading these videos, they're very helpful!
How can we assume there be no electric field in neutral regions? We are applying a bias voltage, there should be an electric field throughout the material with the applied bias?
This video is really very good with very clear concepts.
One thing i just wannn to say that this is pure EDC lecture.
Amazing lecture ... really helpful, Thank you so much for the one who is explaining!1
Thanks alot for the comment Sandeep Reddy!
This was really a great video , which helped me clearing alot of doubts ... thanks alot
Sir you are so good at this sir Love you sir GATE is now becoming easier for Self study Students Because of SIR's like you 🥰🥰🥰
2:10
Sir in previous lecture u said, drift current is independent of applied potential and barrier strength/magnitude. Becos the no of minority carrier near the Junction is independent of that voltages and depends solely on Temperature, as they are generated by Thermal agitation. Please enlighten if I am wrong.
Ohk I got that.
In RB when Max Id flows- Id increases and becomes
Independent means saturates or isnt able to follow the Barrier Electric field due to fixed no of minority carrier.
But the minimum, In case of FB-
Id reduces Due to reduction in EF or DR width.
In short.
Id is proportional to Barrier Potential.
But cannot keep going increasing as the reason are minority which are less.
Very nice explanation ..Thank you so much and thanks for all of those who contribute to teaching others :D
brilliant i dont there is a better video for this concept
simply great
Tell me which book you had reffered to. Why don't you upload complete series of electronic devices and circuits?
very good and very clear! Thank you very much!
Best explanation i ever seen... 😇😇😇😇
awesome video! short and very well explained!!
very nice lecture
these are the best
thanks alot
I am high now....
Why must charge neutrality be maintained at all times in the n-region and p-region outside the depletion region?
because charge can neither be created nor destroyed.
Hi, electron diffusion current and hole diffusion current flow in the same direction?
Just incredible. Thanks a lot.
please make videos for gate and ies electromagentic theory brooo.....
amazing video...really helped me a lot....
Thank you very much
please add more subjects .. thnk you
Sir I have doubt in equilibrium of diode when external force is applied.we took a condition where at t=0 light is off so dp/dt not equal to zero.i don't understand why it is not equal to zero
Why are we talking about light here?
@@techgurukula I have no doubt in the video.i have been to gate coaching.I had a doubt in that concept
@@ganeshniranjan2003 this playlist ua-cam.com/play/PL311CA3047EB6EC58.html is created with at most care - to have everything explained logically. Please go through the sequence.
Hope that helps.
@@techgurukula thank u sir
This saved my exam
Sir, please help me understand below concept:
once the carriers cross the junction..won't it again expose acceptor and donar dopant ions on their respective side and increase the depletion width ??..
thats a very good question, were you able to find answer to that.
Are these videos covering the whole syllabus for gate ..? .
Great explaination sir🙏🙏
6:57 why wouldn't Pn-Pno change anything? both are minority charge carrier densities? How is Pn = Pn-Pno?
awesome .seems like u devoured the milliman book
Is the law of junction still valid under bias voltage applied?
Minho Kim
Yes it is .. But the Junction voltage changes ... it decreases if the bias is Forwar Bias and it inreases if the bias is Reverse Bias (assuming the bias voltage is directly applied to the junction itself)
What's charge neutrality?
total no. of holes =total no. of electrons
good explanation
very good!
god bless you !!
No drift current is considered?????
+Dhiman Bhowmick I think there are three things you should always consider, Jdiff Jdrift and Va. Here Jdiff is 0 if Va is 0 since it is out of depletion region. Then he used the equation with dp/dx considered with Va to calculate its Jdiff. All of them have been considered. That's how I convinced myself at least. Hope it helps.
+Dhiman Bhowmick wait.....sorry......i shouldn't say Jdiff is 0 if Va is 0....it should be Jdrift =0 no matter what Va is cause the dE/dx=0 in nondepletion region
What is Ln and Lp?
diffusion lengths of electron and oles
Ln = square root(Dn*Tn)
Explain on white background 😡😡😡
broooo y do u explain on black background 😡😡😡
U r explaning the same thing over & over. which creates lots of confution
WTF!! Change background black to white 🙏