Thank you for this wonderful and informative video, I'm designing a vibrating ball-mill (the total mass is 1 ton), I need the formula to calculate the suitable vibrator for this application.
To minimize the error it is better to neglect first and last loop as the length may change for these loops when position of electrical vibrator is changed
Here for example in longitudinal mode our experimental value is 52.85 Therefore the percentage error will be calculated as below Actual value - experimental value This is 50 - 52.85 =2.85 Then divide by actual value and multiply with 100 So the percentage error is 5.7% The negative sign is ignored
in transverse mode it is 1/2L whereas in longitudinal mode it is 1/L. When we mathematical formulation or analysis of stationary waves the eigen frequency (which we are finding) is c/λ. but since the string is divided into n segments each separated by λ/2 therefore l=nλ/2so frequency is nc/(2l). for more queries you can mail me at ripin.kohli@gmail.com
In longitudinal mode if you observe during 1 vibration of tongs complete loop is formed while in transverse mode during 1 complete vibration of tongs half loop is formed
Thanks MAm..Tommorow is my Physics practical Viva..So,Now I understood it very well
I got it mam completely, I'm thankful to you Mam😊
Dil se than you mam, it gives pure feel of lab, every point is clear now .
Glad you liked it
Can u tell why we used that bulb ...& Not any low power consumption led or something
To bulb here is used to provide the low resistance... instead of bulb you can use some external low resistance
Good job mam... very informative.
Nice and impressive.Good luck
Thank you mam for to elaborate and easy to understand the experiment❤
Thank you for this wonderful and informative video,
I'm designing a vibrating ball-mill (the total mass is 1 ton), I need the formula to calculate the suitable vibrator for this application.
NYC explanation
Very gud Ripin it will help my students very much
Thank you... Do share and support
Marvelous Ma'am .
Love you 😘 for this experiment
Nice mam👌👌
Excellent mam
Nice explanation !
Why is bulb connected in circuit ? What's reason ?
mam please explain how to make graph between 1/p^2 vs T
Mam can u tell us the range of frequency comeout in this experiment so we can sure that we r correct or not?
The actual frequency is 50 Hz. However there can be some errors while performing the experiments... the permissible value for the errors is 10%
Thanks a lot mam , it helped
Thankyou mam ❤
Mam is it necessary to neglect the first and last node, or it will produce a minute difference in the result if we consider them also???
To minimize the error it is better to neglect first and last loop as the length may change for these loops when position of electrical vibrator is changed
love you mam❤️❤️ I feel as perform in lab
I am from Pakistan 🇵🇰🇵🇰
Glad you liked it.
mam but where does P goes
you havent used it anywhere in the formula
P is used to find the length of each loop.
P is total number of loops.
L is total length.
@@ripin2884 wahi toh longitudinal wala formula me n=P/L underoot T/m hona chaiya
@@ripin2884 and transverse wala me n=1/2L underoot T/m
That's what has been done.
P/L is written as 𝓵
Thankyou mam ❤️, it was very helpful
Glad you liked it
Mam eska permisiable error kaisi nikalte hai
The percentage error has a simple formula (actual value- experimental value)/ actual value
Then multiply with 100
Here for example in longitudinal mode our experimental value is 52.85
Therefore the percentage error will be calculated as below
Actual value - experimental value
This is 50 - 52.85 =2.85
Then divide by actual value and multiply with 100
So the percentage error is 5.7%
The negative sign is ignored
Mam hamne ese hi nikala tha but mam ne bola ye standard error h..vo vala vala error jo deln/n karke nikalte hai..🙏🏿🙏🏿 please bata do mam
Thanks ma'am
thank u mam
Ma'am formula mein 1/ 2L kyu hota hai please btao
in transverse mode it is 1/2L whereas in longitudinal mode it is 1/L. When we mathematical formulation or analysis of stationary waves the eigen frequency (which we are finding) is c/λ. but since the string is divided into n segments each separated by λ/2 therefore l=nλ/2so frequency is nc/(2l). for more queries you can mail me at ripin.kohli@gmail.com
@@ripin2884 Thanku so much Ma'am 💖💓
Thanks mam
Ma'am why the formulas for frequency are different in the second case it is half of the first one???
In longitudinal mode if you observe during 1 vibration of tongs complete loop is formed while in transverse mode during 1 complete vibration of tongs half loop is formed
Yes, it's half , it's proved formula, Dr sb have done very good work I appreciate .
Dr sb very good 👏👏👏
Thanku mam 🥰
You are welcome
👌🏻👌🏻
Thanku mam
You are welcome
Kindly check out the latest video
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Thank you mam
Excellent mam
Thank you ma'am