NOT Gate using Transistor on a Breadboard
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- Опубліковано 25 вер 2024
- This video describes how to make a NOT gate on a breadboard using BC547 transistor.
When the switch is OFF, the transistor is also OFF and the current flows through the LED. The LED lights up indicating a HIGH output.
When the switch is turned ON, the transistor also turns ON thus creating a short circuit through the transistor's collector and emitter. Hence the current does not flow through the LED. This indicates a LOW output.
I like how you show the diagram being reproduced as you fill in the breadboard! I wish everyone did that!
Thank you for your feedback!
Very helpful easy to understand
Thanks for tutorial. It helped me a lot
Thank you for watching the video. Glad you found it helpful. Do watch my other videos on 'Logic Gates using Transistors'.
I have just 1 small problem. When I use the not gate (turn on button), I can't use anything else using the same power supply. And that is a problem I have. Could you explain a way to make a not gate NOT deactivate the battery? If so, thanks!
Hi, sorry for the delayed response. This is a common issue that occurs with some circuits such as NOT Gate using transistors. This problem might be because when the NOT gate is activated, it’s drawing too much current from the power supply, leaving insufficient power for other components.
A possible solution is you could use a current limiting resistor. This resistor can be added to your circuit to limit the amount of current going into your NOT gate. Let me know if this solution works.
@@electronics_champ Thanks! I will try that solution.
Very nice video 👌👌👌
If I'm using 3.3V of power supply, what should the Ohms on the resistors be?
You can find that out using Ohm’s Law, which is V = I * R. V is volts, I is amps, and R is resistance. You already have V (3.3); and a typical LED can handle 20 milliamps, so I is .02; so you want to know the resistor value.
R = V/I or R = 3.3/.02 which is 165 ohms. 165 ohms is a reasonable resistor for any LED using a battery up to 9 volts
I would use a 165 ohm resistor (based on Ohm’s Law).
Good keep it up
is it just me or does the music remind you of terraria
❤️❤️❤️👍👍👍
Doesn not work!!! Fake news !!!!
Computer is an electronic/electrical device. It is not logic or gate or binary device.
The whole idea of so called AND, OR and NOT Gate in fact is nothing more than three circuit systems.
1. Series. 2. Parallel. 3. Short/open.
That is in plain English, clear and simple.
AND is series wiring. OR is Parallel wiring. Not Gate is short/open. It is so obvious.
You can easily bring those three situation without any transistor.
Hook your LED and supply the right voltage. This will remove any need for those resistors. Toss them.
Wire the LED using two connecting wires ( call it switches) to either positive side or negative side, makes no difference. Make those two wires you connect to be switches hooked up in series and there is your AND Gate.
Then do it in parallel. And there is your OR Gate
And what is the so called NOT Gate?
Then directly install the LED to the power source, there is your light on with no switch whatsover.
Have another wire in hand with a resistor ( say 50 Ohms) hooked up in one end of it and wire that resistor back to the power source. The instant you touch the other end of the wire to that one side of the LED, current will flow through that lower resistor circuit and the LED will get nothing.
This is the TRUTH behind all this head scratching, dizzying lingos.