AC voltage across pure inductor (derivation) | Alternating current | Physics | Khan Academy
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- Опубліковано 11 тра 2021
- When an alternating voltage is applied to a purely inductive circuit, the current lags the voltage by 90 degrees. Let's calculate the expression for this current.
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Created by Mahesh Shenoy
Sir please don’t stop and keep posting such videos our country needs ppl like who would spread the kind of knowledge that gives ppl interest in studying unlike the normal coaching institutes
Bruh its so true
And refer reamining khan academy channels too
Your enthusiasm and explanations are of high quality.
Although I'm not sure of your explanation regarding the value of the constant C.
"Because it is a constant, if it is 0 for these values, it should be 0 for any value of Vo" -> that sounds false to me. C could simply have Vo on its numerator, no ?
You can't replace the values of the constants (Vo) when calculating C, you need to determine it for a **particular value of t**. For example, t=0.
Am I missing something ?
You are not teaching
YOU ARE CONVEYING ALL THE FACTS RELATED TO A THING THAT AN ORDINARY PERSON THINK HOW IT WILL APPEAR OVER THERE
REALLY HAVE NO WORDS TO SAY
GOD BLESS YOU
❤️❤️ it is amazing to learn these concepts with you
Please upload full syllabus of class 12th
Omg Khan academy has helped so much in the last few days it was everything I was looking for
Much needed one in the right time. Thank u Mahesh sir😄
I know I aced ac current from my brain, stomach and heart 💖
Amazing and fluent explanation !
Excellent....it's like a suspense movie.... eagerly waiting for next session
it's really nice to see someone doing what they like to do
great content!
I'm little bit weak in English but but but....your videos make it very smooth
Really amazing ❤
Clean and clear ❤❤❤
Great effect keep doing
Superb. Love from Pakistan ❤
Love your video
Sir, the back emf at any instant will always be equal and opposite to the source voltage then how can a current flow in the circuit
Bro do you come to know answer of this question ❓ please tell me also
It changes all time,not always equal ,as inductor in DC voltage,at switch closed back emf equal, in ac same way but back emf equal to source v at instant and slowly lows and changes as voltage changes polarity and so on
And see Vs depends on Ldi/dt , current changes sinusoidally and emf changes as current changes
if vs and vl are equal then why currrent flow ? if current flow but in which direction opposite to source voltage direction ?
The same qn is troubling me so much
Remember, I is rising gradually in a purely inductive circuits. Because at the beginning back emf(the V of inductor) is same as source voltage, I=0. Then V of L decreases with time and I starts to increase. So yeah, your question is valid but only for a small amount of time(at the beginning).
Please make a video which shows how changing electric field produce magnetic field in electromagnetic field
Thank u Mahesh sir
Thank´s for this!
Glorious
Nice explanation
amazing
❤❤❤❤❤Isthuuthiii🎉 thankuuu very much sr❤
07:46 😂😂😂
Sir, I think C is a constant w.r.t time. I mean c might be a function of Vo. So putting Vo =0 will be inconclusive. Like it might be possible C = Vo/wL . I think a better way to figure out constant would be using the average value of the function.
Sir if induced emf and applied voltage are same then current should not flow
Like two battery of same volt are connected with same polarity..
In my heart in my bones in my stomach 😂😂.
If the source voltage and the induced voltage are equal and opposite throughout the entire cycle, how does current flow at all?
Amazing work, but is there a playlist for these videos?
Yes it's named as Alternating current
Hello sir canyou even explain how the current and the voltage are out of phase
Which application u r using for making this video
@ 3:28 If V(L) = V(S), how can there be any current at all?
Rest of the lecture was awesome but, Can someone explain why the inductor has the same polarity as the battery? Shouldn't it be opposite in order to oppose the applied voltage?
simple answer is “no”, however, there is a particular concept that may cause confusion to those learning about inductors. While there is no defined electric polarity for inductors, direction of current does matter because of a phenomenon called inductor kickback.
what's the name of the playlist?
If you are watching this video !!! then you gonna rock !!!
🏆❤️
that's very nice video
Is angrezz was lessen so Indian also strated using their acsent
sorry but I have a question: why the circuit doesn't exist without the resistor.
Because every circuit (the wires) would have some resistance... It can't be zero
@@dodokoi036 ok but let suppose that the wire have a resistance how we add this to equation , we addet like a resistor equation or what ???
Thank you for you answer
V/I = R
If R=0,then V=0 means no flow of current so no circuit... People also say that infinite current flows because nothing is there to oppose the current. Infinite current is just impossible
Angrez
You failed to explain a key point. Why does the induced EMF with the SAME polarity as the source voltage cause a Voltage in the opposite direction from the source? Shouldn't the induced EMF have an opposite polarity? How can it be in the "same direction" if the EMF is in the opposite direction.
I can't understand that too. My teacher said it would be opposite. Can you explain that please?
@@Fateymaa I decided to think of the induced EMF as a "battery" that is producing an EMF opposite in direction to the source voltage, even though its polarity (the plus/minus orientation) is the same as the source voltage. That is, in the circuit represented in the video, the induced EMF is pushing conventional current counterclockwise, while the source voltage is pushing it clockwise.
@@Festus2022 Thanks a lot. Earlier, I, kind of, came up with the same conclusion. It feels right now.
🤣🤣