Excellent tutorial, Thank you so much for your great presentation 🙂, i wonder why the 2.8K views only managed to raise '8' comments, were they out of phase, a sort of cognitive discharge that they couldn't handle the 'Charge' ? 🤔 it was much more worthy of 2 Billion thumbs up and endless comments to express their gratitude for the kind effort of this video.
Wonderfully explained. What a boon UA-cam would have been 60 years ago when I was taking physics in college. I’m subscribed and I will be linking my grandson so he has the opportunity to see a master educator explain things that you can’t see but must deduce thru meter readings. Excellent work!!! 🎉
God bless you man how nice you explain I my dear you are among highest level of good men those who teach arachnid and would like to help others that is what count wish you best
Thank you so much for your help. Other youtube videos didnt help me out in understanding phases but this one definitely did! Thank you so much and i hope you have a great day!
@ 2:48 I don't think the current has a particular direction in a AC-circuit. For CAPACITORS: C = Q/V or Q = C . V. Thus, I = dQ/dt = C . dV/dt. In other words, the SLOPE of the V-curve determines the amount of I. For INDUCTORS: V = L . dI/dt (Faraday's law). In other words, the SLOPE of the I-curve determines the amount of V. For RESISTORS: V = R . I (Ohm's law). In other words, the AMOUNT of I determines the amount of V Notice that C, L and R are constants determined by the configuration of the element.
You still need to define a 'direction' for reference. If you change that direction, there will be an associated sign change, such that either reference choice gives the same result overall.
@jacobvandijk6525 Yes, since Ic = C(dV/dT) ,it's the rate of change in V across the capacitor leads that determines the amount of current into and out of the plates. Since the derivative of a sine wave creates a cosine wave, the capacitor shifts the current forward by 90°
Bob somehow lost the rights to the name RSD Academy and was forced to remove references to that name from his videos. He has been editing all of them and reuploading them here.
And on another channel, current flows ‘outside’ the wires..as in the magnetic field. No way could i be an electrical engineer designing this stuff. Great explanation but i have a headache now.
Sir, you have done the phase angle subject as easy as possible thank you so much for your help and support us ❤🎉
literally no one explained this much details to me. love the lecturing and our lecturer. One of the great teaching.
fantastic
Excellent tutorial, Thank you so much for your great presentation 🙂, i wonder why the 2.8K views only managed to raise '8' comments, were they out of phase, a sort of cognitive discharge that they couldn't handle the 'Charge' ? 🤔 it was much more worthy of 2 Billion thumbs up and endless comments to express their gratitude for the kind effort of this video.
Wonderfully explained. What a boon UA-cam would have been 60 years ago when I was taking physics in college. I’m subscribed and I will be linking my grandson so he has the opportunity to see a master educator explain things that you can’t see but must deduce thru meter readings. Excellent work!!! 🎉
Thank you Sir, you are saving lives.
this is the best explanation ever
God bless you man how nice you explain I my dear you are among highest level of good men those who teach arachnid and would like to help others that is what count wish you best
Thank you so much for your help. Other youtube videos didnt help me out in understanding phases but this one definitely did! Thank you so much and i hope you have a great day!
As soon as graduate and get. A job Iwill support
Excellent! Thank you.
Excellent tutorial. Thank you
Definitely the best, you made me understand the concept. Thanks man❤
This is such a great video. Thank you
this was fantastic, thx
Amazing video, learned a lot❤
Nice work
textbook ?
Thanks a lot.
Thanks for the video
@ 2:48 I don't think the current has a particular direction in a AC-circuit.
For CAPACITORS: C = Q/V or Q = C . V. Thus, I = dQ/dt = C . dV/dt. In other words, the SLOPE of the V-curve determines the amount of I.
For INDUCTORS: V = L . dI/dt (Faraday's law). In other words, the SLOPE of the I-curve determines the amount of V.
For RESISTORS: V = R . I (Ohm's law). In other words, the AMOUNT of I determines the amount of V
Notice that C, L and R are constants determined by the configuration of the element.
You still need to define a 'direction' for reference. If you change that direction, there will be an associated sign change, such that either reference choice gives the same result overall.
@@Rene_Christensen Agree. But drawing only one arrow could confuse people.
@jacobvandijk6525 Yes, since Ic = C(dV/dT) ,it's the rate of change in V across the capacitor leads that determines the amount of current into and out of the plates. Since the derivative of a sine wave creates a cosine wave, the capacitor shifts the current forward by 90°
Just out of curiosity …..what happened to the other channel????u had more subscribers …..lol
It fazed out.
Bob somehow lost the rights to the name RSD Academy and was forced to remove references to that name from his videos. He has been editing all of them and reuploading them here.
you may be the reason i wont fail out of college
College is a scam, they don't explain as good as this to us.
And on another channel, current flows ‘outside’ the wires..as in the magnetic field. No way could i be an electrical engineer designing this stuff. Great explanation but i have a headache now.
'Shocking' revelation 🙂
Crystal clear😅
Te amo muito
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Definitely the best, you made me understand the concept. Thanks man❤