Given, s (height) = 15m mass = 1 Kg p=mv P=1xv using third law of motion.... v^2-u^2=2as u=0, as coconut is initially at rest. on substituting u=0, in third equation of motion..... v^2-0=2x10x15 (on taking g=10m/s^2 v^2=300 v=√300 v=10√3 on substituting the values in p=mv..... p=1x10√3 p=10√3 kgm/s(taking √3 = 1.732) p=10x1.732 p=17.32 kgm/s Therefore, the momentum of the falling coconut is 17.32 kgm/s.
Hey, sir I really like your teaching style you make physics so much interesting. I think if more & more teachers started teaching like you then India as a country will prosper!!!! For the ❤ of physics......
Using kinematics, First we calculate the time it takes for the coconut to reach the ground... d = Vi (t) +1/2 (a)(t)² 15m = 0m/s(t) + 1/2(9.8m/s²)t² Hence: t=√3 = 1.73 To calculate the final velocity we use: Vf = Vi + (a)(t) Vf = 0m/s + 9.8m/s²(1.73s) Vf = 16.95 m/s Finally, the momentum when it hits the ground is: p = mv p = (1kg)(16.95m/s) p = 16.95 kg • m/s or 17 kg • m/s Which I think is pretty dangerous especially if it hits you directly on your head 😂
You can directly go for the final velocity from v² -u² =2as ( a is acc due to gravity here , and s is displacement that is 15m and u is initial velocity which is 0 in this case ).
You have made a little mistake on time calculation. Remember that, if in decimal the value is equal to or greater than 5, then we have to round the digit to the next digit. So, here, the time should be 1.75 s. That's why your answer is not correct.
Initially the coconut was at rest so it's initial velocity 'u' will be zero. According to Newton's third equation of motion v^=u^+2as u=0 a=g= 9.8 m/s^ s=15m. v^=0+2×9.8×15 =294 so v=√294= 17.14 approx. Momentum =Mass × velocity. So P= 1kg×17.14 m/s. =17.14 kg.m/s
Initially, the coconut was at rest so it's initial velocity 'u' will be zero. u = 0 v= ?(Have to find out) height / s = 15 m a = 10m/s (Gravity Approx.) Now by third equation of motion :- v² - u² = 2as v² = 2× 10 ×15 m²/s² v² = √300m²/s² v = 10√3 m/s = 10×1.73 = 17.3 m/s Mass of coconut = 1 kg Velocity of it during reaching the ground = 17.3 m/s P = mv Momentum = Mass x Velocity 1 kg × 17.3 m/s = 17kg m/s === So the momentum of the falling coconut is **17Kg m/s**. Always love your videos sir🔥🔥! This was a nice one! A nice question too! hope my answer is right .
Sir, please start courses for 11th for physics, chemistry, and maths.... It will help us very much. Concepts like Chemical Thermodynamics and Organic Chemistry is tough. It Will be Easy if you teach us sir.
at the uppermost height u = 0 v= ?? h= 15 m g = 10m/s Now by third equation of motion v² - u² = 2gh v² = 2× 10 ×15 m²/s² v² = √300m²/s² V = 10√3 m/s = 10×1.73 = 17.3 m/s Mass of coconut = 1 kg Velocity of it during reaching the ground = 17.3 m/s Momentum = Mass × velocity 1 kg × 17.3 m/s = 17kg.m/s So we clearly see that this is the sufficient amount of momentum to kill a person.
the momentum of the falling coconut =mass of coconut * final velocity of coconut =1kg * final velocity(v) v^2=u^2+2as =0+2*10*15 =150*2 =300 v=sqrt(300)=17.3m/s momentum = 17.3 kg m /s
Sir,falling of coconut is enough to break anyone’s skull because the momentum of coconut will be 17.32 kg/m/s if g=10 and if g=9.8 the momentum will be 17.163 kg/m/s.
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Given,
s (height) = 15m
mass = 1 Kg
p=mv
P=1xv
using third law of motion....
v^2-u^2=2as
u=0, as coconut is initially at rest.
on substituting u=0, in third equation of motion.....
v^2-0=2x10x15 (on taking g=10m/s^2
v^2=300
v=√300
v=10√3
on substituting the values in p=mv.....
p=1x10√3
p=10√3 kgm/s(taking √3 = 1.732)
p=10x1.732
p=17.32 kgm/s
Therefore, the momentum of the falling coconut is 17.32 kgm/s.
A nerd
Not third law of motion it is third equation 😊😊
Hey, sir
I really like your teaching style you make physics so much interesting. I think if more & more teachers started teaching like you then India as a country will prosper!!!!
For the ❤ of physics......
Thanks a ton!!
Using kinematics,
First we calculate the time it takes for the coconut to reach the ground...
d = Vi (t) +1/2 (a)(t)²
15m = 0m/s(t) + 1/2(9.8m/s²)t²
Hence: t=√3 = 1.73
To calculate the final velocity we use:
Vf = Vi + (a)(t)
Vf = 0m/s + 9.8m/s²(1.73s)
Vf = 16.95 m/s
Finally, the momentum when it hits the ground is:
p = mv
p = (1kg)(16.95m/s)
p = 16.95 kg • m/s or 17 kg • m/s
Which I think is pretty dangerous especially if it hits you directly on your head 😂
Perfect bro
You can directly go for the final velocity from v² -u² =2as ( a is acc due to gravity here , and s is displacement that is 15m and u is initial velocity which is 0 in this case ).
@@amitkumarray275 You're right. Sorry I forgot about.
You have made a little mistake on time calculation. Remember that, if in decimal the value is equal to or greater than 5, then we have to round the digit to the next digit. So, here, the time should be 1.75 s.
That's why your answer is not correct.
@@rakibulhasan-yv8fr ya
Initially the coconut was at rest so it's initial velocity 'u' will be zero. According to Newton's third equation of motion v^=u^+2as u=0 a=g= 9.8 m/s^ s=15m. v^=0+2×9.8×15 =294 so v=√294= 17.14 approx. Momentum =Mass × velocity. So P= 1kg×17.14 m/s. =17.14 kg.m/s
His answer is correct
Hmmmm topper...
Initially, the coconut was at rest so it's initial velocity 'u' will be zero.
u = 0
v= ?(Have to find out)
height / s = 15 m
a = 10m/s (Gravity Approx.)
Now by third equation of motion :-
v² - u² = 2as
v² = 2× 10 ×15 m²/s²
v² = √300m²/s²
v = 10√3 m/s = 10×1.73 = 17.3 m/s
Mass of coconut = 1 kg
Velocity of it during reaching the ground = 17.3 m/s
P = mv
Momentum = Mass x Velocity
1 kg × 17.3 m/s = 17kg m/s
=== So the momentum of the falling coconut is **17Kg m/s**.
Always love your videos sir🔥🔥! This was a nice one! A nice question too! hope my answer is right .
Huh 11th legends use v=√2gh directly instead of simply dressing the steps
Thanks a lot sir you have help me to master the concepts of physics. Love you sir ❤
Sir, please start courses for 11th for physics, chemistry, and maths.... It will help us very much.
Concepts like Chemical Thermodynamics and Organic Chemistry is tough. It Will be Easy if you teach us sir.
at the uppermost height
u = 0
v= ??
h= 15 m
g = 10m/s
Now by third equation of motion
v² - u² = 2gh
v² = 2× 10 ×15 m²/s²
v² = √300m²/s²
V = 10√3 m/s = 10×1.73 = 17.3 m/s
Mass of coconut = 1 kg
Velocity of it during reaching the ground = 17.3 m/s
Momentum = Mass × velocity
1 kg × 17.3 m/s = 17kg.m/s
So we clearly see that this is the sufficient amount of momentum to kill a person.
Sir, the location you are in .
(Samudra) Kovalam beach i visited the place.
Good explanation sir ❤️
You're the best teacher ever...
Thanks a lot!!
Momentum is 17.32 kg m/s using the relation p2=2×m×ke. Taking g as 10 m/s2
I started to watch your video.your teaching is awesome ❤️
Hello Sir...quite a interesting question...Do we have to use v² = u² + 2gh?? If yes then by calculating we get....p = 17.3205080757 kg m/s
So the falling coconut is this dangerous!!🤔👆🏻
Interesting and Funny video😀
Thank you sir for your good explanation!
Thank you sir for nice explanation about momentum ♥️ your teaching style
Hi sir your videos are soo helpful thank u soo much 👋
Great to hear that!
Amazing but newton would have sat under coconut tree that would be good for us 🙃
Sir im from kerala and im a big fan of you. This video make me so happy😻
You are my best teacher sir 🔥
Wow I always watch you're videos, I appreciate you.
And I'm trying to response.thanks.
So nice of you
here intial velocity is 0
so, v^2 =2gh
v= (2x9.8x15)^.5
v = 17.14 m/s
P = mv
p = 17.14 x 1
p = 17.14 kg m/s
You are an excellent explainer, it is sad to see that you don't have over 1 million views.. Also it is a very good explanation well done bro
Very good explanation sir.. Love from bihar
Thanks!!
Sir What is the answer
Can you tell I want to check ?
The force applied on the ground is 10 N
And momentum is 10√3
Super explanation sit
Thank you 🙂
How do u know the velocity of coconut
Awesome explanation sir
Hope you will ask more questions from physics sir
17.14
Very good!! Correct. Be sure to write the units kg m/s
thank you sir
Most welcome!
the momentum of the falling coconut =mass of coconut * final velocity of coconut
=1kg * final velocity(v)
v^2=u^2+2as
=0+2*10*15
=150*2
=300
v=sqrt(300)=17.3m/s
momentum = 17.3 kg m /s
sir..could you please do a video on electric generator
V2-u2+ 2as
more such questions pls!!
Very good explanation sir.love from Odisha......
Sir can you upload video about hydrodynamics
Sir can u please bring a coconut for me from there 😀😀
Sir,falling of coconut is enough to break anyone’s skull because the momentum of coconut will be 17.32 kg/m/s if g=10 and if g=9.8 the momentum will be 17.163 kg/m/s.
Good explanation sir 😊
Sir please make a video on square roots
the coconut reaches the ground approximately with 17.3 kg m/s
Super!! Correct :)
Always love these fun videos
Love from Bengaluru
Good explanation sir♥️
Your a great teacher sur
Sir
P=300Ns(assuming g to be 10m/s²)
Kerala 💕 God's Own Country 🌎💚❣️
Hi sir ,put video about the aeroplane
From sri lanka 🇱🇰💙🇨🇮🙏🙏🙏
Thanks:)
V = root (2gs)
Momentum = Mass x V
Very good! Substitute the values and calculate the answer!
Why did u say mass of coconut instead weight
15
Nice one sir☘️
Is it 17.32 kgm/s??
pls reply fast sir
17.14 kgms-¹
Super!! Right answer!!
15 sir
Sir,
Why don't you also teach 12th class🥺
We will try to make Class 11 and 12 in the future!
What will be the ans sir
sir can you pay a visit to hydrabad
Momentum = 17.32kgm/s^2
And sir you are enjoying in Kerala without us🤨😂
Very good!! Correct answer!! Unit of momentum is kg m/s
15 will be the ans..
May be
Sir plz tell it is correct or not .....
Kerala🤚
sir can you make a video on how to crack bitsat
When the coconut hits the ground, the momentum would be 17.1464281995 Kgm/s
Super! Right answer!!
The momentum of coconut is approx 17.5 kgm/s
What is your name, sir?
The momentum of the coconut is 15kgper metre square
Hello sir ! Do. You remember me ?
Hey Anoop! Hope you are doing good!
@@ManochaAcademy yes sir !
9.8 Newton seconds will be the answer the sir...
Use Equations of Motion to calculate speed of coconut when it hits the ground. Then you will get the momentum.
Why didn't Newton sit under coconut tree😢😮😢😂
10root3 kgm/s or 17.32 kg m/s
Answer 17 kgm/s
450
Before Newton .it was known from Sanskrit
First comment and like 😄
Thanks a lot!
17.16 kg m/s
1st comment
Thanks for watching so fast!
Coconut force= 10 N
The work done is 150 joules
momentum will be 15kgms2
After few approximations 8.82kgm/s²
i'll never go under a coconut tree sir
Yes sir, 15 kgm/s.
Love from Kerala , Malayali da 🌴🥥 Gods own country. Kera means coconut in Malayalam
Thanks for watching! I always love visiting Kerala! Such a beautiful place!
17.1kgm/s
17.3 kg m/s
Im pretty sure chingam (from motu patlu) sir is immune to this 😂
.
1 st like and second comment
15
15
15