Citrate Synthesis of Gold Nanoparticles

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  • Опубліковано 1 сер 2012
  • Full procedure can be found at: education.mrsec.wisc.edu/citr...
    Properties of materials change at the nanoscale. In bulk at the macroscale, the element of gold is gold colored, but at the nanoscale, the element of gold is red to purple in color. The formation of gold nanoparticles can be therefore observed by a change in color since small nanoparticles of gold are red. The layer of absorbed citrate anions on the surface of the nanoparticles keep the nanoparticles separated, and the presence of this colloidal suspension can be detected by the reflection of a laser beam from the particles. Switching to a smaller anion allows the particles to approach more closely and another color change is observed.
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  • Наука та технологія

КОМЕНТАРІ • 50

  • @ellogroresearch2072
    @ellogroresearch2072 2 роки тому +5

    Thanks for sharing. I have to comment on something because I have been studying this for quite some time. Now we are talking about the stability of the product obtained. There is a lot of talk about the ways of manufacturing gold but not about stability. That is, how long the product remains in the same characteristics.
    In my case I have not achieved stability for more than 30 days. Here in this video I do not see information on the products added as reagents for example.

  • @riniriniksha3454
    @riniriniksha3454 2 роки тому

    In which size it is in red colour and in purple colour ? please tell me the size in nm.

  • @TheSpinninHead
    @TheSpinninHead Рік тому

    Can we use AuCl3 too?

  • @justinmillard3595
    @justinmillard3595 2 роки тому

    gold is also AuKCaYZr, “Oh Kaiser”, as 1:3 K:Ca or 1:1 Y:Zr, welded and hammered together...

  • @rolo210
    @rolo210 6 років тому

    Hello,
    I prepared gold nanoparticles by this (Turkevich) method. Then I add safranine T and solution change colour from red to blue-violet. I think there was aggegation. BUT I have problem - after a few minutes measuring cuvette remained dirty. How I can clean cuvette, please? I need to dissolve gold nanoparticles aggregate and clean the cuvette glass.
    Thank you for reply.

    • @scottbryant7090
      @scottbryant7090 6 років тому

      Roland Sura How critical are these measurements during synthesis?

  • @user-xh5wk4uo5y
    @user-xh5wk4uo5y 7 років тому

    thanks for your effort may I ask about stained glass if I put a layer from that nano gold on glass cup and heat till 600 c will give me a bright gold layer or not?

    • @vadamaryol6666
      @vadamaryol6666 5 років тому

      if you put a layer of gold nanoparticles you would get the pink red color shown here. If you want gold color you would need to apply gold leaf to the surface of the glass.

  • @lieushoo
    @lieushoo 10 років тому +5

    Does this method apply to other metal nanparticles, such as palladium?

    • @vadamaryol6666
      @vadamaryol6666 5 років тому +2

      lieushoo, my guess is no. I think this a very specific reaction for making gold nanoparticles.

  • @DawaStories
    @DawaStories 4 роки тому

    What is that solution added to change the color on 1:47, is it sodium citrate??

    • @ezrzr7898
      @ezrzr7898 4 роки тому +1

      Sodium chloride solution

  • @bushrafatima2472
    @bushrafatima2472 3 роки тому +7

    Thanks for your efforts! I need your suggestion . My problem is that when I form gold nanoparticles through this method, the color of the solution turned purple from red. Is it normal? What should I do? Kindly give me positive feedback.

    • @WisconsinMrsec
      @WisconsinMrsec  3 роки тому +3

      Hi Bushra, the color of the nanoparticle depends in part on how large the nanoparticle is. As the nanoparticles grow larger, they will turn purple from red. You will need to remove the nanoparticles from the heat to prevent further growth. See the full written procedure for more information: education.mrsec.wisc.edu/citrate-synthesis-of-gold-nanoparticles/
      Also see this explanation on the nanoparticle size and color: sustainable-nano.com/2019/11/12/gold-nanoparticles-color/

    • @baguazhang2
      @baguazhang2 2 роки тому +2

      @@WisconsinMrsec Interestingly, I also found that shape influences color. If you add some silver and make gold nanostars, you get a blueshift as the spikes on the stars get longer.

  • @viper619ful
    @viper619ful 7 років тому

    what is that solid that is put in that soln @ 0.17

    • @SuperSquark
      @SuperSquark 7 років тому +1

      Magnetic stirrer bar

    • @viper619ful
      @viper619ful 7 років тому

      SuperSquark Cardboard Quark thank you

  • @lologrelot7642
    @lologrelot7642 7 років тому +1

    I tried this synthesis, but it failed... I followed the protocol, HAu boiled, I added the sodium citrate, the solution went black, but then returned to a transparent solution, and I had a weird black substance floating...
    Does someone have an idea what went wrong ?

    • @razorwings
      @razorwings 7 років тому

      The gold crashed, the black substance is precipitated gold. Did you ever figure out what you did wrong?

    • @lologrelot7642
      @lologrelot7642 7 років тому

      razorwings Well I am not sure, that's why I asked... I really followed the protocol, but it may be a problem of badly washed glassware...

    • @angelicajusino3169
      @angelicajusino3169 6 років тому +2

      Dirty glassware can defintely cause this. Dirty surfaces cause nucleation of the gold and won't allow it to be separated by the citrate. Try washing your glassware first (acid bath is more efficient). I also don't use stir bars when I make mine... I just swirl by hand -- I seemed to get better results that way.

    • @Ilovecomedy7
      @Ilovecomedy7 4 роки тому

      Did you make a mixture of HAuCl4 and Na3Cit first and add heat ? If you heated a solution of HAuCl4 and added Na3Cit later, you may have gold in a bulk size

  • @shaliniseth3641
    @shaliniseth3641 4 роки тому

    which is more concentrated red or purple?

    • @WisconsinMrsec
      @WisconsinMrsec  4 роки тому +2

      The purple tube had sodium chloride added to it, which caused the nanoparticles to clump together and appear purple to us. Ideally, if you are doing this experiment, you would add equal amounts of sodium chloride to one tube and water to the other such that the final concentration is the same for both.

    • @shaliniseth3641
      @shaliniseth3641 4 роки тому

      @@WisconsinMrsec Thanks

  • @StevenSchoolAlchemy
    @StevenSchoolAlchemy 2 роки тому +1

    I've noticed a few people working with citric.

    • @gbhxn731
      @gbhxn731 Рік тому

      I want to ask,if in alchemy ,what you used to produce nano gold ,if you dont mind ,can you answer my question 🙏

  • @baguazhang2
    @baguazhang2 4 роки тому

    Why Do I get large gold flakes instead of nanoparticles?

    • @aussieandrew
      @aussieandrew 3 роки тому

      because your a miner

    • @baguazhang2
      @baguazhang2 2 роки тому +1

      @@CristinxcxzzX Thanks for the reply. I found the issue a week or so after I posted this, and the primary culprit was low quality DI water from our university's DI tap. They changed water sources and didn't filter out the organic matter well enough, which also screwed up other people's experiments where they were measuring total organic carbon. I also needed to clean my glassware better. I started using Millipore water and washing all my glassware with fresh Aqua Regia. I even made some Piranha solution to get rid of any organics that might have been left behind by other lab members. I created a new single step process for creating larger gold nanoparticles from these smaller gold seeds.

    • @jimibmore
      @jimibmore 11 місяців тому

      @@aussieandrew you're

    • @aussieandrew
      @aussieandrew 11 місяців тому

      @@jimibmore you´re welcome

  • @StevenSchoolAlchemy
    @StevenSchoolAlchemy 2 роки тому

    I like that hot plate!

  • @nhah2424
    @nhah2424 8 років тому +1

    for what you give light on the solution?

    • @jenniehe9130
      @jenniehe9130 8 років тому +2

      +nunu awaliyah To prove the colloidal property by Tyndall effect

  • @yanisun4016
    @yanisun4016 7 років тому +1

    What's the function of boiling of the solution?

  • @Fickfehler
    @Fickfehler 4 роки тому +1

    Can anyone explain why it goes from blue to red? From what I understand the solution should be going from red to blue, since as they grow they will absorb a bigger wavelength and thus become more blue?

    • @MotoRobee
      @MotoRobee 4 роки тому

      I making some colloid at home from real gold bars with 36v 0.8amp ....
      This method seems like a reverse method ..so far I only achieved the purple stage .... After 3hour of electrolisis.
      Im just testing the waters ..... I'm gonna let it do its job for 6hour and see what changed ..

    • @mimas165
      @mimas165 4 роки тому

      @@MotoRobee Not sure what procedure you follow - is it electrolysis in distilled water using gold wires/bars as the electrodes? Anyway, I tried silver wires in pure water, 30V DC with pre-set current limit 4.5 amps; I tried to make an arc by rubbing the wires against each other and causing them to spark under surface. The next day some gray precipitate settled at the bottom, but water became yellowish-gray indicating silver colloidal suspension.
      Would like to know how your gold colloid/nanoparticles react to a strong neodymium magnet.

    • @alex_goodwin
      @alex_goodwin 3 роки тому +3

      A year later, but maybe my answer will be useful to someone.
      The reaction mechanism is approximately the following: surprisingly, but first, the gold nanoparticles are organized into nanorods as long as there is a sufficient amount of aurate ions in the solution. When there are few of them, under the influence of citrate ions, the rods are crushed into separate spherical nanoparticles, which give the solution a wine-red color.
      Good luck to all!

  • @justinmillard3595
    @justinmillard3595 2 роки тому +1

    gold [79] = iodine [53] + iron [26]; the red solution is iron, red like ferrous sulfate; and the purple solution is iodine;