Size is fix means 64 k But can be stored at any location within the size , DS Hold the starting address from where u want to store data but its not actual address DS value added with offset or displacement address to get physical address. Same in case of CS
Dekho college ke papers to teacher par depend karte hai but I will suggest solve the paper of koe039 of last sem And koe039 and koe 049 of previous year Gor college PUT
Top of extra segment will have value 7FFFFh hai na mam…???
Yes if start with 70000h
Mam how do you calculate the physical address.. At starting?
While calculating address of source we have to take ds or es
As in lecture second you told es but now ds
Depends on data
And what mentioned in question
mam plz make a one more long length vedio related to this topic
Ok
Mam,, Plz make video on Memory Banking Also
Ok
Can we take any value as CS, DS starting address?
Size is fix means 64 k
But can be stored at any location within the size , DS Hold the starting address from where u want to store data but its not actual address DS value added with offset or displacement address to get physical address. Same in case of CS
@@TechnoTutorials2783 I mean the 7000H and 5000H values ma'am...can they be taken randomly??
And why is the cs value 348A?
@@vinayvipparti8467 yes
@@vinayvipparti8467 because DS is 16 bit register which store starting 4 digit of address
Mam digital electronics ke most important questions batadijiye mere pu exam 14 ko or aktu 25se start hai
Dekho college ke papers to teacher par depend karte hai but I will suggest solve the paper of koe039 of last sem
And koe039 and koe 049 of previous year
Gor college PUT
@@TechnoTutorials2783 but mam aap apne hisaab se important most in aktu bata dijiyega
Thanks mam ❤😊😊🤗🤗
Thank you mam
64k ×4 doesn't equall to 1mb
I know
8086 can access 1 MB
But it never work with 1 MB
It work with 4 segments of 64KB
Mam please explain kerdijia 20 ko hex m 14 kese likha apne
20 ko 16 se divide karo
Q=1 remainder =4
Hence 20 =14 in hex