How To Construct and Solve Born-Haber Cycles
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- Опубліковано 27 лип 2024
- This video will help you understand how to construct a Born-Haber cycle from scratch, and how to use it to find the lattice enthalpy for an ionic compound. We'll go through three examples that get progressively more complicated.
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Timestamps:
0:00 - What is a Born-Haber cycle?
1:35 - How to set up a Born-Haber cycle
3:37 - Solving the NaCl Born-Haber cycle
5:16 - Solving the CaO Born-Haber cycle
6:31 - Solving the MgBr2 Born-Haber cycle (slightly trickier!)
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#chemistry #alevel #physicalchemistry #education
hidden gem tbf
Can't believe how underrated this channel is. You managed to make me watch theoric chemistry videos on my own.
This was absolutely the best explanation on born-haber cycle 🔥💯
the animations are truly brilliant
love the animations! make it really easy to follow
Thank you very much, my teacher. This video summarizes my understanding of this topic
Because in the final year curriculum (in Arab countries the final grade is grade 12) there is this lesson in the chemistry curriculum, and you explained the whole lesson to me, thank you very much.
I appreciate your efforts and keep going
Absolutely fantastic
Another great tutorial.
Thank u so much
On the last example why did we have to place 2 as the coefficient is it because Bromine is a diatomic
thanks a lot
thanks sir
Powerful
Do we normally have to draw the diagram in A Level exam or would we only need to calculate the values?
From what I've seen, it usually involves completing a partially-filled Born-Haber cycle, and calculating a missing enthalpy change. Check with your exam board to be sure!
for the MgBr2, why is the atomisation doubled, isn't there a 2 below the Br so wont it be the same?
overall it was easier to understand though thank you, except for the last one
The enthalpy of atomisation describes the formation of ONE mole of gaseous atoms. In the MgBr2 example, we form TWO moles of gaseous atoms, so we need to double the enthalpy of atomisation for bromine.
@@Chemistorian Sir, but for NaCl, why did you not do 1/2 atomisation of Cl since there is 1/2 mole. Sorry for the silly question.
For NaCl, there’s half a mole of Cl2, but that forms ONE mole of Cl atoms. It’s always based on how many moles of gaseous atoms are formed.
Ohh! TYSM SIR