Ive taken calc 1,2,3, linear algebra, intro to differential equations, and am now in complex vector analysis and somehow avoided learning about hyperbolic functions. This was great explanation and just what I needed for this class. Thank you :)
Bruh I'm a fucking engineering 1st year student and this is the first time I'm hearing about hyperbolic functions. I dont recommended walking on any bridges i make in the future
Professor Dave, you continue to deliver on the kicks in the discovery. Learning that Hyperbolic geometry is literally geometry with Hyperbolas has warmed my soul
Great video Dave. Enjoy all your uploaded material. You truly have mastered the art of distilling a topic to it bare essence. Your fan following is very lucky to have you. Just missed one small point though in this particular video. You forgot to explicitly describe the relationship between these trigonometric hyperbolic functions to an actual graphical hyperbola. That I think would have made the video just a tiny bit more complete.
It was the best . I liked your video very much. I was so confused about these h functions but your amazing video helped me a lot. Thank you very much sir.
I Had a calculus class this morning about this exact hyperbolic functions, and it took 90minuts, and professor dave finished it in 7 minutes. Thank you professor dave
The graph of the system y = (1/2)e^x y = -(1/2)e^x is clearly not a hyperbola. On a hyperbola with no vertical asymptotes, the limit of dy/dx as x approaches plus or minus infinity should be finite (it should approach a line). For y = (1/2)e^x , dy/dx = (1/2)e^x which increases without bound as x approaches infinity (the graph does not approach a line).
Agreed! i'm not taking anything away from Professor Daye, but the grapth of Ae^x is the graph of the exponential function, not the graph of the hyperbola. The easy equation of a hyperbola is y=1/x. the area under that curve is ln. the inverse function of ln is e. so there's ur connection b/n e and hyperbolas. A rotated hyperbola has the equation y^2-y^2=R^2
The hyperbolic functions do come from a hyperbola, Dave's explanation is not how it works. Sal Khan has the right idea. "Hyperbolic functions and the unit hyperbola | Hyperbolic functions | Precalculus | Khan Academy." Dave is generally very good, but he's wrong about this.
Curse you Texas Instruments users. Casio is standard for us Aussies :) I just bought an FX-82AU plus II for $12 (Co-op Bookshop on campus had a 70% off clearout on everything), but I kinda have strong feelings for my decade old FX-100AU. Can't have enough calculators.
Because when multiplying 2 exponent functions, you can add the exponents to each other. So e^y . e^-y = e^y-y = e^0 = 1. I hope you understand it. If not, feel free to ask questions.
nope. the signs are different. that change in sign made all that huge difference. example: d[tanh^-1 x] = 1/(1-x2) d[tan^-1 x] = 1/(1+x2) and no you cant multiply the other by negative to get the other. they are completely different.
I'm disappointed in this vid. Professor Dave is my favorite for math videos to assign to my students, because the vids are professionally made, clear, understandable, and have good graphics. Some math vids are just unwatchably bad. I need a good vid on hyperbolic functions, but this one has a glaring error. Dave says that 1/2 e^x and -1/2 e^(-x) form a hyperbola. They do not. Hyperbolas have linear asymptotes. Exponentials do not. The hyperbolic functions do come from a hyperbola, but that's not how it works. Sal Khan has the right idea. "Hyperbolic functions and the unit hyperbola | Hyperbolic functions | Precalculus | Khan Academy" I want a vid with the production values of Professor Dave Explains, but with a correct explanation of how the hyperbolic functions relate to the unit hyperbola, and there isn't one. I'm bummed.
He's not saying that it makes a hyperbola. It makes a function called a hyperbolic sine. It is related to hyperbolas in a similar way that sine and cosine are related to the circle, but it isn't a hyperbola itself. It also has a lot of properties in common with sine and cosine, but it isn't either of those functions either.
@@carultch I know what the hyperbolic sine function is. That is not the point. Listen to the vid from 1:20 to 1:35, where he says: "Now what does this mean graphically? Well, let’s take this expression and break it up into two terms: one-half e to the x, minus one-half e to the negative x. If we sketch these two curves, we get a hyperbola." That is incorrect. Sketching those two curves does not create a hyperbola.
Ive taken calc 1,2,3, linear algebra, intro to differential equations, and am now in complex vector analysis and somehow avoided learning about hyperbolic functions. This was great explanation and just what I needed for this class. Thank you :)
Same....
bruh im taking hyperbolic functions in calc 2
Bruh I'm a fucking engineering 1st year student and this is the first time I'm hearing about hyperbolic functions. I dont recommended walking on any bridges i make in the future
@@mayankjain04 lmao same
I'm a second-year math major and I'm just learning about them now on my own. Why do they skip these?
Professor Dave, you continue to deliver on the kicks in the discovery.
Learning that Hyperbolic geometry is literally geometry with Hyperbolas has warmed my soul
Thank you, Jesus.
Fu ck you don't mocking
@@hunterz3163 aww is hunter mad abt some dead dude
@@hunterz3163 cope
@@sfl928 bruh you get 0 women
@@carmen_13 bro has 💅 in his bio 💀
Great video Dave. Enjoy all your uploaded material. You truly have mastered the art of distilling a topic to it bare essence. Your fan following is very lucky to have you. Just missed one small point though in this particular video. You forgot to explicitly describe the relationship between these trigonometric hyperbolic functions to an actual graphical hyperbola. That I think would have made the video just a tiny bit more complete.
what is that relationship?
Caranya.seorang.seni.bangunan.
It was the best . I liked your video very much. I was so confused about these h functions but your amazing video helped me a lot. Thank you very much sir.
Brilliant. Truly short and poignant, thank you for making this and uploading it.
I Had a calculus class this morning about this exact hyperbolic functions, and it took 90minuts, and professor dave finished it in 7 minutes.
Thank you professor dave
Might have mentioned that y=cosh x makes a catenary.
I never learned hyperbolic functions in Calc 2, this is a great help in calc 3
I love how easy you just made this look!
What has my life come to
No*x^3
Yes*x^2
No*x
Yes
@@chemicallystimulated476 No*x^-1
I am from india but
I understand thes explain easily
So I want to tell you
Thank you very much
Wish you were my face to face teacher!!
Wish you were my face
@@nyksiex 🤣🤣🤣
The video I was searching for..,is Finally found👍. Very well explained
A 6 years old video taught me about EVERYTHING of Hyperbolic Functions. Am I grateful for that❤❤
Very good and conceptually clear explanations.
Awesome and lucid explanation
I have been roaming for so long
But finally i have found him 🙏
His name is Professor Dave
Sameee😭🤭
Me too lol
well explained sir dave.
The graph of the system
y = (1/2)e^x
y = -(1/2)e^x
is clearly not a hyperbola. On a hyperbola with no vertical asymptotes, the limit of dy/dx as x approaches plus or minus infinity should be finite (it should approach a line). For y = (1/2)e^x , dy/dx = (1/2)e^x which increases without bound as x approaches infinity (the graph does not approach a line).
Agreed! i'm not taking anything away from Professor Daye, but the grapth of Ae^x is the graph of the exponential function, not the graph of the hyperbola. The easy equation of a hyperbola is y=1/x. the area under that curve is ln. the inverse function of ln is e. so there's ur connection b/n e and hyperbolas. A rotated hyperbola has the equation y^2-y^2=R^2
@@MrWill2714 But those are really hyperbola.
The hyperbolic functions do come from a hyperbola, Dave's explanation is not how it works. Sal Khan has the right idea. "Hyperbolic functions and the unit hyperbola | Hyperbolic functions | Precalculus | Khan Academy."
Dave is generally very good, but he's wrong about this.
Thank you sir ❤
blessings to professor dave
thanks professor jesus, helps a lot
Just amazing, way better than our teacher in Universities.
Amazing explanation sir! Keep doing.. great work!
You're so good at teaching, sir!
Super.... It was very easy for understand
Thank you so much, this was very helpful!!
Thanx for explaining
Very comprehensive thank you sir.
That's exactly what I needed. Thanks.
Happy teacher's day sir ❤🎉
Thank you so much. Helping me a lot!
If I pass Calc it’ll be because of you 💕
Really helped thank you
Amazing video and epic intro !!!
Hi buddy
Thanks for the translation, it was amazing information❤
Thanks, Dave! God bless you, brother!
Thankyou sir , your lecture helped me from a horrible maths class .
It's amazing how similar they are to normal trignometric functions!
Sir..you are simply superb!!!
Simple and to the point thanks a lot
Thank you, sir
تشکر از شما استاد بزرگ👍
Thankyou😊
Thanks a lot for the amazing explanation sir
Umm... Thank you. Will help me alot for my exam.
Also, we now officially call sech "SHREK".
THANK YOU SIR
GOD BLESS YOU
Thank you father
That was helpful
You're the man
Thanks sir.u are best
Thankyou Professor Dave
Curse you Texas Instruments users. Casio is standard for us Aussies :)
I just bought an FX-82AU plus II for $12 (Co-op Bookshop on campus had a 70% off clearout on everything), but I kinda have strong feelings for my decade old FX-100AU. Can't have enough calculators.
I'm pretty sure 90% of the people on the planet use casio calculators
"I don't always drink hyperbolic functions. But when I do, I prefer Dos Hyperbolas - The most interesting function in the world."
thank you so much
Wait..I don't get it!
Why (e pwer y) Times (e bower -y) is equal to 1???
I need to understand.
Because when multiplying 2 exponent functions, you can add the exponents to each other. So e^y . e^-y = e^y-y = e^0 = 1. I hope you understand it. If not, feel free to ask questions.
How does someone with 2+ million subscribers answer all those email questions lol
well done good explanation , thank you
Very good
Happy Birthday Danae Bertoli from Arkadiko Dramas in Greece. #happy18#zoom#Panagiotis#Efthimis#corona
Happy birthday darling, we still love you, even if you didn't come to the first computer class
My perfect tutor you and chatGPT. I hate my actual tutor never explained well
great video, but i don't understand where does the formula come from, i mean what does euler's number have to do with the hyporbola or its sine???
thank you, calculus jesus
So nice sir
Superb sir
Thanks
Please explain Taylor's theorem for differentiability of function..
Thank u sir
Omg you are a life saver 😱
I love this man
Am happy fr this
What math class do you learn this in?
This was completely unknown to me for all this time??? It was never mentioned in any trigonometry cpurse i took??? Haha what
Hi dave
Sir pls explain about Spintronics .....
Anyone noticed that cut at 3:20?
Amazing
is their anti derivative the same as the ones with trigonometric functions too?
nope. the signs are different. that change in sign made all that huge difference.
example:
d[tanh^-1 x] = 1/(1-x2)
d[tan^-1 x] = 1/(1+x2)
and no you cant multiply the other by negative to get the other. they are completely different.
Tq so much but one suggestion that subtitles in this vedio disturb to see the equations
Turn off caption in your settings
Nice TY
Taking this in high school
Learning math is just learning calculator button
i loved the intro
Due to the subtitles can't able to see the lower portion plz do something to solve its an earnest request🙏
just turn off subtitles for those sections
Which app you use to edit
Adobe after effects
Nice
Jesus. You are genius! 🤯🙏
I'm disappointed in this vid. Professor Dave is my favorite for math videos to assign to my students, because the vids are professionally made, clear, understandable, and have good graphics. Some math vids are just unwatchably bad.
I need a good vid on hyperbolic functions, but this one has a glaring error. Dave says that 1/2 e^x and -1/2 e^(-x) form a hyperbola. They do not. Hyperbolas have linear asymptotes. Exponentials do not.
The hyperbolic functions do come from a hyperbola, but that's not how it works. Sal Khan has the right idea. "Hyperbolic functions and the unit hyperbola | Hyperbolic functions | Precalculus | Khan Academy"
I want a vid with the production values of Professor Dave Explains, but with a correct explanation of how the hyperbolic functions relate to the unit hyperbola, and there isn't one. I'm bummed.
Then make it lazy teacher
@@ConceptualCalculus You might not struggle so much with your job if you could depend on your teaching instead of other people's videos
Weird flex but ok
He's not saying that it makes a hyperbola. It makes a function called a hyperbolic sine. It is related to hyperbolas in a similar way that sine and cosine are related to the circle, but it isn't a hyperbola itself. It also has a lot of properties in common with sine and cosine, but it isn't either of those functions either.
@@carultch I know what the hyperbolic sine function is. That is not the point. Listen to the vid from 1:20 to 1:35, where he says:
"Now what does this mean graphically? Well, let’s take this expression and break it up into two terms: one-half e to the x, minus one-half e to the negative x. If we sketch these two curves, we get a hyperbola."
That is incorrect. Sketching those two curves does not create a hyperbola.
🙏🙏 thanks
Genius
!
يخي انقذتنا،،شكرا
Hello , What is the range of sin h when y=0
the range of function has nothing to do with the coordinates, the range still same which is all real numbers
Jesus himself is on our rescue.
Sir plz solve this problem,
Cosh1/2x=√1/2(1+coshx)
You didn't give the derivative of inverse of cosech , sech and coth
Which country you have live
thanks sir .But electricity vedios may i get ur playlist ?
all my playlists are on my home page, try classical physics.
❤❤❤️ from 🇱🇰
Thank you math jesus