Human Eye and The Colorful World 01 | Human Eye | Power of Accommodation | Defects | Class 10
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- Опубліковано 22 вер 2024
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Focal length = 36.36cm
Power = 2.75 dioptre
Nature = converging
Kese nikala
बहन सही ha
1:07:00
Numerical:
f=400/11
p=+2.75D
lens required- convex lens
nature- converging
Nice
Bhery Goot
super
human eye ncert pg no. 188 in the paragraph of ''power of accomodation'' in the 4th line its written that ''when the muscles are relaxed,the lens becomes thin''. but sir is telling the exact opposite in the video at 15:19 . i am really confused please reply
Q.3 = 2.75 D. Convex lens , converging type.
Plz explain
Ya it's right
Ya you are right
@@pcprashantchaudharygaming4896 kaisa hai
Good
Q3- f=36.36 cm
P=+2.75 D
Nature is converging (convex)
How?
@@sabeehamazhar504use the freaking formula, take v as -80 and u as -25 use the lens formula to find focal length then find the power using the formula P=1/f.
15:50 Mistake! Pls make a correction everyone
When eye lens relax it becomes thin and when eye lens contracts it becomes thick.
Saste Nash mat karo😂😂
@@rohanraj7835he is saying true brother
Yes 🥰 all human sometimes makes mistakes. It should be tolerated...!!
@@rohanraj7835 Yes he is saying the truth only
Who cares
3 DAYS TO GO ✌🏻❤️✌🏻❤️ YOU WILL ROCK 💥
ALL THE BEST FOR YOUR EXAM 98%😃
Thanks brother
Tommorow
Thnx bhai
@Anu oh bro same mera school nhi khula but still studying
Starting animantion was superb and give me thrill ❤️❤️❤️❤️ and ur voice was also changed😁😁
Loved the class sir! You are an excellent teacher!!!
True
100/true
Sath prate sath
Yes true
You are right
Ans of challenger question
(i) f= -18 cm or -0.18m
(ii) f = +66 cm or + 0.66 m
Hope it helps u 😊😊😊
Correct 💯
How??? Plz
@@manuchaudhary4849 Apply p= 1/f with sign
@@manuchaudhary4849 apply p=1/f for finding ans in metre and for finding ans in cm apply P=100/F
@@ethicalhackervishu6041 thanku💕
Q3 power= positive 2.75 nature=converging
Challengeer Q ....for distant F= -18.1 Cm for near vision F= 66.6cm.
😢
Q3 == +2.75D nature of lens = converging
Challenger question==
Distant vision= -18.18 cm
Near vision= 66.66 cm
How do you know that answer will be in centimeters it can be in meters also
Generally,we take focus in metres only in case of determining power and if we have been asked to find just focus then cm is used commonly. but if u want , u can find in metres also but don't forget to convert all the value in same units when u have to use lens formula
How is answer 2.75D??
1:08:20 boht acccha padhaye sir aap 🙂 best video lecture on human eye and the colourful world👍👍👍👍👍👍🙏I just wanna thank you
Tum hi top karoge yarr 🥰🤗
I just loved the way of teaching . Maja aa gaya sir 🙏🏻🙏🏻
1:07:17 (i) Distinct Vision :- f=-0.181m
(ii) Near Vision =0.66m
Bhai kaise bnaya tune?
@@sukuna7890 focal length is reciprocal of power
Bhai, Challenger question to Mazak tha, Matlab Kya bolu🤣, bohot zyada easy tha
Dono ka ans -18.18
😂
Sir I have a doubt as you said when ciliary muscle relaxed the lens become thick and the focal length become small . But in our text book when the ciliary muscles relax the lens become thin and the focal length increase.
Right
I have faced the same problem
Plz solve this problem
I have faced the same problem. Plz
Plz sir sort our this problem
Sir i have a doubt,
In NCERT, it is given that when muscles are relaxed the lens become thin.
And here u r telling that the becomes thick.
I am confused about this now sir ,
Yes
I am from West Bengal board. I also watch your videos.
Same here bro
Tum concept era mein bhi ho na
Haa
@@MINDKING-MK nice.
North or south Bengal?
01:7:23 q1- distant vision = -0.18m and near vision =+0.66m
Kaise aya bhai pls explain
Ye kese aaya ?
Power ki formula kya hai 1/f ya 100/f?
Power of the lens =Plus 2.75D
Type of the lens is converging lens
Thanks sir It helped a lot ...🙏
👌👌 very fast answer bro
Congratulations 🎇👍👏
23:43 close room work 😂 by rakshak sir
Sir can you make another one shot video for 2023 boards including mcq and other necessary questions that are must for the school boards class10 I would be thankful to you🙂😉
😢😢😢🎉🎉🎉😢
😅
😅😊
🙏
🙏
1:07:07
Focal length= 400/11cm
Power= 2.75D
Lense= convex lens
Also converging
😅
Que3. Nature of lens is convex and Power is +2.5
Challenger. (i) 0.18 and (ii) 0.67
Thanks for the great session sir😇
Glt hai
@@aaryanrupa4158 18.18 hai kya sahi ?
Are idiots dono answer thik hai bas cm aur m ka difference liya hai tumne parthsoni2118 ne m ke liye P = 1/f liya hai aur tumne cm ke liye P = 100/f liya hai . Be attentive in the physics wallah classrom ....😊😊
galat hai3rd ka ans 2.75 D hai@@YASHSHARMA_045
The best physics teacher that i have ever seen is you sir
You are right
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He is Second to alakh sir
@@studypoint2966 from edumantra ?
Question 3rd numerical ... Focal length - 400/11
And power - 2.75 dioptre
The lens is converging ( convex)
Challenger question ans.
Distant vision f - -18.18
Near vision f- +66.6
Power of convex lense is postive
Focal length is also positive
Band kamre me Kam Karte Hai 😂😂😂 rakshk sir funny dialogue 😅😅😅😂😂😂😂😂😂
Distinct vision :p=100/f in Cm so f=100÷(_5.5) which is _18.18cm and similarly for near it is 66.6 cm
Shi h
You are right bro
Quesion no'3 = 2.75D ,
=Convex lens ,
=Converging type
Sir I have a doubt if maximum focal length is 2.5 cm and minimum 2.27cm then the lens 2f must be 5cm if the image always forms at 2.5cm then the object should be beyond C which is beyond 5cm then when we place object at 7or 8 why is the image blurr because image forms between F and 2f e
6 sns
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Power is 2.75 d and nature is - convex lens , hypermetropic eye , converging work , real and inverted image on corrective and suitable power lens
Hi
@@madhav1550 hello
I have very important question to ask! As you said In the video that for the correction lense the object Will be the real object but for the crystalline lens the object Will be the virtual or in other words the image of the correction lens! but how is it that the image of the correction lens has it behind of the lens!??
Write the question in the systamatic way to understand
@@itsmeayush3377 I mean the object what we are seeing through a corrective lens is a virtual right?
The eye itself sees this virtual image as if it was the actual object and creates the final real image on the retina of the eye.
@@laxmiparida4119 obviously no
@@laxmiparida4119 nope...we see real objects
F-36.3,P-2.75D, convex lens because it helps converging the ray
What is hypermetropia? State two causes with help of ray diagram show a , this defect b, correction of this defect
Sir you are 2nd best teacher of physics on UA-cam because the 1st on is unbeatable (Alakh Pandey Sir) but i love you teaching technique. I am in class 9 inside of this I caught every topic of this chapter very easily because of you
Love ❤from Patna
Pahle 9th padhlo
@@143_Prince-.😂
1:07:11
Focal length is 36.36 cm
Power is 2.7 D
Nature : converging (convex)
Also
In last question :-
(i) -0.18m
(ii) 0.66m
By swati Sharma..
Concex 😂
How?
@@chaipeelo274😮Friendship is a devoted relationship between two individuals. They both feel immense care and love for each other. Usually, a friendship is shared by two people who have similar interests and feelings.
Chalenger question:-
1) distant focal length = -1.81m(-181cm),
2) near focal length = 0.66m(66cm)
Galat
1st wala
Yes it is 0.1818..
@@meitnabhikhaasnahi1470 is 18.1 cm focal length correct?
yes it's correct
(i)distinct vision = -18.18 cm= focal length
(ii)near vision= 66.66cm= focal length
Bhi galt ha
Focal length 3.2 CM
ha
@@darknightgaming7255bhai power dia hi hain uska reciprocal chahiye 😂
sir the answer of the first given question by you is 2.74D and a convex lens with nature converging
Thank you so much sir for teaching in such a great way...💯
Hi
"Isliy Bhagwan ne humko ya nature ne humko" this line shows that you are a true physics teacher! 🤓😎
53:42 YAAR LOGO KO AISA Q LAGTA HAI KI GEETA RAMAYAN SIRF BUJURG HI PADHTE HAI? HAMARE PARIWAR ME TO SBHI NE PADHA HAI EVEN MAINE BHI AUR MERA DHRM BHI YAHI KEHTA HAI !! FIR HAMARE GRANTH BUDDHE LOGO KE LIYE HI SIMIT KYUN HAI?🙂
Sahe bola bhai
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Where is purple heart
Sir you are the life of physics in 10th ❤❤
Now l am in 11th and l miss my 10th days 🎉
Why u watching dis
@@JAANY_GAMER for memories i suppose
@@goofyahhswastik anybody ask
@@JAANY_GAMER u literally asked??
@@abhi.108 bruh man
Rod and cone cells are present on retina and transfer the light signals to electrical signals and these electrical signals are interpreted by the brain.
But in case of myopia or hypermetropia when image is formed behind or in front of retina then at that place no rod and cone cells are present
So there is nothing to transfer the light signals into electrical signals so then no image should be formed
But still a blurred image is formed???
answer of last 3rd question should be convex lens and convering nature.🧐🧐🧐🧐🧐
HERE THE VALUE OF (F) IS +400/11 AND THE VALUE OF (P) IS +2.75D.
THEREFORE, THE LENS IS CONVEX LENS AND SINCE IT'S NATURE IS CONVERGING LENS.
WONDERFUL 😃EXPLANATION BY YOU SIR I UNDERSTOOD ALL THE THINGS CLEARLY👍 LOTS OF LOVE FROM MY SIDE 💖❤🥰
This chapter is deleted 🤔
@@shivasstories7239 No bro, it is in the syllabus of 2022-2023.
It was deleted for our seniors.
Mera P- 2.77 aara
Same answer
@@rishuvlogs5470 👍 good
PW is a great team and working institute
Sir, in iris the amount of light entering the eye by adjusting the size of pupil ..... But u say that in pupil it regulates the amount of light entering to the eye ... Sir plz comment the answer that which one is right or wrong .... I also check in Google but iris help the amount of light entering to the eye ... Hai ...
But knowing & research this I think that ur answer is wrong .... So plz answer my question sir ..... l hope you may answer the comment 🙏🙏🙏
Physics जलवा 😢😢
*after seeing rakshak sir video *
Physics हलवा 😇😎
Aap gjb ke padhate ho sir ,dil se thank you 💯💞🙏
I am watching this in 2022
And now the syllabus once again increased.......
Same here🥲🥲
Yes bro
Sir ncert ke bahar ka bhi explain kar diya kariye achha hai hm competition wale bacche bhi aap ki class dekhte hain..
Thanks sir.
In the third no. Of numerical question the f= 400/11 cm
P= 11/4 D
and The nature is converging
Q3. P=+2.75D
Nature: Converging (convex)lens
Challenger question
I)-0.181m
ii)0.667m
Challenger question- Focal length for lens of power -5.5D is -18.18cm and for power of 1.5 D is 66.66cm
How?
Power of lens formula = p=100/f
-5.5=100/f then f is multiple with -5.5
-5.5f=100
F=100/-5.5
F=-18.18 cm in m =- 0.18m
Do this same process again next question:
All teachers are amazing 😍😍
☺️☺️☺️
Nice
@@md_ankit_unique5957 hlo bro 💗
very interesting way of teaching art student hone k bd bhi boht ache se smjh me aya thank u sir
Q. No.-3
Focal length= 36.36cm
Power= 2.75D
Nature= Covex lens or converging lens
Humari khud ki eyes iss video ko dekh ke apne bare me samjh rhi hai!!💀😂
😂😂😂😂😂😂
Actually challenger question was easiest one🙂
1)-18cm is focal length(concave lens hai)
2)66cm focal length(convex hai)
Yeah you are wrong you did 100÷5.5 which is wrong 😅
@@dhararajpara9916 centimetre mei laane ke liye 100 se hi multiply krte h
you all are wrong
The both ans is -18.18
Challenger question :
( i ) distant vision : -18.1 cm
( ii ) near vision: 66.7 cm
@greenstuff3791 Isn't the power alredy given? Then we should just do the reciprocal of it isn't ?
Sir eyes have so much fluid also these fluid have their own optical density then light rays coming will suffer deviation??
Sir myopic eye lens thin hota h......
Challenger questions
1) focal length = - 0.18 m
2) focal length = +0.67 m
Hmna p=100/f liya ha
Agr koi p=1/f la ga different answer aya ga by the way ya la skta ha ke na😅
Distant vision - 0.18 m
Near vision - 0.67 m
Your answer is wrong
For near vision:1000/1.5
For distant vision:1000/-5.5
39:48 (with great power comes great responsibility )
Sir iam from Maharashtra board but i follow ncert by physics wallah. Your explanation is very realistic and it gives the power to imagine the physics because I love physics ❤❤❤❤ . Love you sir.
sir your teaching level is awesome 🙏❤️
Sir how can you say that if we divide a object in to infinite times we got zero?
I can't understand this
What are teachers of physics wallah ! amazing 🥰🥰
Sir l love your physics u r great teacher of physics 💓🙏
❤️ Top notch explanation sir ❤️.
From Maharashtra board ( eng medium )
bro MH board me kitne percent aye?
@@SUMIT08-07 96.60%
15:45 sir you said that when muscles are relax then lens is thick
And when muscles contracts then the lens is thin
But it is just opposite. But no problem, because every human being make mistakes
I write this so that everyone can learn write thing who are depended on you and me also 😅
Sir you are best for me you created my interest in physics 😀😍😃😃🥹👌👌👌✌️🫶
Sir you are amazing 👏 you are the best teacher of the world 🌎
P=-2.75D
Nature of the lens - Converging (Convex Lens)
His eyes are weak ... We need to strengthen them... We need a convex lens
@@rajanshukla2512 yes You are correct.
Give soln pls
1:06:11
Ans - Converging lens (convex)
P = 2.75 Dioptre
Converging but how
@@mahi_536 bcoz it is convex lens and convex lens is converging lens.
Right 🤛
Because power is in +ve diapter convex lens
Bhai mera toh .00275 aa raha hai
Class starts at 3:49
Thank me later
This sir is the best in the whole team
Thank you very much, sir... always been interested in your teaching only
😂😂😂😂😂😂😂😂
P=2.75
Nature=converging
Lense=convex
Nahi aaya yarr
Correct vro 👍🏻
F=36.36 and,
P=2.7
Badhiya Bhai mujhe bhi ans check karna tha accha hua likh diya 👍👍
@@ranjeetsingh-fe7qn 👍👍
I am from AMU board and i always watching every chapter videos of physics from 9th class.your explanation is very well and easy to understand topics god bless you sir
ham bhi amu se hi hain
Acchaa bhai
@@anees_khan338amu?
" Aligarh Muslim University " (Amu)
are phones allowed in amu class 9th hostel
Challenger Question's Answer:
(i) The focal length of the lens required for correcting distant vision is - 0.18 metres.
(ii) The focal length of the lens required for correcting near vision is + 0.67 metres.
You have used the wrong formula.. use this one
P = 100/f because power given is in cms...
Sir your teaching is super duper !!!!😊😊
we need teacher like you in our school
Sir said that when the ciliary muscle relaxed the lens become thick but in NCERT it is clearly written that when the ciliary muscle relax the lens become thin
What to do😔?
Books has some mistakes at some places. The lecture has all the content correctly explained.
@@prabjeetsingh4768 but on Google also it is writter that when salary muscle relax lens become thin
❤❤You are the best teacher..❤❤ 💚💚Uddan coach is the best..💚💚 💙💙Tomorrow is my paper 📄📄 of Science 🔬🔬...💙💙Thnx sir 💚💚.. You are amazing 💚💚
Focal length :36.36
And power of lens is 2.5 diaptor
Q no. 3
Power is 2.75d
Focal length : 36.3
Power : 2.75 D
Thanks ans ke liye😊
1:07:00
P=2.75 D
Convex lens - converging nature
Pls explain ki focal length -400/11 kaise aaya?
@@rudrakumar3037 ye 2.77 aayega na??
Sir,whose focal length you have calculated,corrected lens or eye lens?
Sir very good teaching but when ciliary muscles relaxed the lens becomes thin but you said opposite to it I just want to make clear it for other students like me
Ys same doubt
Sir please kimdly once check the accomdation power of lens . when ciliary muscles contract it relaxes the tension on lens making it spherical decreasing focal length. Ulta hai jo aapne samjhaya hai uska .
😂
Sir when the ciliary muscles are relaxed the eye lens become thin not thick