Scattering in 1D. Incoming and outgoing waves

[@zphuo]

@12:00, is't due to |A|=|B| the outgoing wave function only have phase factor ?

[@Cannongabang]

yeah but since this time there is a potential, and since in the absence of it there is no phase change, everything he says makes sense i guess

[@pinakichatterjee705]

It's because of probability conservation. The probability going in should be the probability going out unless there is any probability accumulated in x

[@not_amanullah]

Thanks 🤍❤️

[@pinakichatterjee705]

Can't the particle just go into the potential and stay there? If potential is sufficiently negative that the total energy becomes negative it should form a bound state there no?

[@hopefibration2232]

Given that we're talking about scattering states, I think the assumption is that E > V.

[@asheshkafle4984]

At 5:50 how can there be reflected wave from a infinite potential barrier? The wave function must vanish there no??

[@pinakichatterjee705]

@@asheshkafle4984 an infinite barrier is always perfectly reflective. similar to how a particle just bounces back and forth inside a 1 D box outside which the potential is infinite. wavefunction vanishing doesnt mean it can't reflect. just that it can't penetrate the barrier and wavefunction outside is always 0.

[@diviner524]

The total energy is conserved. If we assume E>0 when the particle is outside the potential (which is pure kinetic energy), then the particle will have a high kinetic energy when it is inside the well (Ek = E + V0), so it won't be trapped.

[@brainstormingsharing1309]

👍👍👍👍👍

[@not_amanullah]

This is helpful ❤️🤍