Thank you very much sir! the way you explained it's really easy to keep it mind without effort anytime. simply u make it very easy to us. do upload other parts of arithmetic! eagerly waiting
2^20/10 can be solved as (2^4*5)/10= (16 ^5)/10 therefore remainder is 6 I have made 6 at unit place because as sir has make diff in every question of 1 because 1 gives same result wtever the power is in the same way 5 and 6 also give the same resukt whatever the power is ..
In ques2 at 2:46 👉( 2^20)/10 2^3 = 8 is near to 10 => (2^(3*6) + 2^2 )/10 => (8^6 + 4)/10 => Rem = 2+4 = 6 (2 has become +ve because of the even power)
Hi sir in ur previous part 1 2^99 /33 was solved in diff way and now 2^20/10 In other pattern can u plz compare both methods and focus on different pattern
sir in that question 43^86/5 .Why shall we take square of 43 ? simply we can divide 43 by 5 remainder +3 =+3^2*43 whole divided by 5 =-1^43=-1 then 5-1 =4
If 5^135 is divided by 7 then remainder is 2. Hint-multiply by 2 in both numerator and denominator then by simplify answer become 4. Now we want to divided by 7 not 14 so, in end we divided by 2 and finally answer become 2. (This doubt is for Arnab barman)
2^4 divided by 3 gives remainder of 1 as 2^4 =16 and 16 divided 3 gives remainder 1 but according to your trick remainder should be 2 as 2^4/ 3 gives remainder of -1 , it cant be answer so subtract it from 3 get 2 Confused
2 power 20and divided by 10 hai to iska answer +2 aa raha hai Kyoki 2²°= 2 ki power 5×4 lika sakte hai agar hum ese karte hai to 32⁴/10 Jaise sir ne bataya hai ushke accroding karte hai to 10×3=30 so remainder hoga +2 Agar jo jo meri baat se agary hai vo like kare and commnet kare
U solve 43^86÷5=4 and 39^42÷10=9 in this -1 should be convert into 1 because -1^42=1 According to u,43^86÷5 should be 2..There is a lots of confusion so plzz make it clear...U solve every ques in diff. Way even ques r of same type
A question like 9^1000/17. Even if we do 9 square, cube, to the power 4,5 the difference with denominator doesn't show up as plus 1 or -1. So basically how to solve questions like this in which the difference isnt coming as plus one or minus one.
Hi sir Please solve this question and I already try but can't solve this and also provide the solution Please ! What is the remainder when the no 4444^4444 is divisible by 9 ? 1. 4 2. 6 3. 7 4.8
Sir ,141×2 =282 hota hai jab ki hamko 242 bana na hai ...Ques 3 . Reply sir answer thik hai mgr power 121 hoga...odd number hai power 121,141 iss liye chal gaya
Hello sir you have explained very clearly it is very easy to understand and remember the techiques.I Requested to give a few number of questions with direct answers but not eplanation it will be very helpful for us and we can practise more ,thank you sir.
sir apne ek q bataya tha jaise 2 power 100 diveded by 3 on solving the above get remainder -1 while substracting 3 get final reult 2 which is wrong plz give another method
2^20/10 remainder is not 3 . the reaminder is 6 check it again and please modify ur trick sorry to say this , Because of you so many people are going wrong with this trick . first try to explain the trick with all conditions and exceptions and then solve problems.
i have seen most of your videos and they are amazing but can make one more on remainders showing how to get remainder if we write a series of numbers and divide it by some numbers (eg. if we write 1to 29 side by side i.e. 12345....26 and divide it by 9, what will be the remainder?). waiting for your reply and next videos!
Sir, the types of questions u mentioned in this video is sufficient for IBPS PO pre / clerk or not.. Sir plzz suggest.. I show all these sessions of reminder theorem.
sir in qsn 2 2^20/10 is same as 2^19/5....so remainder should be same.....so why you multiplied by 2.....( remainder should not change as both mean the same....correct me if i am wrong
in the previous video part 1, u mentioned that (39^42)/10 which gives -1 but it is 10-1=9 but according to second video which is a even power it should be 1 because of 42...why is it wrong then?
Guys ..sir ki pehli video mei ek question hai 39^42/10 , uska answer 1 aayega , sir ne by mistake 4 likh diya hai , because power jo hai wo even hai ....wha comments turned off hain isley yha pe likha...
in the question ((7^9)-4)/7 , using an example of 14 is the only way to solve this que ? coz there r soo many other multiples of 7 from which the answer is not coming. (only with some specific numbers)
Thank you very much sir! the way you explained it's really easy to keep it mind without effort anytime. simply u make it very easy to us. do upload other parts of arithmetic! eagerly waiting
12^107/37
(2^4)/5 actually the remainder is 1 ,but when i follow your method it is 2 ..i cant understand why it is like this
@vinod sharmai also want this type of problem's solution
@@yagadasukrishna6448 1 hi hoga try again
@vinod sharma 1
43^86=(40+3)^86 . 40^86 is divisible by 5 , so 3^86 =9^43 . 9^43/5 ,rem is -1 . so 5-1=4 .
2^20/10 can be solved as (2^4*5)/10= (16 ^5)/10 therefore remainder is 6
I have made 6 at unit place because as sir has make diff in every question of 1 because 1 gives same result wtever the power is in the same way 5 and 6 also give the same resukt whatever the power is ..
In ques2 at 2:46 👉( 2^20)/10
2^3 = 8 is near to 10
=> (2^(3*6) + 2^2 )/10
=> (8^6 + 4)/10
=> Rem = 2+4 = 6
(2 has become +ve because of the even power)
Hi sir in ur previous part 1 2^99 /33 was solved in diff way and now 2^20/10 In other pattern can u plz compare both methods and focus on different pattern
sir in that question 43^86/5 .Why shall we take square of 43 ? simply we can divide 43 by 5 remainder +3 =+3^2*43 whole divided by 5 =-1^43=-1 then 5-1 =4
If 5^135 is divided by 7 then remainder is 2. Hint-multiply by 2 in both numerator and denominator then by simplify answer become 4. Now we want to divided by 7 not 14 so, in end we divided by 2 and finally answer become 2. (This doubt is for Arnab barman)
What is the remainder when 444 ^444 ^ 444 is divided by 7 ? (GMAT Type Question)
4 ( 3×3×3/7 )
@@ShikshitRajasthani 6
What is the remainder when 13 ^ 5 + 14 raise to the power 5 + 15 ^ 5 + 16 to the power 5 is divided by 29
And soon plz
Sir if 5^540÷ 7=?,so what will be the remainder
Cyclicity of 3 is 4...
86/4 remainder is 2...so 3^2=9
9/5..remainder is 4
Answer is 4
2^4 divided by 3 gives remainder of 1 as 2^4 =16 and 16 divided 3 gives remainder 1 but according to your trick remainder should be 2 as 2^4/ 3 gives remainder of -1 , it cant be answer so subtract it from 3 get 2
Confused
At 11:36 there Is no need to find square of 43. Without any division also ans can be calculated. Correct me if I am wrong sir..
2 power 20and divided by 10 hai to iska answer +2 aa raha hai
Kyoki 2²°= 2 ki power 5×4 lika sakte hai agar hum ese karte hai to 32⁴/10
Jaise sir ne bataya hai ushke accroding karte hai to 10×3=30 so remainder hoga +2
Agar jo jo meri baat se agary hai vo like kare and commnet kare
2²⁰= 1048576
Divided by 10, you will get 6 remainder
Sir in question 6, it is 5x9= 45 so why not remainder= -2?
U solve 43^86÷5=4 and 39^42÷10=9 in this -1 should be convert into 1 because -1^42=1 According to u,43^86÷5 should be 2..There is a lots of confusion so plzz make it clear...U solve every ques in diff. Way even ques r of same type
A question like 9^1000/17. Even if we do 9 square, cube, to the power 4,5 the difference with denominator doesn't show up as plus 1 or -1.
So basically how to solve questions like this in which the difference isnt coming as plus one or minus one.
9^16 will leave remainder 1 when divided by 17
Sir, u made some Qs so complicated
2 ^ 20 => (2 ^ 5 ) ^4 / 10 => 2 ^ 4 /10 => 6 remainder
43 ^ 86 / 5 = 3 ^ 86/5 => (3 ^2 ) ^ 43 /5 => -1 ^ 43 => -1 + 5 => 4
Sir plz solve this question-: What will be reminder when 27^400 is dividing by 25.
Thank you for your videos. At 5:27 you multiplied 3x2 to get the final remainder of 6. Was that to return 2^1 removed earlier? Please verify.
Yes..
Hi sir
Please solve this question and I already try but can't solve this and also provide the solution
Please !
What is the remainder when the no 4444^4444 is divisible by 9 ?
1. 4
2. 6
3. 7
4.8
Very carefully and Nicely he has picked out all the easy questions in remainder theorm and sweetly explained it .. 👏👏
Can you compare the solution of 3^60 divide by 28 in 1st lecture and solution of 51^25 divided by 13 in 2nd lecture ?
Which one is correct ?
Sir ,141×2 =282 hota hai jab ki hamko 242 bana na hai ...Ques 3 . Reply sir answer thik hai mgr power 121 hoga...odd number hai power 121,141 iss liye chal gaya
In question 39 power 42 divided by 10 , -1 comes as remainder.. will it not become 1 due to even power ??
Hello sir you have explained very clearly it is very easy to understand and remember the techiques.I Requested to give a few number of questions with direct answers but not eplanation it will be very helpful for us and we can practise more ,thank you sir.
what is the remainder when 1!+2!+........ 100! is divisible by 15 ?
Sir your teaching style is excellent...... I got my answer..... Thank you sir
(2^100)/101 and (23^45+13^45)/18 find the remainder of both .sir please give me the solution of both .
Thankyou sir. Pagal hogya hua tha mai iss concept ke chakro me. You cleared it very well. Thanks a lot
Q1) 7^45 divided by 47
Q2) 8^900 divided by 29
plzz sir give me the solution
it was a very usefull video. Go with further example then u will get to understand easily
Before video. You do (power of39 is 42)÷10 = remainder 10-1=9. But here power is even . The answer should be 1. Plz see every thing
In question 2- wen you divide 5 by 2 the remainder is 3 and not 2.
Calculate 3^287 % 23?
Bahut achi explanation sir...thank you very much...I can understand when I first time seen your videos sir ...thank u
sir apne ek q bataya tha jaise 2 power 100 diveded by 3 on solving the above get remainder -1 while substracting 3 get final reult 2 which is wrong plz give another method
Hi Sir, very nice concept, please let me know which equipment are u using for this video. Thank you sir.
Nice Video, very helpful for beginners
Q2 could have a better solution if you write 2^20 as 16^5 here we get 6 reaminder after divide by 10
what is the remainder when 3^1000(3 raised to power 1000) divided by 23
2^20/10 remainder is not 3 .
the reaminder is 6
check it again and
please modify ur trick
sorry to say this
, Because of you so many people are going wrong with this trick .
first try to explain the trick with all conditions and exceptions and then solve problems.
When 3^247 is divided by 17 then what will be the remainder? Sir how to use the trick in this question?
sir ager hum 2^20/10 iss ko hum asisa kyu nhi kr sakta hai like 8^6*4/10=-2, 10-8=2 answer is 2 kyu nhi ho sakta hai plz tell me
43 p 86/5 , here 5*9=45 so -2 then 5-2=3 remainder 3 ? please explain this.
We can easily solve que 6 simply writing (45-2)^86 and further (-2)^86/5....so simple..
i have seen most of your videos and they are amazing but can make one more on remainders showing how to get remainder if we write a series of numbers and divide it by some numbers (eg. if we write 1to 29 side by side i.e. 12345....26 and divide it by 9, what will be the remainder?). waiting for your reply and next videos!
1
(2^4)/5 actually the remainder is 1 ,but when i follow your method it is 2 ..i cant understand why it is like this
Sir can you please solve this question : 39^150 / 7
Sir, the types of questions u mentioned in this video is sufficient for IBPS PO pre / clerk or not.. Sir plzz suggest.. I show all these sessions of reminder theorem.
Find the remainder 723^243+318^243 divided by 17
6:45 iska ans toh 3 aana tha na 3^243/5=5-2=3
Find the reminder when 7^23 is divided by 8 solve the problem please
(3¹⁹⁶+4¹⁹⁷+5¹⁹⁸)÷197 than what is the remainder sir ?
Sir thanks for yr guidelines but we are still confused at some points when to use which trick
U r right
Yes sir I am getting confused in some problems
Yes sir same with me to
You are doing really awesome.
It's just need some time for people to come across you and follow you in millions.
When 25732 ^1234 is divided by 11,the reminder obtained is :
9÷5 reminder is 4 but 9^2÷5 is 1 why power are creating difference
why did you closed the comments in part 1 video
What is the remainder when 3^243 is divided by 5?__sir your trick is not applicable for it,,sir,, answer please
nice explanation sir i want full aptitude problems sir
nice simplification but sir question6. me 43ka square 1849 solve karna kya jaruri hai...if simple 3*3=9
Sir ea tho same type Ka hai (5^70+7^70)/74
Sir ea bathao
Sir how to solve 73+75+78+57+197 is divided by 34 ..
If power is considered then why the remainder of 39^42/10 is 9 in place of 1 in previous video ?
3^243=9^121*3 not 141 correct it please.
Remainder of 122^122 divide by 31
find the remainder when 73+75+78 is divided by 34
What is the remainder when 15 to the power 400 is divided by 800?
Use Cyclicity formula as well, will make these things much easier where diff. is huge.
Find remainder when 51 ^203 is devided by 7? ..plz show me how to solve it ..
What will be the remainder when
18^19^20 is divided by 100 ?
What is the concept of this type question. Why "the powers of nominator doesn't matter"?
sir in qsn 2 2^20/10 is same as 2^19/5....so remainder should be same.....so why you multiplied by 2.....( remainder should not change as both mean the same....correct me if i am wrong
Sir
1- 27^27/100
2- 3^40 / 11
how to solve this
Sir, can't we consider difference of 2 as near to the denominator ??
in the previous video part 1, u mentioned that (39^42)/10 which gives -1 but it is 10-1=9 but according to second video which is a even power it should be 1 because of 42...why is it wrong then?
1 hai bhai remainder 9 nai h
67^67 +68 divided by 68, the reminder is???
Find the remainder when (53)49 is divided by 36.plz sir solve this
question 7:sir 3/5 remaider 3 bhola aap pehle in this one you are simplyfying
Guys ..sir ki pehli video mei ek question hai 39^42/10 , uska answer 1 aayega , sir ne by mistake 4 likh diya hai , because power jo hai wo even hai ....wha comments turned off hain isley yha pe likha...
Pls solve 2^39 divided by 39 by sir's method....
find remainder when 29 to the power 21 is divided by 17
Sir 39^42÷10=????
51^25÷13=????
Reminder btana sir
What is the remainder when 5^91 is divided by 91?
32 per pawer 32 per pawer 32 divided by 9 solve it
Sir please solve some more subractions equations which is not divisible by denominator..
At 5.01 minutes should not the remainder be 3?? Instead of 2????
You made me understand very clearly thanks a lot sir,,, some more difficult question plz.....
find the remainder when 11to the power 35 is divided by 55
nice explanation + easy trics
Remainder when 1^5 +2^5 +3^5+...........100^5when divided by 4 is ? Plz tell me someone fast
ua-cam.com/video/25wVMWu16aI/v-deo.html
please visit our channel
thx sir.very useful ..but plz explain us if some que came like what's the rem.when 2 raise to the power 9 divided by 5..
The remainder when 10^10+10^100+10^1000+......+10^10000000000 is divided by 7 is ?
in the question ((7^9)-4)/7 , using an example of 14 is the only way to solve this que ? coz there r soo many other multiples of 7 from which the answer is not coming. (only with some specific numbers)
Remainder when 2 ^4901 divided by 11
17to power(16) divide by 7
The least remainder when 17^30 is divided by 5 is
Fantastic sir thank u very much
sir math (-34)+79(-89-58)
Nicely explained