Thank you very much sir! the way you explained it's really easy to keep it mind without effort anytime. simply u make it very easy to us. do upload other parts of arithmetic! eagerly waiting
2^20/10 can be solved as (2^4*5)/10= (16 ^5)/10 therefore remainder is 6 I have made 6 at unit place because as sir has make diff in every question of 1 because 1 gives same result wtever the power is in the same way 5 and 6 also give the same resukt whatever the power is ..
Hi sir in ur previous part 1 2^99 /33 was solved in diff way and now 2^20/10 In other pattern can u plz compare both methods and focus on different pattern
If 5^135 is divided by 7 then remainder is 2. Hint-multiply by 2 in both numerator and denominator then by simplify answer become 4. Now we want to divided by 7 not 14 so, in end we divided by 2 and finally answer become 2. (This doubt is for Arnab barman)
In ques2 at 2:46 👉( 2^20)/10 2^3 = 8 is near to 10 => (2^(3*6) + 2^2 )/10 => (8^6 + 4)/10 => Rem = 2+4 = 6 (2 has become +ve because of the even power)
sir in that question 43^86/5 .Why shall we take square of 43 ? simply we can divide 43 by 5 remainder +3 =+3^2*43 whole divided by 5 =-1^43=-1 then 5-1 =4
A question like 9^1000/17. Even if we do 9 square, cube, to the power 4,5 the difference with denominator doesn't show up as plus 1 or -1. So basically how to solve questions like this in which the difference isnt coming as plus one or minus one.
Hello sir you have explained very clearly it is very easy to understand and remember the techiques.I Requested to give a few number of questions with direct answers but not eplanation it will be very helpful for us and we can practise more ,thank you sir.
Hi sir Please solve this question and I already try but can't solve this and also provide the solution Please ! What is the remainder when the no 4444^4444 is divisible by 9 ? 1. 4 2. 6 3. 7 4.8
2^4 divided by 3 gives remainder of 1 as 2^4 =16 and 16 divided 3 gives remainder 1 but according to your trick remainder should be 2 as 2^4/ 3 gives remainder of -1 , it cant be answer so subtract it from 3 get 2 Confused
Sir ,141×2 =282 hota hai jab ki hamko 242 bana na hai ...Ques 3 . Reply sir answer thik hai mgr power 121 hoga...odd number hai power 121,141 iss liye chal gaya
sir apne ek q bataya tha jaise 2 power 100 diveded by 3 on solving the above get remainder -1 while substracting 3 get final reult 2 which is wrong plz give another method
U solve 43^86÷5=4 and 39^42÷10=9 in this -1 should be convert into 1 because -1^42=1 According to u,43^86÷5 should be 2..There is a lots of confusion so plzz make it clear...U solve every ques in diff. Way even ques r of same type
i have seen most of your videos and they are amazing but can make one more on remainders showing how to get remainder if we write a series of numbers and divide it by some numbers (eg. if we write 1to 29 side by side i.e. 12345....26 and divide it by 9, what will be the remainder?). waiting for your reply and next videos!
sir in qsn 2 2^20/10 is same as 2^19/5....so remainder should be same.....so why you multiplied by 2.....( remainder should not change as both mean the same....correct me if i am wrong
2 power 20and divided by 10 hai to iska answer +2 aa raha hai Kyoki 2²°= 2 ki power 5×4 lika sakte hai agar hum ese karte hai to 32⁴/10 Jaise sir ne bataya hai ushke accroding karte hai to 10×3=30 so remainder hoga +2 Agar jo jo meri baat se agary hai vo like kare and commnet kare
Sir, the types of questions u mentioned in this video is sufficient for IBPS PO pre / clerk or not.. Sir plzz suggest.. I show all these sessions of reminder theorem.
in the question ((7^9)-4)/7 , using an example of 14 is the only way to solve this que ? coz there r soo many other multiples of 7 from which the answer is not coming. (only with some specific numbers)
sir, ur teaching is excellent, it is easy to understand and now i am feeling comfortable in solving the questions after watching ur videos. Thank u sir...
in the previous video part 1, u mentioned that (39^42)/10 which gives -1 but it is 10-1=9 but according to second video which is a even power it should be 1 because of 42...why is it wrong then?
In previous video me aap ne 39 ki power 42 h es ko 10 se divided kar rhe h es me remainder -1 aaya then -1 ki power 42 hogi to wo +ve ho jaye ga i.e 1 so remainder 1 aana chaye but aap ne es question me remainder 9 nikala. how ?
Thank you very much sir! the way you explained it's really easy to keep it mind without effort anytime. simply u make it very easy to us. do upload other parts of arithmetic! eagerly waiting
12^107/37
(2^4)/5 actually the remainder is 1 ,but when i follow your method it is 2 ..i cant understand why it is like this
@vinod sharmai also want this type of problem's solution
@@yagadasukrishna6448 1 hi hoga try again
@vinod sharma 1
43^86=(40+3)^86 . 40^86 is divisible by 5 , so 3^86 =9^43 . 9^43/5 ,rem is -1 . so 5-1=4 .
Sir your teaching style is excellent...... I got my answer..... Thank you sir
2^20/10 can be solved as (2^4*5)/10= (16 ^5)/10 therefore remainder is 6
I have made 6 at unit place because as sir has make diff in every question of 1 because 1 gives same result wtever the power is in the same way 5 and 6 also give the same resukt whatever the power is ..
Hi sir in ur previous part 1 2^99 /33 was solved in diff way and now 2^20/10 In other pattern can u plz compare both methods and focus on different pattern
Thankyou sir. Pagal hogya hua tha mai iss concept ke chakro me. You cleared it very well. Thanks a lot
If 5^135 is divided by 7 then remainder is 2. Hint-multiply by 2 in both numerator and denominator then by simplify answer become 4. Now we want to divided by 7 not 14 so, in end we divided by 2 and finally answer become 2. (This doubt is for Arnab barman)
Very carefully and Nicely he has picked out all the easy questions in remainder theorm and sweetly explained it .. 👏👏
In ques2 at 2:46 👉( 2^20)/10
2^3 = 8 is near to 10
=> (2^(3*6) + 2^2 )/10
=> (8^6 + 4)/10
=> Rem = 2+4 = 6
(2 has become +ve because of the even power)
sir in that question 43^86/5 .Why shall we take square of 43 ? simply we can divide 43 by 5 remainder +3 =+3^2*43 whole divided by 5 =-1^43=-1 then 5-1 =4
What is the remainder when 13 ^ 5 + 14 raise to the power 5 + 15 ^ 5 + 16 to the power 5 is divided by 29
And soon plz
Cyclicity of 3 is 4...
86/4 remainder is 2...so 3^2=9
9/5..remainder is 4
Answer is 4
Bahut achi explanation sir...thank you very much...I can understand when I first time seen your videos sir ...thank u
At 11:36 there Is no need to find square of 43. Without any division also ans can be calculated. Correct me if I am wrong sir..
it was a very usefull video. Go with further example then u will get to understand easily
A question like 9^1000/17. Even if we do 9 square, cube, to the power 4,5 the difference with denominator doesn't show up as plus 1 or -1.
So basically how to solve questions like this in which the difference isnt coming as plus one or minus one.
9^16 will leave remainder 1 when divided by 17
Hello sir you have explained very clearly it is very easy to understand and remember the techiques.I Requested to give a few number of questions with direct answers but not eplanation it will be very helpful for us and we can practise more ,thank you sir.
Thank you for your videos. At 5:27 you multiplied 3x2 to get the final remainder of 6. Was that to return 2^1 removed earlier? Please verify.
Yes..
Sir, u made some Qs so complicated
2 ^ 20 => (2 ^ 5 ) ^4 / 10 => 2 ^ 4 /10 => 6 remainder
43 ^ 86 / 5 = 3 ^ 86/5 => (3 ^2 ) ^ 43 /5 => -1 ^ 43 => -1 + 5 => 4
Sir plz solve this question-: What will be reminder when 27^400 is dividing by 25.
Sir in question 6, it is 5x9= 45 so why not remainder= -2?
In question 39 power 42 divided by 10 , -1 comes as remainder.. will it not become 1 due to even power ??
Nice Video, very helpful for beginners
Hi sir
Please solve this question and I already try but can't solve this and also provide the solution
Please !
What is the remainder when the no 4444^4444 is divisible by 9 ?
1. 4
2. 6
3. 7
4.8
2^4 divided by 3 gives remainder of 1 as 2^4 =16 and 16 divided 3 gives remainder 1 but according to your trick remainder should be 2 as 2^4/ 3 gives remainder of -1 , it cant be answer so subtract it from 3 get 2
Confused
Sir ,141×2 =282 hota hai jab ki hamko 242 bana na hai ...Ques 3 . Reply sir answer thik hai mgr power 121 hoga...odd number hai power 121,141 iss liye chal gaya
nice explanation + easy trics
Sir if 5^540÷ 7=?,so what will be the remainder
Can you compare the solution of 3^60 divide by 28 in 1st lecture and solution of 51^25 divided by 13 in 2nd lecture ?
Which one is correct ?
Nice understanding very good
nice explanation sir i want full aptitude problems sir
what is the remainder when 3^1000(3 raised to power 1000) divided by 23
sir apne ek q bataya tha jaise 2 power 100 diveded by 3 on solving the above get remainder -1 while substracting 3 get final reult 2 which is wrong plz give another method
U solve 43^86÷5=4 and 39^42÷10=9 in this -1 should be convert into 1 because -1^42=1 According to u,43^86÷5 should be 2..There is a lots of confusion so plzz make it clear...U solve every ques in diff. Way even ques r of same type
What is the remainder when 444 ^444 ^ 444 is divided by 7 ? (GMAT Type Question)
4 ( 3×3×3/7 )
@@ShikshitRajasthani 6
In question 2- wen you divide 5 by 2 the remainder is 3 and not 2.
what is the remainder when 1!+2!+........ 100! is divisible by 15 ?
Fantastic sir thank u very much
(2^100)/101 and (23^45+13^45)/18 find the remainder of both .sir please give me the solution of both .
Sir, can't we consider difference of 2 as near to the denominator ??
sir ager hum 2^20/10 iss ko hum asisa kyu nhi kr sakta hai like 8^6*4/10=-2, 10-8=2 answer is 2 kyu nhi ho sakta hai plz tell me
Q1) 7^45 divided by 47
Q2) 8^900 divided by 29
plzz sir give me the solution
nice simplification but sir question6. me 43ka square 1849 solve karna kya jaruri hai...if simple 3*3=9
43 p 86/5 , here 5*9=45 so -2 then 5-2=3 remainder 3 ? please explain this.
You are doing really awesome.
It's just need some time for people to come across you and follow you in millions.
Sir thanks for yr guidelines but we are still confused at some points when to use which trick
U r right
Yes sir I am getting confused in some problems
Yes sir same with me to
Hi Sir, very nice concept, please let me know which equipment are u using for this video. Thank you sir.
(3¹⁹⁶+4¹⁹⁷+5¹⁹⁸)÷197 than what is the remainder sir ?
Bro this is too good. But could you please do your videos in english so all of us can understand
i have seen most of your videos and they are amazing but can make one more on remainders showing how to get remainder if we write a series of numbers and divide it by some numbers (eg. if we write 1to 29 side by side i.e. 12345....26 and divide it by 9, what will be the remainder?). waiting for your reply and next videos!
1
What is the remainder when 15 to the power 400 is divided by 800?
When 3^247 is divided by 17 then what will be the remainder? Sir how to use the trick in this question?
thx sir.very useful ..but plz explain us if some que came like what's the rem.when 2 raise to the power 9 divided by 5..
(2^4)/5 actually the remainder is 1 ,but when i follow your method it is 2 ..i cant understand why it is like this
Q2 could have a better solution if you write 2^20 as 16^5 here we get 6 reaminder after divide by 10
very good explanation
Before video. You do (power of39 is 42)÷10 = remainder 10-1=9. But here power is even . The answer should be 1. Plz see every thing
Sir please solve some more subractions equations which is not divisible by denominator..
sir in qsn 2 2^20/10 is same as 2^19/5....so remainder should be same.....so why you multiplied by 2.....( remainder should not change as both mean the same....correct me if i am wrong
Bahot acha video tha sir
Very helpful video
Awesome tricks sir
very nice....
Nicely explained
2 power 20and divided by 10 hai to iska answer +2 aa raha hai
Kyoki 2²°= 2 ki power 5×4 lika sakte hai agar hum ese karte hai to 32⁴/10
Jaise sir ne bataya hai ushke accroding karte hai to 10×3=30 so remainder hoga +2
Agar jo jo meri baat se agary hai vo like kare and commnet kare
2²⁰= 1048576
Divided by 10, you will get 6 remainder
If power is considered then why the remainder of 39^42/10 is 9 in place of 1 in previous video ?
Sir, the types of questions u mentioned in this video is sufficient for IBPS PO pre / clerk or not.. Sir plzz suggest.. I show all these sessions of reminder theorem.
great sir
what is remainder of 32^32^32 when it is divide by 7.
1
How can I solve the problem that is to find the remainder when 16^53 is divided by 7
superb sir excellent 🙏.......
At 5.01 minutes should not the remainder be 3?? Instead of 2????
What is the remainder when 3^243 is divided by 5?__sir your trick is not applicable for it,,sir,, answer please
Find remainder when 51 ^203 is devided by 7? ..plz show me how to solve it ..
sir pz tell what is the shotcurt to solve the below qustion
what is the reminder when 11^13-13^11 is devided by 143
pz solve it and this type of qustions
in the question ((7^9)-4)/7 , using an example of 14 is the only way to solve this que ? coz there r soo many other multiples of 7 from which the answer is not coming. (only with some specific numbers)
Sir how to solve 73+75+78+57+197 is divided by 34 ..
sir, ur teaching is excellent, it is easy to understand and now i am feeling comfortable in solving the questions after watching ur videos. Thank u sir...
Batakrushna Kanhar thanks
What is the remainder when 5^91 is divided by 91?
Sir 39^42÷10=????
51^25÷13=????
Reminder btana sir
You made me understand very clearly thanks a lot sir,,, some more difficult question plz.....
What will be the remainder when
18^19^20 is divided by 100 ?
Use Cyclicity formula as well, will make these things much easier where diff. is huge.
it's superb trick but sir b'coz i am a slow catcher I am unable to catch it, can u please elaborate it more ans bit slow as well?
in the previous video part 1, u mentioned that (39^42)/10 which gives -1 but it is 10-1=9 but according to second video which is a even power it should be 1 because of 42...why is it wrong then?
1 hai bhai remainder 9 nai h
Find the reminder when 7^23 is divided by 8 solve the problem please
Remainder of 122^122 divide by 31
Sir can you please solve this question : 39^150 / 7
sir 32 per power 32 fir power per power 32 ko 7 se divide karne per reaminder kya hoga ? please solve it is .
Weldone sir, nice explanation....I like it.
Thanks a lot man@
It help a lot 🙏 thank you
How slove that types question ...what remainder when 3^32is divide by79
Sir plz Sol (3 ki power 7 ki power 11 )divide by 5 . What is remainder ?
question 7:sir 3/5 remaider 3 bhola aap pehle in this one you are simplyfying
Thank you so much bro❤️❤️
What is the concept of this type question. Why "the powers of nominator doesn't matter"?
Hello sir! Will you be doing any videos on NABARD Grade A and B for 2017 preparation techniques ?
Thank u very much sir.
In previous video me aap ne 39 ki power 42 h es ko 10 se divided kar rhe h es me remainder -1 aaya then -1 ki power 42 hogi to wo +ve ho jaye ga i.e 1 so remainder 1 aana chaye but aap ne es question me remainder 9 nikala. how ?
Sir when we divide 5^200 ÷ 7 what will be the remainder please tell??
Thank you sir it was brilliant
Thank U so much sir ,😍😍😍