Remainder Theorem Shortcut Technique

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  • Опубліковано 7 лис 2024

КОМЕНТАРІ • 813

  • @Raulmndl
    @Raulmndl 7 років тому +42

    Thank you very much sir! the way you explained it's really easy to keep it mind without effort anytime. simply u make it very easy to us. do upload other parts of arithmetic! eagerly waiting

  • @invectus7171
    @invectus7171 6 років тому +6

    43^86=(40+3)^86 . 40^86 is divisible by 5 , so 3^86 =9^43 . 9^43/5 ,rem is -1 . so 5-1=4 .

  • @pargatsingh11
    @pargatsingh11 6 років тому

    2^20/10 can be solved as (2^4*5)/10= (16 ^5)/10 therefore remainder is 6
    I have made 6 at unit place because as sir has make diff in every question of 1 because 1 gives same result wtever the power is in the same way 5 and 6 also give the same resukt whatever the power is ..

  • @aditigupta1796
    @aditigupta1796 4 роки тому

    In ques2 at 2:46 👉( 2^20)/10
    2^3 = 8 is near to 10
    => (2^(3*6) + 2^2 )/10
    => (8^6 + 4)/10
    => Rem = 2+4 = 6
    (2 has become +ve because of the even power)

  • @ambsjoshi
    @ambsjoshi 7 років тому +4

    Hi sir in ur previous part 1 2^99 /33 was solved in diff way and now 2^20/10 In other pattern can u plz compare both methods and focus on different pattern

  • @ranitbhattacharyya3800
    @ranitbhattacharyya3800 7 років тому

    sir in that question 43^86/5 .Why shall we take square of 43 ? simply we can divide 43 by 5 remainder +3 =+3^2*43 whole divided by 5 =-1^43=-1 then 5-1 =4

  • @utkarshagrawal6051
    @utkarshagrawal6051 7 років тому +1

    If 5^135 is divided by 7 then remainder is 2. Hint-multiply by 2 in both numerator and denominator then by simplify answer become 4. Now we want to divided by 7 not 14 so, in end we divided by 2 and finally answer become 2. (This doubt is for Arnab barman)

  • @DollyDolphin
    @DollyDolphin 3 роки тому +1

    What is the remainder when 444 ^444 ^ 444 is divided by 7 ? (GMAT Type Question)

  • @ayushmaansatyam6911
    @ayushmaansatyam6911 5 років тому +2

    What is the remainder when 13 ^ 5 + 14 raise to the power 5 + 15 ^ 5 + 16 to the power 5 is divided by 29

  • @dipanshuchouhan922
    @dipanshuchouhan922 3 роки тому +1

    Sir if 5^540÷ 7=?,so what will be the remainder

  • @UPSC-fy6ct
    @UPSC-fy6ct Рік тому

    Cyclicity of 3 is 4...
    86/4 remainder is 2...so 3^2=9
    9/5..remainder is 4
    Answer is 4

  • @TY-xq7zn
    @TY-xq7zn 3 роки тому

    2^4 divided by 3 gives remainder of 1 as 2^4 =16 and 16 divided 3 gives remainder 1 but according to your trick remainder should be 2 as 2^4/ 3 gives remainder of -1 , it cant be answer so subtract it from 3 get 2
    Confused

  • @heytikadeshmukh892
    @heytikadeshmukh892 6 років тому

    At 11:36 there Is no need to find square of 43. Without any division also ans can be calculated. Correct me if I am wrong sir..

  • @deepikaagarwal8374
    @deepikaagarwal8374 8 місяців тому +1

    2 power 20and divided by 10 hai to iska answer +2 aa raha hai
    Kyoki 2²°= 2 ki power 5×4 lika sakte hai agar hum ese karte hai to 32⁴/10
    Jaise sir ne bataya hai ushke accroding karte hai to 10×3=30 so remainder hoga +2
    Agar jo jo meri baat se agary hai vo like kare and commnet kare

    • @CompassionateIAS
      @CompassionateIAS 6 місяців тому

      2²⁰= 1048576
      Divided by 10, you will get 6 remainder

  • @chaarugupta6327
    @chaarugupta6327 6 років тому +1

    Sir in question 6, it is 5x9= 45 so why not remainder= -2?

  • @raushanbharti7181
    @raushanbharti7181 6 років тому

    U solve 43^86÷5=4 and 39^42÷10=9 in this -1 should be convert into 1 because -1^42=1 According to u,43^86÷5 should be 2..There is a lots of confusion so plzz make it clear...U solve every ques in diff. Way even ques r of same type

  • @amandugar4229
    @amandugar4229 4 роки тому +1

    A question like 9^1000/17. Even if we do 9 square, cube, to the power 4,5 the difference with denominator doesn't show up as plus 1 or -1.
    So basically how to solve questions like this in which the difference isnt coming as plus one or minus one.

  • @jagannathgaidhani5333
    @jagannathgaidhani5333 3 роки тому

    Sir, u made some Qs so complicated
    2 ^ 20 => (2 ^ 5 ) ^4 / 10 => 2 ^ 4 /10 => 6 remainder
    43 ^ 86 / 5 = 3 ^ 86/5 => (3 ^2 ) ^ 43 /5 => -1 ^ 43 => -1 + 5 => 4

  • @arpanasingh3048
    @arpanasingh3048 4 роки тому

    Sir plz solve this question-: What will be reminder when 27^400 is dividing by 25.

  • @IODell
    @IODell 4 роки тому +4

    Thank you for your videos. At 5:27 you multiplied 3x2 to get the final remainder of 6. Was that to return 2^1 removed earlier? Please verify.

  • @vipulgour1608
    @vipulgour1608 4 роки тому

    Hi sir
    Please solve this question and I already try but can't solve this and also provide the solution
    Please !
    What is the remainder when the no 4444^4444 is divisible by 9 ?
    1. 4
    2. 6
    3. 7
    4.8

  • @amoghdattatri2731
    @amoghdattatri2731 6 років тому +4

    Very carefully and Nicely he has picked out all the easy questions in remainder theorm and sweetly explained it .. 👏👏

  • @animeshkumar6216
    @animeshkumar6216 2 роки тому

    Can you compare the solution of 3^60 divide by 28 in 1st lecture and solution of 51^25 divided by 13 in 2nd lecture ?
    Which one is correct ?

  • @knowledgeispower7687
    @knowledgeispower7687 3 роки тому

    Sir ,141×2 =282 hota hai jab ki hamko 242 bana na hai ...Ques 3 . Reply sir answer thik hai mgr power 121 hoga...odd number hai power 121,141 iss liye chal gaya

  • @ashvtamahajan8045
    @ashvtamahajan8045 7 років тому +1

    In question 39 power 42 divided by 10 , -1 comes as remainder.. will it not become 1 due to even power ??

  • @arshiyaaadil9783
    @arshiyaaadil9783 6 років тому +2

    Hello sir you have explained very clearly it is very easy to understand and remember the techiques.I Requested to give a few number of questions with direct answers but not eplanation it will be very helpful for us and we can practise more ,thank you sir.

  • @MOVIES-WORLD323
    @MOVIES-WORLD323 6 років тому

    what is the remainder when 1!+2!+........ 100! is divisible by 15 ?

  • @bharatipandey2728
    @bharatipandey2728 7 років тому +2

    Sir your teaching style is excellent...... I got my answer..... Thank you sir

  • @SUDHANSHUKUMAR-cw8lv
    @SUDHANSHUKUMAR-cw8lv 6 років тому

    (2^100)/101 and (23^45+13^45)/18 find the remainder of both .sir please give me the solution of both .

  • @AyushmaanNargotra
    @AyushmaanNargotra 2 роки тому

    Thankyou sir. Pagal hogya hua tha mai iss concept ke chakro me. You cleared it very well. Thanks a lot

  • @ashishvats7812
    @ashishvats7812 7 років тому

    Q1) 7^45 divided by 47
    Q2) 8^900 divided by 29
    plzz sir give me the solution

  • @smritimadheshia7530
    @smritimadheshia7530 5 років тому +1

    it was a very usefull video. Go with further example then u will get to understand easily

  • @AlamgirMollickBabla
    @AlamgirMollickBabla 5 років тому

    Before video. You do (power of39 is 42)÷10 = remainder 10-1=9. But here power is even . The answer should be 1. Plz see every thing

  • @omarkhan2642
    @omarkhan2642 6 років тому

    In question 2- wen you divide 5 by 2 the remainder is 3 and not 2.

  • @sumanrana4083
    @sumanrana4083 4 роки тому +1

    Calculate 3^287 % 23?

  • @ravitompaki1209
    @ravitompaki1209 3 роки тому

    Bahut achi explanation sir...thank you very much...I can understand when I first time seen your videos sir ...thank u

  • @vikassingh9266
    @vikassingh9266 7 років тому

    sir apne ek q bataya tha jaise 2 power 100 diveded by 3 on solving the above get remainder -1 while substracting 3 get final reult 2 which is wrong plz give another method

  • @lightbrowser7943
    @lightbrowser7943 6 років тому +1

    Hi Sir, very nice concept, please let me know which equipment are u using for this video. Thank you sir.

  • @gautambhutia9648
    @gautambhutia9648 6 років тому +1

    Nice Video, very helpful for beginners

  • @surajdev1186
    @surajdev1186 3 роки тому

    Q2 could have a better solution if you write 2^20 as 16^5 here we get 6 reaminder after divide by 10

  • @rahulhooda1001
    @rahulhooda1001 7 років тому +1

    what is the remainder when 3^1000(3 raised to power 1000) divided by 23

  • @sahithmylavarapu149
    @sahithmylavarapu149 5 років тому +1

    2^20/10 remainder is not 3 .
    the reaminder is 6
    check it again and
    please modify ur trick
    sorry to say this
    , Because of you so many people are going wrong with this trick .
    first try to explain the trick with all conditions and exceptions and then solve problems.

  • @robinpegu5329
    @robinpegu5329 5 років тому

    When 3^247 is divided by 17 then what will be the remainder? Sir how to use the trick in this question?

  • @ambreshgupta9141
    @ambreshgupta9141 7 років тому +1

    sir ager hum 2^20/10 iss ko hum asisa kyu nhi kr sakta hai like 8^6*4/10=-2, 10-8=2 answer is 2 kyu nhi ho sakta hai plz tell me

  • @hemanthnadhvinnakota281
    @hemanthnadhvinnakota281 3 роки тому

    43 p 86/5 , here 5*9=45 so -2 then 5-2=3 remainder 3 ? please explain this.

  • @mdshafikansari1599
    @mdshafikansari1599 5 років тому +1

    We can easily solve que 6 simply writing (45-2)^86 and further (-2)^86/5....so simple..

  • @bazega3328
    @bazega3328 7 років тому +1

    i have seen most of your videos and they are amazing but can make one more on remainders showing how to get remainder if we write a series of numbers and divide it by some numbers (eg. if we write 1to 29 side by side i.e. 12345....26 and divide it by 9, what will be the remainder?). waiting for your reply and next videos!

  • @yagadasukrishna6448
    @yagadasukrishna6448 3 роки тому

    (2^4)/5 actually the remainder is 1 ,but when i follow your method it is 2 ..i cant understand why it is like this

  • @shauryajayswal4191
    @shauryajayswal4191 3 роки тому +1

    Sir can you please solve this question : 39^150 / 7

  • @arupsingh345
    @arupsingh345 7 років тому +1

    Sir, the types of questions u mentioned in this video is sufficient for IBPS PO pre / clerk or not.. Sir plzz suggest.. I show all these sessions of reminder theorem.

  • @salim9956
    @salim9956 6 років тому

    Find the remainder 723^243+318^243 divided by 17

  • @nitingarg3665
    @nitingarg3665 4 роки тому +2

    6:45 iska ans toh 3 aana tha na 3^243/5=5-2=3

  • @toxicstatus8246
    @toxicstatus8246 7 років тому

    Find the reminder when 7^23 is divided by 8 solve the problem please

  • @littlebratgaming1082
    @littlebratgaming1082 3 роки тому +1

    (3¹⁹⁶+4¹⁹⁷+5¹⁹⁸)÷197 than what is the remainder sir ?

  • @manishdagar3617
    @manishdagar3617 7 років тому +3

    Sir thanks for yr guidelines but we are still confused at some points when to use which trick

  • @prabhatrathi8940
    @prabhatrathi8940 7 років тому +3

    You are doing really awesome.
    It's just need some time for people to come across you and follow you in millions.

  • @albertfranklin434
    @albertfranklin434 6 років тому

    When 25732 ^1234 is divided by 11,the reminder obtained is :

  • @apurvasrivastava3739
    @apurvasrivastava3739 6 років тому

    9÷5 reminder is 4 but 9^2÷5 is 1 why power are creating difference

  • @rohit2660
    @rohit2660 Рік тому

    why did you closed the comments in part 1 video

  • @mainakdas2696
    @mainakdas2696 5 років тому

    What is the remainder when 3^243 is divided by 5?__sir your trick is not applicable for it,,sir,, answer please

  • @prasanthireddy952
    @prasanthireddy952 5 років тому +1

    nice explanation sir i want full aptitude problems sir

  • @mhnsrj
    @mhnsrj 6 років тому

    nice simplification but sir question6. me 43ka square 1849 solve karna kya jaruri hai...if simple 3*3=9

  • @manindranarala9836
    @manindranarala9836 4 роки тому +1

    Sir ea tho same type Ka hai (5^70+7^70)/74

  • @Awadhpalsinghyadav_official
    @Awadhpalsinghyadav_official 7 років тому

    Sir how to solve 73+75+78+57+197 is divided by 34 ..

  • @lalitjain1828
    @lalitjain1828 4 роки тому

    If power is considered then why the remainder of 39^42/10 is 9 in place of 1 in previous video ?

  • @shubhamchoudhary4855
    @shubhamchoudhary4855 6 років тому

    3^243=9^121*3 not 141 correct it please.

  • @sidsharma2271
    @sidsharma2271 4 роки тому

    Remainder of 122^122 divide by 31

  • @anishimishra7456
    @anishimishra7456 4 роки тому

    find the remainder when 73+75+78 is divided by 34

  • @baranmalyabhattacharjee202
    @baranmalyabhattacharjee202 7 років тому +1

    What is the remainder when 15 to the power 400 is divided by 800?

  • @sanchitbhargava7738
    @sanchitbhargava7738 4 роки тому

    Use Cyclicity formula as well, will make these things much easier where diff. is huge.

  • @randhirkadam3757
    @randhirkadam3757 6 років тому

    Find remainder when 51 ^203 is devided by 7? ..plz show me how to solve it ..

  • @rahulkushwaha7604
    @rahulkushwaha7604 6 років тому

    What will be the remainder when
    18^19^20 is divided by 100 ?

  • @ambikasingh7
    @ambikasingh7 4 роки тому

    What is the concept of this type question. Why "the powers of nominator doesn't matter"?

  • @manishgusain8274
    @manishgusain8274 7 років тому

    sir in qsn 2 2^20/10 is same as 2^19/5....so remainder should be same.....so why you multiplied by 2.....( remainder should not change as both mean the same....correct me if i am wrong

  • @amitkumar-cs4ms
    @amitkumar-cs4ms 6 років тому

    Sir
    1- 27^27/100
    2- 3^40 / 11
    how to solve this

  • @aditigupta1796
    @aditigupta1796 4 роки тому +1

    Sir, can't we consider difference of 2 as near to the denominator ??

  • @barunsarraf8863
    @barunsarraf8863 6 років тому

    in the previous video part 1, u mentioned that (39^42)/10 which gives -1 but it is 10-1=9 but according to second video which is a even power it should be 1 because of 42...why is it wrong then?

  • @mohammadsalahuddin4548
    @mohammadsalahuddin4548 5 років тому

    67^67 +68 divided by 68, the reminder is???

  • @pappuchaudharyofficial
    @pappuchaudharyofficial 4 роки тому

    Find the remainder when (53)49 is divided by 36.plz sir solve this

  • @bunnyashok8343
    @bunnyashok8343 7 років тому

    question 7:sir 3/5 remaider 3 bhola aap pehle in this one you are simplyfying

  • @souravsharma7285
    @souravsharma7285 Рік тому

    Guys ..sir ki pehli video mei ek question hai 39^42/10 , uska answer 1 aayega , sir ne by mistake 4 likh diya hai , because power jo hai wo even hai ....wha comments turned off hain isley yha pe likha...

  • @paraschauhan3400
    @paraschauhan3400 6 років тому

    find remainder when 29 to the power 21 is divided by 17

  • @heeragoyal2156
    @heeragoyal2156 7 років тому

    Sir 39^42÷10=????
    51^25÷13=????
    Reminder btana sir

  • @bhavneetgrover1363
    @bhavneetgrover1363 5 років тому +1

    What is the remainder when 5^91 is divided by 91?

  • @mithleshkumar2664
    @mithleshkumar2664 6 років тому

    32 per pawer 32 per pawer 32 divided by 9 solve it

  • @princeejain6929
    @princeejain6929 4 роки тому

    Sir please solve some more subractions equations which is not divisible by denominator..

  • @mehuljindal1444
    @mehuljindal1444 6 років тому

    At 5.01 minutes should not the remainder be 3?? Instead of 2????

  • @onkarsubba2137
    @onkarsubba2137 6 років тому +1

    You made me understand very clearly thanks a lot sir,,, some more difficult question plz.....

  • @mangalbarman822
    @mangalbarman822 5 років тому

    find the remainder when 11to the power 35 is divided by 55

  • @govindagupta7821
    @govindagupta7821 5 років тому

    nice explanation + easy trics

  • @KamalSingh-xj7xf
    @KamalSingh-xj7xf 7 років тому

    Remainder when 1^5 +2^5 +3^5+...........100^5when divided by 4 is ? Plz tell me someone fast

    • @sushantdash7479
      @sushantdash7479 6 років тому

      ua-cam.com/video/25wVMWu16aI/v-deo.html
      please visit our channel

  • @ashishbharti6165
    @ashishbharti6165 7 років тому

    thx sir.very useful ..but plz explain us if some que came like what's the rem.when 2 raise to the power 9 divided by 5..

  • @rahulraman968
    @rahulraman968 6 років тому

    The remainder when 10^10+10^100+10^1000+......+10^10000000000 is divided by 7 is ?

  • @premanshdewangan
    @premanshdewangan 6 років тому

    in the question ((7^9)-4)/7 , using an example of 14 is the only way to solve this que ? coz there r soo many other multiples of 7 from which the answer is not coming. (only with some specific numbers)

  • @educationaldestinationedwi1459
    @educationaldestinationedwi1459 6 років тому

    Remainder when 2 ^4901 divided by 11

  • @prasadj2696
    @prasadj2696 6 років тому

    17to power(16) divide by 7

  • @sonalsingh4330
    @sonalsingh4330 5 років тому

    The least remainder when 17^30 is divided by 5 is

  • @varunkumar-ux6xh
    @varunkumar-ux6xh 5 років тому

    Fantastic sir thank u very much

  • @rajnikantkumar4618
    @rajnikantkumar4618 4 роки тому

    sir math (-34)+79(-89-58)

  • @balajimathsclassesbydst8081
    @balajimathsclassesbydst8081 4 роки тому

    Nicely explained