Special Relativity | Lecture 1

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  • Опубліковано 5 січ 2025

КОМЕНТАРІ • 1,3 тис.

  • @jesusthroughmary
    @jesusthroughmary 3 роки тому +398

    Imagine getting lectured on special relativity by Prof. Susskind for free, what a time to be alive

    • @hancockay
      @hancockay 2 роки тому +5

      For free? Only on yt

    • @saimbhat6243
      @saimbhat6243 2 роки тому +7

      Very original comment. I have not read this same comment a million times. Obviously not. Your brain sure comes up with new creative ideas every time. Bravo

    • @jesusthroughmary
      @jesusthroughmary 2 роки тому +37

      @@saimbhat6243 imagine being bitter over seeing many people be grateful for the same thing

    • @lillyclarity9699
      @lillyclarity9699 2 роки тому +2

      @@jesusthroughmary its hard to imagine "jesusthroughmary" actually appreciates the physical science involved. don't you people think the earth was made 6 thousand years ago or something? I'd always figured with folks like that in your community, y'all must not appreciate science very much?

    • @jesusthroughmary
      @jesusthroughmary 2 роки тому +11

      @@lillyclarity9699 and you claim to be educated, what a world

  • @marcusaureliusanonymous
    @marcusaureliusanonymous 3 роки тому +176

    I fell asleep listening to Veritasium and somehow ended up here when I woke up to this.
    If Veritasium is an exotic starter, then this is the main course and I'm loving it!
    Good Job you.... YT machine learning recomendation engine!!

    • @atkgrl
      @atkgrl 3 роки тому +1

      Me too. How wonderful

    • @coreyduenas3939
      @coreyduenas3939 3 роки тому +1

      Me too. That’s pretty awesome.

    • @BODenKai
      @BODenKai 2 роки тому +5

      always ends up in some kind of stanford lecture for me when i wake up lol. wish i could retain knowledge while i was sleeping.

    • @designertune9330
      @designertune9330 2 роки тому +1

      I fell asleep to professor Dave

    • @lisanelke9726
      @lisanelke9726 2 роки тому +1

      I fell asleep watching a philosophy channel and woke up to this lol 🤣

  • @daspas2111
    @daspas2111 3 роки тому +653

    I fell asleep with my phone on and this is what i found, not disappointed

  • @TravelTheGalaxy
    @TravelTheGalaxy 2 роки тому +47

    Thank you Stanford University, having access to these lectures means more than you know. I was an average student in grade school who couldn't pinpoint what direction to follow and now at 28 it's clearer and although the signs have always been there I'm seeing and listening with clearer senses and again I'm so very grateful you have these lectures available for people like me. Education in this world is important more now than ever and I hope you all know how much value you're adding to the world by sharing knowledge. Thank you again so very much. I hope one day to be an official student.

    • @veto_it
      @veto_it 2 роки тому +1

      What direction did you choose to follow?

    • @Jeremy-fd2pw
      @Jeremy-fd2pw 7 місяців тому

      Can u explain what he is saying

  • @gorog
    @gorog 7 років тому +71

    Thank you so much to whoever was behind the decision to film these and post them online for free. I'm going through it slowly but it's amazing to have the opportunity to watch these amazing lectures.

    • @alwaysdisputin9930
      @alwaysdisputin9930 5 років тому +2

      Yeah it is
      or sum
      i wake up every morning, & when my mind is freshest i make a few flashcards. A gentle stream cuts through stone
      I use supermemo to stop me from forgetting what i learnt
      This is because in the past, i worked through this really nice, gentle big book called Engineering Maths (by KA Stroud). But I forgot a lot of it = it was rather a case of "in 1 ear & out the other". But with Supermemo the knowledge is permanent

    • @dhanulal
      @dhanulal 3 роки тому

      @@alwaysdisputin9930 ip

    • @Jeremy-fd2pw
      @Jeremy-fd2pw 7 місяців тому

      Can u explain it

  • @Prabhakar-gf2oq
    @Prabhakar-gf2oq 9 місяців тому +1

    I cannot think of physics without prof Suskind. It is amazing to see a genius like him teach being humble to the core despite his genius! He is exemplary in every way! God bless him and wish he gets his Nobel Prize which he richly deserves very soon!

  • @RaulToyotaofGladstone
    @RaulToyotaofGladstone 3 роки тому +709

    I fell asleep watching different ways too cook an omelette and somehow woke up to this. I know I don’t belong here so I’ll see myself out hehe

    • @hanswerner8194
      @hanswerner8194 3 роки тому +34

      Hahahaha it's completely the same thing what happened to me rn

    • @AlanCanon2222
      @AlanCanon2222 3 роки тому +79

      How fast was the omelette going, with respect to your reference frame?

    • @frogz
      @frogz 3 роки тому +21

      get back here, google knows something you dont, it knows you need more quantom physics

    • @1musichombre
      @1musichombre 3 роки тому +2

      I was watching how to make 3d rockets, so i feel i am at least in the same universe, plus i recognise Prof. Suskind

    • @DMahalko
      @DMahalko 3 роки тому +8

      Veritasium - Simplest math problem no one can solve, UA-cam autoplayed this next ... um ok .. sure I suppose I'm ready for this now, after watching that... saved myself thousands on college ..

  • @massimoacerbis8138
    @massimoacerbis8138 4 роки тому +31

    Countless times i have been studying length contraction
    This is the first clear explanation about the meaning of measurement
    "No contradiction"

  • @ThomasNeal
    @ThomasNeal 3 роки тому +148

    I’ve waken up to this video so many times I’m starting to sort of understand special relativity

    • @NazriB
      @NazriB 3 роки тому

      Lies again? Special moment

    • @johnwow2646
      @johnwow2646 2 роки тому +3

      I woke up to this... I'm going to watch from the beginning to make sure I get it right.

    • @Jeremy-fd2pw
      @Jeremy-fd2pw 7 місяців тому

      What is he explaining

    • @yungifez
      @yungifez 3 місяці тому

      How time gets wacky when you move at high speeds ​@@Jeremy-fd2pw

  • @aabidabdelghani8692
    @aabidabdelghani8692 4 роки тому +6

    I respect professors who go read the original work of scientists and turn it into an amusing lecture. I just enjoyed every second of this video. Thank you very much Sir

  • @soulmas520
    @soulmas520 3 роки тому +27

    Wondering why these kind of lectures help me sleep so well when I came to the ugly realization that it's most likely because it brings me back to a simpler time of... sleeping in class.

  • @Trvgn
    @Trvgn 8 років тому +71

    Many thanks to Stanford and Prof. Susskind. I've watched a few series, and I really love the way he explains things, in a very logical and simple way. Helped me understand many things that apparently were not as clear as they should have been to me!

  • @dwilliams4142
    @dwilliams4142 6 років тому +13

    Super thanks for making this public. My classes and text barely touch on these concepts. Can't thank you enough.

  • @alahemy
    @alahemy 3 роки тому +35

    Professor Leonard Susskind is one of the fathers of string theory, I am happy to watch this lecture series.

    • @Imassin
      @Imassin 2 роки тому +1

      a sahaniss iy mazigh 😀

    • @Jeremy-fd2pw
      @Jeremy-fd2pw 7 місяців тому

      This is awesome

  • @superserkit
    @superserkit 10 років тому +21

    This first lecture really blew my mind the first time i saw. This isn't gold; it's platinum! Susskind continues to inspire my own teaching, and of course, my study of physics :)

  • @alcarp2896
    @alcarp2896 Рік тому +2

    Thank you Dr Susskind. Posting this comment right at the top here as a high school physics teacher. The first 4 lectures are the perfect introduction for my students into special relativity, taught the way it was meant to be taught--straight from Einstein's paper, explained in common language. I show these first 4 videos every year at the end of our units on classical mechanics as a follow-up. The kids love them, and love Dr Susskind. Thank you thank you! Follow up--thank you for our list of Susskind-isms--"time is time is time is time", "derove", and who could forget poor Seymore, out there on his world line all alone waiting for a light ray.

    • @huixiong6247
      @huixiong6247 Рік тому

      The word "derove" did stand out in my memory but I didn't think of anything wrong with it until I read your comment, haha

    • @Mina-gk8jm
      @Mina-gk8jm Рік тому

      What's the difference between this course "Special Relativity" and "Modern Physics: Special Relativity" also by Susskind?

  • @guyedwards22
    @guyedwards22 3 роки тому +27

    It's actually amazing that working through deriving the way space and time relate to each other under coordinate transformations is extraordinarily clear and makes total sense, as long as the only special assumption is that the speed of light must remained fixed. Also, I've always wondered why Einstein would make that assumption in the first place, but his mention of thinking about Maxwell's Equations also makes total sense. You shouldn't be able to make the electromagnetic field vanish by moving fast enough.

    • @imsimonhello
      @imsimonhello 3 роки тому

      Njjybbh hi ghnkyhhubsw. A

    • @frankdimeglio8216
      @frankdimeglio8216 3 роки тому +1

      TIME DILATION IS FULLY EXPLAINED, AS THE ULTIMATE MATHEMATICAL UNIFICATION OF PHYSICS/PHYSICAL EXPERIENCE IS CLEARLY PROVEN:
      A PHOTON may be placed at the center of what is THE SUN (as A POINT, of course), AS the reduction of SPACE is offset by (or BALANCED with) the speed of light; AS ELECTROMAGNETISM/ENERGY IS GRAVITY; AS E=MC2 IS F=MA. Gravity IS ELECTROMAGNETISM/energy. (The stars AND PLANETS are POINTS in the night sky.) Time DILATION ULTIMATELY proves ON BALANCE that electromagnetism/ENERGY IS GRAVITY, as C4 is a POINT that is ELECTROMAGNETIC/GRAVITATIONAL (ON BALANCE) as SPACE; AS E=mc2 IS F=ma; AS ELECTROMAGNETISM/ENERGY IS GRAVITY. Time DILATION proves that electromagnetism/ENERGY IS GRAVITY, AS E=mc2 is DIRECTLY and fundamentally derived from F=ma. E=mc2 IS F=ma. A planet AND a star thus constitute what is A POINT in the night sky. It ALL CLEARLY makes perfect sense. Gravity IS ELECTROMAGNETISM/ENERGY. ACCORDINGLY, I have ALSO fully explained the MATHEMATICAL UNIFICATION of Einstein's equations and Maxwell's equations (GIVEN THE ADDITION OF A FOURTH SPATIAL DIMENSION); AS E=mc2 IS F=ma. The Sun AND the Earth are F=ma AND E=mc2. Great. SO, ultimately and truly, TIME is NECESSARILY possible/potential AND actual IN BALANCE; AS E=MC2 IS F=ma; AS ELECTROMAGNETISM/ENERGY IS GRAVITY. AGAIN, time DILATION ULTIMATELY proves ON BALANCE that E=MC2 is F=ma; AS ELECTROMAGNETISM/energy is gravity. Great. Indeed, this NECESSARILY represents, INVOLVES, AND DESCRIBES what is possible/potential AND actual IN BALANCE. (E=mc2 IS F=ma.) Therefore, INSTANTANEITY is thus FUNDAMENTAL to what is the FULL and proper UNDERSTANDING of physics/physical experience; AS E=MC2 IS F=ma; AS ELECTROMAGNETISM/ENERGY IS GRAVITY. SO, GRAVITATIONAL force/ENERGY IS proportional to (or BALANCED with/as) inertia/INERTIAL RESISTANCE; AS E=MC2 IS F=ma; AS ELECTROMAGNETISM/ENERGY IS GRAVITY. Gravity/acceleration involves BALANCED inertia/INERTIAL RESISTANCE, AS E=MC2 IS F=ma; AS ELECTROMAGNETISM/energy is gravity. Accordingly, the rotation of WHAT IS THE MOON matches it's revolution. MOREOVER, a given PLANET (including WHAT IS THE EARTH) sweeps out equal areas in equal times consistent WITH/AS E=MC2, F=MA, AND what is perpetual motion; AS ELECTROMAGNETISM/ENERGY IS GRAVITY. "Mass"/ENERGY IS GRAVITY. ELECTROMAGNETISM/ENERGY IS GRAVITY. Gravity AND ELECTROMAGNETISM/energy are linked AND BALANCED opposites, AS E=MC2 IS F=MA; AS ELECTROMAGNETISM/ENERGY IS GRAVITY. GREAT !!! It ALL CLEARLY makes perfect sense. BALANCE and completeness go hand in hand. Very importantly, outer "space" involves full inertia; AND it is fully invisible AND black. E=mc2 IS F=ma. "Mass"/ENERGY involves BALANCED inertia/INERTIAL RESISTANCE consistent with/as what is BALANCED ELECTROMAGNETIC/gravitational force/ENERGY, AS E=mc2 IS F=ma; AS ELECTROMAGNETISM/ENERGY IS GRAVITY. (Energy has/involves GRAVITY, AND ENERGY has/involves inertia/INERTIAL RESISTANCE.) E=MC2 IS F=ma. Objects fall at the SAME RATE (neglecting air resistance, of course), AS ELECTROMAGNETISM/ENERGY IS GRAVITY. Gravity IS ELECTROMAGNETISM/energy. E=MC2 IS F=ma. It ALL CLEARLY makes perfect sense. Magnificent !!!
      By Frank DiMeglio

    • @frankdimeglio8216
      @frankdimeglio8216 3 роки тому

      This is what you need to know.
      THE FULL UNDERSTANDING OF TIME (AND TIME DILATION), AS E=MC2 IS CLEARLY F=MA ON BALANCE; AS ELECTROMAGNETISM/energy is gravity:
      INSTANTANEITY is fundamental to what is the FULL and proper UNDERSTANDING of physics/physical experience (in and with TIME), AS E=MC2 IS F=ma; AS ELECTROMAGNETISM/energy is gravity; AS the stars AND PLANETS are POINTS in the night sky. TIME dilation ULTIMATELY proves ON BALANCE that ELECTROMAGNETISM/energy is gravity, AS E=MC2 IS F=ma; AS ELECTROMAGNETISM/energy is gravity. (Gravity IS ELECTROMAGNETISM/energy.) THE EARTH/ground AND THE SUN are CLEARLY E=MC2 AND F=ma IN BALANCE, AS the stars AND PLANETS are POINTS in the night sky; AS ELECTROMAGNETISM/energy is gravity. TIME is NECESSARILY possible/potential AND actual IN BALANCE, AS E=MC2 IS F=ma; AS ELECTROMAGNETISM/energy is gravity !!!! TIME dilation ULTIMATELY proves ON BALANCE that E=MC2 IS F=ma, AS ELECTROMAGNETISM/energy is gravity. It all CLEARLY makes perfect sense. Balance and completeness go hand in hand. E=MC2 IS F=ma. This NECESSARILY represents, INVOLVES, AND DESCRIBES what is possible/potential AND actual IN BALANCE, AS ELECTROMAGNETISM/energy is gravity !!! Comparatively, consider the man who IS in outer "space". Great. AGAIN, the stars AND PLANETS are POINTS in the night sky !! AGAIN, TIME DILATION ULTIMATELY proves in what is a BALANCED FASHION that ELECTROMAGNETISM/energy is gravity; AS E=MC2 IS F=ma; AS gravity/acceleration involves BALANCED inertia/INERTIAL RESISTANCE. Gravity IS ELECTROMAGNETISM/energy ON BALANCE. E=MC2 IS F=ma ON BALANCE !!! NOW, carefully consider that the stars AND PLANETS are POINTS in the night sky !!! Great !!! "Mass"/ENERGY involves BALANCED inertia/INERTIAL RESISTANCE consistent with/as what is balanced electromagnetic/gravitational force/ENERGY, AS E=MC2 IS F=ma ON BALANCE; AS ELECTROMAGNETISM/energy is gravity. It all CLEARLY makes perfect sense, AS BALANCE AND completeness go hand in hand. E=MC2 IS F=ma ON BALANCE !!!
      By Frank DiMeglio

    • @frankdimeglio8216
      @frankdimeglio8216 3 роки тому

      UNDERSTANDING TIME AND THE CLEAR MATHEMATICAL PROOF THAT E=MC2 IS F=MA ON BALANCE, AS ELECTROMAGNETISM/energy is gravity:
      ELECTROMAGNETISM/energy is gravity. The stars AND PLANETS are POINTS in the night sky. Gravity AND ELECTROMAGNETISM/energy are linked AND BALANCED opposites, AS ELECTROMAGNETISM/energy is gravity; AS “mass”/ENERGY IS GRAVITY; AS E=MC2 IS F=ma. Therefore, the planets will move away very, very, very slightly in BALANCED relation to what is THE SUN. (Also, carefully consider what is THE EARTH.) Great !!! This explains the cosmological redshift AND the “black hole(s)”. GRAVITATIONAL force/ENERGY IS proportional to (or BALANCED with/as) inertia/INERTIAL RESISTANCE, AS E=MC2 IS F=ma ON BALANCE; AS ELECTROMAGNETISM/energy is gravity. Gravity/acceleration involves BALANCED inertia/INERTIAL RESISTANCE, AS E=MC2 IS F=ma ON BALANCE; AS ELECTROMAGNETISM/energy is gravity. Gravity IS ELECTROMAGNETISM/energy. “Mass"/ENERGY involves BALANCED inertia/INERTIAL RESISTANCE consistent with/as what is BALANCED electromagnetic/gravitational force/ENERGY, AS E=MC2 IS F=ma ON BALANCE; AS ELECTROMAGNETISM/energy is gravity. SO, the rotation of WHAT IS THE MOON matches it's revolution; AND objects fall at the SAME RATE (neglecting air resistance, of course) !!! Time dilation ULTIMATELY proves ON BALANCE that E=MC2 IS F=ma, AS ELECTROMAGNETISM/energy is gravity !!! It all CLEARLY makes perfect sense, AS BALANCE AND completeness go hand in hand. Balanced inertia/INERTIAL RESISTANCE is fundamental. Time is NECESSARILY possible/potential AND actual IN BALANCE, AS E=MC2 IS F=ma ON BALANCE; AS ELECTROMAGNETISM/energy is gravity !!! GREAT. Stellar clustering ALSO proves ON BALANCE that E=MC2 IS F=ma, AS ELECTROMAGNETISM/energy is gravity.
      By Frank DiMeglio

    • @alcarp2896
      @alcarp2896 2 роки тому

      @@frankdimeglio8216 Speed of light being constant in al frames I believe Einstein learned from the Michelson-Morley Experiment into the luminiferous ether.

  • @Prabhakar-gf2oq
    @Prabhakar-gf2oq 11 місяців тому

    I can only say that prof Suskind is one of his kind and I feel I am really privileged to hear him speak and teach physics. He is a real genius!

  • @saptarshighosh9205
    @saptarshighosh9205 8 років тому +14

    this video is amazing. Truly easy and fundamental. Thank you so much for the upload. Much appreciated. And professor Susskind, I must say that I am a big fan!

  • @oldadajbych8123
    @oldadajbych8123 Місяць тому +1

    Great lecture. What I really miss in all those lectures are examples. Examples with numbers. The course would take twice as much time, but the number of people who understood would increase much more. I know it; I do lectures on much less complicated technical subjects, and as soon as you come from theoretical equations to practical use, it can be seen how many students get enlightened. Covariant and contravariant vector, show the transformations - 2 dimensions would be enough.

  • @jersn5560
    @jersn5560 8 років тому +330

    Wow, this prof is really good. Never in my lifetime I can get to be lectured on Can'tafford university. XD

    • @FilterChain
      @FilterChain 7 років тому +19

      Jers N thats Leonard Suslikin (excuse the spelling ) the father of string theory, hes very famous

    • @nageshmodak9765
      @nageshmodak9765 6 років тому +8

      can anyone tell me what is x prime i didnt understand it

    • @Pozzaa90
      @Pozzaa90 6 років тому +3

      It's the spatial coordinate of the moving reference frame. 13:58

    • @brennanbelei9139
      @brennanbelei9139 6 років тому +3

      Enter the Braggn' False

    • @jacobvandijk6525
      @jacobvandijk6525 5 років тому +3

      If you think he is good, I wonder what kind of teachers you have had.

  • @travia525
    @travia525 7 років тому +2

    This is a God sent seriously. Been reading through three books today and a lecture discussing the same topics u talked about in the first 11 minutes. Yours made so much sense - I really appreciate all the chronological science history as you teach. So many leave the little things out.

  • @uzairakram899
    @uzairakram899 3 роки тому +15

    I have always had trouble thinking about relativity and this really helped me in starting to wrap my head around it

    • @woodpeckery
      @woodpeckery 3 роки тому +1

      And, so did you notice any corresponding change in your relations with special relatives? 🤔

    • @uzairakram899
      @uzairakram899 3 роки тому +1

      @@woodpeckery starting to understand them better as well

    • @ernestogarcia3193
      @ernestogarcia3193 3 роки тому

      @@woodpeckery LMAO

    • @Jeremy-fd2pw
      @Jeremy-fd2pw 7 місяців тому

      What is he talking about

  • @astrobear8790
    @astrobear8790 11 місяців тому

    I watched this, well more like tried to watch this right before I started my bachelors in Astrophysics a couple years ago. I was beyond lost. Now after a couple years under my belt, it makes so much sense now. I love the way he teaches this topic.

  • @onbored9627
    @onbored9627 6 років тому +148

    Wow. when he got to the lorenz transformations I was just blown away. I had seen this before but seeing how einstein actually worked this through... it gave me chills. a true legend. thank you prof susskind.

    • @zombiesalad2722
      @zombiesalad2722 5 років тому +7

      Yeah, I read somewhere that Einstein's method was like climbing the hill from a very steep path where there is a less steep one available (now).

    • @gaemer3967
      @gaemer3967 4 роки тому +5

      @@zombiesalad2722 I heard the same thing from minutephysics.

    • @new-knowledge8040
      @new-knowledge8040 4 роки тому +8

      The funny thing is, if you know absolutely nothing about physics, you can discover SR all by yourself. Sadly, most folk have been trained to think that this is not the case at all, even though a high school dropout can do it.

    • @KishanSingh-fv9qj
      @KishanSingh-fv9qj 3 роки тому +14

      @@new-knowledge8040 yes for sure only if he has the same level of boldness as sir Einstein to declare time is not absolute:)

    • @nojamkat
      @nojamkat 3 роки тому

      Zabzazim

  • @vwcanter
    @vwcanter Рік тому +2

    This knowledge is so valuable. It was so difficult to find a lecture that used this simple method of plotting these quantities on a Cartesian plane. That makes it so much easier to see how all these quantities relate. Sure, it is a longer video than you find on some of the pop science channels that are popular. But an investment of a hour is more than worth it. The attempts to gloss over this step on popular videos might make the video get more plays and likes. But it shorts the viewer on the necessary steps.

    • @petergreen5337
      @petergreen5337 Рік тому

      ❤Precisely . Those steps require real care.

  • @funky555
    @funky555 3 роки тому +6

    Im using these videos to fall asleep too to hopefully learn something and get smarter the same way i learnt every word to every song i use to sleep

  • @Ohhelmno
    @Ohhelmno 3 роки тому +1

    UA-cam knows me well. Fell asleep watching a Jon Stewart interview, woke up to this… luckily I am passingly familiar with physics and relativistic physics so, I quite enjoyed this and was unable to go back to sleep.

  • @jeppepuus
    @jeppepuus 2 роки тому +6

    This is great! I am in the equivalent of last year of high school and love watching university lectures of subjects I have in school. Having a proper explanation of these concepts makes understanding the analogies we’re fed in school a lot more digestible. Can’t wait for University next year!

  • @__username1
    @__username1 20 днів тому +1

    I'm a freshman undergraduate student. There would be no way I was going to pass the first semester exams if not for lectures on physics from mit and Stanford. In my university, they barely explain this stuff and expect you to already know/understand it anyway

  • @fathomtheuniverse1
    @fathomtheuniverse1 11 років тому +47

    I just want to thank you, Stanford University, for uploading these lectures. awesome info here!

    • @darkmemer6663
      @darkmemer6663 3 роки тому

      @@agiarusso keep your kinda cool babe babe I miss know knew it I y hmm Nakul good jkk

    • @iiNguyen
      @iiNguyen 3 роки тому

      @@darkmemer6663 mmm

  • @ericstromquist9458
    @ericstromquist9458 5 років тому +1

    These special relativity lectures, and the whole series of physics courses of which they are a part, are excellent. Susskind's explanations are very thorough. Thanks to them, I understand the material better than I did when I was a physics major 40 years ago. He does occasionally slip up with minus signs, but this gives you the opportunity to redo the derivation and figure out where the slip occurred, where doing this definitely helps you learn the material better.

    • @lawrence1318
      @lawrence1318 5 років тому

      Rather, the idea is based on an error in logic:
      _"The 2 photons will have been sent simultaneously only if they arrive simultaneously at the midpoint, therefore if they arrive simultaneously at the midpoint then they will have been sent simultaneously."_
      That is, "if p then q, therefore if q then p".
      This is a formal fallacy in propositional logic, called "affirming the consequent".
      The truth of the matter is that the photon at B is fired later than the photon at the origin, and this because it has to travel a shorter distance in order to arrive at A at the same time as the photon from the origin arrives at A. And so we see from the chart that B is at t>0.
      So there is only 1 time scale, t, for you can't have a moving system of clocks and have those clocks not tick. Clocks tick. That's what they do.
      So t' is only 0 along the x axis, which is where (and when) the first photon is fired, for the first photon is fired at the origin and at the origin t' is on the x axis. After that, t' is greater than 0, because its clocks are ticking. And so t' is synonymous with t, and therefore superfluous: we only need t.
      The problem is that the issue is not really a physics issue, but a logic issue. Physicists are not necessarily good at logic. Logic is a different skill.
      If you wish to see how SRT is errant at its very first derivational step, just search "Nullification of Relativity Theory via the Sufficiency of the Galilean Velocity Transformation", click on the viXra link, and then click on v2 of the PDF.

    • @thebeast5215
      @thebeast5215 3 роки тому

      @@lawrence1318 yea, dude, I'm sure you're right and physicists are wrong.

  • @alwaysdisputin9930
    @alwaysdisputin9930 5 років тому +22

    Fred = Leonard
    28:45 _"My friends who are separated by equal distance: there's me, the 1 in front of me & the 1 in front of him"_
    30:52 _"Let's give these people names: Fred, Anne..._
    _& See More"_

  • @openenquiry
    @openenquiry 3 роки тому +5

    Below is an attempt at calculating how many people go on to complete all the lectures.
    As of July 15, 2021, here are the stats for the views and likes for the 10 videos in this series:
    Lecture 1: 897024; 6.7k
    Lecture 2: 212144; 1.2k
    Lecture 3: 225383; 1.2k
    Lecture 4: 139619; 779
    Lecture 5: 99385; 543
    Lecture 6: 80824; 512
    Lecture 7: 65712; 478
    Lecture 8: 67962; 480
    Lecture 9: 74709; 464
    Lecture 10: 71365; 508
    Around 900k people watched the first video, and 6.7k liked it. 71k watched the last video, and 508 liked it. As a rough first approximation, at most around 8% of the viewers who watched the first video might have gone on to complete all the lectures.

  • @Akash_Tyagi_93
    @Akash_Tyagi_93 8 років тому +75

    YOU ARE LEGENDS. THANK YOU FOR THE VIDEO LECTURES. Forever in your debt.
    Grateful.

    • @physicsevolutionandscope9588
      @physicsevolutionandscope9588 6 років тому +2

      Sahi bole bhaai...Gajab hai ye to

    • @jeeaspirant2016
      @jeeaspirant2016 4 роки тому

      @@physicsevolutionandscope9588 hi indian

    • @quetime8264
      @quetime8264 3 роки тому

      @@jeeaspirant2016 vwcevqvqvqvvvgeb lkkkjjjjjjjjjjjpoppjjppojppjojopjkjjjjkkmkkkmkkkkkmllllmllmmmlmkllllllllllllmlmlmlmmlkllklkkllllllklkmllmmmlmlmkkkkkkkllpmlppmpllllllllllllklklmpllllllpmllkklllllllkllklkklllkllllllpkllkllkllklllpllklllmkkmlkllllllkllppkkllklkllllkkklllllllkkkkllllllkmppplllkkpllklmlkllllllkkmlkklllklkkllklkmkkkllllllklkllmklfffffg

  • @marxman1010
    @marxman1010 2 роки тому +1

    At 1:27:25, it shows t is dilated when t'=1 from the view point of moving frame, but t' is contracted from the view point of the rest frame. For example t=1, x=1 are both contraceted in the moving frame to sqrt(1-v^2). Time and space are both contracted in the moving frame. Contraction of time is slowing down of the clock, i.e. dilation of time.

  • @meowwwww6350
    @meowwwww6350 2 роки тому +5

    Give this man a nobel prize for teaching

  • @alicemeraviglia8863
    @alicemeraviglia8863 5 років тому +52

    I beg you please to allow for at least auto-generated subtitles to be turned on, so I can share this with Spanish speaking friends.

    • @cedricvillani8502
      @cedricvillani8502 3 роки тому +4

      NOPE, sorry but your friends are not allowed to synchronize their watches with any X’s, V’s, or T’s. It's just not possible, I'm sorry.

    • @cedricvillani8502
      @cedricvillani8502 3 роки тому

      @@TheOGC4 si

  • @棣棠-u6p
    @棣棠-u6p 5 років тому +99

    Every time when I have class about special relativity, I consider myself taking philosophy.

    • @aloknathsingh4647
      @aloknathsingh4647 4 роки тому +14

      Lol, that was funny. But on a serious note, the barrier is indeed high but once you cross it, it makes perfect sense.

    • @User-ei2kw
      @User-ei2kw 4 роки тому +5

      @@aloknathsingh4647 thx bhai how long is is taking you? maths in sr very simple for me but concepts in problems is very hard

    • @fleisbester612
      @fleisbester612 4 роки тому

      Alok Nath Singh The problem is that’s wrong. The first postulate is impossible.

    • @HughesMath1
      @HughesMath1 4 роки тому

      Approaching philosophical questions happens all the time with Sean Carrol biggest questions in the universe, Cosmology beginning of universe and black holes. Sean Carroll is another great explainer.

    • @michaelspooner9160
      @michaelspooner9160 4 роки тому

      @@HughesMath1 🔹°= -🔹🚽❓♓/t-2.Special relativity x y and z.Transfers and rotations.Spacial set of coordinates.Thank you thinking out loud use of objective units.Yipes,my coordinates are different from your coordinates.I end up apologizing to someone.Is it year of the Ox yet?

  • @owen7185
    @owen7185 3 роки тому +1

    There are professor's who are born to lecture, and he's one of them. Amazing. The way interacts, asks questions during the problem solving he's awesome

  • @stacyblauvelt6016
    @stacyblauvelt6016 3 роки тому +3

    I shall watch this particular lecture regarding Lorentz Transformations. This Is amazing lecture by an amazing teacher. Dr. Susskind.

  • @ishfaqzahoor8267
    @ishfaqzahoor8267 4 роки тому +4

    I have seen this type of work from renowed teachers but the way Einstein himself have done and explained by this sir was absolutely great....thanks for making it understandable

    • @Notyourhandle777
      @Notyourhandle777 2 роки тому

      If I could meet Einstein, I’d bring him the best strongest coffe I could get, and just sit back and see what happens, science!!

  • @TheShenergy
    @TheShenergy 12 років тому +21

    This is one of my favorite topics! Thank you so much!

    • @Jeremy-fd2pw
      @Jeremy-fd2pw 7 місяців тому

      Tell me what he's explaining

  • @marxman1010
    @marxman1010 2 роки тому +1

    At 1:02:25, the equations of lorents transformation has a domain of all real numbers except for v=1. The equations derivation, however, depends on x=t when v = 1. Refer to the video at 50:34. Isn't it a big contradiction? Trying to explain the equations when v = 1 seems to be completely meaningless.

    • @guitarlover7665
      @guitarlover7665 3 місяці тому

      v= 1 condition is meaningless as nothing can travel with the velocity of light for now. it should be less than that

  • @rifatzehra6546
    @rifatzehra6546 3 роки тому +5

    All flowed over my head but I am glad that I watched this anyway

  • @zack_120
    @zack_120 Рік тому +1

    1:04:35 - since t=vx (44:36), t'=(t-vx)/√(v/c)=0, contrasting with the answer later of t'=t ! How to explain it?
    The math in this lecture is beautiful, e.g slope of line 0‾b = v (44:25) 👍
    33:20- this is the foundation of the following contents, wish have spent more time on it.

    • @agrajyadav2951
      @agrajyadav2951 Рік тому

      t=(v/c^2)x is a the line depicting simultaneoty in different frames of reference

    • @agrajyadav2951
      @agrajyadav2951 Рік тому

      The slope was v/c^2 as he said later

  • @SpaceMilk07
    @SpaceMilk07 10 років тому +15

    I think I will subscribe to this channel, thank you for putting out free education.

  •  2 роки тому +1

    I wonder has my brain learned something of these lectures all the time I have listened to these while sleeping 😂

  • @echolee601
    @echolee601 6 років тому +49

    Just reading his new book “Special Relativity and Classic Field Theory”

    • @robbyandrews6318
      @robbyandrews6318 5 років тому +1

      NO KIDDING! YOU KNOW, I WAS THINKING THE SAME THING! IF I WERE TAKING A CLASS I WOULD HOPE TO GET SOMETHING OUT OF IT.( REGURUTATINE. IS IT WHAT I AM PAYING 4. SOME1 HAS TO TEACH A CLASS BASED ON EVERYONE ELES'S HISTORY BOOK BULLSHIT! HOW MANY TIMES DO I HAVE TO SIT IN A CLASS WONDERING? WHEN ARE YOU GOING TO TEACH ME SOMETHING? YES, YES. I HAVE HERD ALL OF THAT BULLSHIT BEFORe. FUCK! I COULD WATCH THAT ON THE DISCOVERY. HISTORY CHANNEL. LOLOLOLOLOLOL JUST( AMGEN ) ALL OF THE MONEY THAT I COULD SAVE!!! WOW!!! THAT IS FUCKING AMAYZZZZZING. P.S. LOOK AT( AMERICA IS NOT THE GREATESt CONTRARY) WE NEED TO WAKE UP PEOPLE. BECAUSE I DON'T LIKE BEING 2ND BEST!!!!!!!!!!!!!!!!!!!!!!!!

    • @unrelentingawesomeness7501
      @unrelentingawesomeness7501 4 роки тому +4

      @@robbyandrews6318 you're an intellectual

    • @samuelmcdonagh1590
      @samuelmcdonagh1590 4 роки тому +2

      unrelenting awesomeness haha

    • @robbyandrews6318
      @robbyandrews6318 4 роки тому

      Godammm. How right that You are. Lol.

    • @robbyandrews6318
      @robbyandrews6318 4 роки тому

      CLASSIC FIELD. YOU DO MEAN OR IS THAT WITH AN I? CLASSIC POS. TELL YOU WHAT HUNNY. IF YOU ARE THAT GOOD. LEAVE ME A MESSAGE. WHEN YOUR N- PHYSICS IS BETTER THAN MINE. PLEASE CALL ME!! I CAN'T FUCKING WEIGHT. M-0 G-0. Know if EYENSTIN. DID I SPELL THAT WRONG. TELL ME THEN. WHAT WAS HIS UP TAKE ON HYGIENE. YESTERDAY'S BULLSHIT.

  • @Five_y_kay
    @Five_y_kay Рік тому +1

    Thanks Stanford, and Dr Susskind for these great lectures! Never had the chance to take relativity.

  • @umutkerememer4063
    @umutkerememer4063 3 роки тому +6

    Very good! Thank you Stanford.

  • @jenniferlaflora3293
    @jenniferlaflora3293 4 місяці тому +1

    Sorry about my battery it’s ran on faux loc for ahead bandwidth 22:21

  • @MuggsMcGinnis
    @MuggsMcGinnis 7 років тому +9

    I wish I could hear the audience questions. For that matter, closed captions would help, too.

  • @yousseftemmam2317
    @yousseftemmam2317 4 роки тому +2

    It's a very interesting lecture. However I can't understand is why at 47:17 did he put x' = (x - v*t)*f(|v|). Actually there is no obligation to put such equation. From a general perspective we can simply put x' = h(x,t,v) and h = 0 when x = v*t. If someone understood why he made such an assumption, I'll be glad to hear the explanation :) Thanks !

  • @modernwarrior-bf4ut
    @modernwarrior-bf4ut 4 місяці тому +4

    why everyone is falling sleep and waking up here ?

  • @disfigured75
    @disfigured75 9 років тому +1

    36:18 I really don't understand where the "x + t = constant" bit comes from. Everything else in this lecture makes sense, but I don't get where he came up with that property. Could someone help me understand? Thank you.

    • @caution2toxic287
      @caution2toxic287 9 років тому

      That's the equation of light going the "other" way (we have only one direction, the x axis, so we can talk about light going forward and backward in a certain reference frame).
      The equation for a light beam going forward is x = d+t (so the slope is 1, the speed of light; d is a constant representing when the light beam is at position x=0). In the case of the lecture, d is 0, so the equation is x = t.
      The equation for a light beam going backwards is x = d-t (d has the same meaning as above, but slope in this case is -1) => x+t = d (a constant)
      Hope you understand now! :)

    • @LillianWinterAnimations
      @LillianWinterAnimations 8 років тому

      +Veridian x + t is a constant because.. well I'll give a quick proof actually.
      so, a line with that angle has a slope of 1, or -1.
      In other words, f'(x) = +- 1
      so, if we take the antiderivative, we have..
      f(x) = +- X + A
      where A is a constant.
      so, where the slope is positive, f(x) = x + 1, we can express it as x - t = constant
      or rather, x - f(x) is a constant.
      how is this?
      X - (X + A), or..
      X + F(X) = -A
      -A
      That's not a variable.. that's a constant. Replace F(X) with t because t is on the y axis there, and you have your answer.
      meanwhile, X + (-X + A) (negative slope)
      (X - X) + A
      A
      Also a constant.

  • @NickPDX22
    @NickPDX22 3 роки тому +4

    I love this man... going to be a very sad day when he departs us!

    • @user-qt2we6mb6k
      @user-qt2we6mb6k 3 роки тому +1

      @DeeJay1210 Pretty sure he means when he retires mate.

    • @Jeremy-fd2pw
      @Jeremy-fd2pw 7 місяців тому

      What he talking about

  • @thebeast5215
    @thebeast5215 3 роки тому

    This man is so well spoken and looks great... don't know why I felt the need to say that.

  • @massimoacerbis8138
    @massimoacerbis8138 4 роки тому +3

    Esteemed professor
    Yes Galileo did write about
    Wonderful pages about a moving ship
    Train did not exist yet at his age
    Thanks

  • @marksilliman4556
    @marksilliman4556 3 роки тому

    1:06:26 If anyone else is confused about why V on top is divided by C^2 as opposed to C: V and X are both proportional to the value of C. V/C*X/C == V/C^2*X.

  • @OswaldChisala
    @OswaldChisala 8 років тому +3

    More humor at 1:23:00. That Rolex watch from New York stole the show. This was an excellent lecture, professor. :)

    • @aaronjs99
      @aaronjs99 7 років тому +1

      Try 1:44:00 too. 'Derove'... ;)

  • @FractalWoman
    @FractalWoman Рік тому

    Around the 30.30 minute mark, you indicated that a stationary mover would move along the x-axis but in reality, the stationary observer would stay at x=0 but move up the time axis. The time changes for the stationary observer but not the spatial extent. Or am I missing something.

  • @swamijee
    @swamijee 6 років тому +32

    'We DEROVE the invariant!'- luvvv the guy!

  • @vesuvandoppelganger
    @vesuvandoppelganger Рік тому +1

    "In May and November, the Earth is moving at "right angles" to the line to Algol. During this time we see minima happening regularly at their 2.867321 day intervals. However, during August, the Earth is rapidly moving towards Algol at about 107,229 km/hr as explained on my How Fast Are We Moving? page. (The Earth moves approximately 202 times its own size in one day.) So in 2.867321 days the Earth moves about 7,379,039 km closer to Algol. _But the varying light from Algol doesn't know this - its light waves left Algol 93 years ago and are travelling at a constant speed._ The result - we "catch a bunch of minima early" during August as shown on Chart 2. Exactly the opposite happens during February - the Earth is moving away from Algol that fast and it takes longer for the group of minima to reach us so we see them taking longer between events. How long? 7,379,039 km divided by the speed of light 299,792.458 km/sec is 24.61382 seconds. So in May and November when we are not moving towards or away from Algol - the period seems constant. It is our rapid movement towards or away from the events in August and February that causes the timing differences."
    I assume that light is passing the earth at c when the earth isn't moving towards or away from Algol.
    In February the earth is moving away from Algol and the time between the eclipses is 2.8675875347 days and the light is passing the earth at 186,265 mi/sec.
    In May and November the earth is not moving towards or away from Algol and the time between eclipses is 2.867321 days and the light is passing the earth at 186,282 mi/sec.
    In August the earth is moving towards Algol and the time between eclipses is 2.8670608912 days and the light is passing the earth at 186,299 mi/sec.

  • @young-jinahn6971
    @young-jinahn6971 9 років тому +5

    Amazing. I hope I can take it until lecture 10.

  • @antongeorgiev1704
    @antongeorgiev1704 4 роки тому

    CONCERN SUMMARY: What is the Symmetry assumption motivation?
    DETAILS:
    At the point where we found:
    x'=(x-vt)f(v)
    t'=(t-vx)f(v)
    To find f(v), since "who is to say which frame is moving", we (Einstein) make the assumption that you can't determine, so they should be symmetric, so:
    x=(x'+vt)f(v)
    t=(t'+vx)f(v)
    hence we can now find f(v)
    But what is the motivation behind that assumption? What is the exact motivation for ruling out the possibility that there is an absolute speed for observer 1 and observer 2 with respect to something?

    • @computerengineering390
      @computerengineering390 4 роки тому

      1) "But what is the motivation behind that assumption?": I suppose that you are referring to suddenly these two equations appeared x=(x'+vt)f(v) t=(t'+vx)f(v).
      Answer: You don't need more assumptions than these two equations and the fact that any referential see light with the same velocity. For this absolute speed, in both equations ,we must have: x^2 + y^2 + z ^2 = c^2 * t^2 and x'^2 + y'^2 + z'^2 = c^2 * t'^2 (Equations for some light beam starting in t= 0, at the origin, in the two frames.). The movement is in one direction so: let's assume y = y' and z = z' ( these two coordinates won't interfere in the derivation, you can assume different (y,y'), (z, z') and the same result would appear). So, now we have : x^2 - c^2 * t^2 + c^2 * t'^2 - x'^2 => x^2 - x'^2 + c^2 * ( t'^2 - t^2) = 0. Now substitute x' by x'=(x-vt)f(v) and t' by
      t'=(t-vx)f(v), and remember that this must always be true, so force to be an identity for x and t. You will get the transformations from there.
      2) What is the exact motivation for ruling out the possibility that there is an absolute speed for observer 1 and observer 2 concerning something? :
      My answer: any observer can determine speed in their referential. They only need to measure space and time. If you can't determine velocity in your referential, this whole discussion is pointless. For me, he blundered at this point. You don't need to consider relative velocity between these two frames. You can derive the relative velocity from the transformation.
      3) In my perspective, there are many leaps of ideias. For example, These two equation x'=(x-vt)f(v)
      t'=(t-vx)f(v), come from the fact that x' is invariant in lines x = vt + k ( because, for any observer with velocity v determined by observer 1, in their frame, they don't distance from each other) and t' is invariant in lines t = vx/c^2 + k (this derives from the definition of simultaneous event from Einstein) ( Here I'm not considering c = 1, but you can).
      You just need to see that lines t = vx+ k (In observer 1 referential) (I returned with c = 1) have the same t' (Each one with a different t', but in the same line t' is the same). So this lines are the level curve for the function t'(x,t) and then we have t'(x,t) = (t -vx) * f(v). The same can be said for x'(x,t) = ( t -vt) * f2(v) relative to lines x = vt + k. See one thing: x = vt + k => k = x-vt. k is a constant for the line that denominates the linear coefficient. So, for some k : x'(x,t) = (t-vt) * f2(v) => x'(x,t) = k * f2(v). For a given v and k, x'(x,t) is a constant.

  • @its_a_gus_thing
    @its_a_gus_thing 9 років тому +309

    He looks like Mike from Breaking Bad

    • @Daniel-dc5mr
      @Daniel-dc5mr 8 років тому +2

      lol true

    • @jedimindtricks87
      @jedimindtricks87 7 років тому +4

      He looks like a mix between John Malkovich and that guy lol

    • @physics110
      @physics110 6 років тому

      oh man..that's him!!!!

    • @robertbrandywine
      @robertbrandywine 6 років тому +1

      I was thinking the same thing.

    • @pitreason
      @pitreason 5 років тому +1

      For me he looks like Jacque Fresco

  • @Dennis-er8xc
    @Dennis-er8xc 3 роки тому +1

    There are different ways to think about this problem. And the scenario used @ 33:10 to explain the dynamics makes it simpler.

  • @waikikiman007
    @waikikiman007 10 років тому +4

    Clocks and lengths do not actually change in YOUR frame or reference when you are moving. They only appear to in somebody's else frame of reference that is stationary relative to yours. And Visa a Versa..

    • @Banjo-ed5vv
      @Banjo-ed5vv 6 років тому +1

      You have not understood special relativity

    • @HilbertXVI
      @HilbertXVI 6 років тому +1

      @@Banjo-ed5vv More than you, really

    • @Banjo-ed5vv
      @Banjo-ed5vv 6 років тому

      @@HilbertXVI I have a big shlong that's all mate

  • @sazawal
    @sazawal 10 років тому +1

    At 1:15:50, we found using Lorentz transformation that the length of a stationary meter scale measured from a moving reference frame is contracted by a factor of sqrt(1-v^2). But in the space-time plot the length of meter scale from x'=0 to x'=1 along the x' axis appears to be greater than 1 (from basic geometry). What am I missing here?

    • @sazawal
      @sazawal 10 років тому +2

      Ok, so he spoke about it later in the lecture.

  • @tgifhounds
    @tgifhounds 10 років тому +3

    “If Einstein is right”… that statement alone transforms this into a philosophy class alas to run with it is mind-boggling.

  • @rbwinn3
    @rbwinn3 Рік тому +1

    Here is the problem with Special Relativity. Suppose that there is a clock in a flying airplane. Einstein says this about that clock. "The time which elapses between two strokes of the clock is not one second, but 1/sqrt(1-v^2/c^2) seconds, a somewhat larger time. As a consequence of its motion the clock goes more slowly than when at rest." (Relativity, the Special and General Theory, A. Einstein, p.44)
    x'=(x-vt)/sqrt(1-v^2/c^2)
    y'=y
    z'=z
    t'=(t-vx/c^2)/sqrt(1-v^2/c^2)
    inverse equations
    x = (x' + vt')/sqrt(1-v^2/c^2)
    y = y'
    z = z'
    t = (t' + vx'/c^2)/sqrt(1-v^2/c^2)
    These equations do not agree with reality because they show that the speed of the airplane is the same as observed from either frame of reference. v is the speed of the airplane and is the same speed as calculated from the time of either clock. We common people live in something called reality where if the pilot of the airplane has a slower clock to time the flight of the airplane, he will get a faster speed for the airplane than an observer on the ground will get using a faster clock on the ground to time the flight of the airplane. What the above equations describe is a miracle, a supernatural event. Here are the correct equations for relativity.
    x'=x-vt
    y'=y
    z'=z
    t'=t
    These equations are called the Galilean transformation equations and are the equations that scientists used until 1887 when the Michelson-Morley experiment took place, and scientists found that they could not describe the results of that experiment using the Galilean transformation equations. The problem they encountered was that if t'=t, then the two equations that would show the same speed of light in both frames of reference, x=ct and x'=ct', could not both be true because x and x' were not the same distance unless v=0.
    But Newton and Galileo were both capable of working simple algebra. If there is a clock in the airplane that shows some other time than t, the time of a clock in the frame of reference at rest. Either of these two earlier scientists could have described a clock with a different rate. They would have just used a different set of Galilean transformation equations with different variables for velocity and time. So if there is a clock in the airplane that is slower than a clock on the ground, then the inverse equations would be
    x = x' - (-vt/n')n'
    y = y'
    z = z'
    n = n'
    where n' = is the time of the slower clock in the airplane, and (-vt/n') is the velocity of the airplane according to the time of the slower clock on the airplane. These equations describe relativity, not only for a slower clock such as Einstein describes in his Special Theory of Relativity, but also for a faster clock such as scientists say they encounter in a GPS satellite. So to describe light as traveling at c=186,000 miles per second in both frames of reference according to clocks in those frames of reference, we do not say x=ct and x'=ct', as Einstein said, but x=ct and x'=cn' the times of the two clocks in question. We have now resolved the problem scientists could not solve in 1887 without resorting to length contractions, curved space, or other miracles that have been used by scientists since that time. Scientists, of course, are not going to like this because they are paid trillions of dollars by governments to say that Einstein's description of relativity is correct.

    • @hollaadieewaldfeee
      @hollaadieewaldfeee Рік тому

      SRT = Doppler effect;-)
      Nothing else;-)

    • @rbwinn3
      @rbwinn3 Рік тому

      @@hollaadieewaldfeee It is not relativity. I can tell you that much. It sets up time as some kind of force that controls space. Why would the rate of transitions of a cesium atom on an insignificant planet be the controlling force for all other things in existence?

    • @Endgator
      @Endgator 4 місяці тому

      You start by quoting Einstein and then attempt to argue that the time dilation predicted by Special Relativity leads to contradictory or miraculous results when considering the speed of an airplane from different reference frames, but your claim is riddled with misunderstandings. Here are the breakdowns of your argument.
      Time Dilation and Reference Frames:
      Einstein’s equations for time dilation, such as t'=(t-vx/c^2)/sqrt(1-v^2/c^2), do not suggest a contradiction or supernatural event. They describe how time passes differently for observers in different inertial frames moving relative to each other. The key point is that each observer measures time and space according to their own reference frame. An observer on the ground and an observer on the airplane will each measure different times and distances, but these differences are consistent when transformed between frames using the Lorentz transformations.
      Relative Velocity Measurement:
      Your claim also asserts that the speed of the airplane should be perceived differently by the pilot and an observer on the ground due to differing clock rates. However, Special Relativity already accounts for this by incorporating the concept of time dilation and length contraction. The velocity of the airplane is the same in both frames because it is a relative velocity, not an absolute one. What changes between the frames is not the speed of the airplane itself, but the measurement of time and distance.
      The idea that a slower clock on the airplane should result in a higher calculated speed in that frame is incorrect because it fails to consider that the distance measured in the airplane’s frame (due to length contraction) would also differ. Special Relativity shows that both time dilation and length contraction ensure the speed of the airplane remains consistent across all inertial frames.
      Galilean vs. Lorentz Transformations:
      Your claim also suggests reverting to the Galilean transformation equations as a solution. However, this approach overlooks why Lorentz transformations replaced Galilean transformations in the first place. Galilean transformations assume that time is absolute and the same for all observers, which fails to explain the results of the Michelson-Morley experiment, which showed that the speed of light is constant in all inertial frames.
      The Lorentz transformations provide the correct relationships between time and space for observers in relative motion. These transformations are not arbitrary or miraculous; they are a necessary consequence of the principles that the speed of light is the same in all inertial frames and that the laws of physics are invariant under changes in reference frames.
      GPS Satellites and Relativity:
      Your claim also references GPS satellites, suggesting that they operate under principles different from those of Special Relativity. This is incorrect. GPS technology actually relies on both Special and General Relativity to function accurately. Time dilation occurs due to both the relative velocity of the satellites (Special Relativity) and the difference in gravitational potential between the satellites and the Earth’s surface (General Relativity). Far from disproving relativity, GPS systems confirm the accuracy of Einstein’s theories.
      Your claim suggests new transformation equations are necessary to avoid supposed paradoxes in Special Relativity. However, these paradoxes only arise from misunderstandings of how time, space, and velocity transform between different reference frames. The Lorentz transformations, as part of Special Relativity, accurately describe how different observers perceive time and space, ensuring consistency with the experimental evidence, including the constancy of the speed of light. The proposed “correct equations for relativity” based on Galilean transformations cannot explain the behavior of light and are incompatible with the experimental data that led to the development of modern physics.
      The ideas presented in your claim reflect a fundamental misunderstanding of the principles underlying Special Relativity and overlook the extensive experimental confirmation of Einstein’s theories.

  • @gorgolyt
    @gorgolyt 11 років тому +41

    Isn't this guy Mike from Breaking Bad?

  • @dionsilverman4195
    @dionsilverman4195 6 років тому

    Question, around 51:25 when he shows that the two scaling functions (Lorentz factor) f(v) and g(v) must be equal for the space and time components by saying that when x = ct, x' = ct', doesn't this only show that f(c) = g(c)?
    x' = (x - vt)•f(v) and t' = (t - vx)•g(v), setting x=t, x'=t',
    x' = x(1 - v)•f(v) = x(1 - v)•g(v) = t'
    (1 - v)•f(v) = (1 - v)•g(v) only for the initial assumption v = c.
    I could construct a similar function (4 - v)•2v = (4 - v)•v² which is only true for v = 2.
    Also, is the assumption the gamma is only a function of the magnitude of the velocity, and not the vector the assumption that the universe is isotropic?

  • @rifatzehra6546
    @rifatzehra6546 3 роки тому +3

    I would be highly grateful if english auto generated subtitles would be provided for this playlist

  • @vesuvandoppelganger
    @vesuvandoppelganger 2 роки тому +1

    It is possible to derive 2 contradictory time dilation equations. The first paragraph below describes the situation with Sally aiming a flashlight straight up and down so that Sally sees the light moving straight up and down and John is outside the spaceship and sees the light forming a triangle with the floor of the spaceship. The second paragraph describes Sally aiming a flashlight towards the left while the spaceship moves to the right. Now the situation is exactly reversed. Sally sees the light forming a triangle with the floor and John sees the light bouncing straight up and down.
    Sally is in a moving spaceship. John is outside the spaceship. Sally is moving to the right at .6c. The height of her spaceship is .8 light-seconds. If Sally has a light clock with the light bouncing straight up and down the light will make a 3-4-5 right triangle from the viewpoint of John. If the change in time for Sally is delta T_o and the change in time for John is delta T then the following equation can be derived: delta T = delta T_o/((1-.6^2)^.5). So .8 seconds for Sally = 1 second for John.
    Now Sally has a light clock but this time she is holding a flashlight at an angle of 53.13 degrees above the horizontal and pointed to the left. Now the leftward movement of the light exactly matches the rightward movement of the spaceship from John's viewpoint. Now the light is bouncing straight up and down from the viewpoint of John and the light is making a 3-4-5 right triangle from viewpoint of Sally. If the change in time for Sally is delta T_o and the change in time for John is delta T then the following equation can be derived: delta T_o = delta T/((1-.6^2)^.5). So 1 second for Sally = 0.8 seconds for John. The 2 equations are in direct contradiction to each other.
    Special relativity is falsified.

    • @Jeremy-fd2pw
      @Jeremy-fd2pw 7 місяців тому

      What is he talking about

    • @vesuvandoppelganger
      @vesuvandoppelganger 7 місяців тому

      The first situation is the standard derivation of the time dilation formula. In the second situation the observations of the movement of light are simply reversed from the first situation.

  • @KuldeepKumar-hl4jz
    @KuldeepKumar-hl4jz 4 роки тому +7

    No book has shown that why (ct)^2 - (X^i)^2 is the length element. They just say it is because of invariant purpose.

    • @nge1301
      @nge1301 3 роки тому

      It's a statement of the invariance of the speed of light.
      The fact that the expression you wrote is the same in any two frames is a statement that the speed of light c is the same in those two frames.

  • @deedubya286
    @deedubya286 12 років тому

    Time stops at velocity=c. He covers this toward the end of the lecture while discussing time-like and space-like intervals. Watch at around 1:45:00.

  • @danomicky
    @danomicky 12 років тому +3

    these lectures are so valuable

  • @LeavingCertMaths
    @LeavingCertMaths 12 років тому +1

    44:00 The 2 in the numerators come from twice the distance between the moving clocks. Since the 2's cancel, the slope v is independent of the units of this value. We could change the distance between the moving clocks and the slope of the line joining the moving clocks at 0 and b would still be v. This shows that the t' = 0 axis passes through b.

  • @namanagarwal7729
    @namanagarwal7729 7 років тому +3

    Can anyone tell me in which of his lectures he teaches spacetime diagrams?

  • @marxman1010
    @marxman1010 2 роки тому

    At 48:03, x' = x - vt could be incorrect, so add f(v) to the right of the equation, interesting.

  • @yrebrac
    @yrebrac 10 років тому +6

    One question after watching the first hour.. how was v supposed to be defined? In terms of the stationary reference frame? If so wouldn't the moving frame measure v differently since it measures x t differently?

    • @seanki98
      @seanki98 6 років тому

      v is just the relative speeds between the reference frame.

    • @seanki98
      @seanki98 6 років тому

      There is no such thing as a stationary reference frame. You arbitrarily choose a reference frame and call that stationary.

    • @seanki98
      @seanki98 6 років тому +2

      Let me phrase that better. The point of relativity is that there is no such thing as "the stationary reference frame". What we do instead is we compare two different reference frames, which move relative to each other at a speed v. There is no need to confuse yourself with the fact that x and t are measured differently. It is really a matter of symmetry. S' moves at a speed v relative to S means that the origin in the frame of reference of S, yes measured in x and t coordinates of S, moves at a speed v in the positive x-direction. But clearly, no-one stops you from choosing S' to be the frame that is stationary (i.e like jumping onto the spaceship which is moving relative to the earth), in which case clearly S will move with speed v in the opposite direction-:in your -x' direction.
      You only begin to worry about x and t being measured differently when you consider TWO events which are separated in space or time. In this case you simply are tracking the origin of the other reference frame.

    • @Jeremy-fd2pw
      @Jeremy-fd2pw 7 місяців тому

      Okay 👌👍

  • @JellyComb420
    @JellyComb420 2 роки тому

    I'm always waking up to this guy

  • @parkkhyle6686
    @parkkhyle6686 10 років тому +4

    Thanks a million times for the video, but could the camera man be less active and be more static throughout the lecture? I'm feeling dizzy..

  • @karlwashere123
    @karlwashere123 12 років тому +4

    first of Susskind's videos that I feel I'm ahead of... that's a first.. wish I had started here:)

  • @thomaswhite4692
    @thomaswhite4692 9 років тому +1

    How he arrived at the conclusion that the f() was commutative and used that property in solving for f()? 56:59

    • @sumsar01
      @sumsar01 9 років тому

      +Thomas White if x = x*C. Then C = 1.
      So (1-v^2)*f^2 = 1.
      f^2 = 1/(1-v^2)
      f = 1/sqtr(1-v^2). sqtr(1) = 1

    • @abhishekgy38
      @abhishekgy38 6 років тому

      Bro, I'm being haunted by the same question. Have you been able to find a convincing answer yet?

  • @enaud847876
    @enaud847876 7 років тому +8

    how to enable subtitles? thanks I am deaf

    • @oldcar8592
      @oldcar8592 7 років тому

      Subtitles don't work with this lecture. Try MIT Opencourseware Relativity where they work. Just click the CC on the bottom

    • @enaud847876
      @enaud847876 7 років тому

      thanks

    • @enaud847876
      @enaud847876 7 років тому

      on youtube i dont find MIT Opencourseware Relativity.. do you have a link?

    • @sayantansaha9047
      @sayantansaha9047 7 років тому +1

      ocw.mit.edu/index.htm

    • @oldcar8592
      @oldcar8592 7 років тому +1

      ocw.mit.edu/courses/physics/8-04-quantum-physics-i-spring-2013/lecture-videos/lecture-1/

  • @LillianWinterAnimations
    @LillianWinterAnimations 8 років тому +2

    Lots of people are confused by x + t being a constant, so.. here's an algebraic proof I drew up for those interested.
    so, a line with that angle has a slope of 1, or -1.
    In other words, f'(x) = +- 1
    so, if we take the antiderivative, we have..
    f(x) = +- X + A
    where A is a constant.
    so, where the slope is positive, f(x) = x + 1, we can express it as x - t = constant
    or rather, x - f(x) is a constant.
    how is this?
    X - (X + A), or..
    X + F(X) = -A
    -A
    That's not a variable.. that's a constant. Replace F(X) with t because t is on the y axis there, and you have your answer.
    meanwhile, X + (-X + A) (negative slope)
    (X - X) + A
    A
    Also a constant.

    • @WaddiaS
      @WaddiaS 8 років тому

      True, but (x+t) can also be understood as a constant by just sticking to simple intuitive concepts of lines and gradients rather than scrutinizing it with calculus.

    • @LillianWinterAnimations
      @LillianWinterAnimations 8 років тому +1

      Waddia S. Agreed! I think that's a great way to think of it. This is just for those who have difficulties with intuition in mathematics :3

  • @RunItsTheCat
    @RunItsTheCat 9 років тому +10

    If anyone is looking for an easier explanation of special relativity's concepts, I highly recommend VSauce's "Would Headlights Work at the Speed of Light?" video. He has a lot of graphical and animated explanations there, while these lectures involve more mathematical proofs and calculations. I found learning the concepts first and coming back here for the math much easier, especially since I'm doing this before quantum mechanics (standard curriculum teaches QM first).

    • @chrisa4284
      @chrisa4284 9 років тому +2

      +RunItsTheCat I would argue that Special Relativity is MUCH easier than QM. And, indeed, at my university special relativity is taught in 1st year whereas QM is taught in 2nd year

    • @zekeriasvarg530
      @zekeriasvarg530 9 років тому

      +RunItsTheCat First notice that their is an Eter. Thats fact! So no we debunk this
      shit by the sionist fraud St Einstein. Dayton Miller redid the
      Michaelsson experiments but 10000 more carefully and did se interaction.
      To day we see it for Bifeldt Brown , Casmir effect and 100 other
      things. The EM wave does spread out transversal into Eter with C but
      the dielectric vawe propagates faster ( Tesla did calculate) . The
      magnetic propagation vawe never determined at all ! But true they
      probably are longitudal and thats for study. So no go and study the
      artifact,, co-rotating magnet and faraday disk for example. If we
      check two conductors parallell with same vector currents. If you are the
      "electron" propagating in one conductor and your buddie is in the other
      conductor moves parallell to you with same speed, do you se any
      relative movement? No HELL no. You are moving at constant speed and so
      is your friend. BUT YOU VILL notice that your conductor moves to your
      friends conductor and the opposite !!!!!!!!! The relativists explains
      this with circular argument introducing their fraud theory. If we take
      in an eter you got your relativity but the relativists does not like
      eter but today they call it dark energi and a lot of other crap. REad
      Bjerknes book St Einstein pdf at youtube to get why the banksters gaved
      us this fraud. E = MC2 was known by Maxwell before Einstein was dry
      behind the ears. The space is working by electricity and birkeland,
      Tesla and the real physisits did all this finnished together with the
      guru and legend Hannes Alfvén. The establishment does not wont us to
      know as they want us to live dumbed down.

    • @RunItsTheCat
      @RunItsTheCat 9 років тому +14

      Zekerias Varg "Quality trolling"

    • @zekeriasvarg530
      @zekeriasvarg530 9 років тому

      +Alter Kater Nature was my teacher.

    • @zekeriasvarg530
      @zekeriasvarg530 9 років тому +1

      +Alter Kater "bullshit" that you cant debunk.

  • @steelsnake14
    @steelsnake14 3 роки тому +1

    I fell asleep on my phone watching UA-cam last night, woke up hearing this guy 57 minutes into some lecture

  • @JesusDominguez-Perez
    @JesusDominguez-Perez 8 років тому +77

    Says that he's not going to get in depth about inertial frames of reference..... *begins explaining inertial frames of reference* LOL

    • @samuelson4244
      @samuelson4244 7 років тому +25

      A physicist going in depth and a layman going in depth are two different frames of reference. For the former you're gonna see a ton of math.

    • @stez7199
      @stez7199 7 років тому

      Yea, he's done that a few times in the previous two courses. Always a good laugh.

    • @netrapture
      @netrapture 6 років тому +3

      He said he's not going to get into the PHILOSOPHY

    • @chuckys7358
      @chuckys7358 3 роки тому

      @@samuelson4244 4r4 ⁵I 5⁵545rrrrr=rrrr5r5r⁵⁵rr5⁵r5r56⁵really bad ⅚54th 54th 54th ⁵is the 54th ⁵that ⁵is 4555⁵⁵5 r⁵that can make 4554⁵for 45⁵or n.

  • @vesuvandoppelganger
    @vesuvandoppelganger Рік тому +1

    Here's something to look at...
    Ship1 at rest at top:
    T--------------------N
    N--------------------T
    The moment when T of ship1 is lined up with N of ship2 must be the same moment in both frames of reference because there is only 1 moment when this occurs. At this moment for someone at N of ship1 to see T of ship2 they have to look in 2 different directions simultaneously. This is impossible. N of ship1 is simultaneously both passed and not passed T of ship2. This is impossible.

  • @turtledicc4630
    @turtledicc4630 3 роки тому +5

    So this is why I'll be going to school on 4 hours of sleep.

  • @raymondblake5765
    @raymondblake5765 4 роки тому

    At 1:18, how do we calculate the length of the metre stick calculated by the stationary observer? Do we say when t=0, x^1= 1, and then plug this into the Lorentz transformation? This gives you the expected result, but I'm just really confused...

  • @anahg5017
    @anahg5017 10 років тому +3

    Thank you very much for the videos, I really love it!

  • @bilkanyildirim6655
    @bilkanyildirim6655 6 років тому +2

    I am a high school student who tries to learn some advanced physics on his own. Such a helpful video.

  • @mrflibble5717
    @mrflibble5717 9 років тому +5

    Great Lectures, thanks Prof. Susskind

  • @BenRochlin
    @BenRochlin 11 років тому

    The point is that any line at this angle can be written as y=-x + c (for some constant c) ... and yes that c intercept is the constant since rearranging gives y+x=c along that line.

  • @Johncowk
    @Johncowk 9 років тому +37

    Really nice, although it has to be watched in speed 1.25 or 1.5 x)