How to Solve for the Coefficient of Friction

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  • Опубліковано 27 сер 2024
  • In this video tutorial I explain how to use the friction force equation to solve for the coefficient of friction.

КОМЕНТАРІ • 74

  • @quacxks100
    @quacxks100 2 роки тому +103

    This is gonna help me sooooo much.
    Have a physics test tomorrow,
    Will update.
    Update: 92%!!!
    Let's, GOOOOOOO

  • @sapaiVFX
    @sapaiVFX 2 роки тому +14

    Thx a lot for this. Helped w/ my IB physics lab report

  • @monikachaudhary9569
    @monikachaudhary9569 2 роки тому +4

    Hi , Thankyou so much .
    Lots of love 💕💕 from INDIA.

  • @yaduvanshiayush3215
    @yaduvanshiayush3215 2 роки тому +2

    It's amazing explanation..!! Love from India dude ❤💗

  • @pr3ttysus922
    @pr3ttysus922 Рік тому +1

    you saved my life, THANK YOU SO MUCH!

  • @kevinkinal9557
    @kevinkinal9557 3 роки тому +6

    The 10 sec version Coef of Friction = Force/ wt.
    For ex, if 1 lb moves a 2 lb object Coef = .5 (it takes half the wt to move it)

  • @jinanabrahams5195
    @jinanabrahams5195 Рік тому

    Thanks so much. My teacher just threw me in the deep end, and this really saved me😊

  • @VinsanityNailed
    @VinsanityNailed Рік тому +7

    Please please please leave your units in. You don’t explain WHY the coefficient of friction doesn’t have units. It’s because the units divide out. Leaving units out is a really bad habit for students

    • @kivalbalasar9403
      @kivalbalasar9403 Рік тому +2

      Dont put units in for coefficient of friction you lose marks

  • @danuwu2514
    @danuwu2514 2 роки тому +1

    Thank you so much, you made it so easy for me!

  • @andrefelipe2643
    @andrefelipe2643 2 роки тому +7

    Thank you ! 😃 you made it look quite easy, I am not even good at math and I understood that 😅.

  • @learningtwice347
    @learningtwice347 Рік тому +1

    Thanks 😊🙏

  • @jyotsnarishita669
    @jyotsnarishita669 Рік тому

    It helped me a lot thanku
    I am glad I watched your video
    I got 100 /100 💯💯

  • @dennybuka969
    @dennybuka969 Рік тому

    Love you ❤you saved my life

  • @BattierJam
    @BattierJam Рік тому

    Thank you so much for this my teacher is terrible at explaining things

  • @ellaea4505
    @ellaea4505 Рік тому

    physics final thank you for the help

  • @dianelibarnes2519
    @dianelibarnes2519 3 роки тому

    Thank youuuuu ❤️❤️❤️ I was really having troubles with this one 😭😭

  • @samsonphiri8951
    @samsonphiri8951 6 місяців тому

    Since the 7 tones load is pulled along horizontal the normal force= weight of the Load which is equal to 68600N and the acting at the of 30° by the free body diagram the horizontal force = 39606.23N this is the force which must be overcome to accelerate the load of 7000kg.

  • @annrahennaramirez5821
    @annrahennaramirez5821 Рік тому

    thank you this is the video that im looking for two days hahahaha

  • @renadi5673
    @renadi5673 3 роки тому +1

    شكراً لك كان مفيد جداً لي

  • @user-vp2mo4sm2o
    @user-vp2mo4sm2o Рік тому

    How do you calculate the coefficient if there where two blocks with different masses connected

  • @aradhyth9
    @aradhyth9 Рік тому +1

    It can be obtain by inequality

  • @jippo91
    @jippo91 Рік тому

    What if i have to calculate the coefficient of friction in an angle and with the downwards force. For example when i have a box on a sin=15° degree angle slope and the downwards force "gravity" is 200N. I have been trying to solve this for two days and i'm supposed to get the answer Gx = 51,763N. I just dont get it. The equation goes sin=15°, G=200N, Gx=Fu. Sin= Gx:G, Gx= 200N • sin15°, Gx= 51,763N. What am i missing?

  • @twangerrrrrr
    @twangerrrrrr Рік тому

    I have my grade 11 physics dynamics test next period in a couple of minutes. I hope I do well. I missed 2 days of school because I moved homes and now I fell behind in friction and gravitation.

  • @vladvalevski5608
    @vladvalevski5608 2 роки тому

    Saved my life

  • @ShivamYadav-jo5bl
    @ShivamYadav-jo5bl Рік тому

    You are very op brother

  • @gordspins7298
    @gordspins7298 2 роки тому

    yes. this video was very helpful thanks

  • @amartitesfaye7297
    @amartitesfaye7297 2 роки тому

    Thanks for this video!

  • @kristalsmith2552
    @kristalsmith2552 6 місяців тому

    Thank You!!!!!!!

  • @lifesavergaming5583
    @lifesavergaming5583 Рік тому +1

    Brilliant

  • @user-kg1cf8ty3s
    @user-kg1cf8ty3s Рік тому

    a load of 7tonnes is pulled along a horizontal track by a force inclined at 30 degrees to and above the track .Find the frictional force if the coefficient of friction is 0,2..................help..??

    • @DMaciaga
      @DMaciaga  Рік тому

      You'll have to find the normal force (mgcostheta) then plug that into the friction force equation (Ff = mu x Fn). Looks like you'll have to convert 7 tons to kg.

    • @samsonphiri8951
      @samsonphiri8951 6 місяців тому

      I have done that 7000kg *9.8 to find the weight of the Load. And the weight of the Load= to the normal force since it is pulled along the horizontal surface.

  • @gabriellesanthya9539
    @gabriellesanthya9539 4 роки тому +1

    Hi is it possible if you explain superposition theorem 😊

  • @karabogift2297
    @karabogift2297 Рік тому

    Thnx

  • @vinchenzowitbooi_8599
    @vinchenzowitbooi_8599 3 роки тому +1

    This video saved my liiiife oh my gaaawd😂😂

    • @sohanreddyk2537
      @sohanreddyk2537 2 роки тому

      And how is that dude

    • @c7nal7ammadi78
      @c7nal7ammadi78 2 роки тому +1

      @@sohanreddyk2537 maybe he had an exam and watched this vid??????

  • @efath-bz8hv
    @efath-bz8hv 2 роки тому

    thank you brother

  • @krazzyyyyy7302
    @krazzyyyyy7302 2 роки тому

    Tnx a lot sir!

  • @russkayaimperiya5779
    @russkayaimperiya5779 2 роки тому

    THANK YOU!

  • @hellleyy
    @hellleyy 3 роки тому

    Thank you👍

  • @Soyuzniki21
    @Soyuzniki21 Рік тому

    Isnt that the limiting friction?

  • @xyama8433
    @xyama8433 2 роки тому

    thanks so much

  • @Rookiwi
    @Rookiwi 4 місяці тому

    thanks bruh

  • @irshadtarsoo7734
    @irshadtarsoo7734 3 роки тому

    Thank youu❤️💯👍

  • @arielleestrada7753
    @arielleestrada7753 2 роки тому +1

    i love you

  • @proplayer6053
    @proplayer6053 2 роки тому

    Thanks ☺️

  • @nadia-tw1en
    @nadia-tw1en 2 роки тому

    THANK YOU

  • @tsekokatse2118
    @tsekokatse2118 3 роки тому

    Thank you

  • @J.Michael1
    @J.Michael1 3 роки тому

    Thanks!!!

  • @c7nal7ammadi78
    @c7nal7ammadi78 2 роки тому +1

    انا عندي امتحان و الساعة 4 الفجر و للحين ما درست😂😂

    • @forza_INT
      @forza_INT 2 роки тому

      😂😂😂نفس بعض

  • @sulaimankhan2152
    @sulaimankhan2152 Рік тому

    king

  • @jimtsitsos
    @jimtsitsos Рік тому

    the greek letter is called "me" :')

  • @jjeonacid1282
    @jjeonacid1282 2 роки тому

    what if there’s a frictional force present in the box??

    • @shumailkhan7205
      @shumailkhan7205 2 роки тому +2

      Friction is a force that is between 2 surfaces. so friction is between the box and the ground. There is no friction 'present in the box'

  • @apanba1050
    @apanba1050 Рік тому

    L

  • @SpartanWolf120
    @SpartanWolf120 Рік тому

    Eat your cereal