Thank you so much sir for your excellent way of explanation, all the minute concepts are cleared from depth........also infinite thanks for such a good response to doubts and comments.......huge respect sir..........
Loved the Video sir. Please upload the following ASAP 1. statistical analysis of traffic data; 2.Signal design by Webster’s method 3.Geometric design of railway Track - Speed and Cant. 4. Concept of airport runway length, calculations and corrections; taxiway and exit taxiway design
The capacities of one way 1.5 m wide side walk(Persons per hr)& one way 2-lane urban road (PCU per hour,with no frontage acess, no standing vehicles and very little cross traffic) are respectively ....
Hi, The above specifications are from IRC-86 code book. capacity of one-way 1.5 m wide sidewalks is 1200 person per hour. And, capacity of one-way 2-lane urban road with no frontage access, no standing vehicles and very little cross traffic is 2400 persons per hour
It is the ratio of velocity of separation and velocity of approach. velocity of separation is the difference in velocity between two colliding vehicles after collision (accident). And velocity of approach is the difference in velocity between two colliding vehicles before collision. For a perfectly elastic collision, velocity of separation will be equal to velocity of approach. Hence coefficient of restitution will be equal to 1. For a perfectly inelastic collision vehicles move together after collision and hence difference in velocity after collision is zero (velocity of separation=0) . Hence for a perfectly inelastic collision, coefficient of restitution will be equal to 0
Superb sir, you are amazing in teaching ❤️💐🙏🏻😍
I was actually watching your geometric design video in gate academy and in search for traffic engineering lectures..Thank you for providing this
Thank you :) will upload more videos ..
I know this all concept.Thank for revision. Love the way you teach sir.🤩
Thank you.. prepare well
Thank you so much sir for your excellent way of explanation, all the minute concepts are cleared from depth........also infinite thanks for such a good response to doubts and comments.......huge respect sir..........
Thank you Ananya, prepare well
Thank you so much sir... My interest get boosted whenever I listened to your lectures. Awesome way of teaching sir ..👏
Thank you. Keep preparing :)
Loved the Video sir. Please upload the following ASAP
1. statistical analysis of traffic data;
2.Signal design by Webster’s method
3.Geometric design of railway Track - Speed and Cant.
4. Concept of airport runway length, calculations and corrections; taxiway and exit taxiway design
Thank u sir for wonderful knowledge
Thank you so much sir for the valuable content 🤩
❤️ from Warangal
We want more videos sir
Thank u very much sir ... Waiting for more lectures on transportation 😍
Thank you Shabin..share with your friends as well
Hi
Please do a revision video of flexible and rigid pavement
Ashique, will try to upload in near future
Sir continue uploading lecture we support you
Thank you so so so so so much sir ❤️❤️❤️🙏
Thank you. Will upload more videos
The capacities of one way 1.5 m wide side walk(Persons per hr)& one way 2-lane urban road (PCU per hour,with no frontage acess, no standing vehicles and very little cross traffic) are respectively ....
Hi,
The above specifications are from IRC-86 code book.
capacity of one-way 1.5 m wide sidewalks is 1200 person per hour. And, capacity of one-way 2-lane urban road with no frontage access, no standing vehicles and very little cross traffic is 2400 persons per hour
Sir what is coff of restitution of elastic collision and pls tell for inelastic also thank you in advance
It is the ratio of velocity of separation and velocity of approach. velocity of separation is the difference in velocity between two colliding vehicles after collision (accident). And velocity of approach is the difference in velocity between two colliding vehicles before collision. For a perfectly elastic collision, velocity of separation will be equal to velocity of approach. Hence coefficient of restitution will be equal to 1. For a perfectly inelastic collision vehicles move together after collision and hence difference in velocity after collision is zero (velocity of separation=0) . Hence for a perfectly inelastic collision, coefficient of restitution will be equal to 0
👌✌️✌️
Thank you
We want more playlist
Sir please upload more lecture as far as possible GATE is coming near by near its a humble request to you sir ....... please sir please
please sir you can provide the video of highway material
Ashok, yes will upload in near future
hello