Your teaching style is amazing. In the statics books I have read, they love to overcomplicate these things, when in reality it can be very clear and intuitive if someone explains it in such good way.
I love you man. You just cleared my conceptions about shear force and bending moment diagrams. May God give you good health and all the happiness you desire. Loved your videos, Thank you so much.
🤣 Im just here for 7:35... 'and THEN what? BAM!'.... it just keeps getting better🤪🤓👍 Thanks for always clarifying my midnight Strengths HW insanity.... with smiles worth replaying.
for those who dose understand why y=9-2x.I think the best way to understand is that the x is negative in x-yplan. but we need a positive distance to compute the total force in rectangle.
Thanks But don't worry I still don't understand. It's like i have no idea what he's talking about. I remember solving equations like this one on my own but in a completely different way
Your videos are great Jeff! Thank you for posting. This one was tough, hopefully The exam probs aren't this hard. I could not wrap my head around the equation y=9-2x
He tooks B as (0,0) and in the function Y=2x+9 he makes the sostitution x=-x, (as the x has to be negative in the graph) in order to find the Y required, and in this way it comes out Y=2(-x)+9
Can you add this video to your statics playlist also? I didn't know about this video and had to deal with more advanced problems like this in statics. is there a video with these diagrams but with back to back triangles (both max heights at the center) on a cantilevered beam? im having trouble once i get to the second triangle.
Thanks For Ur great effort Dr.Jeff , But I think it's quite enough to Find the moment and derive the equation to get the shear force directly or integrate the shear force to find the moment.
Very clear explanation, thanks for this. Can we make a formula for the whole beam or only for the part we cut? I noticed in this example that when you try to enter a value of 6 for x you get weird numbers which don't add up. I am in particular curious about this because this problem has a linear load that stops in the middle and thus these are two different loads. I can imagine when the load continued to the end 1 equation is easier.
No it is correct. We are assuming the 9 is the y intercept of the equation of a line y=Mx+b. The reason it’s 6/3 is rise/run and the slope was made negative because it’s is going downward from the intercept. When you want to know if the slope is positive or negative follow the line from the intercept
can someone explain on how or why did he put negative on the 2x ? I'm only confuse on that part. I've been reading the comments but I seem to still not get it.
@@vikneshmaniam5618 Look at it like a coordinate system. On his diagram his origin is on the right side of the beam where By=14.25 points upward (14:04). The slope is indeed going up where y=2x+9. At the origin x=0, so y=9 which makes sense because the force distribution at that point is 9kN/m. The height at the other end of the beam lies on top of the negative x axis of the coordinate system (quadrant II). If the function f(x)=2x+9 and x is (-x) then y=-2x+9. I hope that makes sense
Hi Jeff. Im confused about something. Why is the bending moment diagram sloping up instead of down after the 3 meter mark? I get the straight line from 0 to 3 (first half) but why curve the line upwards on the bending moment diagram?
According to the previous lesson (24), I use the semi parabolic area formula to calculate the x and I found x and M as 1.5625 and 14.8438, respectively. I think the semi parabolic area equation is not suitable for that kind of curve. (Please correct me if I'm wrong)
at 14:00, how do you just switch the sign and figure out what x is... and it only gets more confusing from there. I mean, I passed calc 3 with an A and I’m not really getting this
He used the right hand side of the drawing as the origin, so if you made a mirror image of the picture from the origin (so that x would be increasing from left to right), the slope would become negative. At least, that's how I reasoned it out.
@@sebastianfinn3028 thanks ! I had the same final results but with different x value Now i see why , the both methods are correct but each one uses a different reference
Sir could you please make video on finding Shear force and Moment using heavy side notation or step function ? And with different types of distributed forces like UDL and UVL as well as support ?
Your teaching style is amazing. In the statics books I have read, they love to overcomplicate these things, when in reality it can be very clear and intuitive if someone explains it in such good way.
Hands up for you sir. In this pandemic we need a professor like you ,👋
Bobo rin ako sa math pero hinding hindi susuko! haha
I love you man. You just cleared my conceptions about shear force and bending moment diagrams. May God give you good health and all the happiness you desire. Loved your videos, Thank you so much.
you are the best professor i ever had .god bless you
Wonderful solids lessons!! really taking the time to explain the problems along with a good sense of humor :))
🤣 Im just here for 7:35...
'and THEN what? BAM!'.... it just keeps getting better🤪🤓👍
Thanks for always clarifying my midnight Strengths HW insanity.... with smiles worth replaying.
for those who dose understand why y=9-2x.I think the best way to understand is that the x is negative in x-yplan. but we need a positive distance to compute the total force in rectangle.
also, you can just use Y=2x+9, and put the negatiove sing on the x, when compute the total force area.
Thanks
But don't worry
I still don't understand.
It's like i have no idea what he's talking about. I remember solving equations like this one on my own but in a completely different way
Your videos are great Jeff! Thank you for posting. This one was tough, hopefully The exam probs aren't this hard. I could not wrap my head around the equation y=9-2x
He took (0, 0) point at B. Which makes tan(6/-3) and intercetps at 9 on Y axis.
He tooks B as (0,0) and in the function Y=2x+9 he makes the sostitution x=-x, (as the x has to be negative in the graph) in order to find the Y required, and in this way it comes out Y=2(-x)+9
I don not get it the slop should be positive when apply in math.@@ashikrahman5370
Why the sositution should be x=-x. @@roccovigorelli2322
Great Explaination! This actually makes so much sense now:) Thank you!
Thanks Jeff!!! Your lessons that make me recall exactly when I was in Civil class sometime in 25 years ago. Appreciated Sir.
very good professor, thank you!
my question is why did you sir have to put a negative for x @ 14:11
hello did you manage to find the reason for this?
Can you add this video to your statics playlist also? I didn't know about this video and had to deal with more advanced problems like this in statics. is there a video with these diagrams but with back to back triangles (both max heights at the center) on a cantilevered beam? im having trouble once i get to the second triangle.
Thanks For Ur great effort Dr.Jeff , But I think it's quite enough to Find the moment and derive the equation to get the shear force directly or integrate the shear force to find the moment.
Thank you I’ve been looking for a solution for this kind of load for ages
Why i sub x=6 in the moment eq i get -4.5 not zero?
Awesome presentation. I like your humor. 😚
thank you for the lesson
Very clear explanation, thanks for this. Can we make a formula for the whole beam or only for the part we cut? I noticed in this example that when you try to enter a value of 6 for x you get weird numbers which don't add up. I am in particular curious about this because this problem has a linear load that stops in the middle and thus these are two different loads. I can imagine when the load continued to the end 1 equation is easier.
thank you for the lesson..the video helped me sooo much for my final exam
Can you please explain from where you got y=6/3(x)+9
I did not understand that one
I think, it should be like y=6/3(x)+ 3
Haha me too. If he found X from the A part, it would be easier to understand. Another video can help...
No it is correct. We are assuming the 9 is the y intercept of the equation of a line y=Mx+b. The reason it’s 6/3 is rise/run and the slope was made negative because it’s is going downward from the intercept. When you want to know if the slope is positive or negative follow the line from the intercept
If we were solving the top part of the triangle the intercept would be at 3 and the slope would be a positive 2x
Good work Dr Hanson
Interesting lecture.
Think so much from UN. OF Mosul
thank you sir !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Take me home :) :) :)
The load backpack is such a cute concept lol
I have a question: At 7:35, wouldn't the shear graph drop straight down 3 kN before becoming parabolic?
can someone explain on how or why did he put negative on the 2x ? I'm only confuse on that part. I've been reading the comments but I seem to still not get it.
me too bro, isnt the slope upwards
@@vikneshmaniam5618 Look at it like a coordinate system. On his diagram his origin is on the right side of the beam where By=14.25 points upward (14:04). The slope is indeed going up where y=2x+9. At the origin x=0, so y=9 which makes sense because the force distribution at that point is 9kN/m. The height at the other end of the beam lies on top of the negative x axis of the coordinate system (quadrant II). If the function f(x)=2x+9 and x is (-x) then y=-2x+9. I hope that makes sense
at 10:19 why is it fast and then slow ? It is flat and then goes down that would be slow then fast if I am not mistaken
never mind. I see why I am wrong. Its how it is accumulating load not the shape of the curve
אתה באמת מלך
Hi Jeff. Im confused about something. Why is the bending moment diagram sloping up instead of down after the 3 meter mark? I get the straight line from 0 to 3 (first half) but why curve the line upwards on the bending moment diagram?
Why is the equation 9-x^2?
The rectangle (9-2x^2) plus the triangle (x^2)
Might want to mention the limits for x where functions apply?
thank you for re uploading
According to the previous lesson (24), I use the semi parabolic area formula to calculate the x and I found x and M as 1.5625 and 14.8438, respectively. I think the semi parabolic area equation is not suitable for that kind of curve. (Please correct me if I'm wrong)
x=0.9495
m=13.173
equation of dist. force : -2X-3
Equ. of shear: 3.75-x^2-3X
Equ. of the moment: 11.25+3.75X-1.5X^2-(1/3)*X^3
#1 Professor
How do I know that I'm turning my diagram at a right point??
Just watch the direction of the arrows on the graph above the one you’re working on. Not sure if this answers your question…
how did he get the rise=6 and run=3??
he concentrated on the triangle,,,,,,,,for the triangle,the height is 9-3=6 and the breadth =3
love u man
Great example sir !!
A great one indeed 👍
absolutely and completely helpful (kowtow)
Nice teacher
How did the rise = 6? isn't it 9?
It went from 3 to 9, so the rise was 6.
at 14:00, how do you just switch the sign and figure out what x is... and it only gets more confusing from there. I mean, I passed calc 3 with an A and I’m not really getting this
x=0.9495
m=13.173
equation of dist. force : -2X-3
Equ. of shear: 3.75-x^2-3X
Equ. of the moment: 11.25+3.75X-1.5X^2-(1/3)*X^3
He used the right hand side of the drawing as the origin, so if you made a mirror image of the picture from the origin (so that x would be increasing from left to right), the slope would become negative. At least, that's how I reasoned it out.
@@sebastianfinn3028 thanks !
I had the same final results but with different x value
Now i see why , the both methods are correct but each one uses a different reference
Sir could you please make video on finding Shear force and Moment using heavy side notation or step function ? And with different types of distributed forces like UDL and UVL as well as support ?
Freshman humor 🙄
Thank you sir
Diagram moment go down.
dM(x)/dx should be V. in this case is -V. Am I wrong?
When I integrate V, I get -M, is that what you get too? -11.25? It should be +11.25, right?
Thank you !!!!!
when I tell you I got disappointed when you didn't call the 3.75kn force a van Halen force :)
Good
Who noticed that the video is coming up to 4K hhhhhhh nice!
why when i put 6 for the x in the moment equation it doesn't give me zero. what did i do wrong?
How to draw it by integration method
This where i am good about ... Not water.
thank youuuu
Can someone assist here please. When I integrate V, I get -M. Any idea what I did wrong?
Why doesn't the total area for the v diagram equal 0
Take me home to the place where shear equals zero. Now listen on Spotify :P
goat
It seems the shear diagram is incorrect if x=2.05 from B . It should be modified later on it gave me a lot of confusion.
for practice i decided to find x on the other side of the beam and i got 0.95 which is the same, so I believe it is correct
@@brucelee1048 I had that too!
Thanks
How to draw it by integration method