Convert Elements to Oxides

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  • Опубліковано 16 лис 2024

КОМЕНТАРІ • 10

  • @windowsstriker5612
    @windowsstriker5612 Рік тому

    Perfect,need this for thesis

  • @gustavomirandadiazgeologia6754
    @gustavomirandadiazgeologia6754 2 роки тому

    Thanks so much Keith, your video is really useful!

  • @karunakaran1969
    @karunakaran1969 Рік тому

    Hal, Nice explanation, i dont understand , where u got the first row value like sol , could expalin that row.

    • @keithputirka
      @keithputirka  Рік тому

      That's a renormalization on a volatile-free basis of estimates of the Solar photosphere composition ("Sol" for short"); I believe that particular composition is the "recommended" value from Lodders et al. (2009).

  • @alicanaktag1829
    @alicanaktag1829 2 роки тому

    Thank you so much for sharing Dr. Putirka. By the way, I guess the conversion factor of K seems to be a little bit problematic in the video.

    • @keithputirka
      @keithputirka  2 роки тому

      Thank you for that correction. I'll add a note to the description

  • @aminadz7890
    @aminadz7890 Рік тому

    Thank you, so useful ...
    But, how to convert oxides to atoms percentage?

    • @keithputirka
      @keithputirka  Рік тому

      In the conversion table that appears in in columns P to AA, you would use row 6 instead of row 5, so you would take oxides (which could be entered in columns B-L instead of elements) and multiply those oxides by the correction factors in row 6. Then be sure to edit the headers, so if you are performing the multiplication in columns Q to AA, then the header in cell Q9 becomes "Element, weight proportion" (instead of "Oxide, weight proportion"), and cell A9 wold be changed to "Oxide %".

    • @keithputirka
      @keithputirka  Рік тому

      Hi Amina - I later realized that this video says nothing about how to deal with Oxygen. I've recorded (and will soon post) a new video to illustrate the conversion of oxides to elements, and also how to deal with O, including some caveats for systems that are possibly very O-rich. Thank your for your question. And my apologies for not thinking it through earlier.

  • @karstgeo7290
    @karstgeo7290 2 роки тому

    Appreciate it!