🔴 TORQUE - Derivation || Rotational Motion - Part 02 || in HINDI
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- Опубліковано 29 січ 2018
- In this Physics video lecture in Hindi for class 11, class 12 and IIT JEE we derived the expression for torque. We found that torque is the cross product of position vector of the point where the force is being applied from the axis of rotation. Torque about the axis of rotation is the product of the force applied and the perpendicular distance of the point of application of the force from the axis. Initially, it seems that force is responsible for rotation of a body, but it is not true. Sometimes, esp. when force is applied through the axis of rotation, it does not produce any rotational motion but translational motion. So we needed to introduce a new term called torque.
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Arijit Daripa
EduPoint,
Dam Road,
Chandil,
Dist- Seraikela-Kharsawan,
Jharkhand,
India.
Literally yaar what a sir
Kya he samjhate hai ye kya he samjhatee hai
Aajj tak kitne iiten or famous academic teachers se padha hai
Par is sir ke baath he kuch or hai
This man deserve national award hats off
Best teacher I have seen ever
Lol
I love teachers who derive everything.. ❤️ and explain wonderful
Sir.. Physics mujhe sirf aapse hi samjhta hai
Sir aap intuition ke hero ho
King of concept
Sir your video is very hopeful for me..
Thanx a lot of you for making a video on this topic..
Sir your God of concepts. Amazing!!!!!!
Yeh sehi tarika he jo bhi achase samjho jaeogi . Etna sare video dekha basic to ehiper hen. Tq
Great explanation ! ... your explanation is always helpful 😊
Sir I like your teaching process.thank you.
I watched it second time for revision.
Your explanation ability is super sir.
Kya baat hai minde blowing
Sir I can't express my words thanx a lotttttt 👌👌👌👌👌👌👌👌👌
God of physics
Indian government should give you best teacher award sir.
Lol
Kuch bhi
Yes bro
Me also
Hum ache teacher ko Professor bulate hai 🎓🎓
to
Good morning Professor
All the concepts of rotational motion please .
You are doing great work . Keep going 👍 👍 👍
You are an amazing teacher 👌👌
Boss of basic Physics...take Love from Bangladesh 🇧🇩🇧🇩🇧🇩...Very helpful and concepts was totally awesome...
Sir your teaching process is awesome
Sir i love u me depressed hogya tha ye na samjj aane se
But after seeing ur vedio i got it
So thankful 🙏 sir
REALLY GREAT EXPLANATION SIR 😎😀
Thank you for lectures sir 😃😃
sir continue this chapter
Thank U sir
Nice video sir 🙏
Superb sir....👍👍👍👍
Thanks sir
Wow!
Thanks sir❤️
dear respected sir, can u please tell me difference between TORQUE,MOMENT and COUPLE.?
Torque(moment of a force) is produced by a single force applied at some distance from axis of rotation where as couple is a pair of equal and opposite forces applied at different points and distances from axis of rotation.
SUPER SE UPER
Very very good explanation 👍👍👍👍
Sir, if the vertical component of force is in the negative direction of x then how can we derive the torque equation?
You said in this video that it will be vigorous. But pls make a video on that.
Pls pls pls.
You can do that by yourself, just try once
@@KM-om1hm i tried but (xFy+ yFx) i got this equation of torque.i got positive in stead of negative.because Fx and dx are working on a same direction then it come positive
sir plz make a video on optical instruments of 'ray optics'.Thank you.
Hello Adil Parvez !
Yes ! Coming soon.
Please stay with us.
Very nice
Sir please make videos for class-11 waves
❤
Sir I am preparing for IIT-JAM so I am studying form point zero. What you thik this would be effective for
Me . I am in bsc-1 from Bihar. Please help
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thanks sir i like you from pakistan
Sir pls give lecture on board.
Sir plz dual nature and radiation pe video banaye....
JEE diya kya
So you just assumed without saying that the coordinate system that you're working with is a right handed system and "proved" that *T* = *r* *×* *F* ....
That is just outright misleading !
You can't prove that this direction is more meaningful than that direction.
All the directions are the same...
Take a left handed coordinate system and you would get *T* = *F* × *r* which is equally correct in that particular frame.
Very hard derivation
Sir, why is work done= F.S
F.S=F.(1/2)at². [taking u=0]
=F(1/2)(mat²)/m
=F(1/2)(Ft²)/m
=(1/2).(F²t²)/m
Work/Energy should depend upon magnitude of the Force applied and time until force is applied but according to W=F.s, energy we apply also depend upon the mass of body in which we apply energy,
If we apply same Force in same time in ball and if we apply same Force in same time in elephant, elephant gets more K.E. than ball.
Plz don't hit dislike because no-one can teach by this way
alpha beta ke equal kaise hua hai
Your shirt is really bad
Pagal lecture dekh