Spring-Mass-Damper System, 2DOF

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  • Опубліковано 24 гру 2024

КОМЕНТАРІ • 33

  • @antoniosantos6104
    @antoniosantos6104 15 днів тому

    Amazing video, I am currently studying for my final for a Dynamic Systems and Modeling class and was looking for extra practice. You videos are exactly what I was looking for!

  • @Are-you-mad-at-me
    @Are-you-mad-at-me 4 роки тому +11

    I was stuck on this concept and then i just went and compared class notes with your video and understood everything. Thank you so much.

  • @youham7066
    @youham7066 Рік тому +1

    Finally found a helpful and full steps video related to my coursework. I hope youtube can recommend more similar video like this 😁. Thanks for saving my time!!!

  • @marcusmaree5338
    @marcusmaree5338 2 роки тому +1

    This has been extremely helpful. Thank you very much!

  • @Final1Boss
    @Final1Boss 4 роки тому +3

    Thank you!! you should get a Nobel prize for your perfect teaching

  • @aidanstark5381
    @aidanstark5381 Рік тому

    Thank you very much! This video was extremely helpful in my studies.

  • @Jotaruiz30
    @Jotaruiz30 4 роки тому +2

    Muchas gracias por compartir, muy bien explicado y me sirvio para entender bien el tema.

  • @natursweg7815
    @natursweg7815 3 роки тому +1

    Thank you for this video! It was very clear and helpful!

  • @omarrefe460
    @omarrefe460 3 роки тому

    Thank you so much ... THANK YOU !!!

  • @우창-n9t
    @우창-n9t 5 років тому +1

    this video helped me a lot. Thank you

  • @cleternal
    @cleternal Рік тому

    good job! thanks a lot

  • @bowaleed3900
    @bowaleed3900 2 роки тому +4

    I think "C2" force must be flipped since it "Pulled by the ext. force" , as well as the forces itself should be opposite to each other , Newton 3rd Law

  • @aliakbas7387
    @aliakbas7387 Рік тому

    Sir, how can we demonstrate that if we chose C2 too large that system behaves as a single mass M=m1+m2?

  • @fikrimisnadi2374
    @fikrimisnadi2374 2 роки тому

    Do you have any example with external force

  • @diegomestrecam7674
    @diegomestrecam7674 4 роки тому

    Thanks! One question how would tf change if we also had a spring and damper between car 1 and 2 ?

    • @theryderproject5053
      @theryderproject5053  4 роки тому

      Yes if you have more springs it would change transfer function.

  • @behnazhadi7110
    @behnazhadi7110 Рік тому

    Thanks

  • @ridwanhusainishraq
    @ridwanhusainishraq 2 роки тому

    Dear Maam
    could you please make a video on transfer function of 2nd order differential equations involving friction coefficient on the floor?

  • @benguyldzzeyrek7388
    @benguyldzzeyrek7388 4 роки тому +1

    why do we write x1-x2

    • @theryderproject5053
      @theryderproject5053  4 роки тому

      I think it is the derivative of this (velocities) because that's the velocity that the damper is moving at - need to take the difference because both ends can move.

    • @benguyldzzeyrek7388
      @benguyldzzeyrek7388 4 роки тому

      @@theryderproject5053 so can we write x2-x1 in the same manner

    • @theryderproject5053
      @theryderproject5053  4 роки тому

      @@benguyldzzeyrek7388 The direction matters. Try rewatch from around 1.45. I've assumed that m1 is going to move to the right so the force is directed back to the left. This makes the order for the force x1dot-x2dot.

    • @theryderproject5053
      @theryderproject5053  4 роки тому

      Also watch from 11.15 for a method to double check whether you've got the signs right.

    • @benguyldzzeyrek7388
      @benguyldzzeyrek7388 4 роки тому

      @@theryderproject5053 okay thank you so much

  • @devilal8388
    @devilal8388 3 роки тому

    Hello mam
    Does this 2 DOF system will vibrate or not
    Like displacement is periodic function of time in this case
    Please tell me

    • @theryderproject5053
      @theryderproject5053  3 роки тому +1

      How it will vibrate is going to depend on the type of force input and the values associated with the components. This is demonstrated in some later videos in the vibration and control playlist.

  • @abdullatifaydn6681
    @abdullatifaydn6681 5 років тому +2

    the left side of the equation must also be positive because they are in opposite directions...(+)kx + (+)cx + (+)c(x-x) =mx ....this correct

    • @TheNightDevilX
      @TheNightDevilX 4 роки тому +1

      No, because left side is summing all forces, negative and positive, and right side is just m*a, or m*x in this case in positive x direction.

    • @Final1Boss
      @Final1Boss 4 роки тому +2

      it's correct in the video, it could either be -kx1 -c1x'1 -c2(x'2-x'1) = m1x1" or -kx1 -c1x'1 +c2(x'1-x'2) = m1x1"

  • @danielmj4773
    @danielmj4773 6 років тому

    But why dont we use x1 to find the transfer function

    • @theryderproject5053
      @theryderproject5053  6 років тому +1

      Only because the original question asked for the transfer function X_2/F. If you were asked for X_1/F then you would solve for it using Cramer's rule.

    • @danielmj4773
      @danielmj4773 6 років тому +1

      @@theryderproject5053 oh . On thank you. This video has been a huge help