A Set is Closed if and only if it contains all of it's Limit Points

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  • Опубліковано 18 гру 2024

КОМЕНТАРІ • 18

  • @technofanatic01
    @technofanatic01 3 роки тому +10

    You're my hero. It's been very difficult finding help in analysis and topology

  • @DanielPerezMunoz-mf3iz
    @DanielPerezMunoz-mf3iz 25 днів тому

    Great, I understood everything, I must accept that the first direction of the proof was not so clear, but with time I got it. And the reciprocal was easy for me, God bless you Gandalf jajaja

  • @algorithmo134
    @algorithmo134 3 роки тому

    Hey, The Math Sorcerer I have a question. At (2:10), you wrote there exist x is not in A, s.t x is a limit point. x is a limit point of what?
    Do you mean limit point of A?

  • @prity9644
    @prity9644 3 роки тому +1

    It's very helpful 🇮🇳🙏

  • @francineochoaf.160
    @francineochoaf.160 4 роки тому +2

    Thank you so much!!!! you helped me a lot

  • @dubble.
    @dubble. 2 роки тому

    It's weird, never seen anyone do any concrete examples of this, they just go through the proof. Could you please do an example? For example for the subset {(x, y) in R^2 | x^2+xy+y^2 = 4}.

  • @fvs3189
    @fvs3189 4 роки тому +1

    hey! im just starting my studies in basic topology (with baby rudin). and i cant visualize what is a limit point. Do you have any intuitive way of understanding this concept? thanks

    • @bgbd182
      @bgbd182 4 роки тому

      I think of a *limit point of a set A* as a point that is "really REALLY close" to the set A; for example, in the case of a metric space, say X, you'd have that a limit point x of the subset A of X follows that d(x,A)=0 ("the distance of x to A" is the smallest possible). Remember that "the distance of a point y in X to the subset B of X" is d(y,B):=inf{d(y,z) : z is in B}

  • @David-m4v8y
    @David-m4v8y 3 роки тому

    Could you possibly make a video on how to formally prove that the set given by U = [0, 1) ∪ [2, 3] is not compact. Thanks in advance.

  • @lukaliu3422
    @lukaliu3422 3 роки тому

    It’s very helpful!

  • @shirleymoon9934
    @shirleymoon9934 Рік тому

    Im studying limit point of an interval, this method also seems applicable when it comes to an interval (the proof given by my tutor was too complicated

  • @nadaabdulla7556
    @nadaabdulla7556 4 роки тому +1

    I don't get the definition of the limit point!

  • @OleJoe
    @OleJoe 4 роки тому +4

    I remember a related concept of "adherent points". A set is closed iff it contains all its adherent points. The proof is almost the same.
    I think the only real difference is when it comes to the singleton set, {x}.

    • @TheMathSorcerer
      @TheMathSorcerer  4 роки тому +2

      yeah!! adherent points are points in the closure, very very similar definition, almost the same but they are not:)

    • @OleJoe
      @OleJoe 4 роки тому +3

      @@TheMathSorcerer One thing that was frustrating for me as a student was when I went to the library to get a supplimental explanation for a concept that I was having trouble understanding from the lectures and the textbook, I found that other authors would give "equlivant" definitions of the same concepts. What was a definition in our textbook was a theorem in the library book and vice versa. A => B => C => A. We go around in a circle. Pick your definition, A, B, or C. Then prove the other two.

    • @TheMathSorcerer
      @TheMathSorcerer  4 роки тому +3

      @@OleJoe omg yes!!!!!!!! I totally agree this happens so much especially in proof based mathematics. It's constant and it is unfortunate. I remember this happening with my definition of limsup and liminf, ahh so many different definitions:)