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so basically we have something called difference of squares when you factorize it you will have the same base but one in positive and the other in negative and in the question they already told us that a plus b is 2 so he replaced it and you can divide by two and then it'll be 16 divided by 2 which is 8 i hope this is clear
problem 16 you are really confusing. It's is very simple: three cases, a=2, a=4 or a=16. For x =2 then b = 16, (16/4= 4 and 2*4=16) . For a=4 then b= 8 (8/4 = 2 and 4^2=16) and finally for a=16 then b=4 (4/4 =1 and 16^1 = 16). So b can be 16, 8 or 4
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You might also like:
SAT Strategies: ua-cam.com/video/CTLl6-wwrBU/v-deo.html ua-cam.com/video/_Jc5ZPZhTgE/v-deo.html
Full SAT Practice Test Section: ua-cam.com/video/TT2KOQLqb0I/v-deo.html
Wonderful. I subscribed alrwady!!🎉
Excellent pedagog
Grateful for your videos
i’m glad they are helpful for you
Thank you
i’m glad it was helpful
Hello, on 9:44 you factored a squared- b squared into (A+B)(A-B)=16, could you please walk me through how you did that? Thanks alot 😄
so basically we have something called difference of squares when you factorize it you will have the same base but one in positive and the other in negative and in the question they already told us that a plus b is 2 so he replaced it and you can divide by two and then it'll be 16 divided by 2 which is 8 i hope this is clear
On 7… once you get to a^2 -b^2 =16,
Wouldn’t that be 5 and 3?
5^2 -3^2 = 16
And 5-3=2.
problem 16 you are really confusing. It's is very simple: three cases, a=2, a=4 or a=16. For x =2 then b = 16, (16/4= 4 and 2*4=16) . For a=4 then b= 8 (8/4 = 2 and 4^2=16) and finally for a=16 then b=4 (4/4 =1 and 16^1 = 16). So b can be 16, 8 or 4
For 14, why wouldn't 2/2=1?
you can’t cancel the 2s because they are being raised to different powers - if they were being multiplied by something then you could cancel them
16 if you can use easier way
thank you