Divisibility Rules 4 || Number Systems || Quantitative Aptitude || CAT Preparation 2024
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- Опубліковано 16 жов 2024
- Number System by Ravi Prakash | Quantitative Aptitude for CAT 2024
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Best wishes to u sir...free coaching for CAT...Forget other coaching classes..
Next Anand Kumar of india 🤗RAVI PRAKASH❤️
No ,he is 1st Ravi Prakash of India
Everyone have their own unique identify for which they are known.
Never merged one's identity with another
Hey can u address me where I can find the quizzes??
@@rajdebnath9681 if u somehow find it pls share here also
@@zoro3188 at the end, he said he will discuss the peculiar case of 11 and 9... where is that video?
@@HelloMahimaShetty unacademy plus course mein
Thanks alot sir for providing the complete course for free....
explain -10^3 =r=-1 so first starting should be negative right--why +1 starting..why
Rightmost is -1 indeed...but as 600 is an even term...it doesn't matter...it's just a lucky mistake@@Anandappus-cq9mu
@@Anandappus-cq9mu Cause 1st 3 digits don't have 10^3. It is like 1 divided by 33 or 11. So it is just 1 ( 10^0, 10^1, 10^2)
Those who didn't get the concept, please watch the remainders lectures first. It will take you hardly 8 hours to get hold of all those.
is this the least class of divisibility rules?
8 hours feels exaggerated, the concept videos are of around 240 min in total explained in a very simple manner tbh. Shouldnt take that long imo. Even lesser if you watch it on a faster speed
@@owaowa8442 Yea, on 2x speed it'll take max 3 hours
Rightmost is always 1 and groups of three is great concept!
Thankyou somuch for such amazing explanations sir . I could not stop myself from commenting here n admiring you .you are great sir 👍
explain -10^3 =r=-1 so first starting should be negative right--why +1 starting..why
Odd power gives us remainder -1 and even power gives us +1 always and most of series starts with 1 so sir ne jaldi jaldi bol Diya ki starting is always-1 and ending is always with +1@@Anandappus-cq9mu
@@gungunjain2623 but doesn't that make the answer also wrong if it should be done from right to left and sir is doing it from left to right (-1 and then +1)
@@ZecTox left to right isliye bola kyoki jab group divide hoge to vo right side se ni hoge only left se hi start hoge and agar end m kuch adjustment aya or or + - ko interchange kiya to galat ho jayega question
Please provide the link for the peculiar case of 9 and 11 you mentioned at the end of video.
pls response
Bhai you can used 9 in form of 3 square . Seen in lecture of divisibity rule 1 there were a question of 3 and also 11
11:14 question asked in Upsc Csat 2023 ...just like similar pattern ..thanks to rodha sir with in a second you will get the answer
Where is the video for "peculiar case of 11 & 9" sir?
sir the separate video for 11 is missing
First question can also be solved by
taking [(sum of even numbers between 300 to 400) - (sum of odd numbers between 300 to 400)]
which = [(17550) - (17500)] = 50
And then 50/13 remainder 11.
❤️❤️
17550 ? How
@@36_parthshrimali84 calculate the sum of even between 300to400
Thank u so much for this reply 😍😍😍😘.I was confused in this question.
@@tamannatanwar575 how it is calculated I got ans as 17150
Sir , we students completely following u and completely depended on u....
Sir plzx make sure that ur course is enough for cat exam.... I mean to get in some of best B schools
Are you preparing for CAT'21?
@@sjsthomasnick3002 is this helpful? please say yes.
Yes
@@amritapatjoshi6695
Sir for 11 if we divide 100/11=1 .So we get 1 as remainder . So sir why 1000/11=-1 is taken and a group of 3 is made . Why a group of 2 is not made.???
sir, how could we solve for remainder when multiples are involved, for eg, 3^100 divided by 21 for remainder
How is answer 13 ? when you subs y=4 in 7x+6=3y+1 , you get x=1 ??
Where's the peculiar case videos as he mentioned in the end?
If anyone knows about it please respond
did u find the video for it?
@@AkankshaSonaje-w4z nope
Heartly Thank you for providing this much knowledge as free price, you are such a great sir...
Thank you soo much sir for providing , complete course for free...... And its amazing explanation ... Thank you for every video .. 🙏
explain -10^3 =r=-1 so first starting should be negative right--why +1 starting..why
@@Anandappus-cq9muwatch the first video of divisibility rule, very carefully.
God of cat prep
For 11 why not make group of 2, because after dividing 100 with 11, we get reminder +1
19:00 75x(-9) /101 if do manually i am getting remainder 69.
75x-9 = -675/101 remainder = 69. How 32 came can anyone explain?
-675/101= -69
Remainder can't be minus therefore 101-69= 32
-675/101 = -69 => 101-69 = 32.... Watch the Remainders video first or you wont get it. When the remainder you get is negative and there is no way to get a positive remainder, you have to add the new found remainder with the divisor, which in this case is 101.
@@suryansh0075 No, it can be, as per our convenience. that is why negative remainder concept exists.
@@suryansh0075 you can leave it as it is and no problems will happen. The thing is you won't get that in the exam options.
In last question 5647 till 300 digit... First Vala negative ku ni Liya gya Hai? 10^2 gives - 1 remainder... If anyone knows pls reply.. 19:28
Sir actually 5:09 there are 100 numbers in between 301 and 400 400-301+1 =100 including 301
just mind blowing
When 1234567.......9899 is divide by 99 then find remainder.
Can anyone help me with this!?
7x+6=3y+1 is solved by hit and trial method as when you put x=1 you will get y=4 and by this way you are getting 13on both the side.
Go through all the remainders' videos
sir can i solve ssc cgl quant question with these cat quant series please reply
At the end of the lecture you said we'll discuss peculiar questions of 11 and 9...which lecture is that sir?
Exactly where is that video
Guess thats in remainders video
If anyone find it, then please drop the link here.....
Where can i practice more questions?
Thank you so much Ravi sir
Preparing for upsc csat
In 56745674............ 300 digits wala. Question i am getting 69 as remainder from solving 47*75-56*75/101
Actually that is the negative remainder bcoz it comes out to be 3525-4200/101 i.e -675/101 R=-69 and the alternate positive remainder comes out to be 32 that is 101-69=32
what about the number when divided by 5,15 or 25 ?
Thanks a lot sir❤
Sir 301302...400 in that que 400 is also not divisible by 3 then why u havenot divided it accordingly
Thank you sir.........................
In the first question, won't we have 312 where the remainder = 0. What will happen in those cases where we have multiples of 13 ?
Sir in first'question 400/13 ,how the remainder is 1??
How you solved the 5647 multiply 75 divide by 101
We have ( 5647 × 75 ) / 101
Since 101×56 = 5656
5656-5647 = neg. Remainder 9 ( -9 )
Similarly when u divide 75 by 101 we will get neg. Remainder of -26
-9 × -26 = 234 / 101 leaves 32 remainder
Alternately.. you can solve by taking positive remainders
We have (5647 × 75 ) / 101
5647 ÷ 101 -> Quotient = 55 , Remainder= 92
75 ÷ 101 -> Quotient = 0 , Remainder= 75
( 92 × 75 ) / 101
This also gives remainder - 32 ( this method will taker longer time to calculate)
5:00 14:00 20:00 24:00
At 5:00 how exactly did sir get 50? I used sum of n numbers in AP to eventually get the same answer but I'd like to know how he was able to get it directly
brother he made 2 groups from last which consist of 6 digits, which means 300/6 = 50
thank you so much for this content.
5555...wala problem... can't we just do 55/21 it gives 13 too.... to justify... 55555....602 digits/21 is 5555.....602digits/7 *1/3 ......so..55/7 *1/3 is 55/21 ...so answer..13
how is this related to divisibility rules
all we are learning is remainders only
If any number is completely divisible then there will be zero remainder and if it's not completely divisible then there will some remainder left.
Thank you sir very much for free course
Sir please tell me at what power of 10 when divided by 21 leaves +1 or -1 as remainder
10 power 1 only
@Bhuwan Pandey 4359 Haan bhai 10⁰ pr Remainder+1 aata hai
10 power 3 =-1
Time stamp: 6:58
It should be -50 na? The remainder would differ in that case. Please clarify this sir
It should be 50 only.
400-399 + 398-397 + 396+395 +..................+ 304-303 + 302-301.
So it's giving the answer-
1+1+1+1+1+.......till 50 times.
So the answer will be 50.
Hope you got it now.
It also gives -1for 50 times what about that
When we multiply, 55555.....602 digits, to 602, shouldn't it be multiplied by 301 instead?
No, the sum of digits means adding 5 - 602 times only thus 5*602 is right
Sir in Question "5647" question, if 10^4/101 is giving the remainder +1 and this is true for 10^4k/101, then why 10^2k/101 is not following this pattern?
10^2/ 101 will give a remainder of -1, so when you square it,i.e it becomes 10^4, now the remainder becomes +1. so 10^2k will always give a negative remainder if the k is an odd number. and it will always return a positive remainder if k is an even number. say 10^6 will leave a remainder of -1 , and say 10^8 will leave 1 as remainder. Remember every multiple of 4 is a multiple of 2 but every multiple of 2 is not necessarily a multiple of 4.
I'll tell you the best way to solve this question. 10^4 will give a remainder of 1 everytime . so you break 56475647.... in groups of 4 , since there are 300 digits and 300 is perfectly divisible by 4, you can have (75*5647)/101. it looks complicated but it's not.
@@chaitanyathyagi7360 answer coming 37 from your method
@@chaitanyathyagi7360 and by solving 47*75-56*75/101 ii am getting 69 answer
@@ayushbhargava1062 you are getting -69.
Add this: 101-69 = 32.... Watch the Remainders video first or you wont get it. When the remainder you get is negative and there is no way to get a positive remainder, you have to add the new found remainder with the divisor, which in this case is 101.
in 5555.. /21 question ,after getting remainders(1 and 6) in cases of 3 and 7,did sir explain why 7x+6=3y+1 will give remainder, or do I just accept thats how theorem works?
You need to watch the remainder videos first and then see the divisibility rules video , then you will understand the whole thing
can any one explain -10^3 =r=-1 so first starting should be negative right--why +1 starting..why
Bcz in 1st 3 digits 10^0 is common which gives remainder +1 ..
sir what is cheinese Remainder theorem
Watch remainders videos
anyone tell the concept of 26×9 please and 5656 and if we divide 675/9 then why the answer is 32 is not possible.
It can be as 675 will be negative = -675/101 so remainder will be -69 so now for positive answer 101-69 answer is 32
when using divisibility for 21 we are using 7 for divisibility why cant we do for 3 ?
7 & 3 both
Sir 1000/21 gives us remainder as 13 not +1 or -1
sir if we use 10^6/21 = +1 in place of chinese remainder theorem .......... in question for 555555....602 digit/21............we got remainder 2 instead of 13 ? can u explain sir.
10^6/21= -1… you’ll get the correct answer
In the first problem how come there 300 digits?? At the end it’s given 400 digits
explain -10^3 =r=-1 so first starting should be negative right--why +1 starting..why
Why not 101 split into 3x 37? Will I get same answer
How 101 is 37*3 ????
How did you get -26 ?
75/101...
Remainder would be (-26).
Got it?
@@jainamhemanee1125 but I get it as 43 and when I again divided it I got 26
@@jainamhemanee1125 also when we directly do it we will get it as 625/101 r= 19
@@jainamhemanee1125 is there any procedure on taking reminder
@@jisartjolly714
It's 675. When 75*(47-56) = 75 * (-9) = -675/101 = -69 => 101-69 = 32.... Watch the Remainders video first or you wont get it. When the remainder you get is negative and there is no way to get a positive remainder, you have to add the new found remainder with the divisor, which in this case is 101.
what to do in case the number of digits is a prime number ? and also for eg 987987..upto 123 digits divided by 101 ? this one
in 5555.. /21 question ,after getting remainders(1 and 6) in cases of 3 and 7,did sir explain why 7x+6=3y+1 will give remainder, or do I just accept thats how theorem works?
@@dhruv20 watch the Remainders concepts video for the explanation to your answer, there he has explained the logic of Chinese Remainder theorem which is used here
Riya watch the previous video question 345345... (200 digits) - that’ll help you as to how to deal if the number of digits in the question is not exactly divisible in pairs
I hope that’ll answer both your questions
Remainder is 78, that's what I'm getting
And also -23 both are possible..
great video bro
I am not understanding that who we will traces the last number for starting number the form of +1 or -1
Please help 😭😭
Remember that first number is always +1 and followed by -1+1and so on and if dividend is smaller then divisors then it will always be negative
+1 start me hoga
Last agar even pair hoge to +1 odd hoge to -1
Thanks from heart
Can anyone explain why in the last question, in the first method, when we are making two digit groups its alternatively remainder +1 and -1. But in second method for the group of 4 digits, all of them are +1. Please can anyone help 🙏
if you divide 100 by 101 you will get a reminder of -1 and as sir said in previous lecture if the reminder is -1 then it will be -1 alternatively e.g. 10^2 =-1, next 10^2 = +1( to understand why it is so, you should refer lecture 1)........now if you divide 10000 by 101 you will get a reminder of +1 so all pairs of 10^4 will be giving +1 as reminder
@@princegoud7844 thank you!
@@priabhavnahey nigga have u got into iim?
Happy teacher's day sir ❤️
in 5555.. /21 question ,after getting remainders(1 and 6) in cases of 3 and 7,did sir explain why 7x+6=3y+1 will give remainder, or do I just accept thats how theorem works?
@@dhruv20 watch reminders first before starting divisibility rules
Why did you divide 5647 and 75 separately
because when we divide 300/4 (taken terms ) it will give us 75 and R=+1
Where is Chinese Remainder theorem?
Remainders
@@Rodha sir where are the videos regarding peculiar cases of 11 and 9?
(Q). 555....602 digits
I couldn't able to understand concept of x=0 and y= not an integer and x=1 and y=4. How they yeild 13 as answer pls explain sir.
It's just hit and trail method as they have already said you have to find any one value of X or Y, by finding this you will be able to get the answer of 7X + 6 or 3Y + 1
And your final result after putting value of x or y or both, will be the answer of the question.
So 13 is the final answer of the problem.
@@anilbhai1652 (5×602)/21= (14×5)/21=70/21 /7
Aise krne se 7 answer aa rha h ..ye glt h kya???
where is Chinese remainder theorem explained?
In remainders
shivam kamat (13)
7-8-2021
thank you sir 🙏
Thank you Sir 🙏
can someone explain the first problem
why is 10^3/13=-1
why is he taking powers of 10
as 1001 factor is 13 ,11, 7 so 1000/1001 gives rem as - 1 so 1001 which is a multiple of 13 will also give rem as 1.(13*77=1001)
You need to see the previous video which is divisibility rules and remainder 4 , you will get to know about this rule
please anyone can help me in last que method 1
What a lecture sir❣️❣️♥️
in 5555.. /21 question ,after getting remainders(1 and 6) in cases of 3 and 7,did sir explain why 7x+6=3y+1 will give remainder, or do I just accept thats how theorem works?
Hi, sir. I believe the divisibility for '11 ' should be calculated digits-wise and not in sets of three like 7 or 13. You explained about this in the "Divisibility 1 video" as well.
I think it would purely depend upon the question, to say which method is the best.
Amazing sir.
I couldn't understand 7X+6 = 3Y+1 thing. Plz explain it sir:(
watch videos on remainder later in this playlist
Same doubt how it's 13
sir tussi god ho
Thank you so much sir.❤❤
in 5555.. /21 question ,after getting remainders(1 and 6) in cases of 3 and 7,did sir explain why 7x+6=3y+1 will give remainder, or do I just accept thats how theorem works?
thank you sir!!!!!
explain -10^3 =r=-1 so first starting should be negative right--why +1 starting..why
Sir in que 301302303-----------400 at last how 50/11 comes that's I don't understand pls tell me sir pls pls
if you understood plzz explain
The question is changed to divisiblty by 11 and for 11 also 10^3 / 11 is -1 and also it comes as sum of digits frm last at odd places minus at even places so it becomes 50 same as with 13 and therfire bcmes 50/11
in 3 3 grops which is plus and minus subsequently that group u add one to another like
400-399=1
398-397=1
..
.
302-301=1
that one is 50 times so u can get
50*1=50
SIR YOU ARE GOAT
Unable to get it. :(
explain -10^3 =r=-1 so first starting should be negative right--why +1 starting..why
what is the remainder when 123456123456... (300 digits) divided by 101 can anyone help me with this ?
It is completely divisible by 101, so 0 remainder will come. Pls correct me if I'm wrong 😄😄
I think it's 84
Sir you are great
Can anyone help with the concept of-9 and -26 for the last question
Divide 5647 by 101
positive reminder is 92
Negative reminder is -9(101-92)
Same with 26(negative remainder)
Please someone tell me how 75 came ?
Thank you sir ❤️
4:38 sir 50 kaha se aaya?
Every Time 1-1 Will Be Add
raviprakash sir ki JAI :-)
Thanks u sir
Can someone explain me the 5555_______602digits/21 wala question?
watch remainder theorem video first than you will get this!
How to find value of X and y?
take x=1 and u can get y value
Using Chinese rem theoram
Watch linear equtions video.
watch remainders videos later in playlist
tysm
Please explain the last question again sir
explain -10^3 =r=-1 so first starting should be negative right--why +1 starting..why
13:50 where the hell this 13 come from
Put the value of x/y in the equation... like 7(1)+6=13
thankyou
Is this the last lecture of divisibility?
there are more questions in practice session of Numbers
Sir can you pls analyse the IPMAT exam and make videos for them as well? I'm finding these videos a lot difficult.
Bhai kya ye sara jo Ravi sir padha rhe hai wo sb important hai IPMAT ke liye, mtlb pura padhu inka ki kuch kuch jo bhut hard hai usse chod skta hu
2:12 Why will the last number be treated as +1 and not -1 ?
Take 10 power 0 common
10power 0 =1
So 1/x reminder is 1
@@immandisriharsha1800 Tu toh studd hai re!!!
10
Can anyone please clear my doubt ?.
If anyone watching this comment please do reply
Yes
@@rikky6769 hii
@@jaseelt3635 Tell me your doubt
@@jaseelt3635 Tell me any doubt
😍