This is a pretty different type of video from anything that I've done before, but I hope it's still good regardless. Reddit thread: / need_help_on_this_nich...
My solution without watching the video: Since the quadrilateral is cyclic, angle ADC is 120 degrees. Solve for AC using Law of Cosines on ABC: obtain AC=sqrt(21). Then solve for AD using Law of Cosines on ACD. The math works out nicely and we obtain AD=1. Using the triangle area formula (1/2)ab*sin(theta), we can compute the area of each triangle individually. They have areas 5*sqrt(3) and sqrt(3), which adds to 6*sqrt(3) for the total area. Seems too tough for a classroom setting, but it's not a hard problem at the competitive math level.
If you're willing to attempt a weirder problem, try that one math problem from season 2 of Assassination Classroom. The solution is explained in the anime, but very poorly, so you might also have to do some searching around for that one.
Good question. I’m not really sure what the problem is saying to do, to be honest. The Crunchyroll sub says “Break the formula into two” for the instructions, but that seems like a lazy translation to me. I guess you could factor out a 7 from each term, resulting in 7((2/7)x + (3/7)a), but I don’t see any practical purpose for doing that. Unfortunately, I can’t read Japanese, so I can’t get any further clarification from the paper itself.
My solution without watching the video:
Since the quadrilateral is cyclic, angle ADC is 120 degrees.
Solve for AC using Law of Cosines on ABC: obtain AC=sqrt(21). Then solve for AD using Law of Cosines on ACD. The math works out nicely and we obtain AD=1. Using the triangle area formula (1/2)ab*sin(theta), we can compute the area of each triangle individually. They have areas 5*sqrt(3) and sqrt(3), which adds to 6*sqrt(3) for the total area.
Seems too tough for a classroom setting, but it's not a hard problem at the competitive math level.
If you're willing to attempt a weirder problem, try that one math problem from season 2 of Assassination Classroom. The solution is explained in the anime, but very poorly, so you might also have to do some searching around for that one.
anime problems require real life solutions
Wow amazing👍
in the same episode, yuuko had a printout probelm that was 2x+3a=7() whats the answer?
Good question. I’m not really sure what the problem is saying to do, to be honest. The Crunchyroll sub says “Break the formula into two” for the instructions, but that seems like a lazy translation to me. I guess you could factor out a 7 from each term, resulting in 7((2/7)x + (3/7)a), but I don’t see any practical purpose for doing that. Unfortunately, I can’t read Japanese, so I can’t get any further clarification from the paper itself.