Excellent video series Sir! Would you be so kind to clarify a couple of things? 1) let’s assume Arrhenius law applies on a specific performance of my product. Can I say that Arrhenius law states I can reach a specific value of that performance (not necessarily a failure. For example a value of a retention force) with a variety temperature-time values obeying the Arrhenius equation? 2) let’s suppose now that in an accelerated test I reach the performance level Pa after t1 days when operating at T1 and suppose we can reach the same level Pa after t2 days when operating at T2. The acceleration factor would be AF=t2/t1. If now in the accelerated test still at T1 a go on for a longer time t3>t1 until the performance reaches the value Pb, can I say that the same level Pb will be reached at T2 after t4=AF*t3 with AF being the same as before? Many thanks in advance for your answers.
Sir thanks for uploading this series. Very well researched and explained with good solved examples for ease of consumption. Can you apply this laws in TTS superposition of material
Thanks for your keen interest. The b value has to be determined experimentally. For example, you can use the Minitab procedure explained in the thrird video to find acceleration factor and then value of b can be calculated.
@@instituteofqualityandrelia7902 I would like your video to be subtitled in Spanish. Because I understand that in my language, there is not much information about ALT ...
Very useful subject on ALT sir. Thank you.
Most welcome Prabhakar!
Sir thanks for uploading this series. Very well researched and explained with good solved examples for ease of consumption.
I am glad to know!
Thank you for the video sir.. Very well explained
You are most welcome
This is a Brilliant series. Thank you
Thank you!
Excellent video series Sir! Would you be so kind to clarify a couple of things? 1) let’s assume Arrhenius law applies on a specific performance of my product. Can I say that Arrhenius law states I can reach a specific value of that performance (not necessarily a failure. For example a value of a retention force) with a variety temperature-time values obeying the Arrhenius equation? 2) let’s suppose now that in an accelerated test I reach the performance level Pa after t1 days when operating at T1 and suppose we can reach the same level Pa after t2 days when operating at T2. The acceleration factor would be AF=t2/t1. If now in the accelerated test still at T1 a go on for a longer time t3>t1 until the performance reaches the value Pb, can I say that the same level Pb will be reached at T2 after t4=AF*t3 with AF being the same as before? Many thanks in advance for your answers.
Hello Marco, thank you. Unfortunately I am unable to understand your question. Apologise.
Sir thanks for uploading this series. Very well researched and explained with good solved examples for ease of consumption. Can you apply this laws in TTS superposition of material
Hello. Sorry I missed your message. I did not understand your question.
Thank you Sir
Most welcome!
Thankyou for ALT video series sir. Can you please illustrate how to determine b value in power law?
Thanks for your keen interest. The b value has to be determined experimentally. For example, you can use the Minitab procedure explained in the thrird video to find acceleration factor and then value of b can be calculated.
10:52 where did you put voltage 125V?
Thanks. That is just for example.
@@instituteofqualityandrelia7902 Is it true that the equation should have been R(120) and the answer 0.353?
Excellent video, but I could put subtitles in Spanish and French, Thank you.
I do not understand. Do u want to add?
@@instituteofqualityandrelia7902 I would like your video to be subtitled in Spanish.
Because I understand that in my language, there is not much information about ALT ...
@@renzo.carita Ok. I will try to do it. Appreciate your keen interest!
Thank you Sir. How to find activation energy and b if not known
Hello Balaji,
Thanks for your keen interest.
I will try to reply as soon as possible.
Hemant
Temperature in K is always without degree
Ok. Thanks for enlightening.