PYQs on Uniform Continuous | CSIR NET 2011 to 2023 | Short Cut Tricks

[@nishajyoti5896]

Your lecture series is make us strong to fight any exam within suitable time

[@subratpradhan3581]

One correction on the DEC 2023 question :
on 52:30 h(x) = x² is not uniform continuous on
[0, ∞) hence the 4th option will be discarded. Sir, himself has mentioned it's not UC on the next question.
Its not UC because we have two sequences aₙ=√(n+1) and bₙ= √n on [0,∞) such that |aₙ - bₙ|---> 0 as n--->∞ but |f(aₙ) - f(bₙ)|---> 1

[@Zeelkumar31]

U r right 4 th option is not correct..!!

[@knowledgefactory33]

Sir your approach to Csir net Questions is Always Unique...
❤❤❤

[@aishwaryasaini7196]

Thank you sir for providing this lecture

[@aslicodes9736]

great lecture with very useful shortcut methods, thank you sir

[@rakeshkolisetty3746]

Very useful and understandable sir. Thank you so much sir. I have not qualified NET since 4times next time. Your lectures are so helpful and i have to attempt this December

[@garimakashyap3689]

Thank you so much 🙏 dear respected sir 🙏💖

[@NeelamRani_Mathematics]

Very help full lecture for preparing net, I shared it among my students preparing net . thanks sir

[@imkunalkapoor]

Thank you so much sir this is too much helpful and exam so near thanks again

[@mathematics2279]

Thank you so much sir ❤ you solve csir question like board exam questions you have great skills to solve problems and you teach us for free . thanks again ❤

[@celinfionaj4696]

Sir my another request, can you solve csir problems on singularity topic in complex analysis with short cuts. After completing differentiability topic in real analysis , as these series are very useful for our last minute preparation for csir exam.

[@Justyourkaran]

Its my humble request to all the aspirants to kindly like the video too it would take just 2 seconds, but it would benefit the reach of this video thru YT algorithm.
PS: despite 4.2k views only 200 something likes is non-reciprocation of sir's efforts!!

[@subratpradhan3581]

THANKS YOU SIR FOR THE LECTURE IN UNIFORM CONTINUITY 🙏🙏

[@deepikasharma4486]

I must say your analysis is so strong 🙌

[@pusplatasahu5738]

Superb session.....❤

[@himanisingh3784]

Very. Very helpful❤❤❤❤

[@ishadevi2071]

Thnku so much sir its really helpful 😊

[@techmath8922]

I am really happy sir ... I understand all concepts easily

[@charitylyngdoh8912]

Thanks alot Sir

[@professorragavan9783]

Thank you sir ❤

[@kumardillip4505]

Your service for us will be remember for ever ❤❤

[@RanjangamingYT7477]

Thank you ❤

[@Justyourkaran]

Thankyou for this lecture Harish sir, with these videos we are able to analyse that csir is just repeating similar qns year after year. Your approach makes the csir look doable busting all the myths prevailing in Delhi based coachings.
PS: sound issue is still prevailing, kindly look into it. As this problem ruins the quality content that you're delivering in lecture.

[@divakarmaurya9599]

Differentiability ke baad complex analysis (bilinear transformation) ka topic Kara dijiye sir

[@chauhanpriyanka9871]

Thnaku sir apke video se ese lgta h jse csir easy h

[@mathematicslovers2888]

Sir your video lectures are very helpful

[@habibulislam5262]

very helpful👌

[@RanjangamingYT7477]

1:07:06 d option only correct

[@thejupiterplus]

Yes

[@sheemanitinsan7235]

Thank you for more supporting sir 🙏🏻♥️

[@sudhanshu8073]

Answer for the last Question -
a) is wrong because f and g are u.c so both are bounded.
b) is wrong from last two options we conclude that it may not be closed so may not be compact.

[@Rawat1108]

Thankyou sir. The session was awesome. I know you are proficient in this field. Sir please check it according to official answer key correct answers for the question (53:00) in 1,2 and 3, forth one is incorrect. Once again thank you.

[@RanjangamingYT7477]

25:05 sin and cos function always continuous at (0,2pi ) so why not Continuous 😢

[@vahisht1]

53:20 in this question it was asked that which of the following options implies that the function f is UC, it is not already given UC, which you told so :(

[@anshikathakur7085]

Thanks a lot sir ❤

[@deepikasharma4486]

4.4k watch n why you are guys not liking the vedios ? I don't think anyone can explain here on yt history even i went to dips their questions discussions was in the air they didnt wait cz they taught iitians n DU students who were already toppers I never gets why they take choching even after coming from institutions like that.
Well its humble request to all of you who are attending lectures series here to like the vedios n share too

[@rajkumarmanna3855]

Thank you so much sir ❤

[@suniljojo61]

34:46 plz check

[@kulsoomarashid4266]

50:05, last option doesn't seem correct because then f will also be uniformly continuous.

[@Hasnainmaths]

very helpful

[@ChandanKumar-dn9lz]

Charan sparsh Gurudev....

[@kulsoomarashid4266]

Thanks a lot sir

[@kulsoomarashid4266]

Last question, option b is also correct because if I is compact ( closed and bounded) then f and g are both bounded and hence fg is uniformly continuous

[@thejupiterplus]

No

[@professorragavan9783]

Sir I have a doubt in 44:42 ... According to your shortcut, in option c, f(g(x)) g(x) is uniform continuous, but f(x) is un bounded so f(gx) cannot be uniformly continuous.
How can I differentiate option 1 and 3?... Please clarify sir... Thankyou ❤

[@dhrubajotidas8276]

if that condition holds that only gurantees that..if it not then you can't say anything...apply derivative test

[@professorragavan9783]

@@dhrubajotidas8276 Ok thank you

[@nishajyoti5896]

Thank you sir

[@SanchitMehra-mf3rh]

Again thanks sir,

[@mdsalman7651]

Sir please make a video on Statistical Inference

[@ronneysaini7763]

Thanks Sir❤

[@kulsoomarashid4266]

1:03, f is uniformly continuous doesn't imply f satisfies lipchitz condition

[@atamohammad6167]

UC=> lip. But converse need not to be true

[@parthibanrajapalayam1865]

Converse is true only if derivative is bounded

[@goutamjana1292]

Sir please upload sequence and series of function pyq video

[@DrHarishGarg]

Already uploaded.... Check my lecture "Uniform Convergence"

[@DrHarishGarg]

ua-cam.com/video/Qi4cDKUCGmI/v-deo.html
This is the link

[@goutamjana1292]

Okk sir . Thank you sir 🙏🙏

[@rashmimalik9769]

🎉 thanks sir

[@mr.chauhan8644]

Thanku you sir❣️🚩

[@vahisht1]

52:00 Last option is incorrect as x^2 is not uc in R, its graph is parallel to Y axis

[@kulsoomarashid4266]

Ya I have the same confusion

[@animeshpramanik7862]

nice sir

[@subratpradhan3581]

For the last question, By Heine Borel theorem, I is not compact since option(d) is discarded.

[@marubahamad1236]

Thanks sir

[@anitakaushik-be8mo]

25:38 que ka ans shi lga kya sbko ...?? f(2π) ki value galat h ..mere hisab s to c option shi hona chahiye ...anyone correct me if m wrong

[@dhrubajotidas8276]

galat hya woh

[@RanjangamingYT7477]

Yes 👍

[@aishwaryasaini7196]

Kindly provide lecture on abstract algebra also.

[@ronneysaini7763]

Kitne bar bole.. Sit ka domain nahi hbye subject

[@shreya2262]

tysm

[@mathematics2279]

Sir tifr ke last two three years ke real and linear ke questions bhi krwa do if you have time tifr concept are repeate in csir I think . thanks ❤

[@professorragavan9783]

For the last question.
Option a
Since f,g are UC therefore both are bounded. So either f or g us bounded is wrong. So option a is wrong.
Option b
If we choose I as Real numbers then it is not compact. So option b is also wrong.
Is it right sir??...

[@dhrubajotidas8276]

real number is not an interval

[@Siyagupta52]

​@@dhrubajotidas8276 It is an interval

[@aamath]

Great 🙏 .. Some mistake I think in ques. Gate 2004?

[@amarguttevlogs6745]

Last question ans is option
A and C

[@king-by1kh]

Sir f(x) =x and g(x) =1 then clearly h(x) is Uniform continuous on R clearly R is not bounded so how option c is true only option 1 is true sir

[@dhrubajotidas8276]

given I is an interval

[@king-by1kh]

@@dhrubajotidas8276 R is also an interval (-infinity, infinity)

[@Pbt656]

(a, infinity) is also an interval

[@king-by1kh]

@@Pbt656 we have to discard the option so we take R other wise it always hold on finite interval

[@RanjangamingYT7477]

1:07:06 up ne question ko sahi se read nhi kiya 😢

[@kajalsoni6597]

A,b,c

[@nehasharma-zx5xi]

Sound quality sahi nhi h😬....

[@Ekshivbhakat]

B and c

[@sumathinagarajan1937]

ONLY ANSWER C IS CORRECT

[@kanchansharma1675]

🥀

[@divakarmaurya9599]

In last pyq it is not compact since not closed and option a is true b is false

[@king-by1kh]

How option c is true bro if f(x) =x and g(x) =1 then clearly h(x) is Uniform continous On R but R is not bounded so how it is correct

[@user-lo2qx8ow9e]

​@@king-by1kh Bro h is defined from I to R ...so we need to consider an interval in which f and g are u.c that's why interval must be bounded for h(x) to be u.c.

[@king-by1kh]

But it is not necessary because I is also consider as(-infinity, +infinity) f(x) =x is Uniform continuous on R but R=I is not bounded

[@celinjoseph-x4s]

Yes opt a is crt

[@king-by1kh]

I ask about option c brother

[@AnilTiwary-o4p]

Sir make video on NBHM pyq

[@sumathinagarajan1937]

ONLY ANSWE C IS CORRECT

[@ratanprajapatirp3529]

Thank you sir 🙏🙏

[@anuragpandey4912]

Thank you so much sir 🙏🏻🙏🏻🙏🏻

[@Manish-uq5le]

Thanks sir ❤

[@shravankamble4353]

Thank you Sir

[@kancharlaasritha9494]

Thank you sir

[@positivethoughts6419]

Thank you so much sir 😊

[@munishkumar9136]

thank you sir

[@rnithyaraj9498]

Thank you sir