you have 15 apples someone takes 8 how many apples do you now have? 15 - 8 = 7 still a positive amount, yes? so it's the same here~ 15 - 7 = 15 + (-7) = 8 I could've sworn someone asked this exact same question last year~ Please leave your comment live, many can benefit from it!! If you still have doubts, let me know I will help you~
with the right amount of follow ups gpt4 can do every single csec math question correctly (if it didn't get it right on the first try) so you can also work with it (in case you find I'm taking long to respond) I use copilot on the microsoft bing browser it uses chatgpt4 you can have an intelligent back n forth conversation with it it would be able to discuss with you any concerns you have about any of these questions~ I highly recommend it! you can ask it to solve a problem a different way and ask why it performed certain steps etc
yes I will explain, and thanks for using timestamps hehehe~ (n/100) x 40 = 8 (40n) / (100) = 8 multiply both sides by 100 40n = 800 divide both sides by 40 n = 800/40 = 80/4 = 20 the arrow just meant, by cross-multiplication the equation reduces to solving 40n = 800
another way to think about it is diagrammatically: if you drew 5 equal boxes and put 8 in each of them the total is 40 right? now what percentage of 40 equals 8? that'll just be one box right? 1 out of 5 is 20% if you needed to skip doing algebra, you could solve this problem that way~
@@TwixMix look at the 27 second mark here ua-cam.com/video/s9lFlmSHCGI/v-deo.html the question repeated on the most recent paper 1 that's how you solve it, that's how you work with fractions if one-fifth A = y, you multiply both sides by 5 to solve for A those are the operations to use to isolate a variable on one side of the equation what you do to one side of the equation, you have to do to the other to preserve the equal sign x + 5 = y you have to add both sides by -5 to preserve equality in this case we have to use multiplication to preserve equality to solve for n
Sir* I can email you the csec maths pdfs and you can answer them on paper and then compare solutions etc. csec.chemistry.paper1@gmail.com subject "maths paper 1s pdfs" I have about 40 past papers to send~
It's A. The answer in the video is correct. To find YZ(the opposite side) then youd have to do tangent which is opposite/adjacent. Were also given an angle of 30 degrees, meaning youd have do to 10 tan 30 Cosine is adj/hyp, but we dont have a hypotenuse value so that couldnt work
01-B 11-D 21-D 31-D 41-B 51-B
02-B 12-B 22-D 32-B 42-C 52-A
03-A 13-C 23-A 33-D 43-B 53-C
04-C 14-D 24-D 34-A 44-C 54-A
05-A 15-C 25-D 35-C 45-D 55-C
06-D 16-B 26-B 36-C 46-C 56-D
07-C 17-A 27-A 37-A 47-A 57-B
08-A 18-B 28-B 38-B 48-D 58-C
09-D 19-D 29-A 39-C 49-C 59-C
10-C 20-C 30-A 40-B 50-D 60-A
Maths ~ May/June 2018 ~ Multiple Choice Answers
6:11 Isn’t #25 (A)
If you take 8 from 15 you get -7
Therefore you’d get -21 as the result but the result is really supposed to be 21
you have 15 apples
someone takes 8
how many apples do you now have?
15 - 8 = 7
still a positive amount, yes?
so it's the same here~
15 - 7 = 15 + (-7) = 8
I could've sworn someone asked this exact same question last year~
Please leave your comment live, many can benefit from it!!
If you still have doubts, let me know
I will help you~
with the right amount of follow ups
gpt4 can do every single csec math question correctly
(if it didn't get it right on the first try)
so you can also work with it
(in case you find I'm taking long to respond)
I use copilot on the microsoft bing browser
it uses chatgpt4
you can have an intelligent back n forth conversation with it
it would be able to discuss with you any concerns you have about any of these questions~
I highly recommend it!
you can ask it to solve a problem a different way
and ask why it performed certain steps etc
also, consider that:
if you take 15 from 8 then you get -7
8 - 15 = 8 - (8 + 7) = 8 - 8 - 7 = 0 - 7 = -7
@csec-maths-chem-paper1s God bless your heart
thank yu for this video it helps alot its the shorted video of paper on i could find
You're welcome~
Here's a list of the Paper 1s for CSEC Maths I have up currently:
My CSEC Maths Solution Vids for Paper 1s:
May/June 2023 ~ ua-cam.com/video/e2nYeJMNADU/v-deo.html
May/June 2022 ~ ua-cam.com/video/6aIm-w3O568/v-deo.html
May/July 2021 ~ ua-cam.com/video/wHKjwEZhg4k/v-deo.html
May/June 2020 ~ ua-cam.com/video/C2FZym66rFc/v-deo.html
May/June 2019 ~ ua-cam.com/video/8R_9atO-W1E/v-deo.html
May/June 2018 ~ ua-cam.com/video/qFMSHkEht1M/v-deo.html
May/June 2017 ~ ua-cam.com/video/fomv4YaZR7o/v-deo.html
May/June 2016 ~ ua-cam.com/video/4oIjZ3hE0RQ/v-deo.html
May/June 2015 ~ ua-cam.com/video/ndD3mLyTaMg/v-deo.html
May/June 2014 ~ ua-cam.com/video/EcpaBibyTJI/v-deo.html
May/June 2013 ~ ua-cam.com/video/KSmIc0xGjSs/v-deo.html
May/June 2012 ~ ua-cam.com/video/GXy-hPuCSpk/v-deo.html
May/June 2011 ~ ua-cam.com/video/_esRny-ovUU/v-deo.html
May/June 2010 ~ ua-cam.com/video/0W_RkLZ0HP4/v-deo.html
May/June 2009 ~ ua-cam.com/video/sEoA-KhRe98/v-deo.html
May/June 2008 ~ ua-cam.com/video/Mahiu9XyK6M/v-deo.html
May/June 2007 ~ ua-cam.com/video/R4FnosmqmxM/v-deo.html
May/June 2006 ~ ua-cam.com/video/79BX9JuPn5s/v-deo.html
May/June 2005 ~ ua-cam.com/video/rVMaqMPPjCM/v-deo.html
May/June 2004 ~ ua-cam.com/video/8Dxf_JA7cPQ/v-deo.html
May/June 2003 ~
May/June 2002 ~
May/June 2001 ~
January 2023 ~ ua-cam.com/video/lXLhUSsU1Xg/v-deo.html
January 2022 ~ ua-cam.com/video/3uzrUhtKZhA/v-deo.html
January 2021 ~ ua-cam.com/video/yN6QR0rz33I/v-deo.html
January 2020 ~ ua-cam.com/video/KX6Vs6DRZXM/v-deo.html
January 2019 ~ ua-cam.com/video/k0NS48rWPGg/v-deo.html
January 2018 ~ ua-cam.com/video/09scXnajSz8/v-deo.html
January 2017 ~ ua-cam.com/video/Ry8Z2LNIBv0/v-deo.html
January 2016 ~ ua-cam.com/video/NI2LdJHUY2A/v-deo.html
January 2015 ~ ua-cam.com/video/qIPsZrWLnE0/v-deo.html
January 2014 ~ ua-cam.com/video/UZVZtCmvICc/v-deo.html
January 2013 ~ ua-cam.com/video/xD9IxhCFPao/v-deo.html
January 2012 ~
January 2011 ~ ua-cam.com/video/ehmPK9qG9gA/v-deo.html
January 2010 ~ ua-cam.com/video/XYm6DekfHUc/v-deo.html
January 2009 ~
January 2008 ~
January 2007 ~ ua-cam.com/video/3CuI-LvYc4o/v-deo.html
January 2006 ~ ua-cam.com/video/ZxBQKePW35U/v-deo.html
January 2005 ~ ua-cam.com/video/FeVOKismCQE/v-deo.html
January 2004 ~
January 2003 ~
January 2002 ~
January 2001 ~ ua-cam.com/video/K6AcZiC0zKE/v-deo.html
How you got n“=800?” For number 2??? 0:28 especially with the use of arrow, I’m confuse and number 12 2:56 ? Could you explain
yes I will explain, and thanks for using timestamps hehehe~
(n/100) x 40 = 8
(40n) / (100) = 8
multiply both sides by 100
40n = 800
divide both sides by 40
n = 800/40 = 80/4 = 20
the arrow just meant,
by cross-multiplication the equation reduces to solving 40n = 800
another way to think about it is diagrammatically:
if you drew 5 equal boxes
and put 8 in each of them
the total is 40 right?
now what percentage of 40 equals 8?
that'll just be one box right?
1 out of 5 is 20%
if you needed to skip doing algebra,
you could solve this problem that way~
@@csec-maths-chem-paper1swhy multiply both sides by 100? And wouldn’t it be “40*100 = 4000n??” Or I’m misinterpreting .
@@TwixMix look at the 27 second mark here
ua-cam.com/video/s9lFlmSHCGI/v-deo.html
the question repeated on the most recent paper 1
that's how you solve it, that's how you work with fractions
if one-fifth A = y, you multiply both sides by 5 to solve for A
those are the operations to use to isolate a variable on one side of the equation
what you do to one side of the equation, you have to do to the other to preserve the equal sign
x + 5 = y
you have to add both sides by -5 to preserve equality
in this case we have to use multiplication to preserve equality to solve for n
@@TwixMix the 100 cancel's out on the left side
(n over 100) times 100 is n
(40n over 100) times 100 is n
(a over b) times b is just a
You are an absolute life saver, thank you so much
On gang
Thank you so much
you're very welcome! good luck today!! go get 'em!!!
@@csec-maths-chem-paper1s🙏🏾🙏🏾🙏🏾🙏🏾
miss can i ask a qestion is there a site i can do this on
Sir*
I can email you the csec maths pdfs and you can answer them on paper and then compare solutions etc.
csec.chemistry.paper1@gmail.com
subject "maths paper 1s pdfs"
I have about 40 past papers to send~
thank you @@csec-maths-chem-paper1s
isnt 58 d?
correct
yes D
no the answers correct.
it makes sense to me that it should be D also
It's A. The answer in the video is correct. To find YZ(the opposite side) then youd have to do tangent which is opposite/adjacent. Were also given an angle of 30 degrees, meaning youd have do to 10 tan 30
Cosine is adj/hyp, but we dont have a hypotenuse value so that couldnt work
Everything else in the video is correct though?