Thank you for the video. for 9.2 the answer is just that pKa = pH at half equivalennce point. then do 10^-pH for Ka. In other words conc of H+ ions is equal to Ka.
Kp is equal to partial pressure of O2 multiplied by (pp of SO2) squared all divided by (pp of SO3) squared. Is you square root kp, you have to square root every component on the equation. This gives you the equation to kp1. So to get to kp1 you have to square root kp.
@@sudanezz Mathematically when you write down the equation for Kp1 and Kp2 they're the same algebraically if you just square root one of them. You sub in the same values so you can just write down square root of Kp as the answer.
Thank you so much for these videos Mr Davies, they're extremely helpful.
Thank you for watching & and for your kind comment. :-)
@@daviesa-levelchemistry1210 you're very welcome!!
you superstar
In 50:51, for X^-, why do we add the moles of KOH instead of subtracting it to find the final moles so why are we doing 0.0136 + 0.0003?
absolute legend
Thank you for the video. for 9.2 the answer is just that pKa = pH at half equivalennce point. then do 10^-pH for Ka. In other words conc of H+ ions is equal to Ka.
Great video but where in the textbook does it explain how to do a question similar to 9.2- it doesn't say anything about this type of calculation??
Hi thank you so much for these brilliant videos! For Q7.4 please may you explain how Kp₁ is the square root of Kp? Thank you :)
have u figured it out yet?
Kp is equal to partial pressure of O2 multiplied by (pp of SO2) squared all divided by (pp of SO3) squared. Is you square root kp, you have to square root every component on the equation. This gives you the equation to kp1. So to get to kp1 you have to square root kp.
@@sudanezz Mathematically when you write down the equation for Kp1 and Kp2 they're the same algebraically if you just square root one of them. You sub in the same values so you can just write down square root of Kp as the answer.
@@nickboyle5999 thank you so much! good luck to the exam tomorrow, if you have it!
@@ada9994 great - thanks! if you have the exam tmrw, good luck!
For q 8.1 don’t the hydrogen bonds need to be shown to be 180 degrees?
thank you so much
Thanks for watching. best of luck with your exams :-)