L19.3 Differential and total cross section

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  • Опубліковано 19 вер 2024
  • MIT 8.06 Quantum Physics III, Spring 2018
    Instructor: Barton Zwiebach
    View the complete course: ocw.mit.edu/8-...
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    L19.3 Differential and total cross section
    License: Creative Commons BY-NC-SA
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КОМЕНТАРІ • 21

  • @gibbs-13
    @gibbs-13 2 роки тому +21

    If there are 100 people explaining differential cross section, they do in 100 different ways from each other.
    This is one of the best explanations to me!

    • @jacobvandijk6525
      @jacobvandijk6525 Рік тому

      This only means you didn't understand the other explanations. Nothing else.
      You (and these likers of yours) have a very subjective mind. Wake up!
      Teaching is about giving EVERYONE the right example to understand.

  • @TheCrunchyGum
    @TheCrunchyGum Рік тому +4

    3:39 Finally the differential cross section is explained clearly... I have no idea why textbooks and instructors are obtuse about something so simple.

  • @not_amanullah
    @not_amanullah 2 місяці тому

    Thanks ❤️🤍

  • @jacobvandijk6525
    @jacobvandijk6525 Рік тому

    @ 16:37 A STRANGE EQUATION physically. As if a change in solid angle (determined by the experimenter) would change something about the cross-section of the material in target?

  • @JimmyGray
    @JimmyGray 4 роки тому

    Great lecture. Thank you.

  • @not_amanullah
    @not_amanullah 2 місяці тому

    This is helpful ❤️🤍

  • @abhinovenagarajan.s7237
    @abhinovenagarajan.s7237 3 роки тому

    Given that the wave function psi is a 'leading term' solution, how do we know that the remaining terms may not contain functions that depend on (theta,phi) and hence, affect our differential cross section as well?

  • @scienceandstudy6431
    @scienceandstudy6431 4 роки тому +2

    please explain why u took incident wave imaginary part

    • @onderozenc4470
      @onderozenc4470 3 роки тому

      It is plane wave representation. Though the outgoing wave is spherical in terms of both phase and amplitude, its argument becomes suppressed in the intensity expression (complex conjugate).

    • @jacobvandijk6525
      @jacobvandijk6525 Рік тому

      @@onderozenc4470 Now try to answer his question. Only the first sentence has anything to do with it.

  • @onderozenc4470
    @onderozenc4470 3 роки тому +2

    In turkish universities, even the emeretus professors😄don't know about these representations 😝

  • @Shaziakhan75557
    @Shaziakhan75557 4 роки тому

    A cmplt knowledge of the topic could be found here

  • @cikif
    @cikif 5 років тому +3

    2:02 I'm finding as you -should- *shoot* in particles
    3:58 an -iv- *idea*
    5:39 -floods- *flux*
    19:03 approximate solution -for a wave- *far away*

  • @MANOJKUMAR-ev7pl
    @MANOJKUMAR-ev7pl 5 років тому +1

    At 9.12 min why he used imaginary

    • @parasharchatterjee3223
      @parasharchatterjee3223 5 років тому +2

      The probability current density has the formula of the type he wrote. There's another one where its (psi*)del psi - psi del (psi*), which is generally what is derived in textbooks.

    • @onderozenc4470
      @onderozenc4470 3 роки тому

      Wave function multiplied by its imaginary part gives the probability density.

  • @zakirreshi6737
    @zakirreshi6737 4 роки тому

    Playlist link ua-cam.com/play/PLUl4u3cNGP60Zcz8LnCDFI8RPqRhJbb4L.html

  • @scienceandstudy6431
    @scienceandstudy6431 4 роки тому

    please explain why u took incident wave imaginary part

    • @Tom-iv5pw
      @Tom-iv5pw 4 роки тому +6

      It is the definition of 'Probability Current'. Since the sum (or integral) over all possible states will always conserve to 1 - before and after the scattering process - what we assume is that the probability redistributes itself, like how the intermediate state between two different charge distributions would require an electric current to redistribute the conserved overall charge.
      A quick way to obtain this quantity is to take the time-dependent Schrdöedinger equation (Let's call this Eq.1) and its complex conjugate (Eq.2). If we multiply Eq.1 by the complex conjugate of the wave function and Eq. 2 by the wave function and subtract these expressions, we will get an expression which we can be manipulated into something very similar to a continuity equation (divergence of a vector + partial time derivative of a scalar = 0).
      This vector (the one that is acted upon with a divergence in the paragraph above) is the 'Incident Flux' the professor defined in this video.