Electric Field Strength

027 - Electric Field Strength
PhET Simulation - phet.colorado.edu/en/simulatio...
In this video Paul Andersen explains how the electric field strength is directly related to the amount of charge that generates the field.
Do you speak another language? Help me translate my videos:
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Music Attribution
Title: String Theory
Artist: Herman Jolly
sunsetvalley.bandcamp.com/trac...
All of the images are licensed under creative commons and public domain licensing:
"Charges and Fields." PhET. Accessed May 23, 2014. phet.colorado.edu/en/simulatio....
"Electric Field of Dreams." PhET. Accessed May 23, 2014. phet.colorado.edu/en/simulatio....

[@brenocasciello9183]

That was quick, straightforward, and super understandable. My most sincere kudos!

[@theuniquegroupandthebest7706]

True100%

[@mattkwe6473]

Very helpful. Thank you professor Anderson.

[@nabeelabbasi831]

can u plz tell me that in millikan's oil drop method
By changimg the strength of electic field how the charge on each droplet was different

[@samgirl964]

It helped clear my concept thankyou!

[@925LY]

Bozeman > Kahn. Quick and to the point, thank you.

[@abdallahmohamedelhady6668]

Very helpful, thank you man 👏

[@MrSaltytoast]

thank you Mr Anderson

[@deepakpundir5374]

Very amazing explanation , I wish you were my teacher

[@barathkumarg4214]

Mr Anderson I have a doubt In JJ Thomson experiment whether the deflection is directly proportional to electric field intensity or not?
Please explain @Bozeman_science @Anderson

[@benalright2009]

Helpful. Thanks

[@magicalDisneyforever]

Your videos are so interesting! Thankyou :)

[@fattah.architect]

much much helpful..thanks

[@maryammuhammed7839]

Nicely e explained

[@Nooble5]

Hi Paul Andersen or anyone that knows the answer,
What software do you use for your presentations? I tried looking around but couldn't find any detail about it.
Thanks!

[@Nooble5]

Oh wow. Thank you! I didn't realize such an amazing thing like this exists.

[@gabrielsanchez8501]

Thank you for the interesting videos!
There is something I don't understand about this topic. If we rearrange the formula "F= q x E" to find E (i.e. E= F/q), it shows that E (Electric field strength) and q (charge) have an inversely proportional relationship to one another. Which means that if we increase charge, E should decrease.
This video is stating the opposite isn't it? That if we increase charge, we also increase the electric field strength?

[@shaoyangzhang7974]

I guess this may help you:
E = F/q, and F = kQq/r^2. i.e. E = (kQq/r^2)/q, so E = kQ/r^2.
The q you are talking about is canceled out and doesn't matter anymore, while the Q Paul is explaining will make E increase as Q increases

[@theorangejuiceprogrammer9227]

Thank you!!! :)

[@paigebosworth9574]

Is a field of 70 volts per meter abnormally high?

[@Michael-go9hm]

Thanks boss

[@hongtien010192]

Thanks :)

[@walekhan3470]

sir, why electric field lines are headed away from positive charge and move toward negative charge?

[@TechInsiderSolution]

Think of it this way, this whole process is due to moving of electrons. Since ONLY the electrons are able to move, in order for the point charges to get different charges the electrons are emitted or gained. The charge that is positive emits (loses) electrons and becomes more positive. The other charge gains electrons and is basically negative. I hope this was helpful :)

[@RenaeStutzman]

Him: "Was it helpful" Me: No, no, it was not. My negative energy is increasing over here.

[@finnleytanner4943]

midnight revision lifesaver

[@Pages_Perfected]

where is the law 😄

[@mobzilla2419]

Useless