No. We are assuming that player 2 plays A with probability 1. Thus, Player 2's expected payoff from playing A is their payoff if Player 3 plays C multiplied by the probability that Player 3 plays C, which is 8q, plus their payoff if Player 3 plays D multiplied by the probability that Player 3 plays D, which is 10(1-q). Thus, E(A) is 8q + 10(1-q). This is consistent with other videos when you set p equal to 1. Hope this helps!
hello, I want to ask why you solved the expected playoffs differently than from your other videos. shouldn't E(A) be 8pq and not just 8q?
No. We are assuming that player 2 plays A with probability 1. Thus, Player 2's expected payoff from playing A is their payoff if Player 3 plays C multiplied by the probability that Player 3 plays C, which is 8q, plus their payoff if Player 3 plays D multiplied by the probability that Player 3 plays D, which is 10(1-q). Thus, E(A) is 8q + 10(1-q). This is consistent with other videos when you set p equal to 1. Hope this helps!