Lines in Three Dimensions (1 of 3: How to extend from 2D)

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  • Опубліковано 26 чер 2023
  • More resources available at www.misterwootube.com

КОМЕНТАРІ • 12

  • @bobaroot3789
    @bobaroot3789 Рік тому +13

    He is one of the best math teachers out there.

  • @Malfunct1onM1ke
    @Malfunct1onM1ke Рік тому +3

    Thank you Eddie for you hard work putting Math on UA-cam in an entertaining and informative way.
    I am currently writing my Master Thesis in Engineering but watching this Channel still blows my mind. Even though i learned a lot about math during my lectures, the reasons why we do certain things the way they work has sometimes been left in the dark.

  • @adrianli7757
    @adrianli7757 Рік тому +1

    How is this guy still going. He was a legend 10 years ago and continues to be.

  • @thecleanerjeffgohan895
    @thecleanerjeffgohan895 Рік тому +1

    Eddie, I'm considering a math degree since a physics degree isn't in my city, I like how you can use math in innovation and technology, you think math could be a good choice?

    • @DimensionalIO
      @DimensionalIO Рік тому

      I’m not Eddie, but I would strongly recommend doing the Maths degree. The world needs more mathematicians, especially people who can explain concepts like Eddie. If you’re still considering your career path, go with maths as long as you’re passionate for it.

  • @NaveedButt
    @NaveedButt Рік тому

    Maybe it is my misunderstanding, but while solving for 3rd dimension. Why did you not put in arbitrary values for x and y. You put in values for x only and the result that you get is a set of ines because you are trying to find the plane by putting in half information.
    IMO, we should go for putting in values in pairs, like x=0, y=0 and then try to find out the value for z and then we will end up having the triplets that we want.

    • @carultch
      @carultch Рік тому +1

      What you would need to do for defining a line in 3-D, is to use an intersection of two planes. To keep it simple, you'd use one plane with the desired diagonal slope (such as 3*x + 4*y + 5*z = 6), and another plane that is parallel to the z-axis (such as y = 2*x + 1). The intersection of these planes defines a line.
      Another way is to use a parametric setup, where you use a parameter variable t, and define its x/y/z position as a function of t. Think of t as time in a typical application, although doesn't necessarily need to be time. This is the approach that most computer graphing programs use, and for non-linear shapes defined in the same way, it is called a space-curve. For the line I described above, the parametric equations that describe the line are:
      x = 5*t
      y = 10*t + 1
      z = -11*t - 2/5
      It is arbitrary how fast t moves through space, so there are many other options for how you could define the space-curve for the same 3D line.

  • @akashyadav-zt6wq
    @akashyadav-zt6wq Рік тому

    It is a obvious thing.

    • @dr.handsome3715
      @dr.handsome3715 Рік тому +4

      Then why wasn't it obvious for him or the students?

    • @jursamaj
      @jursamaj Рік тому +2

      Everything is obvious after you know it. :P

    • @akashyadav-zt6wq
      @akashyadav-zt6wq Рік тому

      @@dr.handsome3715 depends from which source and time you have studied it?

    • @akashyadav-zt6wq
      @akashyadav-zt6wq Рік тому

      @@jursamaj not for everyone.