Limit Uniqueness

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  • Опубліковано 28 лис 2019
  • Happy Proof Friday! Here's a proof of the limit uniqueness theorem. At the end of the video I also talk about a couple of other ways you can prove this.
    Thanks for watching! Comment below with questions, and make sure to like / subscribe!
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КОМЕНТАРІ • 22

  • @noahf649
    @noahf649 4 роки тому +6

    Good video Mr. Tucci. Im not sure when you hit 2k subs but congrats!

    • @BrainGainzOfficial
      @BrainGainzOfficial  4 роки тому +2

      It was just a couple of days ago actually! Thanks! Good luck with finals!

    • @noahf649
      @noahf649 4 роки тому

      @@BrainGainzOfficial Thanks! Good luck to you too, if you have any!

  • @steffisnaitang2494
    @steffisnaitang2494 11 місяців тому

    Well explained!👍

  • @brightsideofmaths
    @brightsideofmaths 4 роки тому +2

    I like your blackboard and this very nice video series. Please, keep up the good work :)

  • @bramlentjes
    @bramlentjes 4 роки тому +1

    Awesome video, it is nice that you go through a proof not to fast and give your own ideas on how to see it.

  • @jessicasanchez134
    @jessicasanchez134 4 роки тому +2

    I really enjoy your videos it's my second semester and sometimes I feel really lost 🥺❤️

  • @skulduggery7853
    @skulduggery7853 2 роки тому

    That helped a lot.. Thank you

  • @Sunilkatagi1311
    @Sunilkatagi1311 3 роки тому

    Your explanation was 🔥🔥

  • @exploreit591
    @exploreit591 3 роки тому

    Great explanation sir...I want to know why we take the neighbourhood of a point as an open interval and not closed, and why we take |f(x)-l|

  • @aditisharma7773
    @aditisharma7773 3 роки тому

    Grt video ✌️✌️

  • @mepoor761
    @mepoor761 3 роки тому +1

    From know on
    Consider yourself as a sigmian brother in the sigma communtiy

  • @alexulloa174
    @alexulloa174 4 роки тому +1

    I proved this in calc ab earlier this year

  • @frozenmoon998
    @frozenmoon998 4 роки тому +1

    Some epsilons and deltas Here and There, making it spicy. Good video.

  • @nchanelle
    @nchanelle 4 роки тому +2

    Happy Proof Friday!

  • @jsh_jsh
    @jsh_jsh 4 роки тому +1

    great vid

  • @user-yt8ul4jk5z
    @user-yt8ul4jk5z Місяць тому

    To finish the proof you just have to observe that the epsilon>0 is ARBITRARY: If the absolute disfference of two numbers is less than an ARBITRARY epsilon>0, then the two numbers must necessarily be equal.

  • @alexulloa174
    @alexulloa174 4 роки тому

    It looks exactly like this lol