Like this video but want to learn more about finding the area of a sector? See the video I did here on area of sectors: ua-cam.com/video/nDVUcqqwPJA/v-deo.html
So I am taking this online course, and the examples the instructor gave were all 60 or 90 degree triangles but the actual problems had 123 or 76 degree angles and they never quite explained how to solve for them. they only said use trigonometry. In the two days I've been stuck on this it only took your 4 minute video to make me a master at the concept. Thank you so much
Currently at this in school and its been really confusing and hard to keep up with my mathematics teacher, decided to come know UA-cam and here you are. Your videos are really helpful and I love them. Thank you so much!!
USEFUL RULE: When a sector is 120deg, and you split it into a triangle and a segment, then the middle of the longest side of the triangle will intersect exactly in the middle of the radius and the perimeteter Example: In a 120deg sector, where the radius is 10, splitting the sector into a triangle and a segment, then the height of the triangle will be 5
Thank you so much for doing this video! I really was struggling to find how to do this kind of problem in my notes, but this video helps me so much and this it showed me how to do it very clearly and understandably. I really appreciate your thorough way of solving this problem and for posting this video. So glad I found it! Thanks again! :)
Mario, you did a clear presentation of the problem and it will be helpful to many students. Thanks. However, real life is more complicated. In the case of finding the remaining volume in a horizontal cylindrical tank, all you would know is the diameter of the tank and the depth of the remaining fluid. How would a person calibrate a dipstick for such a tank? That's a much more general version of the problem. It's easy to tell when the tank is either full or empty, but there is an infinite number of possibilities in between.
@@MariosMathTutoring, I will be teaching in Flour Bluff Texas. I passed the exam by the skin of my teeth, but want to thank you for your help. I really enjoy how you explain and simplify things.
I had this type on my Honors Geometry test just yesterday. I had no idea about this. last question. The only one that I really couldn't get. We haven't even learned it before.
This is really helpful!!! However, I'm still struggle with other kind of question based on the segments, there is one which gives me the length of the radius and the height of the segments, how could I work out the segment though
Well, I've made an equation, which also can be derived following the process shown here, being *_r²(π*(θ/360) - sin(θ/2)*cos(θ/2))_* Is there any way to simplify it or is that what I'm stuck with? Edit: OK new question. I have found out that it will simplify quite nicely when sin(θ/2)*cos(θ/2)=sin(θ)/2 But, I cannot figure out how to prove this. How do you derive this equation?
Just right triangles but there is a special law of sines and law of cosines formula for non right triangles...maybe this video I did here will be of help to you: SOH CAH TOA (Trigonometry) ua-cam.com/video/q5JMy_NAP1c/v-deo.html
this is probably very late, but ig better late than never. When you have a right triangle that contains angle measures 30, 60, and 90, this gives us side lengths. The side length between the right angle and the 30 angle is going to be x root 3. The angle measure between the right angle and the 60 angle is going to be x. The hypotenuse is 2x. Since we are already given the 2x in this problem (4), we know that x is 2, therefore giving 2 root 3 in the other side. Since the triangle is congruent, we add 2 root 3 and 2 root three to get 4 root 3. It should be good from there
![Radians, Arc Length & Sector Area of a Circle - [2-21-1]](http://i.ytimg.com/vi/lcuxPNBXhlY/mqdefault.jpg)
Like this video but want to learn more about finding the area of a sector? See the video I did here on area of sectors: ua-cam.com/video/nDVUcqqwPJA/v-deo.html
Cheers. Really helped me!
Glad my video helped you Henry!
Dude I saved 5 marks in my test thnks man
you explained it a lot clearer than other videos i've seen. thank you for including another way to solve it other than the 60 90 30 way.
You’re welcome! Glad you liked my explanation!
4 years late but thanks homie
lol
5 years *
Talib Ahmed sorry
Wow the video is legit 4 years later and your comment is 2 years ago wtf
@@theuglybeing4673 I’m still here
Ok, I'm 58, returning to school, you are saving my life
Glad my videos are helping you Lorraine!
YOU'RE A G THANK YOU SM this just saved me from failing my online quiz tomorrow thanks homie
Glad my video helped you Jannete! Report back if you want and let us all know how your online quiz went.
Lol
I have a quiz tmrw too
Good luck on your quiz Korn!
@@MariosMathTutoring You saved me too. I also have quiz tomorrow.
So I am taking this online course, and the examples the instructor gave were all 60 or 90 degree triangles but the actual problems had 123 or 76 degree angles and they never quite explained how to solve for them. they only said use trigonometry. In the two days I've been stuck on this it only took your 4 minute video to make me a master at the concept. Thank you so much
You’re welcome! Glad to hear my video helped you so quickly!
Saving me right now, I have my exam tomorrow and this is the thing I just didn't remember from class.
Thank you so much!! This helped a ton since it’s kinda hard to learn new lessons in online school😌
Glad my videos are helping you Ella!
Currently at this in school and its been really confusing and hard to keep up with my mathematics teacher, decided to come know UA-cam and here you are. Your videos are really helpful and I love them. Thank you so much!!
Thanks Mario! I was lost on this before and you helped to steer me in the right direction!
nahh Mario you a real one for this my test is tomorrow🙏🙏🙏
USEFUL RULE:
When a sector is 120deg, and you split it into a triangle and a segment, then the middle of the longest side of the triangle will intersect exactly in the middle of the radius and the perimeteter
Example: In a 120deg sector, where the radius is 10, splitting the sector into a triangle and a segment, then the height of the triangle will be 5
so will the base of the triangle be 5(2) sqrt of 3???
Thank you so much for doing this video! I really was struggling to find how to do this kind of problem in my notes, but this video helps me so much and this it showed me how to do it very clearly and understandably. I really appreciate your thorough way of solving this problem and for posting this video. So glad I found it! Thanks again! :)
You’re welcome Alana!
Thanks a lot man this save me from failing
I really appreciate this
Thank you so much sir! My three remaining brain cell understand everything, thank you so much T^T
XD
There is a easy way just to do 1/3 times Pi times (4 squared)-the area of the triangle which is (half times base times height)
it works
Thats the way we do it in my math class
It depends if the base or height is given. Did you know that??
thank god you and this video exist
thank you so much for this simple explanation you have no idea how badly you just saved my grades
Man you are an amazing teacher I swear. My teacher teaches very good but I missed one week of school so I couldn't catch up but you saved my grade!
Wow, thanks!
This helped me a lot!!! Very short but helpful explanation. Thank you!!!
You’re welcome Alessandra!
im from the UK but thank you so much i managed to get a grade 9 ( A*) in my mocks
sir Mario thank you so much .it helps me a lot .God bless .Love from Phillipines.
Mario, you did a clear presentation of the problem and it will be helpful to many students. Thanks.
However, real life is more complicated. In the case of finding the remaining volume in a horizontal cylindrical tank, all you would know is the diameter of the tank and the depth of the remaining fluid. How would a person calibrate a dipstick for such a tank? That's a much more general version of the problem. It's easy to tell when the tank is either full or empty, but there is an infinite number of possibilities in between.
this is useful in preperation for AMC. thank you
Love from India! ♥️🇮🇳
Thanks!!! I got alot of help in my maths homework, our sir gave us alot of homework, almost 100 questions, BRO THATS ALOT FOR LIFE!!!
Glad it helped!
I don't understand the part 2:45 to 3:32, can someone explain
What if you are not given a side length?
Ahhh I really need a teacher like you
Great job there Mario. I am a teacher myself and i thumbs up whenever i find a good teacher online so take a like from me. and keep rocking
Thanks a lot! I really appreciate your positive feedback!
Helped me a lot, thank you :)
THANK YOU Mario
You are a great help
This guy is the best bro
Thank you so much! This really helped me out so much! Sub and like. Keep going!
Glad you liked the video KenanB! Welcome to the channel! Yes, more videos coming out weekly!
Solid video, thanks dude.
hi may I know radius is always the same on both sides?
honestly, you just saved me from getting a 50 on my homework. Thank you legend.
Glad my video helped you Luis!
Thank you, I really enjoy your videos. I hope they help, doing teacher cert tomorrow.
Good luck with your certification tomorrow Valente. Where will you be teaching? Report back if you want and let us all know how it went.
@@MariosMathTutoring, I will be teaching in Flour Bluff Texas. I passed the exam by the skin of my teeth, but want to thank you for your help. I really enjoy how you explain and simplify things.
Awesome! Congratulations! And good luck on your new teaching career!
I had this type on my Honors Geometry test just yesterday. I had no idea about this. last question. The only one that I really couldn't get. We haven't even learned it before.
a true hero
Glad my videos are helping you Yousif!
I have a question. Why did he multiple the base times height on the triangle part with 1/2?
because that's the area formula of the triangle: 1/2 base*height.
Thank you Mario, very cool!
You’re welcome! Glad you liked the video!
dude u r a lifesaver
Glad my video helped you!
How Did you get the base? , The 2√3
8 years later but thankyou very much
You’re welcome.
Studying for a test, thank you! this helped me alot.
@@adilabas228 Monthly
@@Marwan-ru3yx so how was Ur test
@@adilabas228 Not so good but Im catching up pretty well and I made up for it
@@Marwan-ru3yx that's nice
Thanks a lot sir✨
When working out the 3rd length of the right angled triangle why not use pythagoras to work out the length?
This was really helpful 👏🙂👌
For those curious the formula is 1/2 * r^2 * (x-sinx)
Thank you for sharing.
Great video!
Mario are you able to show me how to do the top right triangle i am stuck on how to do them
So, to find segment. I basically subtract the triangle from the sector ?
Wish my teachers were as good at explaining as you
Glad you like my explanations Gabriel!
This is really helpful!!! However, I'm still struggle with other kind of question based on the segments, there is one which gives me the length of the radius and the height of the segments, how could I work out the segment though
Thanks for this explanation sir.🙂
Thank you so much :) I found this video easy to understand. Others just have to catch up on some of the previous Theorems.
You’re welcome! Glad you liked the video!
Well, I've made an equation, which also can be derived following the process shown here, being *_r²(π*(θ/360) - sin(θ/2)*cos(θ/2))_*
Is there any way to simplify it or is that what I'm stuck with?
Edit: OK new question. I have found out that it will simplify quite nicely when sin(θ/2)*cos(θ/2)=sin(θ)/2
But, I cannot figure out how to prove this. How do you derive this equation?
Are there any examples where the triangle, when split in half, is a 45 45 90 instead of a 30 60 90?
Thanks man helped with my work
You’re welcome!
Thanks u just saved my average
Where did the 2√3 came from??
Is that given??
Thank you so much!
You’re welcome!
hi, Mario. you were so helpful!!! :D
Glad my video helped you Ming!
Big help Mario, cheers.
Glad my video helped you!
Thank you! I just finished my test a day ago and guess what? a question exactly the same came on the test. So thank you once again :)
Your welcome!
Can you please do another example on this sir, please.
Well presented. Thank you.
You’re welcome James! Glad you liked how I did the video!
Does sin, cos and tan work for all triangles?
Just right triangles but there is a special law of sines and law of cosines formula for non right triangles...maybe this video I did here will be of help to you: SOH CAH TOA (Trigonometry) ua-cam.com/video/q5JMy_NAP1c/v-deo.html
@@MariosMathTutoring Thank you so much
You’re welcome!
THANK YOU
Thank you so much sir
thanks from bosnia(hvala)
Thank you very much it really helped me wish u the best
Glad my video helped you Lazo Dana!
can you please explain base 4 root 3 and hight 2 is come?
???
its special right trangles look that up
this is probably very late, but ig better late than never. When you have a right triangle that contains angle measures 30, 60, and 90, this gives us side lengths. The side length between the right angle and the 30 angle is going to be x root 3. The angle measure between the right angle and the 60 angle is going to be x. The hypotenuse is 2x. Since we are already given the 2x in this problem (4), we know that x is 2, therefore giving 2 root 3 in the other side. Since the triangle is congruent, we add 2 root 3 and 2 root three to get 4 root 3. It should be good from there
Where did we got 2 square root of 3?
Thanks bro, today is my exam day in math
Good luck!
thanks so much
Thank you Math Jeff Bezos
How to calculate areas of segment dome
Awesome video sir.
Glad you liked the video!
If I worked it out correctly the area is 9.82 Correct? Thanks for your help, this was exactly what I needed! :)
Yes you got it Shirley! 9.83 if you round to the hundredth. Glad my videos are helping you!
Thanks u saved my ass from my teacher 😅😅
Much thanks.
You’re welcome Fechi!
Very very helpful
Glad you found my area of a segment video helpful!
trig exam tomorrow, thanks bro
Good luck on your exam!
I love you so much
Thanks my g
how does it become 2√3?
Solving 45 45 90 and 30 60 90 Special Right Triangles (Lots of Examples)
ua-cam.com/video/Y_qs4cgxbgs/v-deo.html
Where did the 2√3 and 4√3 came from
No idea tbh
2:54 how did you know it'll be 2??
Nvm lol
But what if it's 70 degrees and not 60?
thanks man i must be slow as hell or you just made it look easier than i thougth it was
You're welcome. Glad my video helped you.
Thanks mate
You’re welcome Ishaan!
Good job
Glad you liked the video Nicola!
I am from India🇮🇳🇮🇳🇮🇳
thanks budd
Thank u sir!
You’re welcome Ray!
Thank youuuu sir
You’re welcome Dilah!
Eight years late but thanks dude
You're welcome!
What if the radius is 8 and the sector is 60°?
Thanku
Where did u get 2
+mg g19 you can learn more about 30 60 90 triangles in this video here...
ua-cam.com/video/8N9U8ELNILE/v-deo.html