The Semi Empirical Mass Formula

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  • Опубліковано 16 гру 2024

КОМЕНТАРІ • 104

  • @navjotsingh-bl7jk
    @navjotsingh-bl7jk 6 років тому +1

    Last 35 mins were awesome. No experimental facts, only theoretical work.

  • @LucVanOcken
    @LucVanOcken 10 років тому +3

    Thank you Dr. Robert Eagle. Crystal clear explained! During and by watching this video, I made two new discoveries.

  • @payammadjidi4701
    @payammadjidi4701 7 років тому +2

    I really love the way you explain advanced concepts. I really appropriate your channel.

  • @sayanbhakta2892
    @sayanbhakta2892 4 роки тому +1

    Excellent explanation.....probably the best of it's kind I should say......

  • @AAAAAAAAAAAAAAAAAAAAHH
    @AAAAAAAAAAAAAAAAAAAAHH 3 роки тому +1

    Who downvotes this? Amazing teaching

  • @northernskies86
    @northernskies86 7 років тому

    you make very complicated topics so easy to understand. I looked at Wikipedia and I got nothing. for you, I actually understand the SEMF. I am so glad you are on youtube :)

  • @אביסהר-ט4י
    @אביסהר-ט4י 4 місяці тому

    best physics lecturer in the world/ period!

  • @magp2008
    @magp2008 10 років тому

    I am very happy because you are back. I missed you. I was afraid you stopped your classes. You are great! Thank you very much!

  • @Drishtikon3
    @Drishtikon3 5 років тому +1

    This is the best channel for learning advanced physics 🙏🙏🙏🙏

  • @jimdogma1537
    @jimdogma1537 10 років тому +21

    Grab your popcorn and your calculators everyone, DrPhysicsA is BACK!!!

  • @northernskies86
    @northernskies86 7 років тому +1

    It is amazing how DrPhysicsA can make the most complicated things sound easy :)

  • @sakshibeniwal3729
    @sakshibeniwal3729 6 років тому +1

    Sir ,you just simplified nuclear concepts...thank you sir

  • @iftekmahmud
    @iftekmahmud 10 років тому +4

    Finally you are back Sir!!

  • @ThomasJohnHyde
    @ThomasJohnHyde 10 років тому

    Arrggg why do I find your channel a week after I finish my A Levels? Really nice videos anyway, they help allot :)

  • @MakeMeScientific
    @MakeMeScientific 6 років тому

    The best video lecture. #makemescientific

  • @MsJDW85
    @MsJDW85 7 років тому +5

    This has been so helpful, thank you

  • @luismorana5072
    @luismorana5072 10 років тому +1

    Yes!!!!....I was really concerned that DrPhysicsA was gone for ever. Thanks for not letting us down. Welcome back Professor !!!!

  • @JohnSmith-cy8hq
    @JohnSmith-cy8hq 10 років тому +23

    I was afraid you stopped making videos...

  • @kjv35
    @kjv35 3 роки тому

    Slight correction to the bit around 1:10:00: double beta decay CAN happen and very much does. It is the basis for neutrinoless double beta decay searches. Some example isotopes are Tellurium 130 and Molybdenum 100! DrPhysicsA is right that it is a quite rare process, however!

  • @DamienWilkins1
    @DamienWilkins1 5 років тому

    Beautiful physics and made very clear and understandable! Many thanks, final year physics undergrad

  • @brankozivlak3291
    @brankozivlak3291 5 років тому +2

    Great presentation. Best of all scientific.
    When you talk about stable nuclei in 1:14 minutes, can that also be an explanation for the existence of "magic numbers"?

  • @AchrafAtila
    @AchrafAtila 8 років тому +1

    thank you so much for this good explanation to nuclear physics.

  • @neelsharma2641
    @neelsharma2641 6 років тому +1

    Hello.... Sir thank you
    It's very nice video thanks again for nice lecture.. 🙏

  • @fjficm
    @fjficm 10 років тому

    Thanks better than any text or lecture

  • @orderrr9356
    @orderrr9356 9 років тому +2

    @40.11:
    The extra energy formulation looks like an arithmetic series to me rather than a geometric one. Factoring out 2*delta gives a nice ap 1+2+....+x/2 whose sum can be found and this would produce the same formula as shown.

  • @seale1133
    @seale1133 2 роки тому

    Thank you so much for these videos

  • @gogoat100
    @gogoat100 10 років тому +1

    ahh :) good to see you back. great show !

  • @AirIUnderwater
    @AirIUnderwater 7 років тому

    Where were these videos when I needed them years ago!? T_T

  • @koushikrajkonwar2431
    @koushikrajkonwar2431 4 роки тому

    Sir one day you will be great.

  • @yanemailg
    @yanemailg 8 років тому

    Thank you. Exactly what i needed !!

  • @mfoucault1984
    @mfoucault1984 5 років тому +2

    just great

  • @feelingzhakkaas
    @feelingzhakkaas 9 років тому +1

    Thanks for Clarification.

  • @muddassarhussain8871
    @muddassarhussain8871 6 років тому

    great explanation please upload a lecture about the nuclear energy calculations in nuclear reactor,and a complete analysis of pwrs,lwr,lmfbrs and nuclear fuel cycle

  • @MegaSKyFall
    @MegaSKyFall 6 років тому

    mind blown, ty so much for this video

  • @RTRVII
    @RTRVII 10 років тому

    Very clearly explained. Thanks so much.

  • @heroncortizo1993
    @heroncortizo1993 7 років тому

    47:29
    Is it means a semi empirical Formula does not have all explanations that "what is going on" inside the nucleus?
    --------
    What is interesting is the limit of Being Fe56.... The limit if Super Nova to explode funding the element of Iron....
    It is very interesting this relation.

  • @thearchive26788
    @thearchive26788 4 роки тому

    Does the fact that the binding energy per nucleon reaches it's peak at Fe56 have anything to do with the fact that a star collapses into itself after fusing into iron and couldn't fuse anymore? I've heard that's how black holes are created. Am I wrong?

  • @ketansathwara6271
    @ketansathwara6271 6 років тому

    Great sir hats off👌

  • @poshmark9807
    @poshmark9807 5 років тому

    You're back! Thank you for making these!!

  • @brendawilliams8062
    @brendawilliams8062 2 роки тому

    You are inspiring.

  • @davidwilkie9551
    @davidwilkie9551 5 років тому

    If only for the sake of having fun with imagination and perceptions of evolving projectiondrawing wave-packages of the Superspin modulation integration.., turning the composite numberness of primes and cofactors insideout, or act-ually outsidein to the Singularity Origin, the multi-phase Temporal Superposition-point Singularity positioning of probabilities is an exercise similar/analogous to designing a very complex gearbox of virtual work.
    The design of a Tokomac Fusion Reactor that is purpose built to engage Protons and Neutrons into bigger packages is a clue to how Quantum Operator Fields Modulation Mechanism of probabilities in potential possibilities is arranged naturally, to push the numbers around in synchronicity, from liquid gas/energy->solid mass/energy balanced equations.

  • @pekhoed
    @pekhoed 10 років тому

    i was gonna say R.I.P to DrphysicsA. Now he is clearly alive. Thank goodness

  • @khalil903
    @khalil903 10 років тому +1

    Welcome back!

  • @sinhaji6469
    @sinhaji6469 5 років тому

    Thanku so much sir
    Love from india🙏

  • @ferdinandgrimm9986
    @ferdinandgrimm9986 10 років тому

    finally a new video, thank you!!

  • @sajateacher
    @sajateacher 8 років тому

    I guess this sort of shell model would also apply to quarks or to almost any other structure that could be made out of subatomic particles?

  • @pistolart3302
    @pistolart3302 Рік тому

    عمو دكتور فيزيكس ماتقدرش دير ملخص تع النووي في خمس دقائق وربي يجازيك ❤

  • @ft6755
    @ft6755 10 років тому

    Is there any chance you could order the videos correctly in your Nuclear Physics playlist? This is #3 yet referring to videos further down in the playlist to watch first, rather confusing.

  • @muhieddineshebaro6635
    @muhieddineshebaro6635 9 років тому

    Should the most stable isotope be the most abundant one or it is not necessarly? I am using Weizsacker mass formula to calculate the binding energy of 10 isotopes. But i feel the results that i am obtaining is wrong i refer to a periodic table app (trusted one). I calculate for example the binding energy of an unstable isotope using Weizsacker and the number obtained is the highest than the number obtained when calculating the binding energy of a stable isotope but why?! Plz help me! (2wuestions ro answer plz dude)

  • @logearav
    @logearav 8 років тому

    Thanks Dr.PhysicsA. Very well explained. But how lighter nuclei like He, C, N, O etc have greater BE/A?

  • @sajateacher
    @sajateacher 8 років тому

    Would there be a stable configuration at higher atomic numbers, like maybe above element 119 there could be a stable isotope of some as-of-yet undiscovered element?

    • @misstulipie
      @misstulipie 6 років тому

      There are theories about this! You might be interested in reading about the "Island of Stability" x

  • @vennesatyanarayana5696
    @vennesatyanarayana5696 7 років тому

    sir i have a doubt. in pairing energy term. why the o-e and e-o have zero contribution.even single nucleon can decrease the binding energy of that particular nuclear.why wouldn't it be negative rather than zero.

  • @aakashthakur2785
    @aakashthakur2785 9 років тому

    that is not a geometric series it is an arithmetic series (in the calculation of asymmetric energy)
    thanks for your video sir

  • @muhieddineshebaro6635
    @muhieddineshebaro6635 9 років тому

    and how do i know if an isotope is stable if i have its binding energy? However, and can the binding energy be in the negative form?

    • @DrPhysicsA
      @DrPhysicsA  9 років тому

      Mohieddine Shebaro There is a link between stability and BE. The greater the BE the more energy you need to break it up. Negative BE means the nuclei are not bound - i.e. no nuclei

  • @dvdmine
    @dvdmine 10 років тому

    A quick question about the binding energy of the nucleus, how can we measure the mass of a neutron if you said that measuring the mass of a proton was so hard to do? Thanks

    • @DrPhysicsA
      @DrPhysicsA  10 років тому

      Actually you can measure the mass of the proton. But the nuclear mass of an atom with several nucleon is is more difficult to measure.

  • @benselemrabab5577
    @benselemrabab5577 8 років тому

    بارك الله فيك

  • @qwertycorno
    @qwertycorno 10 років тому

    Can one say in words that for larger A it becomes favourable to have a bit more neutrons than protons because of the Coulomb repulsion?

  • @divyanshukatiyar8886
    @divyanshukatiyar8886 6 років тому +2

    I really appreciate your efforts towards this video, however, I had a doubt about the dependence of the 5th term on 1/(A^(3/4)). Please clarify.

  • @feelingzhakkaas
    @feelingzhakkaas 9 років тому

    Respected Sir,
    Can the BEnergy be created from empty space ?
    i read somewhere that empty space is not really empty it has tremendous energy ...!!!
    please clarify.

    • @DrPhysicsA
      @DrPhysicsA  9 років тому

      +Prakash Kamath In quantum physics empty space (aka vacuum) can have all kinds of quantum effects including creating and annihilating particles. But where something is created from nothing it does not survive long. In a sense it has to pay back the energy borrowed from vacuum. The more you borrow the faster you have to pay it back.

    • @gmtoomey
      @gmtoomey 9 років тому +1

      +DrPhysicsA "There is enough energy inside the space in an empty cup to boil all the oceans of the world." - Richard Feynman, possibly referring to zero point energy

    • @ZainAli-nz2us
      @ZainAli-nz2us 8 років тому

      i think binding energy is because of the particles attraction.......energy in empty space reffers to the dark energy not to the binding energy....

  • @davidsweeney111
    @davidsweeney111 10 років тому

    Thanks for the video very thorough! So now I know why the isotopic mass number of an element is never an integer, not just because protons and neutrons are not exactly 1u to start with but more importantly their mass decreases because of binding energy keeping the nucleus together. So why did they define carbon to be exactly 12 and have everything relative to that? Because the isotopic mass of 12C isn't actually an integer value is it?

  • @rktiwa
    @rktiwa 10 років тому +1

    missed you.

  • @FrEEloa
    @FrEEloa 6 років тому

    you are a monster, i would like to be like you

  • @pabloo.o1912
    @pabloo.o1912 10 років тому

    Finally after so long

  • @aakashthakur2785
    @aakashthakur2785 9 років тому

    in calculation of binding energy you replaced (ZMp+ZMe)c^2 by (Z*mass of H)*c^2+B.E. of H atom but u have already included B.E. of atom at RHS of the eqn then why we need to include BE of H again

    • @DrPhysicsA
      @DrPhysicsA  9 років тому +1

      At what time in the video does this arise?

  • @mjl7810
    @mjl7810 4 роки тому

    Amazing

  • @asdsa7434
    @asdsa7434 10 років тому +1

    Thank god u're back >

  • @markskilbeck
    @markskilbeck 10 років тому

    Awesome content. I've got to say though... you need a better camera!

  • @sumanpramanick1646
    @sumanpramanick1646 6 років тому

    At 40:10 min you say Geometrical Series, but I think the series is Arithmetic series....

  • @seemaphadke178
    @seemaphadke178 9 років тому

    excellent

  • @cadkls
    @cadkls 10 років тому

    At least I understood the first 25 minutes.

  • @pistolart3302
    @pistolart3302 Рік тому

    دعولنا ننجحو غدوا 😢 لواحد مالغري يسلكها فلاونجلي وهكاك ماسلكهاش مع نووي 💔

  • @pekhoed
    @pekhoed 10 років тому

    if two hydrogen atoms fuse to create helium and release energy in the form of binding energy, then where is the extra energy provided by the fusion reaction??? Obviously, hydrogen bomb releases massive amount of energy. I'm baffled. Help me pls

    • @DrPhysicsA
      @DrPhysicsA  10 років тому +1

      the two hydrogen atoms fuse and lose energy that is to say they give off energy. The energy they give off is positive energy leaving a negative binding energy which holds the helium together. You would have to put that much energy back in again if you wanted to break up helium nucleus.

  • @outofturn
    @outofturn 10 років тому

    thank you

  • @muhieddineshebaro6635
    @muhieddineshebaro6635 9 років тому

    plz somebody answer me. "As binding energy increases,stability increases,isotopic abundance also increases ". Is this statement right plz reply!

    • @DrPhysicsA
      @DrPhysicsA  9 років тому

      Mohieddine Shebaro If BE for a particular isotope is high then it will be stable. But that does not mean that other isotopes (i.e. same p value) will be stable.

    • @muhieddineshebaro6635
      @muhieddineshebaro6635 9 років тому

      thx u sir but can u answer the other comment plz if u see it !

  • @proximorum
    @proximorum 10 років тому

    Great!!!

  • @anujrana2583
    @anujrana2583 7 років тому

    why even and odd case has delta equals 0?

    • @northernskies86
      @northernskies86 7 років тому

      Because for an even odd case, there is only one lone pair but an odd odd case there are more unpaired nucleons.

  • @dhireshyadav1783
    @dhireshyadav1783 7 років тому

    But isn't the lost mass obtained as heat or light energy?? The mass isn't actually lost and is conserved by the appearance of heat or light energy. Then why do we really need Binding energy for the energy-mass balance?? There is heat/light energy to balance it. Isn't it??

    • @DrPhysicsA
      @DrPhysicsA  7 років тому

      The BE is the energy you'd have to put in to the system in order to get the individual nucleons out.

  • @blub232324
    @blub232324 10 років тому +2

    Or you could call it the Bethe-Weizsäcker formula ;)

  • @mustafacubukcu2969
    @mustafacubukcu2969 8 років тому

    thanks

  • @pistolart3302
    @pistolart3302 Рік тому

    عقلي تحرق 🔥🤯

  • @01rai01
    @01rai01 8 років тому +1

    50:13 92 Atoms?
    When was this video made, in the stone age

  • @marksmit8575
    @marksmit8575 6 років тому

    This is not a video to watch at 10 pm

  • @juliocesar4442
    @juliocesar4442 10 років тому +1

    LOL, i thought u have desappeared. I thank god for being wrong.

  • @afzalshigri6549
    @afzalshigri6549 4 роки тому

    Cool

  • @tefade2009
    @tefade2009 10 років тому

    BEST

  • @HTMLbrowser
    @HTMLbrowser 5 років тому

    It would be so much better if he represented the Hydrogen kernel by p+ instead of e+.

  • @brendawilliams8062
    @brendawilliams8062 2 роки тому

    Thankyou

  • @vergil20gaming
    @vergil20gaming 10 років тому +1

    1 hour lol

  • @brendawilliams8062
    @brendawilliams8062 2 роки тому

    Thankyou