Hi Guys, please comment and let me know what you think about this Operations Research Open Course. Your feedback is really appreciated. If you enjoy the video, please subscribe and share. All my replies here are only related to the content in my own videos. I am afraid I won't be able to answer other questions. Thanks for your understanding.
Thank you so much for this. We have online classes and our professor can't discuss this topic and we have to self study to be able to understand the concepts behind this. I am very much grateful for this video, sir. It is very clear, precise and concise. It is very easy to follow and understand. More power!
شكرا جدا لحضرتك الحمد لله فهمت الجزء الخاص بالمدى Before I watched your explanation I couldn't know how we calculate the range but now I understand it from you All thanks from Egypt
Thanks for your videos, the lecture that my prof presents is too abstract and a nightmare to follow with too many proofs. This is much easier to digest with subtitle as well!
Thank you for this! But how would you know the sensitivity ranges for the profit without a given additional value for the max z? Should I just assume? Thank very much!
@@YongWang Hi, thanks so much for this video! IT helped me in most part but there are still some uncertainties that I have. At 5:40, for the optimality range, its -1/2 =< -C1/C2 =< -2. May I ask how did you get the value of -1/2 and -2?
Great question. The optimal range formula does not work in that case. But the basic concept of sensitivity analysis still applies, i.e., how the changes in the rhs or coefficients affect the optimal solution.
Ankit, good question. In that case, you can still calculate the optimal value of the objective function and see how the changes in available resources (which is time in this example) can affect the optimal solution.
Yong Wang thanks for the reply. But we r already working on maximum capacity and increasing one more unit applies that we r exceeding it. In that case only one constraint can be changed. Is it right?
Thanks prof but I have a question when u get the slope 0.5≤c1/c2 ≤2 I didn't get it How did u get it while c1/c2 in this problem 300/200 And thanks again ♥️♥️
Hi, thanks so much for this video! IT helped me in most part but there are still some uncertainties that I have. At 5:40, for the optimality range, its -1/2 =< -C1/C2 =< -2. May I ask how did you get the value of -1/2 and -2? Sorry if this is a dumb question but I just started learning this, still haven't really gotten the hang of it yet.
@@kavishdaya3594 those are the slopes of the constraint equations. You can write each in y intercept form (where x2 would be your y value) and you obtain a slope of -1/2 for m2 and -2 for m1 so the objective value line has to lie within those 2 slope boundaries. Ik its a year later but hope this helps lol
-1/2 is the slope of the first constraint and -2 is the slope of the other constraint. you want your optimum solution to be between these two slopes as they give us the feasible solution area.
I haven't done the calculations myself, but I am fairly certain that it is the value you get from plugging the optimal solution of x1 and x2 into the function max(z)=300x1+200x2
Hi Guys, please comment and let me know what you think about this Operations Research Open Course. Your feedback is really appreciated. If you enjoy the video, please subscribe and share. All my replies here are only related to the content in my own videos. I am afraid I won't be able to answer other questions. Thanks for your understanding.
Very good, thanks!
Can you share ppt?
Thank you, well done Yong !
im not enjoying this course not because of the subject but bcs of my lecturers...i really like operations thinggy but my lecturer makes it worse
This is really good !! The visualization is excellent
Very helpful ty
Thank you so much for this. We have online classes and our professor can't discuss this topic and we have to self study to be able to understand the concepts behind this. I am very much grateful for this video, sir. It is very clear, precise and concise. It is very easy to follow and understand. More power!
شكرا جدا لحضرتك الحمد لله فهمت الجزء الخاص بالمدى
Before I watched your explanation I couldn't know how we calculate the range but now I understand it from you
All thanks from Egypt
One of the best videos on this topic. To the point and very clear explanation, thank you sir.
Wow, I've watch every video by you thus far on OR and you are a scientist and an artist!
Thanks, Brent, for the comments
yong abi saol cok güzel anlatmışsın türkiyeden selamlar öptüm canım
You are welcome, Kerem.
That was very useful to understand shadow prices, thank you :D
Thanks for the comment, Sobiah
noods?
I never comment on study videos, but this was awesome and on point. Thanks!
Love how u make it look easy to understand
Thank you very much. All my problems regarding sensitivity analysis were solved :-)
glad to know it helped, Shavindi
I had difficulty understanding this topic, but the video helped a lot. Thank you.
A very good video, thanks for your effort. I hope that it will help with my exam tomorrow
Thank you so much for your explanations. It's much easier to understand the process now (I was lost in class)
Thank you for this series. It is really impressive.
Thanks for the comment, jhon
amazing video finally I understood shadow and optimal range thanks
Very nice explanation.Thanks for your effort.
No problem, Kayambu.
that was the best explanation, i could get on the subject sir
Oh my god!! You made this topic so damn easy!!!!!!!!!!!!!! Thanks, man.
wow. thanks for the lecture on this topic. am nowb bright enough
Glad you liked it, Peter.
Amazing!!!! videos on operations research. You have a great skill of teaching complex subjects
i'll pass the class thanks to you
Thanks, ufuk
Thank you clear explanation. I have a question. How we determine the profit range to change?how about slack and surplus?
Thank you so much for making such a video. You have taught very good!
I really appreciate your videos, sir.
Thank you so much. Very great explanation
I wish I could like this video twice
Thanks for your videos, the lecture that my prof presents is too abstract and a nightmare to follow with too many proofs. This is much easier to digest with subtitle as well!
very good explanation. it was very helpful. good job
crisp and crystal clear ...
Thanks, Asutosh
Damn my professor did a 2h lecture on this leaving everyone fucking confused and here I find a seven minute video where everything is crystal clear...
Thank you sir. You helped me a lot.
Loved this explaining
Thanks, Mohamed.
Thank you very much, you're my savior!!
Thank you for sharing!!
happy to share
Very nice explanation
thanks, dharmender
useful and easy to understand. thx!
The best explanation! Thanks :)
You are welcome, Asit
Good explanation, thanks
Thank u sir, this really save my credits!
Glad it helped
best video ever
Thank you for this! But how would you know the sensitivity ranges for the profit without a given additional value for the max z? Should I just assume? Thank very much!
Yes, Glady. You can just assume.
@@YongWang Hi, thanks so much for this video! IT helped me in most part but there are still some uncertainties that I have. At 5:40, for the optimality range, its -1/2 =< -C1/C2 =< -2. May I ask how did you get the value of -1/2 and -2?
Hi! Great video - it would be excellent if you could also post the AMPL code to solve the problem.
Thank you. It was helpful
Thanks Sir. It is a very clear and helpful video :)
Thanks
Great video!
Thank you for this video!
You are welcome, Vivioux
Fantastic explanation with corresponding graphics. Thanks for your great work!
Can u be a bit clear on the last point that y should -c1/c2 be within both the slope to maintain optimality.
well done thanks for your work
sir, if the number of the coefficient in the objective function is more than two, does the optimal range formula still work?
Great question. The optimal range formula does not work in that case. But the basic concept of sensitivity analysis still applies, i.e., how the changes in the rhs or coefficients affect the optimal solution.
thanks for your effort. This video is really clear and helpful :))
Thanks
How will you calculate the shadow price if there are more than 2 variables and conduct sensitivity analysis on the objective function coefficients?
Do you have any videos for LP problems that have 3 or more variables? How do we find the slope for 3 variables?
it helps me a lot, thankyou!!!!
you are welcome, Dika
good explanation
Very nice and helpful video. But what if we increase the RHS values of both constraints on the same time?
Ankit, good question. In that case, you can still calculate the optimal value of the objective function and see how the changes in available resources (which is time in this example) can affect the optimal solution.
Yong Wang thanks for the reply. But we r already working on maximum capacity and increasing one more unit applies that we r exceeding it. In that case only one constraint can be changed. Is it right?
Thanks prof but I have a question when u get the slope 0.5≤c1/c2 ≤2 I didn't get it
How did u get it while c1/c2 in this problem 300/200
And thanks again ♥️♥️
Thank you! Very Helpful
glad it helped
Very nice! Thank you!
Glad you liked it, Augusto
how did you find the slope and optimality range? please explain asap
super clear!!!
Thank you! Very much
you are the best
I am? Thanks.
sir thank you much for this :)
Thank you very much Sir
Thanks
Thank you so much!!!
That was dope!
MANY THANKS, SIR!
Thanks, Mia
amazing! thank you so much
you are a legend
Thanks, Gokcen. I wish.
Very nice.
Thanks, Shakeel.
Hi, thanks so much for this video! IT helped me in most part but there are still some uncertainties that I have. At 5:40, for the optimality range, its -1/2 =< -C1/C2 =< -2. May I ask how did you get the value of -1/2 and -2? Sorry if this is a dumb question but I just started learning this, still haven't really gotten the hang of it yet.
alright its okay can ignore this, I think I've found out why haha. But still anw, thanks for the vid!
@@JingZhi45 please tell me how was the values determined im also new to this topic
@@kavishdaya3594 those are the slopes of the constraint equations. You can write each in y intercept form (where x2 would be your y value) and you obtain a slope of -1/2 for m2 and -2 for m1 so the objective value line has to lie within those 2 slope boundaries. Ik its a year later but hope this helps lol
very very helpful vidio
glad you liked it, Fozia
Interesting approach, but it'd have been useful to see the graphical interpretation of the last problem.
thank you very much
You are welcome, N K
what would we do if we are given the value for c1 (100 for example) and not c2 for the optimal range?
Then we can put value of c2 from 50 to 200 bcz by puting these values the optimum solution remains between two slopes
@@foziakhan9791 that's right
How did you get the slopes?
Beautiful!
can you please tell me how you got :-
-1/2>=-c1/c2>=-2
as the optimality range?
-1/2 is the slope of the first constraint and -2 is the slope of the other constraint. you want your optimum solution to be between these two slopes as they give us the feasible solution area.
Thanks, Yash. You explanation is clear and correct. Thumbs up!
god bless you
thanks, Abdulla
Beautiful.
Thank you
What is the shadow price in operation research?
thanks man! much appreciated
Thanks, Rainnie
well explained
thanks for the comment, Xalamukani (trying to spell your name correctly)
Thank you!!
thank u for this!
You are welcome, YH
How did you get A and ZA on 2:10 ?
thanks very very very very much
you are very very very very welcome, Mojahed
thank u sir.
no problem, Samiha
You are a fucking leggend my man I jst learned everything i need for my final in a couple of hours
Does anyone know how to get the ranges for the shadow prices? Thanks
Ahmed, The shadow I mentioned in the video is a value, not a range.
Isn’t the modelling wrong. I mean why didn’t we eliminate numbers of products like number of product 1 produced at machine 1.
Heeeeeelp please T.T can you tell me where the 4000/3 from?
I haven't done the calculations myself, but I am fairly certain that it is the value you get from plugging the optimal solution of x1 and x2 into the function max(z)=300x1+200x2
@@rohatrobinsarac4803 that's right. it's the optimal z value
can you add a video about reduced price ?
basically, you just follow the same procedure for reduced price and resources
perfeeeeeeeect
my academic professor would say less than that in 1 hr that's way too unfeasible for me. thanks
the slope should be C2/C1
5:08
başlık neden türkçe?