AC Power (Full Lecture)
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- Опубліковано 25 січ 2018
- In this lesson we'll examine the different dimensions of AC power, apparent, real, and reactive and we learned to calculate these quantities using a variety of methods. (Full Lecture)
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At 18:32 the arrow for absolute value of reactive power (Q) should be pointing up (rather than down) because reactive power magnitude increases with increased phase shift.
The best lecturer on AC power. No one comes close
Amazing Jim. Thank you for sharing your understanding. I Graduated Electrical Engineering and this was my biggest struggle and everything could have been explained in 1 hour. Thank you again for sharing.
Long story short, thanks for this amazing lecture
Lol 🤣
I love how Jim teaches an entire semester worth of material in an hour
I love this guy
still awesome after 3 years
Excellent explanation.
Thanks
At 18:32 the arrow for absolute value of reactive power (Q) should be up going.
True dat. Good catch. Reactive power magnitude increases with increased phase shift.
I remembering reading in my text book on an obscure measurement called reactive factor which is the opposite of power factor, where in PF 1 is the best value & in RF 0 is the best value. Can you elaborate on this please?
If PF equals cos theta then RF equals sin theta
Why do we take negation of angle after multiplying voltage and current to get apparent power,if it's due to complex conjugate ,why it's like that
The only reason this is done is because inductive reactive power is customarily defined as positive or "consuming" reactive power whereas capacitive reactive power is customarily defined as negative or "supplying" reactive power. The complex conjugate simply gives reactive power the proper polarity.
@@bigbadtech I think what he's asking is why is there an angle sign reversal when you take the complex conjugate of a complex number. Suppose you have S = P + i*Q. We have the polar representation as (P^2 + Q^2)^1/2 < arctan(Q/P). If we take complex conjugate S* = P - i*Q we have polar (phasor) representation (P^2 + Q^2)^1/2 < arctan( minus Q/P). This is a reflection of the angle across the real axis and is equal to (P^2 + Q^2)^1/2 < minus arctan( Q/P). So in taking complex conjugate the phasor remains the same except the angle is now multiplied by -1).
Too hard to understand your voice please make clear voice videos
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@@bigbadtech LOL