Balanced Y Configurations (Full Lecture)
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- Опубліковано 23 лип 2024
- In this lesson we'll discuss general 3 phase AC circuit analysis strategies and take a detailed look at balanced 4 and 3 wire Y configured loads in 3 phase AC systems. We'll examine voltage distribution and current flow through balanced Y configured loads and learn that voltage and current magnitude, relative phase shift, apparent, real, and reactive power are identical for each branch impedance comprising the balanced Y configured load. Additionally, we'll learn a balanced configuration carries no current in the 4th neutral wire. Finally we'll learn a balanced 3 wire Y configured load can be effectively treated as a balanced 4 wire Y configuration simply lacking the 4th wire. (Full Lecture)
MINOR ERROR @ 39:30 - Total apparent power should have an angle of 20 (not 28) 432VA at 20 correctly resolves into 405.9W and 147.8VAR
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Minor error @ 39:30 - Total apparent power should have an angle of 20 (not 28) 432VA at 20 correctly resolves into 405.9W and 147.8VAR
We all appreciate your efforts. Thankyou.
Thank you for the lecture. Clear explanation. Did you do commentary on bf4 official game release?you sound just like the commentator
deserved subscription
Thanks
Hello Jim, Please help me understand how you are using "phasors "or "phasor math" @ 3:57 to get the line to line of 208V. Thank You!
Line to line is the difference between the two line voltages. L1 minus L2. Here's are the lectures that explains the math: ua-cam.com/video/deZ8FCZ3iqY/v-deo.html
hello JIm do you have a lecture for Per-phase analysis with examples?
Check out the 3 phase AC circuit analysis playlist: ua-cam.com/video/RToXdTYQteo/v-deo.html tons of examples including unbalanced configurations
Ditto at 31.26. V3 is 120/_+120°
So in the 4 wire Y connection, does each line produce a current that then splits into the other 2 lines? Or does one line produce its own current which then splits into the other 2 lines?
It's a lot more entertaining than that! All your questions answered here: ua-cam.com/video/6y2buxyJbho/v-deo.html
Hi Jim, thanks for the videos, learning lots from you. In this video you state that because the Neutral currents in a balanced system are zero, that you could just remove the Neutral wire/terminal. But surely you would also need to change the supply voltage, as Line to Line is 1.73 of Line to Neutral? Hence the voltage seen by the loads would be higher if we simply removed the Neutral. Or am I missing something? Thanks
In a balanced configuration lacking a neutral each y configured load still effectively sees the line to neutral voltage.
@@bigbadtech Thanks for taking the time to reply. I watched the lecture again, and also the delta loads lecture. I'm embarrassed to say that I still can't understand what you mean. Is there a simple explanation why taking away the N connection from a 4 wire Y connection is different to a 3 wire Y connection, where the loads see a line to line voltage? Thank you!
Think of it this way, load Z1 and Z2 are in series with each other between L1 and L2. These loads "split" the line to line voltage L1-L2 where the term "split" means a vector split accounting for phase angle. Same thing for L2-L3 and Z2-Z3 and L3-L1 and Z3-Z1. Add it up and it appears as if each load experiences the L to N voltage.
@@bigbadtech Thank you sir, I really appreciate your taking the time to explain this for me. Thank you!
Hallo Sir ! thank you for the awesome lecture, again.
I have a question though, Why does the "3 wire Y" configiration system see a 120v potential difference in balanced condition.
I mean, in previous lecture, we learnt that as 208 V .( because of the line to line potential difference)
Voltage is a two point measurement. You're correct that the "line to line" voltage in a 3 phase AC system might experience 208V, however, there's another point in the center of a Y. Each load in a balanced 3 wire Y experiences line to that center point's differential. Given 3 balanced line to line differentials each load effectively experiences a line to neutral differential of 208/sqrt(3) or 120V.
Hey Jim,
At 39:06, when calculating the VA for Z2, I keep getting 144VA at an angle of -100 degrees. What am I missing here?
Classic problem ... apparent power is calculated using relative phase shift only. In each load current lags voltage by a relative 20 degrees. Check out the AC Power lecture at: ua-cam.com/video/nse2vSlOoME/v-deo.html
@@bigbadtech Got it now. Thank you
At 24:54. V3 is 120V/_+120° and not -120°
Please elaborate @ 11:20. The line-line and line-neutral voltages for the Delta configuration are listed. Doesn't Delta only have line-line voltage?
True. A delta configured load does not experience the line to neutral voltage but rather the line to line voltage ... however ... a Y configuration of sources with a neutral (ie: line to neutral voltages) could be used to supply a delta configured load as the diagram indicates.
@@bigbadtech Thanks.
i REVISE N LEARN ENGLISH AT THE SAME TIME....HHH
So, could you clarify the expression @2:33 "A drearded monster of fearsome repute [....?????.....]"
Like yr style Sir Jim. Doubly teacher.