@@aashsyed1277 that’s a command in latex to make a letter look fancy, and like the way sets are usually written. So instead of Z, Q, F, D, C etc you say \mathbb{letter} to make it look that way
@@aashsyed1277 it iabbreviates "math blackboard bold," I think. It is supposed to correspond to the font that math teachers informally write on the blackboard with an extra vertical line to indicate it is a different typeface from the usual letters.
@@fahim1943 it's simple, you know g^20 != e so g^10 must also, same reasoning applied to g^8 implies g^4,2 != e hence, since the order of an element divides the order of G (40 in this case), you are left with the g^40=e hence G=
Gonna start saying \mathbb instead of boldface
What is mathbb?
What is mathbb?
@@aashsyed1277 that’s a command in latex to make a letter look fancy, and like the way sets are usually written. So instead of Z, Q, F, D, C etc you say \mathbb{letter} to make it look that way
@@aashsyed1277 there’s also mathcal which is used sometimes as well. Diff style
@@aashsyed1277 it iabbreviates "math blackboard bold," I think. It is supposed to correspond to the font that math teachers informally write on the blackboard with an extra vertical line to indicate it is a different typeface from the usual letters.
Can we use Lagrange's theorem to solve question 3?
well lagranges theorem is not told at this point so technically no.
Have you figured how to do it without Lagrange s Theorem?
@@fahim1943 it's simple, you know g^20 != e so g^10 must also, same reasoning applied to g^8 implies g^4,2 != e hence, since the order of an element divides the order of G (40 in this case), you are left with the g^40=e hence G=
!!Spoiler alert!!
Oof apparently Z6x Z3 has 10 cyclic subgroups? :S