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Ans for qus 3 is perhaps wrong here. It should be (a+ab)^+ since the regex in the video is also accepting epsilon which is not desired. Education 4u must post the correct answers in comment box if there is any mistake in the video.
Please write, correct ans, please
third question may be wrong 3:19 ,a(ab)*
I have watched some of the lectures those were very understandable thank you ma'am
In question 3 it should be + instead of a * as we have start a string from a and empty string is not accepted na?
(a+ϵ).(b+ba)*. Mam How to write this regular expression to simple English.
If the R:E: for number 3 is= (a+ba)* then whether it would be wright or wrong?? Plz let me know as soon as you can.
No, that would be wrong. The question says, the language should start with 'a'.
Amazing. Thank you!
Pls can you find the set of strings for the regular expression (aa+b)*and (bb+a)*And also (aa+b)*(bb+a)*.
Great lesson
Miss, in 3 rd exmp, epsilon not accept, any One know correct ans
a(a+ba+ab)*
In the 5th example why can't we write it as (10)*
its because other combination like 100 or 110 will not be accepted by (10)*
Bro, (10)* is totally wrong right here, suppose 10101010, which is a RE of (10)*, then have a look ,there are 01 string inside.
thank you
(0+1)*(11+10+00)Ma'am example no.5th ka R.E esa bhi likhh sktaa ha
I think no bro, 011 is a valid expression for you RE and here 01 string is remaining!
Thqu bhanu mam
2021
error
Hlo
Ans for qus 3 is perhaps wrong here. It should be (a+ab)^+ since the regex in the video is also accepting epsilon which is not desired. Education 4u must post the correct answers in comment box if there is any mistake in the video.
Please write, correct ans, please
third question may be wrong 3:19 ,a(ab)*
I have watched some of the lectures those were very understandable thank you ma'am
In question 3 it should be + instead of a * as we have start a string from a and empty string is not accepted na?
(a+ϵ).(b+ba)*. Mam How to write this regular expression to simple English.
If the R:E: for number 3 is= (a+ba)* then whether it would be wright or wrong?? Plz let me know as soon as you can.
No, that would be wrong. The question says, the language should start with 'a'.
Amazing. Thank you!
Pls can you find the set of strings for the regular expression (aa+b)*and (bb+a)*
And also (aa+b)*(bb+a)*.
Great lesson
Miss, in 3 rd exmp, epsilon not accept, any One know correct ans
a(a+ba+ab)*
In the 5th example why can't we write it as (10)*
its because other combination like 100 or 110 will not be accepted by (10)*
Bro, (10)* is totally wrong right here, suppose 10101010, which is a RE of (10)*, then have a look ,there are 01 string inside.
thank you
(0+1)*(11+10+00)
Ma'am example no.5th ka R.E esa bhi likhh sktaa ha
I think no bro, 011 is a valid expression for you RE and here 01 string is remaining!
Thqu bhanu mam
2021
error
Hlo