Uniform Continuity|Uniform Continuity csir net|Uniform continuity Results|Rahul Mapari real analysis

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  • Опубліковано 13 гру 2024

КОМЕНТАРІ • 137

  • @pi_academy_manipur
    @pi_academy_manipur 4 роки тому +4

    I have never experienced such a great explanation of such a hard topic.👍👍🔥🔥🔥

  • @rashmirajput2850
    @rashmirajput2850 4 роки тому +2

    real itna easy ho sakta h ye bs aapki 3 videos dekh k samjh aa gya...u r amazing sir

  • @justiceforsidhumoosewala6225
    @justiceforsidhumoosewala6225 3 роки тому +1

    Thanks sir , u.c Ko itna achey se explain krney k lea

  • @rajendarnagabathula1929
    @rajendarnagabathula1929 4 роки тому +11

    Thank you sir,u r the great person to help so many people like me.

  • @yashpandey1428
    @yashpandey1428 4 роки тому +1

    thanks sir bahut zayada aacha aap samjha diye again thanks sir

  • @esswarid6223
    @esswarid6223 4 роки тому +1

    Superb video sir , looking for more conceptual and csir net related questions discussion

  • @priyasaharan2787
    @priyasaharan2787 2 роки тому +1

    Thanku so much sir, hope so ke ab question attempt ho jaye ache se

  • @shalinisl8920
    @shalinisl8920 4 роки тому +1

    Excellent sir 👌
    Now I am watching all the lectures on real analysis. Thank you Sir

  • @mathematicsmind8648
    @mathematicsmind8648 4 роки тому +1

    UC clear in 3 amazing videos..
    &
    We r eagerly waiting more from you Sir...

  • @raazkaladhillonuboke4689
    @raazkaladhillonuboke4689 2 роки тому +1

    Sir aap jis b language mein teach kr te o wo buat acha teach kr te o I am from Punjab you are the best teacher 👨‍🏫

  • @mizanurrahaman8687
    @mizanurrahaman8687 4 роки тому +1

    Very Nice Expatiation. Thank You Sir .

  • @Divyakant2341991
    @Divyakant2341991 4 роки тому +2

    you Outstanding and mind blowing superb teaching and I have no words for your teaching method

  • @liveyourlife9232
    @liveyourlife9232 4 роки тому +1

    Great job with great effort

  • @tripling2266
    @tripling2266 Рік тому +1

    Amazing sir, the explanation is amazing, I dont have words to say how much I glad to meet u bcz me humesha se ye topic padna chahati thi but mujhe kabhi samjh hi nahi aaya ya yun kahun kisi ne aap jesa samjhaya hi nahi . You are wonderful at this topic.
    Thanks for clearing my doubts.
    just one request plz make another video with full explanation of connected and compact set with example🙏🙏🙏🙏🙏🙏🙏🙏

  • @thiloshkumarc4153
    @thiloshkumarc4153 4 роки тому +1

    Beautiful explanation sir..

  • @Mathematics-0kset
    @Mathematics-0kset 3 роки тому +1

    Thank you. Sir. It is very helpful for csir net exam..

  • @irshadyatoo3294
    @irshadyatoo3294 4 роки тому +5

    God bless you sir I'm from kashmir if can Qualify NET it s only because of teachers like you as u know we don't have facilities in kashmir but still at 2g speed I am watching ur vedios till late nights 👍👍👍👍👍

  • @biswajitlenka2730
    @biswajitlenka2730 4 роки тому +4

    Thank You sir. You're doing such a great work but your channel is so underrated

  • @mathslearner8251
    @mathslearner8251 4 роки тому +1

    Thank u sooo much sir for all your videos. Its very help me to preparing net exam.

  • @Takhelleii
    @Takhelleii Рік тому

    Very 2 helpful nice explanation

  • @manojkumardandapat2037
    @manojkumardandapat2037 3 роки тому +1

    Thank u Sir...Nice explanation

  • @sourenduacharjya9528
    @sourenduacharjya9528 4 роки тому +1

    thank you lot sir. concept clear ho raha hai

  • @ummeammara113
    @ummeammara113 4 роки тому +1

    Thank u very much sir...u explained uniform continuity concept very well

  • @sasikala8048
    @sasikala8048 4 роки тому +1

    Nice explanation sir

  • @suhailawm
    @suhailawm 4 роки тому +1

    sir language not a problem. easy to understand in your explanation method

  • @jagadishchandradehury6249
    @jagadishchandradehury6249 4 роки тому +2

    This is very helpful, thank you so much Sir.

  • @rashmirajput2850
    @rashmirajput2850 4 роки тому +2

    thanks alot sir,clr hua concept sir bcoz of u,plz make a video on R.I. also

  • @selvarajsabitha3122
    @selvarajsabitha3122 3 роки тому +1

    Good job sir

  • @sudhalakshmi7315
    @sudhalakshmi7315 4 роки тому +1

    Thank you so much sir very clear explanation..I don't know hindi but I understood ur way of teach 🙏

  • @umashankarsahu8649
    @umashankarsahu8649 4 роки тому +1

    Thank You so much Sir for all the three videos. It will really be helpful in my preparation.

  • @sahilsethi4644
    @sahilsethi4644 4 роки тому +1

    Thank you so much sir for make me understand the concept of UC

  • @shalu4839
    @shalu4839 4 роки тому +1

    Sir thanku so mch

  • @jalaluddinmondal990
    @jalaluddinmondal990 4 роки тому +1

    Thank you sir.plz make more videos on Abstract algebra for CSIR NET and SET.

  • @aditimaurya3935
    @aditimaurya3935 3 роки тому +2

    Thank you sir ... You explained very well.
    Also please make a video on REIMANN INTEGRAL for IIT JAM🙏🙏🙏

  • @sherifkaja2333
    @sherifkaja2333 4 роки тому +1

    Thank you so much sir. Very nice explanation. 👍

  • @dr.harisankars6433
    @dr.harisankars6433 4 роки тому +1

    Thank you very much sir

  • @MathByManoj-he2iw
    @MathByManoj-he2iw 4 роки тому +1

    Thanks sir ji 🙏🙏 🙏 for this types of lectures...😊

  • @AB_K96
    @AB_K96 4 роки тому +1

    Thanks U sir
    providing Teaching ✌️

  • @amandeepkaur6997
    @amandeepkaur6997 4 роки тому +1

    very well explained

  • @dr.vinodchandra5926
    @dr.vinodchandra5926 4 роки тому +1

    thankyu so much sir.. for helpful vdos.

  • @omkar1070
    @omkar1070 Рік тому

    Well explained sir ❤❤❤❤

  • @mathematicsmind8648
    @mathematicsmind8648 4 роки тому +1

    UC clear ho gaya Sirji.. 😍😍🙏🙏🙏

  • @rashmihr1074
    @rashmihr1074 4 роки тому +1

    Tq so much sir🙏🙏🙏

  • @mithunbapari5361
    @mithunbapari5361 4 роки тому +1

    Great Sir 🙏🙏🙏

  • @shalinisl8920
    @shalinisl8920 4 роки тому

    Excellent sir 👌
    Thank you Sir

  • @risingmathematics2864
    @risingmathematics2864 4 роки тому +1

    Very helpful sir. Thank you.

  • @akankshajangid6335
    @akankshajangid6335 4 роки тому +1

    Sir plz function of bounded variation..

  • @nehapandey5845
    @nehapandey5845 4 роки тому +1

    Thnku sir ,it's very helpful

  • @rainalaha6150
    @rainalaha6150 4 роки тому +1

    Thank you sir.
    Sir , pls make video about metric space pls.🙏

  • @ashtaniprajapati
    @ashtaniprajapati 4 роки тому +2

    Thank you sir

  • @himani8965
    @himani8965 3 роки тому +1

    Thank you toh hum bolenge Sir. Thank you

  • @usmanaziz7087
    @usmanaziz7087 4 роки тому +1

    Most authenic knowledge u have sir love from pakistan ♥️♥️♥️♥️♥️♥️♥️💕💕💕

    • @RahulMapariBasicMaths
      @RahulMapariBasicMaths  4 роки тому +3

      Thank u very much.. I think, it's a beauty, power and respect of Mathematics that, u send me love from Pakistan..
      I salute to Mathematics...

  • @sajhijana2211
    @sajhijana2211 4 роки тому +1

    Thank you sir thank you soo much

  • @soumenpati4133
    @soumenpati4133 4 роки тому +1

    Thank you so much sir... really you are a great 🙏❤️... this is very helpful for us

  • @sangitasaha4228
    @sangitasaha4228 4 роки тому +1

    Thank you soo much sir!

  • @NeelamYadav-cq4bd
    @NeelamYadav-cq4bd 3 роки тому +1

    Thanks sir

  • @ritikashrivastava8773
    @ritikashrivastava8773 2 роки тому

    Thankyou so much sir..🙏🙏

  • @rubinasahoo8238
    @rubinasahoo8238 2 роки тому

    Tq so much sir it is very helpful

  • @inkuydv6549
    @inkuydv6549 3 роки тому

    Sir plz make videos on function of bounded variation with previous yr questions 🙏

  • @periyanayaki6999
    @periyanayaki6999 4 роки тому +1

    Thank u so much sir

  • @liveyourlife9232
    @liveyourlife9232 4 роки тому +2

    Thank you

  • @devakibadekkila7164
    @devakibadekkila7164 4 роки тому +1

    Thank you very much sir:)

  • @pakvlog379
    @pakvlog379 11 місяців тому

    Dense set
    If A cluser is equal to R then A is called dense not limit point
    On the other hand
    If A'=R then A is called perfact set .

  • @komalkumar5073
    @komalkumar5073 4 роки тому +1

    Thanks u sir, it is very helpful for me. Plz make more videos on ode n pde

  • @pankajkajal9622
    @pankajkajal9622 2 роки тому

    Thnku sir🥰

  • @pradeepdholpuria986
    @pradeepdholpuria986 4 роки тому +2

    Pls sir make videos on linear algebra..🙏🙏

  • @dr.ramswroopswami8101
    @dr.ramswroopswami8101 4 роки тому +1

    Nice sir

  • @tapasnaskar52
    @tapasnaskar52 4 роки тому +1

    Sir I think your definition of connected set is the definition of convex set.
    For convex set joining line must be straight line,for connected set joining line may be curved line ie there must be a connection between these two points....

    • @RahulMapariBasicMaths
      @RahulMapariBasicMaths  4 роки тому

      U r right. That's why I have not given technical or bookish definition. It is just to understand the concept.

  • @kanimozhi2268
    @kanimozhi2268 4 роки тому +1

    Pls make vedios on uniform convergent like this..

  • @Vikas_85
    @Vikas_85 4 роки тому +1

    l am very thankful to u sir,
    The concept of uc was well explained.
    Please make videos on connectedness and problems occurred on connectedness in csir exam🙏

  • @rajkaram4026
    @rajkaram4026 4 роки тому +1

    Tq so much sir

  • @NOORALAM-kz4nb
    @NOORALAM-kz4nb 4 роки тому +1

    Please Sir bounder variation k question banao

  • @gulshanjoshila3756
    @gulshanjoshila3756 4 роки тому +1

    Thank u sir

  • @sripad72
    @sripad72 3 роки тому +1

    Rahul ji, u said since
    lim sin(1/x) does not exist as x tends to 0, it is not UC, but limsinx as x tends to infinity doesn't exist, however it is UC. Can u please clarify

  • @charudattashinde4732
    @charudattashinde4732 4 роки тому

    sir kya aapka whatsapp group he net or nbhm ke exams ka..

  • @nilanjana1346
    @nilanjana1346 4 роки тому

    When interval is zero to infinity then what happen? In this case at infinity limit exists is important?

  • @sanjithar2355
    @sanjithar2355 4 роки тому

    Sir, results except Cauchy test is not necessary right?

  • @Kiran-vd7gf
    @Kiran-vd7gf 3 роки тому

    Sir , how we can say that if limit does not exist at end points then function is not uniformly continuous
    eg. f(x)=x is uniformly continuous on(1,infinity ) but limit at infinity do not exist.

  • @murthymechi4296
    @murthymechi4296 3 роки тому +1

    🙏🙏🙏

  • @aliusmansahib9379
    @aliusmansahib9379 Рік тому

    Sir g agr 1/x ko open interval (1 infinity)mei ly to yh b uc nai hona chye same jis trha (0 1)mei Lya hai q k (1 infinity)mei b 1 include to nai hai hm es k kreeb jitni cahay CHOTI value ly skty hai bsss dusry wlai trick sy to yh uc hogaaa kindly plzzz sir clear kr dy reply kr k yh bht concfuse kr rwha hai point

    • @aliusmansahib9379
      @aliusmansahib9379 Рік тому

      Q k xy to 1 k kreeb jitni CHOTI value dy gy 1xy itniii Badi value dy gaaa to phr yh uc nai honaa chye per dsury wlay method Sy yh uc bn jataa hai

  • @subratagorai6612
    @subratagorai6612 4 роки тому

    Sir f(x) = exp(x) cos(1/x) is uniformly continuous on (0,1) ???? Please give reasons......

  • @sanjaypaul4869
    @sanjaypaul4869 4 роки тому +1

    Limit does not exist . Not UC
    Is it an iff condition?

  • @HarpreetSingh-bt5vb
    @HarpreetSingh-bt5vb 3 роки тому

    I think closure of A must be R for dense

  • @niketachoudhary247
    @niketachoudhary247 3 роки тому

    Hello...sir
    If we do second question with interval (0,1) by using theorem that f is u.c. if it's derivative is bounded on (0,1) then it is not true for x.sin1/x

  • @SRMaths-sr7mg
    @SRMaths-sr7mg 2 роки тому +1

    👍👍👍👍❤️❤️❤️❤️❤️

  • @AbhaySingh-wk3vg
    @AbhaySingh-wk3vg 4 роки тому

    Sir tan πx/2 ko jab 1- krke chk ki h limit so x ko 1 Kyu rkh Diya,smjh Ni aaya mujhe

  • @lovelypari373
    @lovelypari373 4 роки тому

    Sir if we can prove that the function is Lipschitz function then it will be uniform continuous??? Can we prove by this method? Is there any limitations of Lipschitz function?

  • @soundharyadevik9694
    @soundharyadevik9694 2 роки тому

    Sir I need english language...I cant able to understand....

  • @mantashawani7959
    @mantashawani7959 3 роки тому

    Sir e^x (0,1) py U.C hai ya nahi? Plz reply

  • @stevenabakash919
    @stevenabakash919 7 місяців тому

    U said the definition of convex set

  • @vineethsasi1985
    @vineethsasi1985 4 роки тому +1

    Sir please explain the definitions in English

  • @rimaauliarahayu
    @rimaauliarahayu 3 роки тому

    for f(x)=e^x if xn= ln (n) and yn= ln (n+1) then |xn-yn| -> 0 but |f(xn) -f(yn)| =1 > epsilon. so e^x non uniform continu. am i wrong?

    • @akash105a
      @akash105a 2 роки тому

      Mod of substitution of the function of those points has to be less than epsilon for mod of substitution of the points less then delta

  • @akash105a
    @akash105a 2 роки тому

    Sir if a function f is closed and bounded on an interval then also it said to be a uniform continuous. Isn't it?
    If it's true then why f = x^2 is u.c when x €R

    • @RahulMapariBasicMaths
      @RahulMapariBasicMaths  2 роки тому

      x^2 is not UC on R

    • @akash105a
      @akash105a 2 роки тому

      @@RahulMapariBasicMaths sorry sir the function is f = x

    • @RahulMapariBasicMaths
      @RahulMapariBasicMaths  2 роки тому

      @@akash105a ok. Now, stat: if function is continuous on closed and bdd interval is UC. It's a sufficient condition and not necessary.

    • @akash105a
      @akash105a 2 роки тому

      That means on intervals which aren't closed and bounded there are some functions which are uniformly continuous while others are not.

  • @AjayGupta-ps8mt
    @AjayGupta-ps8mt 4 роки тому +1

    function e^x is U.C. in R or not

  • @nareshwagh751
    @nareshwagh751 Рік тому

    Sir u told that if limit comes infinity then it is existing infinitely in singularity topic but here u r saying it doesn't exist 🤔

  • @rozil2763
    @rozil2763 4 роки тому

    Lim tends to 0 of Sinx/x is 1 by rule
    But cosx/x is not how please explain sir

    • @Vikas_85
      @Vikas_85 4 роки тому +1

      Because it is not a indeterminate form
      L hospital's rule

  • @bishnu3170
    @bishnu3170 4 роки тому

    Sin(x) is UC on (0,1)

  • @rachnayadav612
    @rachnayadav612 Рік тому

    It's wrong this statement is not vice-versa... Only U.C can be proved ...we cannt claim that function is not U.C by this result

  • @jishanalam007
    @jishanalam007 2 роки тому +1

    Sir R closed set hota h

  • @Sachin-is5oc
    @Sachin-is5oc 2 роки тому +2

    Speak hindi