Interatomic Forces & Energy Curves {Texas A&M: Intro to Materials}

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  • Опубліковано 19 січ 2025

КОМЕНТАРІ • 50

  • @odstknight00
    @odstknight00 8 років тому +6

    This video is so help full, you are saving my intro to strengths grade, thank you and please keep the content coming.

  • @onyangoachieng9178
    @onyangoachieng9178 5 років тому +5

    What an instructor! This is superb. Kenya

  • @droy08_INDIA
    @droy08_INDIA 2 роки тому +1

    Thanks Very Much Helpful I Was Confused And Was Curious To Understand Deeply about Elasticity In Terms Of Interatomic force.

  • @the_lord7961
    @the_lord7961 3 роки тому +1

    Thank you so much for making these videos. Everything makes sense now oml

  • @mr.rachetphilanthrophist601
    @mr.rachetphilanthrophist601 6 років тому +2

    very very very nice explanation ,very knowledgeable teacher you are , i have always been confused in these two curves now you made it clear ........thank you

  • @LonDanDoc
    @LonDanDoc Рік тому

    Prof you are a life saver . Owe you a cold one 👍🏾

  • @davysong9488
    @davysong9488 5 років тому +6

    thank you so much! this is absolutely helpful even for my gen chem class!

  • @hungdo4611
    @hungdo4611 6 років тому +1

    This presentation is completely correct. Nothing is wrong here!

  • @KLCII88
    @KLCII88 6 років тому +1

    Very clear video, just like the others. Thank you so much for the effort you put into these.

  • @iengineer.1686
    @iengineer.1686 5 місяців тому

    Crystal-clear to understand, but I have a question about the Force-radius curve. Why does the force-radius curve start from positive force to negative force. While other literatures draw starting from the negative force to positive?

  • @samgu1930
    @samgu1930 6 років тому +3

    THANK YOU SO MUCH !!! It is really aid for me so much

  • @BaldurKhr
    @BaldurKhr 4 роки тому +2

    Such an easy to grasp lecture. Thank you!
    I imagine atoms as small balls and the electric forces as a compressed spring that tries to split them apart and a tensioned elastic rubber passing right through the middle of the spring which opposes the spring and holds the atom not to depart. Because of the elasticity of the spring and rubber, the atoms are also vibrating.
    Though i don't quite understand, when fire its taking place, why CO2 gains so much speed after recombination?...

  • @fozansharfulhaque1973
    @fozansharfulhaque1973 Рік тому

    Wow such an amazing lecture thank you prof

  • @ahmedtareq3787
    @ahmedtareq3787 Рік тому

    Very informative, Thanks professor 💯

  • @hugom6388
    @hugom6388 11 місяців тому

    They could add on those energy graphs the point (or distance) at which the material changes state.

  • @monicasenese2839
    @monicasenese2839 3 роки тому +1

    Amazing lecture, thank you so much

  • @anashayajneh9510
    @anashayajneh9510 3 роки тому

    you are way better than my teacher👍

  • @wolf.of.scbd14
    @wolf.of.scbd14 4 роки тому

    thank u mister it's helpful for my study

  • @lostinthoughts13
    @lostinthoughts13 6 років тому

    So as we approach zero,we will need to put more and more energy in order to seperate atoms,but ther is a point where we will actually get energy when atoms are seperated (that is when repulsive forces overcome attractive forces) is this correct ?

  • @vijay6543211
    @vijay6543211 5 років тому

    Helped me in knowing about fundamental topics.

  • @aakaspokhrel9254
    @aakaspokhrel9254 3 роки тому

    Thank you myan for this

  • @MakeMeScientific
    @MakeMeScientific 6 років тому +1

    Excellent explanation sir.
    #makemescientific

  • @serisingh
    @serisingh 3 роки тому

    I was hoping he would derive the modulus from the force gradient! My homework asks for the complete derivation, and of course it wasn't covered in my lecture.

  • @Scruffyx56
    @Scruffyx56 3 роки тому

    thank you for the explanation.

  • @sivakumar-ns7pk
    @sivakumar-ns7pk 5 років тому

    What about the magnitude of bonding energy with respect to the potential well?

  • @ashuemmanuel2019
    @ashuemmanuel2019 3 роки тому

    Thanks sir you've been helpful

  • @DoctoreDoom
    @DoctoreDoom 6 років тому

    Amazing thanks for uploading X)

  • @drscott1
    @drscott1 7 років тому +1

    Is not the Coulomb force 1/r squared?

    • @siddharthvyas3078
      @siddharthvyas3078 7 років тому +1

      He is talking about Coulombic potential energy not the force, energy is = (force x distance), so the formula is correct

    • @drscott1
      @drscott1 7 років тому

      Siddharth Vyas now I see he wrote V and not E. Thanks

  • @nicholasmerino9608
    @nicholasmerino9608 2 роки тому

    There’s a variable involving (x)
    Assume x is a variable rate f(y)
    X simply would assume a y constant
    How’s that… y is the dividend

  • @toughguy9886
    @toughguy9886 7 років тому

    Big thanks Dr.

  • @nicholasmerino9608
    @nicholasmerino9608 2 роки тому

    And If y is the divider nf

  • @pingwin2740
    @pingwin2740 7 років тому +2

    oftentimes

  • @pinkybananas1
    @pinkybananas1 8 років тому

    thank you

  • @nicholasmerino9608
    @nicholasmerino9608 2 роки тому

    Of a another X(Y) derivative

  • @mrgreatdude2
    @mrgreatdude2 8 років тому +6

    The force curve seems to be incorrect

    • @mochfakhrizal1478
      @mochfakhrizal1478 7 років тому +2

      i think so. cause at r approach to zero it must be up curve. am i right?

    • @naziajasmeen4203
      @naziajasmeen4203 6 років тому

      YAP!

    • @pjshamberger
      @pjshamberger  6 років тому +5

      Howdy! While energy has an absolute scale (lower energy is more stable), force depends on your coordinate system and on whether you're looking at the force of 'A on B' or 'B on A'. As I did not define the picture completely, and identify **which** force we're talking about, this could either be as shown, or with the sign of force reversed. For this reason, at the level of this video, it's easiest to think about this in terms of "attractive" or "repulsive" force, as labeled (at ~7:40).

  • @shashikantmishra4460
    @shashikantmishra4460 11 місяців тому

    From india❤

  • @nirupamanaik1207
    @nirupamanaik1207 5 років тому

    Tkh

  • @nicholasmerino9608
    @nicholasmerino9608 2 роки тому

    Calculus

  • @nicholasmerino9608
    @nicholasmerino9608 2 роки тому

    There would be a magnitude

  • @김치킨-c2e
    @김치킨-c2e 5 років тому

    ㅋㅋ 꼬우면 안동대오셈

  • @youngsukkim881
    @youngsukkim881 5 років тому

    This explanation is just imaginary. Although interatomic forces between atoms are not zero, the explanations given in this video show that the interatomic forces between atoms are zero when the interatomic distrance is set at equilibrium. In fact, it seems to remain unclear what determines the magnitude of interatomic forces acting between atoms in solids.

  • @aricirwin7631
    @aricirwin7631 9 років тому +2

    Good presentation and great information but you said "Uh" or "Um" 15 times in the first 3 minutes. Huge distraction and all i could do is count crutch words. Sorry

  • @glacieg2640
    @glacieg2640 2 роки тому

    thank you sir