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Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Nice explanation but i have one doubt that you said that after output current became zero then capacitor got discharged but how is this even possible as SCR doesnot support conduction in reverse direction. Please explain!
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One question. At the end the capacitor is discharging. But the scr is turned off. So how will it discharge as there is no closed path as turned off scr means open circuit
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Please can you explain how the current is decreasing when capacitor gets charged upto VS, though the direction of current is the same as in the previous case.
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
I am not understanding when capacitor gets charged upto VS, then the direction of current flow is in the same direction as the previous, then how current will decrease.
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
Sir main dought is if we want to turn off the SCR then we want to Connect L and C are in underdamped mode? Or At the start of the circuit it will be in under damped mode? Pls explain this
I have one doubt , in control system for resonant frequency you mentioned as omega r = root of 1-(2zetta^2), but here you mentioned as omega r =. Root of 1-zetta^2. Why here not 2 zetta square?
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Your explanation made me interest to study subject 👍
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
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Loved it. Tomorrow i am having power electronics internal
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Nice explanation but i have one doubt that you said that after output current became zero then capacitor got discharged but how is this even possible as SCR doesnot support conduction in reverse direction.
Please explain!
Didn't get your question dear.
@@EngineeringFunda if scr isn't bidirectional how does capacitor current flow?
SCR in reverse baising behave like an open circuit and it having high resistance that's why voltage tends to infinite across SCR.
Staring we study the underdamped
RLC circuit. Current flows same as underdamped graph my dear frnd
Very good explanation in simple steps.
Thanks
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
One question. At the end the capacitor is discharging. But the scr is turned off. So how will it discharge as there is no closed path as turned off scr means open circuit
i also have doubt about this....
Thank you sir for the excellent explanation
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
Sir,in the waveforms how can scr current become negative?
Please can you explain how the current is decreasing when capacitor gets charged upto VS, though the direction of current is the same as in the previous case.
Because inductor energy start to decreasing so current decreasing and capacitor further charge with same polarity
I have a doubt sir, i.e. Class E commutation is categorised under which type?
Thank u so much sir for this helpful video.
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
I am not understanding when capacitor gets charged upto VS, then the direction of current flow is in the same direction as the previous, then how current will decrease.
Sir very good explanation, keep it up
Thanks and welcome
Ache se smjh aa gya,thankuu
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
@@EngineeringFunda keep it up sir, u r doing a grt job🙏
I have a dought Is the capacitor will allows the dc?
No
How did you even derive those equations from the previous da? Can’t you explain that?
Very useful class sir👍
Your positive comments motivates me, Thanks and welcome 🙏
U did not explain how the capacitor got discharged, how the voltage decreases to zero in capacitor.....
Why is the current flow still the same when inductor is releasing energy
Sir main dought is if we want to turn off the SCR then we want to Connect L and C are in underdamped mode? Or At the start of the circuit it will be in under damped mode? Pls explain this
L C oscillation means it is critical damped system.
can not understand ta laplace transform plz help me
thank you sir. I am from Bangladesh
Your positive comments motivates me.
Sir impulse communication related to classes D, not for class C
I have one doubt , in control system for resonant frequency you mentioned as omega r = root of 1-(2zetta^2), but here you mentioned as omega r =. Root of 1-zetta^2. Why here not 2 zetta square?
❤️
Your welcome 🙏
@@EngineeringFunda your videos are very useful sir we had completed 3 units by watching the classes of yours
But I have a doubt,how can we apply dc across l or c element
You can apply DC across L and C elements, where L will act like short circuit and C will act like open circuit as if you connect DC across it.
Perfect Explanation 👌
Glad you think so!
waveform smjh nahi aayi
Where can I get this ppt?
Thank you sir
Thanks and welcome
Bro e kaanum 3:03
Thank you sir
Your positive comments motivates me, Thanks and welcome 🙏
Thank you sir
It really helped me a lot
Bro e kaanum 3:03