Integral of 1/(e^x - e^-x) (substitution + partial fraction decomposition)

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[@fabriziorodriguez908]

Thanks. Nice video.

[@IntegralsForYou]

Thank you! 😎

[@Nightingale-s3t]

You are amazing!

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[@shvix_akb8531]

thank you!!!

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You're welcome! 😊

[@nafisaafrin6758]

!

[@IntegralsForYou]

😊

[@djnanduff2914]

Answer is wrong,,, answer is tan^-1(e^x)

[@IntegralsForYou]

The derivative of tan^-1(e^x) is e^x/(1+e^(2x)). I think you did the integral of 1/(e^x + e^-x) instead of 1/(e^x - e^-x) 😉

[@nodistractions3633]

@@IntegralsForYou very humble answer and way of correcting the primary commenter.. Love you!😍😘

[@IntegralsForYou]

@@nodistractions3633 Thank you! 💪❤