Solving Equations Involving Modular Arithmetic - a = b(mod c) | SHS 2 CORE MATH

[@alinekeah3894]

I understand your work correctly. Good teaching.

[@SkanCityAcademy_SirJohn]

Thanks so much

[@OkeneJeremiah-i2q]

Good explanation. Thank you sir

[@SkanCityAcademy_SirJohn]

Thanks so much

[@DekuBernice-wz2rw]

It was very easy but at a point it was quite confusing but I got what I was in search of.

[@SkanCityAcademy_SirJohn]

Oh okay. Thanks anyway

[@rosenobert2801]

God bless you. Thank you so much sir.

[@SkanCityAcademy_SirJohn]

You're most welcome Rose

[@AlhajiAjalloh-j1p]

May God bless you sir

[@SkanCityAcademy_SirJohn]

Thanks so much

[@GideonOgbuehi]

In question 4 y did u not use 87 which when added to three gives 90?

[@SkanCityAcademy_SirJohn]

Yes actually that's a smart move. Thumbs up 😎

[@stanleynnajiofor9548]

Thanks alot... You did a great job

[@SkanCityAcademy_SirJohn]

You are most welcome

[@vivianakoley6799]

Adding 3 to 87= 90 which is divisible by 5.

[@SkanCityAcademy_SirJohn]

do you have a question on that, if yes, kindly specify the time stamp in the video, so i check and get back to you

[@vivianakoley6799]

@@SkanCityAcademy_SirJohn oh it's the very last question.

[@SkanCityAcademy_SirJohn]

Yes, you can add 3 to 87, to get 90 and solve with that. It's also correct, I just wanted us to know how to manipulate our answer to get a positive number when we obtain a negative value.
Whichever way you do it, you will still arrive at the same answer.

[@SkanCityAcademy_SirJohn]

Thanks so much, where do you school?

[@vivianakoley6799]

@@SkanCityAcademy_SirJohn St.Monica's senior high school. Ashanti- Mampong.

[@PMe-my1td]

Would be great if there was an example with large numbers e.g., 125452x - 4 = 4 mod 15044

[@SkanCityAcademy_SirJohn]

Okay

[@fideliaologunleko5243]

Sir we can add 5 to 87 which gives us 90 and 90 is divisible by 5 but this is what happened when I did it.
5x=3 mod 29
5x=3+87(mod 29)
5x÷5=90÷5
x=45 mod 29
And since 45 is greater than 29 we then divide.45÷29=1 r 16.
Therefore x=16 mod 29
I am not sure sir please help me explain. Thank you sir.

[@SkanCityAcademy_SirJohn]

Nice try, but there are some corrections
You add 87 to 3 making 90.
5x = (3+87)mod 29
5x/5 = (3+87)/5 mod 29
x = 18 mod 29

[@SkanCityAcademy_SirJohn]

Are you Nigerian?

[@fideliaologunleko5243]

@@SkanCityAcademy_SirJohn Yes Sir.
13years in Senior Secondary 1

[@fideliaologunleko5243]

@@SkanCityAcademy_SirJohn WOW!!! Thank you Sir.

[@fideliaologunleko5243]

Please sir, can I get on touch with you through whatapp message?

[@WisdomAmedozi]

God bless you

[@SkanCityAcademy_SirJohn]

Amen, and good luck too

[@Techno_Whizz]

Thanx sir,

[@SkanCityAcademy_SirJohn]

Most welcome

[@alexandersam3903]

Tnks man..🤝

[@SkanCityAcademy_SirJohn]

youre welcome

[@AlhajiAjalloh-j1p]

I want to offer five subjects like, further math, physics, chemistry and biology

[@SkanCityAcademy_SirJohn]

I see

[@deborahokyereboatemaa5228]

GF

[@SkanCityAcademy_SirJohn]

please whats GF

[@omardinhoR9]

Very good

[@SkanCityAcademy_SirJohn]

Thanks so much

[@omardinhoR9]

@@SkanCityAcademy_SirJohn no bro Thank you. Whats your profession?

[@SkanCityAcademy_SirJohn]

An engineer